blocks|key|697870|text|p1和p2之间的距离|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|697871|CGFloat+xDist+=+(p2.x+-+p1.x);
CGFloat+yDist+=+(p2.y+-+p1.y);
CGFloat+distance+=+sqrt(xDist+*+xDist+%2B+yDist+*+yDist);|code-block|syntax|javascript|697872|放入一个函数：|697873|func+distance(_+a:+CGPoint,+_+b:+CGPoint)+->+CGFloat+{
++++let+xDist+=+a.x+-+b.x
++++let+yDist+=+a.y+-+b.y
++++return+CGFloat(sqrt(xDist+*+xDist+%2B+yDist+*+yDist))
}|697874|背景：Pythagorean+theorem|697875|如果您只需要计算点之间的距离是增大还是减小，则可以省略sqrt()，这将使其更快一些。|697876|entityMap|0|LINK|mutability|MUTABLE|url|http://en.wikipedia.org/wiki/Pythagorean_theorem^0|0|2|3|2|0|0|0|0|3|J|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]|$9|13|A|14|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|16|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|18|8|@]|D|@$9|19|A|1A|1|1B]]|E|$]]|$1|Q|3|R|5|6|7|1C|8|@]|D|@]|E|$]]|$1|S|3|-4|5|6|7|1D|8|@]|D|@]|E|$]]]|T|$U|$5|V|W|X|E|$Y|Z]]]]

<p>Distance between <code>p1</code> and <code>p2</code>:</p>

<pre><code>CGFloat xDist = (p2.x - p1.x);
CGFloat yDist = (p2.y - p1.y);
CGFloat distance = sqrt(xDist * xDist + yDist * yDist);
</code></pre>

<p>Put in a function:</p>

<pre><code>func distance(_ a: CGPoint, _ b: CGPoint) -&gt; CGFloat {
    let xDist = a.x - b.x
    let yDist = a.y - b.y
    return CGFloat(sqrt(xDist * xDist + yDist * yDist))
}
</code></pre>

<p>Background: <a href="http://en.wikipedia.org/wiki/Pythagorean_theorem" rel="noreferrer">Pythagorean theorem</a></p>

<p>If you only need to calculate if the distance between the points increases or decreases, you can omit the sqrt() which will make it a little faster.</p>


blocks|key|1915864|text|-(float)distanceFrom:(CGPoint)point1+to:(CGPoint)point2
{
CGFloat+xDist+=+(point2.x+-+point1.x);
CGFloat+yDist+=+(point2.y+-+point1.y);
return+sqrt((xDist+*+xDist)+%2B+(yDist+*+yDist));
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1915865|如果使用的是cocos2d，则为|unstyled|1915866|float+distance+=+ccpDistance(point1,+point2);|1915867|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>-(float)distanceFrom:(CGPoint)point1 to:(CGPoint)point2
{
CGFloat xDist = (point2.x - point1.x);
CGFloat yDist = (point2.y - point1.y);
return sqrt((xDist * xDist) + (yDist * yDist));
}
</code></pre>

<p><em><strong>If you are using cocos2d</em></strong></p>

<pre><code>float distance = ccpDistance(point1, point2);
</code></pre>


blocks|key|1918001|text|您可以使用hypot()或hypotf()函数来计算斜边。给定两个点p1和p2|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1918002|CGFloat+distance+=+hypotf(p1.x+-+p2.x,+p1.y+-+p2.y);|code-block|syntax|javascript|1918003|就是这样。|1918004|entityMap^0|5|7|D|8|Y|2|11|2|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|N|$]]

<p>You can use the <code>hypot()</code> or <code>hypotf()</code> function to calculate the hypotenuse. Given two points <code>p1</code> and <code>p2</code>:</p>

<pre><code>CGFloat distance = hypotf(p1.x - p2.x, p1.y - p2.y);
</code></pre>

<p>And that's it. </p>


blocks|key|697961|text|如果要查找两点之间的绝对距离值，则可以使用(对于Cocos2d)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|697962|float+distance+=+abs(ccpDistance(point1,+point2));|code-block|syntax|javascript|697963|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>If you want to find the absolute distance value between two points then you can use (for Cocos2d):</p>

