blocks|key|1950472|text|使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1950473|String+str+=+"whatever";
str+=+str.replaceAll("[,.]",+"");|code-block|syntax|javascript|1950474|replaceAll使用regular+expression。这一点：|offset|length|1950475|[,.]|1950476|每个逗号和/或句点的...looks。|1950477|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.oracle.com/javase/8/docs/api/java/lang/String.html#replaceAll-java.lang.String-java.lang.String-|1|http://www.regular-expressions.info/^0|0|0|0|A|0|C|I|1|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@]|9|@$I|11|J|12|1|13]|$I|14|J|15|1|16]]|A|$]]|$1|K|3|L|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|M|3|N|5|6|7|18|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|19|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]|W|$5|R|S|T|A|$U|X]]]]

Use:

<pre><code>String str = "whatever";
str = str.replaceAll("[,.]", "");
</code></pre>

<a href="https://docs.oracle.com/javase/8/docs/api/java/lang/String.html#replaceAll-java.lang.String-java.lang.String-" rel="nofollow noreferrer">replaceAll</a> takes a <a href="http://www.regular-expressions.info/" rel="nofollow noreferrer">regular expression</a>. This:

<pre><code>[,.]
</code></pre>

...looks for each comma and/or period.

blocks|key|767884|text|将变量重新分配给子字符串：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|767885|s+=+s.substring(0,+s.length()+-+1)|code-block|syntax|javascript|767886|还有一种解决问题的替代方法:您可能还想考虑使用StringTokenizer读取文件，并将分隔符设置为您不希望成为单词一部分的字符。|offset|length|767887|entityMap|0|LINK|mutability|MUTABLE|url|http://java.sun.com/j2se/1.4.2/docs/api/java/util/StringTokenizer.html^0|0|0|N|F|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Reassign the variable to a substring:

<pre><code>s = s.substring(0, s.length() - 1)
</code></pre>

Also an alternative way of solving your problem: you might also want to consider using a <a href="http://java.sun.com/j2se/1.4.2/docs/api/java/util/StringTokenizer.html" rel="noreferrer">StringTokenizer</a> to read the file and set the delimiters to be the characters you don't want to be part of words.

blocks|key|1950518|text|要删除最后一个字符，请按照Mark+Byers所说的操作|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1950519|s+=+s.substring(0,+s.length()+-+1);|code-block|syntax|javascript|1950520|此外，删除不需要的字符的另一种方法是使用.replace(oldCharacter,+newCharacter)方法。|style|CODE|1950521|如下所示：|1950522|s+=+s.replace(",","");|1950523|和|1950524|s+=+s.replace(".","");|1950525|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/1962181/how-do-i-delete-the-last-character-of-a-particular-string-in-java/1962189#1962189^0|D|A|0|0|0|K|10|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@$A|13|B|14|1|15]]|C|$]]|$1|D|3|E|5|F|7|16|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|17|8|@$A|18|B|19|K|L]]|9|@]|C|$]]|$1|M|3|N|5|6|7|1A|8|@]|9|@]|C|$]]|$1|O|3|P|5|F|7|1B|8|@]|9|@]|C|$G|H]]|$1|Q|3|R|5|6|7|1C|8|@]|9|@]|C|$]]|$1|S|3|T|5|F|7|1D|8|@]|9|@]|C|$G|H]]|$1|U|3|-4|5|6|7|1E|8|@]|9|@]|C|$]]]|V|$W|$5|X|Y|Z|C|$10|11]]]]

To remove the last character do as <a href="https://stackoverflow.com/questions/1962181/how-do-i-delete-the-last-character-of-a-particular-string-in-java/1962189#1962189">Mark Byers</a> said

<pre><code>s = s.substring(0, s.length() - 1);
</code></pre>

Additionally, another way to remove the characters you don't want would be to use the <code>.replace(oldCharacter, newCharacter)</code> method.

as in:

<pre><code>s = s.replace(",","");
</code></pre>

and

<pre><code>s = s.replace(".","");
</code></pre>

blocks|key|2176456|text|您不能在Java中修改字符串。它们是不可变的。您所能做的就是创建一个新字符串，它是旧字符串的子字符串，减去最后一个字符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2176457|在某些情况下，StringBuffer可能会对您有所帮助。|2176458|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

You can't modify a String in Java. They are immutable. All you can do is create a new string that is substring of the old string, minus the last character.

