blocks|key|481893|text|从您引用的站点：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|481894|481895|所有https应用编程接口都需要https请求和/v1+-Auth。|blockquote|481896|481897|481898|HTTP-Auth是在基本身份验证中使用的头部。|offset|length|style|CODE|481899|在Java中，您可以简单地将凭据放在URL中：|481900|http://user:pass@www.example.com/|code-block|syntax|javascript|481901|您可以使用URL.getUserInfo()方法验证它是否设置正确。|481902|entityMap^0|0|0|0|0|0|0|9|0|0|0|5|H|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|10|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|11|8|@]|9|@]|A|$]]|$1|G|3|-4|5|6|7|12|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|13|8|@$J|14|K|15|L|M]]|9|@]|A|$]]|$1|N|3|O|5|6|7|16|8|@]|9|@]|A|$]]|$1|P|3|Q|5|R|7|17|8|@]|9|@]|A|$S|T]]|$1|U|3|V|5|6|7|18|8|@$J|19|K|1A|L|M]]|9|@]|A|$]]|$1|W|3|-4|5|6|7|1B|8|@]|9|@]|A|$]]]|X|$]]

From the site you referenced:

<blockquote>
 All /v1 api's require https requests and HTTP-Auth.
</blockquote>

<code>HTTP-Auth</code> is header used in basic authentication. 
In Java, you can simply put your credentials in the URL:

<pre><code>http://user:pass@www.example.com/
</code></pre>

You can verify that it was set correctly using the <code>URL.getUserInfo()</code> method.

blocks|key|1837746|text|HttpUrlConnection允许您执行basic+authentication。更强大的HttpClient库为您提供了more+solutions+(basic、digest和NTLM+-我认为您不需要它们)。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1837747|entityMap|0|LINK|mutability|MUTABLE|url|http://blog.taragana.com/index.php/archive/java-tip-basic-authentication-with-httpurlconnection/|1|http://hc.apache.org/httpclient-3.x/authentication.html^0|M|K|0|1R|E|1|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@$A|O|B|P|1|Q]|$A|R|B|S|1|T]]|C|$]]|$1|D|3|-4|5|6|7|U|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]|L|$5|G|H|I|C|$J|M]]]]

HttpUrlConnection allows you to perform <a href="http://blog.taragana.com/index.php/archive/java-tip-basic-authentication-with-httpurlconnection/" rel="nofollow noreferrer">basic authentication</a>. The more powerful HttpClient libraru offers you <a href="http://hc.apache.org/httpclient-3.x/authentication.html" rel="nofollow noreferrer">more solutions</a> (basic, digest, and NTLM - which I don't think you need).

blocks|key|1781071|text|如果您只需要HTTP基本身份验证，您可以将URL格式设置为：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1781072|http://user:password@www.website.com|code-block|syntax|javascript|1781073|1781074|更新：|1781075|使用提供的示例，这应该是可行的：|1781076|https://user:password@api.del.icio.us/v1/posts/add&url=http://www.google.com&description=awesome|1781077|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Q|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|R|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|S|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|T|8|@]|9|@]|A|$]]|$1|L|3|M|5|D|7|U|8|@]|9|@]|A|$E|F]]|$1|N|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|O|$]]

If you just need HTTP Basic Authentication, you can form your URL like this:

<pre><code>http://user:password@www.website.com
</code></pre>

<hr>

UPDATE:

Using the example provided, this should work:

<pre><code>https://user:password@api.del.icio.us/v1/posts/add&amp;url=http://www.google.com&amp;description=awesome
</code></pre>

blocks|key|1783119|text|HttpURLConnection确实允许您执行基本身份验证，但如果您希望更复杂的身份验证能够工作，请尝试使用Apache+HTTPClient。它可以无缝地处理http身份验证方案，如Basic和Digest，而您甚至都不会注意到。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1783120|HTTPClient+Authentication+Guide|1783121|entityMap|0|LINK|mutability|MUTABLE|url|http://hc.apache.org/httpclient-3.x/|1|http://hc.apache.org/httpclient-3.x/authentication.html^0|1J|H|0|0|0|V|1|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@$A|Q|B|R|1|S]]|C|$]]|$1|D|3|E|5|6|7|T|8|@]|9|@$A|U|B|V|1|W]]|C|$]]|$1|F|3|-4|5|6|7|X|8|@]|9|@]|C|$]]]|G|$H|$5|I|J|K|C|$L|M]]|N|$5|I|J|K|C|$L|O]]]]

HttpURLConnection does allow you to do basic auth, but if you want more complex authentication to be able to work, give <a href="http://hc.apache.org/httpclient-3.x/" rel="nofollow noreferrer">Apache HTTPClient</a> a shot. It can seamlessly-handle http authentication schemes like Basic and Digest without you even noticing.