<pre><code>float distance = abs(ccpDistance(point1, point2));
</code></pre>


blocks|key|2106633|text|我写了这个，我经常使用它：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2106634|-+(float)+distanceBetween+:+(CGPoint)+p1+and:+(CGPoint)+p2
{
++++return+sqrt(pow(p2.x-p1.x,2)%2Bpow(p2.y-p1.y,2));
}|code-block|syntax|javascript|2106635|像这样调用：|2106636|float+distanceMoved+=+[self+distanceBetween+touchStart+and:+touchEnd];|2106637|我通常使用cocos2d，但我仍然使用自己的函数来做一些事情，因为当我在学习的时候，我写了一堆自己的函数来做简单的事情，而不是搜索“官方”的高阶函数，另外我不是一个很喜欢函数(var，var)的人，我更喜欢自己的函数vars和:+vars|2106638|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

<p>I wrote this, I use it a lot:</p>

<pre><code>- (float) distanceBetween : (CGPoint) p1 and: (CGPoint) p2
{
    return sqrt(pow(p2.x-p1.x,2)+pow(p2.y-p1.y,2));
}
</code></pre>

<p>Call like this:</p>

<pre><code>float distanceMoved = [self distanceBetween touchStart and: touchEnd];
</code></pre>

<p>I normally use cocos2d, but I still use my own function for some things because when I was learning I wrote a bunch of my own functions for simple stuff rather than searching for the "official" higher order functions, and additionally I'm not a big fan of functions(vars, vars), I prefer [self functions vars and: vars]</p>


blocks|key|1915938|text|#define+rw_pointOffset(point1,+point2)+CGPointMake(point2.x+-+point1.x,+point2.y+-+point1.y)
#define+rw_pointDistance(point1,+point2)+sqrtf(+powf(point2.x+-+point1.x,+2.0f)+%2B+powf(point2.y+-+point1.y,+2.0f))|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1915939|这就是你使用它的方式：|unstyled|1915940|CGPoint+offset+=+rw_pointOffset(view1.center,+view2.center);
float+distance+=+rw_pointDistance(view1.center,+view2.center);|1915941|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>#define rw_pointOffset(point1, point2) CGPointMake(point2.x - point1.x, point2.y - point1.y)
#define rw_pointDistance(point1, point2) sqrtf( powf(point2.x - point1.x, 2.0f) + powf(point2.y - point1.y, 2.0f))
</code></pre>

<p>And that´s how you use it:</p>

<pre><code>CGPoint offset = rw_pointOffset(view1.center, view2.center);
float distance = rw_pointDistance(view1.center, view2.center);
</code></pre>


blocks|key|698081|text|面向swift用户的|type|unstyled|depth|inlineStyleRanges|entityRanges|data|698082|extension+CGPoint+{
++++func+distance(to+point:+CGPoint)+->+CGFloat+{
++++++++return+sqrt(pow(x+-+point.x,+2)+%2B+pow(y+-+point.y,+2))
++++}
}|code-block|syntax|javascript|698083|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p><strong>For swift users</strong></p>

<pre><code>extension CGPoint {
    func distance(to point: CGPoint) -&gt; CGFloat {
        return sqrt(pow(x - point.x, 2) + pow(y - point.y, 2))
    }
}
</code></pre>


blocks|key|1916025|text|使用Swift+4，您可以从以下5个游乐场代码中选择一个，以获得两个CGPoint实例之间的距离。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1916026|1916027|1.使用Darwin+sqrt(_:)函数|1916028|import+CoreGraphics

func+distance(from+lhs:+CGPoint,+to+rhs:+CGPoint)+->+CGFloat+{
++++let+xDistance+=+lhs.x+-+rhs.x
++++let+yDistance+=+lhs.y+-+rhs.y
++++return+sqrt(xDistance+*+xDistance+%2B+yDistance+*+yDistance)
}

let+point1+=+CGPoint(x:+-10,+y:+-100)
let+point2+=+CGPoint(x:+30,+y:+600)

distance(from:+point1,+to:+point2)+//+701.141925718324|code-block|syntax|javascript|1916029|1916030|2.使用CGFloat+squareRoot()方法|1916031|import+CoreGraphics