In some cases a StringBuffer might help you instead.

blocks|key|650054|text|马克·拜尔斯解释说，最好的方法是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|650055|s+=+s.substring(0,+s.length()+-+1)|code-block|syntax|javascript|650056|例如，如果我们想用ReplaceAll替换\+to+space“”，它就不能正常工作|650057|String.replaceAll("\\",+"");|650058|或|650059|String.replaceAll("\\$",+"");+++//if+it+is+a+path|650060|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

The best method is what Mark Byers explains:

<pre><code>s = s.substring(0, s.length() - 1)
</code></pre>

For example, if we want to replace \ to space " " with ReplaceAll, it doesn't work fine

<pre><code>String.replaceAll("\\", "");
</code></pre>

or 

<pre><code>String.replaceAll("\\$", ""); //if it is a path
</code></pre>

blocks|key|1953137|text|请注意，单词边界还取决于区域设置。我认为最好的方法是使用标准的java.text.BreakIterator。下面是java.sun.com教程中的一个示例。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1953138|import+java.text.BreakIterator;
import+java.util.Locale;

public+static+void+main(String[]+args)+{
++++String+text+=+"\n"+%2B
++++++++++++"\n"+%2B
++++++++++++"For+example+I'm+extracting+a+text+String+from+a+text+file+and+I+need+those+words+to+form+an+array.+However,+when+I+do+all+that+some+words+end+with+comma+(,)+or+a+full+stop+(.)+or+even+have+brackets+attached+to+them+(which+is+all+perfectly+normal).\n"+%2B
++++++++++++"\n"+%2B
++++++++++++"What+I+want+to+do+is+to+get+rid+of+those+characters.+I've+been+trying+to+do+that+using+those+predefined+String+methods+in+Java+but+I+just+can't+get+around+it.\n"+%2B
++++++++++++"\n"+%2B
++++++++++++"Every+help+appreciated.+Thanx";
++++BreakIterator+wordIterator+=+BreakIterator.getWordInstance(Locale.getDefault());
++++extractWords(text,+wordIterator);
}

static+void+extractWords(String+target,+BreakIterator+wordIterator)+{
++++wordIterator.setText(target);
++++int+start+=+wordIterator.first();
++++int+end+=+wordIterator.next();

++++while+(end+!=+BreakIterator.DONE)+{
++++++++String+word+=+target.substring(start,+end);
++++++++if+(Character.isLetterOrDigit(word.charAt(0)))+{
++++++++++++System.out.println(word);
++++++++}
++++++++start+=+end;
++++++++end+=+wordIterator.next();
++++}
}|code-block|syntax|javascript|1953139|来源：http://java.sun.com/docs/books/tutorial/i18n/text/word.html|offset|length|1953140|entityMap|0|LINK|mutability|MUTABLE|url|http://java.sun.com/docs/books/tutorial/i18n/text/word.html^0|0|0|3|1N|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Note that the word boundaries also depend on the Locale. I think the best way to do it using standard java.text.BreakIterator. Here is an example from the java.sun.com tutorial.

<pre><code>import java.text.BreakIterator;
import java.util.Locale;

public static void main(String[] args) {
 String text = "\n" +
 "\n" +
 "For example I'm extracting a text String from a text file and I need those words to form an array. However, when I do all that some words end with comma (,) or a full stop (.) or even have brackets attached to them (which is all perfectly normal).\n" +
 "\n" +
 "What I want to do is to get rid of those characters. I've been trying to do that using those predefined String methods in Java but I just can't get around it.\n" +
 "\n" +
 "Every help appreciated. Thanx";
 BreakIterator wordIterator = BreakIterator.getWordInstance(Locale.getDefault());
 extractWords(text, wordIterator);
}

static void extractWords(String target, BreakIterator wordIterator) {
 wordIterator.setText(target);
 int start = wordIterator.first();
 int end = wordIterator.next();

 while (end != BreakIterator.DONE) {
 String word = target.substring(start, end);
 if (Character.isLetterOrDigit(word.charAt(0))) {
 System.out.println(word);
 }
 start = end;
 end = wordIterator.next();
 }
}
</code></pre>

Source: <a href="http://java.sun.com/docs/books/tutorial/i18n/text/word.html" rel="nofollow noreferrer">http://java.sun.com/docs/books/tutorial/i18n/text/word.html</a>

blocks|key|768000|text|您可以使用replaceAll()方法：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|768001|String.replaceAll(",",+"");
String.replaceAll("\\.",+"");
String.replaceAll("\\(",+"");|code-block|syntax|javascript|768002|等等。|768003|entityMap^0|5|C|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

You can use <code>replaceAll()</code> method :

<pre><code>String.replaceAll(",", "");
String.replaceAll("\\.", "");
String.replaceAll("\\(", "");
</code></pre>

etc..

For example I'm extracting a text String from a text file and I need those words to form an array. However, when I do all that some words end with comma (,) or a full stop (.) or even have brackets attached to them (which is all perfectly normal).

What I want to do is to get rid of those characters. I've been trying to do that using those predefined String methods in Java but I just can't get around it.

How do I delete specific characters from a particular String in Java?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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例如，我正在从一个文本文件中提取一个文本字符串，我需要这些单词来形成一个数组。但是，当我执行所有这些操作时，有些单词以逗号(，)或句号(.)结尾。或者甚至连上括号(这都是非常正常的)。我想做的就是摆脱那些角色。我一直在尝试使用Java中的那些预定义字符串方法来实现这一点，但我就是绕不开它。

问如何在Java中删除特定字符串中的特定字符？
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回答 7

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