blocks|key|736948|text|应避免使用document.all，因为它不符合标准。相反，您可以对特定节点使用document.getElementById()，或者使用$("*")通过jQuery选择所有元素。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|736949|但是，如果您想要使用document.all，请确保从页面中删除<!DOCTYPE>标记，并从<html>标记中删除xmlns属性。|736950|会像这样改变一切：|BOLD|736951|<!DOCTYPE+html+PUBLIC+"-//W3C//DTD+XHTML+1.0+Transitional//EN"+"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html+xmlns="http://www.w3.org/1999/xhtml">|code-block|syntax|javascript|736952|to:|736953|<html>|736954|我已经在FireFox+19.0.2上测试过了，document.all对我来说工作得很好。|736955|原因：当你使用<!DOCTYPE>标签时，你是在告诉浏览器你的网页不符合标准，而标准告诉你不要在脚本中使用document.all，所以浏览器也不允许这样做。|736956|但是当您想使用它时，您显然没有遵循标准，所以甚至不要费心添加<!DOCTYPE>标记，否则document.all将无法工作。|736957|entityMap^0|5|C|14|P|1Y|6|0|W|A|1B|6|0|0|9|0|0|0|3|0|0|O|C|0|0|3|7|A|1H|C|0|U|A|19|C|0^^$0|@$1|2|3|4|5|6|7|11|8|@$9|12|A|13|B|C]|$9|14|A|15|B|C]|$9|16|A|17|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|18|8|@$9|19|A|1A|B|C]|$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|1D|8|@$9|1E|A|1F|B|J]]|D|@]|E|$]]|$1|K|3|L|5|M|7|1G|8|@]|D|@]|E|$N|O]]|$1|P|3|Q|5|6|7|1H|8|@$9|1I|A|1J|B|J]]|D|@]|E|$]]|$1|R|3|S|5|M|7|1K|8|@]|D|@]|E|$N|O]]|$1|T|3|U|5|6|7|1L|8|@$9|1M|A|1N|B|C]]|D|@]|E|$]]|$1|V|3|W|5|6|7|1O|8|@$9|1P|A|1Q|B|J]|$9|1R|A|1S|B|C]|$9|1T|A|1U|B|C]]|D|@]|E|$]]|$1|X|3|Y|5|6|7|1V|8|@$9|1W|A|1X|B|C]|$9|1Y|A|1Z|B|C]]|D|@]|E|$]]|$1|Z|3|-4|5|6|7|20|8|@]|D|@]|E|$]]]|10|$]]

<code>document.all</code> should be avoided as it is not Standards compliant. Instead you can use <code>document.getElementById()</code> for Particular Node or use 
<code>$("*")</code> For selecting all the elements using jQuery.

But still if you would like to use document.all then see to it that <code>&lt;!DOCTYPE&gt;</code> Tag is removed from your page, as well as the xmlns attribute is also removed from your <code>&lt;html&gt;</code> tag.

Change anything like this:

<pre><code>&lt;!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"&gt;
&lt;html xmlns="http://www.w3.org/1999/xhtml"&gt;
</code></pre>

to:

<pre><code>&lt;html&gt;
</code></pre>

I have tested it on FireFox 19.0.2 and <code>document.all</code> works fine for me.

The reason: When you use the <code>&lt;!DOCTYPE&gt;</code> tag you are telling the browser that your webpage is complaint with the standards which tells you to NOT use the <code>document.all</code> in your script, so the browser also does not allow it. 

But as you want to use it, you are obviously not following the standards so don't even bother to add the <code>&lt;!DOCTYPE&gt;</code> tag otherwise <code>document.all</code> won't work.

blocks|key|2349648|text|试着这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2349649|if+(document.all+!==+undefined)
{
+++allElements+=+document.all;
}
else
{
+++allElements+=+document.getElementsByTagName("*");
}|code-block|syntax|javascript|2349650|或更短的版本|2349651|allElements+=+document.all+?+document.all+:+document.getElementsByTagName("*");|2349652|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Try like this:

<pre><code>if (document.all !== undefined)
{
 allElements = document.all;
}
else
{
 allElements = document.getElementsByTagName("*");
}
</code></pre>

Or shorter version

<pre><code>allElements = document.all ? document.all : document.getElementsByTagName("*");
</code></pre>

blocks|key|736917|text|document.getElementsByTagName()在所有现代浏览器(所有比IE5更新的浏览器)中都能完美地工作。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|736918|如果它在Chrome或Safari中不起作用，那么它很可能只是你在其他地方遇到的错误的症状。|736919|entityMap^0|0|V|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|M|8|@]|D|@]|E|$]]|$1|H|3|-4|5|6|7|N|8|@]|D|@]|E|$]]]|I|$]]

<code>document.getElementsByTagName()</code> works perfectly in all modern browsers (everything newer than IE5). 

If it doesn't seem to work in Chrome or Safari, then it's most likely just a symptom of an error you have elsewhere.

blocks|key|2349621|text|我承认，今天可能有一些我不知道的技术，允许以跨浏览器格式完成这类事情，但我过去总是不得不这样做的方式是对您正在使用的浏览器进行某种检查。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2349622|不过，一个更简单的解决方案是尝试运行其中一个，如果什么都没有/null/出现错误，则使用另一个。|2349623|无论如何，如果你真的不想自己处理它，你应该使用一个可以为你处理它的库(例如，jQuery)。|2349624|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

I admit that there might be technologies today I don't know about that allow for this sort of thing to be done in cross-browser format, but the way I've always had to do it in the past is to have a check of some sort for which browser you're using.