func+distance(from+lhs:+CGPoint,+to+rhs:+CGPoint)+->+CGFloat+{
++++let+xDistance+=+lhs.x+-+rhs.x
++++let+yDistance+=+lhs.y+-+rhs.y
++++return+(xDistance+*+xDistance+%2B+yDistance+*+yDistance).squareRoot()
}

let+point1+=+CGPoint(x:+-10,+y:+-100)
let+point2+=+CGPoint(x:+30,+y:+600)

distance(from:+point1,+to:+point2)+//+701.141925718324|1916032|1916033|3.使用CGFloat+squareRoot()方法和核心图形pow(_:_:)函数|1916034|import+CoreGraphics

func+distance(from+lhs:+CGPoint,+to+rhs:+CGPoint)+->+CGFloat+{
++++return+(pow(lhs.x+-+rhs.x,+2)+%2B+pow(lhs.y+-+rhs.y,+2)).squareRoot()
}

let+point1+=+CGPoint(x:+-10,+y:+-100)
let+point2+=+CGPoint(x:+30,+y:+600)

distance(from:+point1,+to:+point2)+//+701.141925718324|1916035|1916036|4.使用核心图形hypot(_:_:)函数|1916037|import+CoreGraphics

func+distance(from+lhs:+CGPoint,+to+rhs:+CGPoint)+->+CGFloat+{
++++return+hypot(lhs.x+-+rhs.x,+lhs.y+-+rhs.y)
}

let+point1+=+CGPoint(x:+-10,+y:+-100)
let+point2+=+CGPoint(x:+30,+y:+600)

distance(from:+point1,+to:+point2)+//+701.141925718324|1916038|1916039|5.使用核心图形hypot(_:_:)函数和CGFloat+distance(to:)方法|1916040|import+CoreGraphics

func+distance(from+lhs:+CGPoint,+to+rhs:+CGPoint)+->+CGFloat+{
++++return+hypot(lhs.x.distance(to:+rhs.x),+lhs.y.distance(to:+rhs.y))
}

let+point1+=+CGPoint(x:+-10,+y:+-100)
let+point2+=+CGPoint(x:+30,+y:+600)

distance(from:+point1,+to:+point2)+//+701.141925718324|1916041|entityMap^0|Y|7|0|0|B|8|0|0|0|4|7|C|C|0|0|0|4|7|C|C|V|9|0|0|0|8|B|0|0|0|8|B|M|7|U|D|0|0^^$0|@$1|2|3|4|5|6|7|19|8|@$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|1C|8|@]|D|@]|E|$]]|$1|G|3|H|5|6|7|1D|8|@$9|1E|A|1F|B|C]]|D|@]|E|$]]|$1|I|3|J|5|K|7|1G|8|@]|D|@]|E|$L|M]]|$1|N|3|-4|5|6|7|1H|8|@]|D|@]|E|$]]|$1|O|3|P|5|6|7|1I|8|@$9|1J|A|1K|B|C]|$9|1L|A|1M|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|K|7|1N|8|@]|D|@]|E|$L|M]]|$1|S|3|-4|5|6|7|1O|8|@]|D|@]|E|$]]|$1|T|3|U|5|6|7|1P|8|@$9|1Q|A|1R|B|C]|$9|1S|A|1T|B|C]|$9|1U|A|1V|B|C]]|D|@]|E|$]]|$1|V|3|W|5|K|7|1W|8|@]|D|@]|E|$L|M]]|$1|X|3|-4|5|6|7|1X|8|@]|D|@]|E|$]]|$1|Y|3|Z|5|6|7|1Y|8|@$9|1Z|A|20|B|C]]|D|@]|E|$]]|$1|10|3|11|5|K|7|21|8|@]|D|@]|E|$L|M]]|$1|12|3|-4|5|6|7|22|8|@]|D|@]|E|$]]|$1|13|3|14|5|6|7|23|8|@$9|24|A|25|B|C]|$9|26|A|27|B|C]|$9|28|A|29|B|C]]|D|@]|E|$]]|$1|15|3|16|5|K|7|2A|8|@]|D|@]|E|$L|M]]|$1|17|3|-4|5|6|7|2B|8|@]|D|@]|E|$]]]|18|$]]