<a href="http://hc.apache.org/httpclient-3.x/authentication.html" rel="nofollow noreferrer">HTTPClient Authentication Guide</a>

blocks|key|1837931|text|这个答案是ok的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1837932|public+String+reloadTomcatWebApplication(String+user,+String+pwd,+String+urlWithParameters,+boolean+returnResponse){++++++++
++++URL+url+=+null;
++++try+{

++++++++url+=+new+URL(urlWithParameters);
++++}+catch+(MalformedURLException+e)+{
++++++++System.out.println("MalformedUrlException:+"+%2B+e.getMessage());
++++++++e.printStackTrace();
++++++++return+"-1";
++++}

++++URLConnection+uc+=+null;
++++try+{
++++++++uc+=+url.openConnection();
++++}+catch+(IOException+e)+{
++++++++System.out.println("IOException:+"+%2B+e.getMessage());
++++++++e.printStackTrace();+
++++++++return+"-12";
++++}


++++String+userpass+=+user+%2B+":"+%2B+pwd;
++++String+basicAuth+=+"Basic+"+%2B+javax.xml.bind.DatatypeConverter.printBase64Binary(userpass.getBytes());

++++uc.setRequestProperty+("Authorization",+basicAuth);

++++InputStream+is+=+null;
++++try+{
++++++++is+=+uc.getInputStream();
++++}+catch+(IOException+e)+{
++++++++System.out.println("IOException:+"+%2B+e.getMessage());
++++++++e.printStackTrace();
++++++++return+"-13";
++++}
++++if(returnResponse){
++++BufferedReader+buffReader+=+new+BufferedReader(new+InputStreamReader(is));
++++StringBuffer+response+=+new+StringBuffer();

++++String+line+=+null;
++++try+{
++++++++line+=+buffReader.readLine();
++++}+catch+(IOException+e)+{
++++++++e.printStackTrace();
++++++++return+"-1";
++++}

++++while+(line+!=+null)+{
++++++++response.append(line);
++++++++response.append('\n');
++++++++try+{
++++++++++++line+=+buffReader.readLine();
++++++++}+catch+(IOException+e)+{
++++++++++++System.out.println("+IOException:+"+%2B+e.getMessage());
++++++++++++e.printStackTrace();
++++++++++++return+"-14";
++++++++}
++++}

++++try+{
++++++++buffReader.close();
++++}+catch+(IOException+e)+{
++++++++e.printStackTrace();
++++++++return+"-15";
++++}+++++++
++++System.out.println("Response:+"+%2B+response.toString());
++++return+response.toString();

++++}+++++++++++++++
++++return+"0";
}|code-block|syntax|javascript|1837933|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This Answer is ok:

<pre><code>public String reloadTomcatWebApplication(String user, String pwd, String urlWithParameters, boolean returnResponse){ 
 URL url = null;
 try {

 url = new URL(urlWithParameters);
 } catch (MalformedURLException e) {
 System.out.println("MalformedUrlException: " + e.getMessage());
 e.printStackTrace();
 return "-1";
 }

 URLConnection uc = null;
 try {
 uc = url.openConnection();
 } catch (IOException e) {
 System.out.println("IOException: " + e.getMessage());
 e.printStackTrace(); 
 return "-12";
 }


 String userpass = user + ":" + pwd;
 String basicAuth = "Basic " + javax.xml.bind.DatatypeConverter.printBase64Binary(userpass.getBytes());

 uc.setRequestProperty ("Authorization", basicAuth);

 InputStream is = null;
 try {
 is = uc.getInputStream();
 } catch (IOException e) {
 System.out.println("IOException: " + e.getMessage());
 e.printStackTrace();
 return "-13";
 }
 if(returnResponse){
 BufferedReader buffReader = new BufferedReader(new InputStreamReader(is));
 StringBuffer response = new StringBuffer();

 String line = null;
 try {
 line = buffReader.readLine();
 } catch (IOException e) {
 e.printStackTrace();
 return "-1";
 }

 while (line != null) {
 response.append(line);
 response.append('\n');
 try {
 line = buffReader.readLine();
 } catch (IOException e) {
 System.out.println(" IOException: " + e.getMessage());
 e.printStackTrace();
 return "-14";
 }
 }

 try {
 buffReader.close();
 } catch (IOException e) {
 e.printStackTrace();
 return "-15";
 } 
 System.out.println("Response: " + response.toString());
 return response.toString();

 } 
 return "0";
}
</code></pre>

blocks|key|1837906|text|我尝试了一下这个美味的api，它的效果非常好。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1837907|import+urllib2,base64
req=urllib2.Request("https://api.del.icio.us/v1/posts/update")
username="Replace+with+your+Username"
password="Replace+with+your+password"
base64string+=+base64.encodestring('%25s:%25s'+%25+(username,+password)).replace('\n',+'')
req.add_header("Authorization",+"Basic+%25s"+%25+base64string)+
response=urllib2.urlopen(req)
print+response.read()|code-block|syntax|javascript|1837908|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I tried this for the delicious api and it worked like a charm

<pre><code>import urllib2,base64
req=urllib2.Request("https://api.del.icio.us/v1/posts/update")
username="Replace with your Username"
password="Replace with your password"
base64string = base64.encodestring('%s:%s' % (username, password)).replace('\n', '')
req.add_header("Authorization", "Basic %s" % base64string) 
response=urllib2.urlopen(req)
print response.read()
</code></pre>

I'm trying to connect a desktop application I am writing with the del.icio.us api @ <a href="http://delicious.com/help/api" rel="nofollow noreferrer">Delicious API</a> and simply provide them with my username and password and to request an url to post a bookmark to my profile.

The problem I have is that I don't understand how to send my login credentials when I open a connection.

How would I go about doing this?

Java HTTP AUTH?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在尝试使用del.icio.us api @ 连接我正在编写的桌面应用程序，只需向他们提供我的用户名和密码，并请求一个url来将书签发布到我的个人资料中。我的问题是，当我打开一个连接时，我不知道如何发送我的登录凭据。我该怎么做呢？

问Java HTTP AUTH？
EN

回答 6

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