A simpler solution, though, is to try to run one of them, and if you get nothing/null/an error, use the other.

Anyway, if you really don't want to deal with it yourself, you should use a library that will deal with it for you (e.g., jQuery).

blocks|key|2349780|text|虽然我不鼓励你做document.all，因为这意味着你正在做很多不需要的客户端解析，但我理解有很多遗留的东西，等等。我想在document.all的包装器方法上发表一点我的想法的扩展。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2349781|document.all+=+document.all+%7C%7C+function(){
+++return+document.getElementsByTagName("*");
};|code-block|syntax|javascript|2349782|当然，这里假设您有一个getElementsByTagName函数，应该是这样的。|2349783|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

While I would not encourage you to do a document.all because it implies you are doing a lot of client-side parsing that is just not needed I do understand there is a lot of legacy stuff out there etc. I wanted to post a little extension of my thoughts on a wrapper method for document.all.

<pre><code>document.all = document.all || function(){
 return document.getElementsByTagName("*");
};
</code></pre>

Of course this assumes you have a getElementsByTagName function, which should be the case.

blocks|key|736417|text|由于没有足够的代表来评论@Khurram+Hassan的答案，我将把它连同我对原始问题的答案一起放在这里。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|736418|首先，是原问题。我的解决方案是(在我自己的代码中，等待我在这个网站上发布的一个问题的答案)+document.getElementsByTagName("*")，它实际上得到了Chrome上的每一个元素。我在Google+Chrome上的google.com上测试了它，加载了一个配置文件，列出了8个最常访问的网站，结果显示有356个带有标签名称的单独元素。公平地说，这包括html、head、body和其他可能没有用处的东西，但它仍然拥有它们。我现在还不能访问Opera，但由于Chrome仍然接受那段JavaScript，我看不出有什么理由它不能在你的代码中接受它。|736419|其次，对于@Khurram+hassan，在这种情况下不能使用document.getElementById()。我刚刚在Chrome上测试了它，结果显示它的值是null。从理论上讲，在这种情况下，可以使用与getElementBy*相反的getElementsBy*的一般形式的任何东西。因此，为了补充我之前的回答，您还可以尝试使用ClassName、Name和TagNameNS，这取决于您要做的是什么。在与之前相同的页面上，我测试了这三个，虽然只有TagNameNS可以工作，但其余的只是返回空列表，而不是错误。|offset|length|style|CODE|736420|此外，如果您的代码中确实不需要<!DOCTYPE+html>，也许您可以将工作代码作为对您的答案的编辑发布，以便我们可以看到它。据我所知，<!DOCTYPE+html>似乎是普遍接受的(并且通常被认为是强制性的)开始HTML页面的方式。如果这不是必要的，那么这将是新的信息(至少对我来说)，可以证明对调试或未来的非公开网页有用。|736421|entityMap^0|0|0|V|P|2W|D|3C|E|4N|9|4X|4|52|9|6B|9|0|F|F|1X|F|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|P|8|@$F|Q|G|R|H|I]|$F|S|G|T|H|I]|$F|U|G|V|H|I]|$F|W|G|X|H|I]|$F|Y|G|Z|H|I]|$F|10|G|11|H|I]|$F|12|G|13|H|I]]|9|@]|A|$]]|$1|J|3|K|5|6|7|14|8|@$F|15|G|16|H|I]|$F|17|G|18|H|I]]|9|@]|A|$]]|$1|L|3|-4|5|6|7|19|8|@]|9|@]|A|$]]]|M|$]]

Without sufficient rep to comment on @Khurram Hassan 's answer, I'll put it here, along with my answer to the original question.

First, the original question. My solution would be (and is in my own code, pending an answer to a problem with it which I put up on this site) document.getElementsByTagName("*"), which actually does get every single element on Chrome. I tested it out on google.com on Google Chrome with a profile loaded and the eight most common visited sites listed, and it came out to 356 individual elements with a tag name. In fairness, this included html, head, body, and others that probably aren't useful, but it still got them. I don't have access to Opera at the moment, but with Chrome still accepting that piece of JavaScript, I don't see a reason why it wouldn't accept that in your code.

Second, for @Khurram hassan, <code>document.getElementById()</code> can't be used in this case. I just tested it on Chrome, and it came up with a value of null. In theory, anything with the general form of <code>getElementsBy*</code> as opposed to <code>getElementBy*</code> could probably be used in this case. So, to add to my earlier answer, you might also try <code>ClassName</code>, <code>Name</code>, and <code>TagNameNS</code> depending on what you're trying to do. On the same page as before, I tested those three and while only <code>TagNameNS</code> worked, the rest just returned empty lists, not errors.

Further, if it is true that you don't need <code>&lt;!DOCTYPE html&gt;</code> in your code, perhaps you could post the working code as an edit to your answer so that we can see it. <code>&lt;!DOCTYPE html&gt;</code> seems, to the best of my knowledge, to be the commonly accepted (and usually assumed to be mandatory) way of starting an HTML page. If it's not necessary, then that would be new information (at least to me) that could prove useful in either debugging or non-public webpages down the road.

<code>document.getElementsByTagName("*")</code> works for IE/Firefox/Opera, But doesn't work for Chrome and Safari.

<code>document.all</code> works for IE/Chrom/Safari, But doesn't work for Firefox.

How can I deal with it?

document.getElementsByTagName("*") Or document.all

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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document.getElementsByTagName("*")可以在IE/火狐/Opera上运行，但不能在Chrome和Safari上运行。document.all可以在IE/Chrom/Safari上运行，但不能在火狐上运行。我该怎么处理呢？

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