<p>With Swift 4, you may choose one of the 5 following Playground codes in order to get the distance between two <code>CGPoint</code> instances.</p>

<hr>

<h2>1. Using Darwin <code>sqrt(_:)</code> function</h2>

<pre><code>import CoreGraphics

func distance(from lhs: CGPoint, to rhs: CGPoint) -&gt; CGFloat {
    let xDistance = lhs.x - rhs.x
    let yDistance = lhs.y - rhs.y
    return sqrt(xDistance * xDistance + yDistance * yDistance)
}

let point1 = CGPoint(x: -10, y: -100)
let point2 = CGPoint(x: 30, y: 600)

distance(from: point1, to: point2) // 701.141925718324
</code></pre>

<hr>

<h2>2. Using <code>CGFloat</code> <code>squareRoot()</code> method</h2>

<pre><code>import CoreGraphics

func distance(from lhs: CGPoint, to rhs: CGPoint) -&gt; CGFloat {
    let xDistance = lhs.x - rhs.x
    let yDistance = lhs.y - rhs.y
    return (xDistance * xDistance + yDistance * yDistance).squareRoot()
}

let point1 = CGPoint(x: -10, y: -100)
let point2 = CGPoint(x: 30, y: 600)

distance(from: point1, to: point2) // 701.141925718324
</code></pre>

<hr>

<h2>3. Using <code>CGFloat</code> <code>squareRoot()</code> method and Core Graphics <code>pow(_:_:)</code> function</h2>

<pre><code>import CoreGraphics

func distance(from lhs: CGPoint, to rhs: CGPoint) -&gt; CGFloat {
    return (pow(lhs.x - rhs.x, 2) + pow(lhs.y - rhs.y, 2)).squareRoot()
}

let point1 = CGPoint(x: -10, y: -100)
let point2 = CGPoint(x: 30, y: 600)

distance(from: point1, to: point2) // 701.141925718324
</code></pre>

<hr>

<h2>4. Using Core Graphics <code>hypot(_:_:)</code> function</h2>

<pre><code>import CoreGraphics

func distance(from lhs: CGPoint, to rhs: CGPoint) -&gt; CGFloat {
    return hypot(lhs.x - rhs.x, lhs.y - rhs.y)
}

let point1 = CGPoint(x: -10, y: -100)
let point2 = CGPoint(x: 30, y: 600)

distance(from: point1, to: point2) // 701.141925718324
</code></pre>

<hr>

<h2>5. Using Core Graphics <code>hypot(_:_:)</code> function and <code>CGFloat</code> <code>distance(to:)</code> method</h2>

<pre><code>import CoreGraphics

func distance(from lhs: CGPoint, to rhs: CGPoint) -&gt; CGFloat {
    return hypot(lhs.x.distance(to: rhs.x), lhs.y.distance(to: rhs.y))
}

let point1 = CGPoint(x: -10, y: -100)
let point2 = CGPoint(x: 30, y: 600)

distance(from: point1, to: point2) // 701.141925718324
</code></pre>


<p>When we do multitouch with two fingers in a UIScrollView, we get two CG points. I want to find the distance between them. Then when again we do the pinch(inside or outside), Then we will again get two points. Then after finding the distance again between these two points , I want to decide whether I pinched in or out. If i have pinched in, surely the new distance will be lesser and vice versa.</p>

<p>But don't know how to find an accurate measurement for the distance between 2 points for doing comparison ? Is anyone having idea about this ?</p>


How to find the distance between two CG points?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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当我们在UIScrollView中用两个手指进行多点触摸时，我们会得到两个CG点。我想知道它们之间的距离。然后，当我们再次进行挤压(内部或外部)时，我们将再次获得两分。然后，在找到这两个点之间的距离后，我想决定是收缩还是收缩。如果我挤进去了，新的距离肯定会更短，反之亦然。但是不知道如何找到两个点之间的距离的准确测量来进...

问如何找到两个CG点之间的距离？
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问如何找到两个CG点之间的距离？EN