blocks|key|4543812|text|角度(也称为直线的斜率)的公式如下：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4543813|angle+=+Math.atan((y2+-+y1)+/+(x2+-+x1))|code-block|syntax|javascript|4543814|其中：(x1，y1)是第一个点(直线起点)的坐标，(x2，y2)是第二个点(直线终点)的坐标|4543815|另外，请注意角度是以弧度为单位返回的，因此如果您需要以度为单位获取角度，则需要乘以180，再除以PI：|4543816|angleInDegrees+=+angle+*+180/Math.PI;|4543817|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

The formula for the angle (also called the slope of the line) is as follows:

<pre><code>angle = Math.atan((y2 - y1) / (x2 - x1))
</code></pre>

Where: (x1,y1) are the coordinates of the first point (start of line) and (x2,y2) are the coordinates of the second point (end of line)

Also, note that angle is returned in radians so if you need to get the angle in degrees you need to multiply by 180 and divide by PI:

<pre><code>angleInDegrees = angle * 180/Math.PI;
</code></pre>

blocks|key|1526956|text|你用你的公式得到了这条线的终点，这条线是正确的。你只需要反转这个方程式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1526957|tan(theta)+=+opposite+/+adjacent|code-block|syntax|javascript|1526958|这就给出了：|1526959|angle+=+arctan(opposite+/+adjacent)|1526960|其中，反方向是高度(y)，相邻方向是长度(x)。|1526961|要小心，因为当相邻的值为零(除以零)时，它就会崩溃，arctan会为零本身抛出一个异常，所以你需要捕获垂直或水平的线的特殊情况。|1526962|正如Miky+D指出的那样，角度是以弧度表示的，但无论如何，您可能需要以这种形式来计算箭头的角度。|1526963|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|W|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

You're on the right lines way there with your formula for getting the end point of the line. You just need to invert the equation:

<pre><code>tan(theta) = opposite / adjacent
</code></pre>

Which gives:

<pre><code>angle = arctan(opposite / adjacent)
</code></pre>

Where the opposite is the height (y) and adjacent is the length (x).

Be careful as this breaks down when the adjacent is zero (divide by zero) and arctan will raise an exception for zero itself, so you need to trap the special cases of the line being vertical or horizontal.

As Miky D points out the angle is in radians, but you'll probably need it in that form for calculating the angle of the arrow head anyway.

blocks|key|1528885|text|每个人都在建议使用Math.atan()的公式，给出了分母中0种情况的警告。已经有一个完整的函数可以做到这一点--它是Math.atan2()。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1528886|只需传入一个X和一个Y值，它就会给出一个角度。没有特殊情况--只有坐标。通常，返回值以弧度表示，从-pi到%2Bpi。|1528887|entityMap|0|LINK|mutability|MUTABLE|url|http://livedocs.adobe.com/flash/9.0/main/wwhelp/wwhimpl/common/html/wwhelp.htm?context=LiveDocs_Parts&file=00001820.html|1|http://livedocs.adobe.com/flash/9.0/main/wwhelp/wwhimpl/common/html/wwhelp.htm?context=LiveDocs_Parts&file=00001821.html^0|9|B|0|1N|C|1|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@$A|Q|B|R|1|S]|$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|-4|5|6|7|X|8|@]|9|@]|C|$]]]|G|$H|$5|I|J|K|C|$L|M]]|N|$5|I|J|K|C|$L|O]]]]

Everyone is suggesting formulas using <a href="http://livedocs.adobe.com/flash/9.0/main/wwhelp/wwhimpl/common/html/wwhelp.htm?context=LiveDocs_Parts&amp;file=00001820.html" rel="nofollow noreferrer">Math.atan()</a>, giving caveats for 0 cases in the denominator. There's a whole function that already does this -- it's <a href="http://livedocs.adobe.com/flash/9.0/main/wwhelp/wwhimpl/common/html/wwhelp.htm?context=LiveDocs_Parts&amp;file=00001821.html" rel="nofollow noreferrer">Math.atan2()</a>. 

Just pass in an X and a Y value, and it gives you an angle. No special cases -- just coordinates. As usual, the return value is in radians, from -pi to +pi.

How can I find the Angle of a line between two points in actionscript 3.

I have an object that dynamically animates out arrows, given the points that represent start, elbows, and then end point.

I need the angle of the line to rotate the arrow at the tip to accurately point with the current segment being drawn

I can easily get the angle for right angled lines by detecting if one axis is 0 but need the angle of any line between two points.

I'm familiar with getting the Points for a line e.g. draw a 100px line at 47 degrees:

<pre><code>var length:Number = 100;
var angle:uint = 48
graphics.lineTo(Math.cos(angle) * length, Math.sin(angle) * length);
</code></pre>

but am struggling to get the angle from the line:

what I need is

given start point and end point of a line, what is the angle of the line.

many thanks for any and all suggustions

Actionscript Angle of a Line Trig

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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