使用TypeScript:
public subscribe:(subscribeFunction:(state)=>void)=>()=>void;这是一个订阅方法,它将函数作为参数获取,类型为function,且给定函数在被调用时将接收状态参数,带参数的函数不会返回任何内容(即: void) ...我迷失在最后一个()=>()=>void上。
我的理解对吗?
发布于 2016-01-22 02:46:01
它用于具有(subscribeFunction: (state) => void) => () => void;类型的名为subscribe的公共属性
// scope
public
// name
subscribe:
// type (function)
// parameters
(
// parameter name
subscribeFunction:
// parameter type (function)
(state) => void
) =>
// return type (function)
() => void;下面是一个编译的例子:
class MyClass {
public subscribe: (subscribeFunction: (state) => void) => () => void;
}
let myInstance = new MyClass();
myInstance.subscribe = (subscribeFunction: (state) => void) => {
console.log("statements might go here");
return () => {
subscribeFunction(1 /* state */);
console.log("nothing returned by this inner function");
};
};
// Example use
// outputs "statements might go here"
let innerFunction = myInstance.subscribe((state) => console.log(state));
// outputs 1 and "nothing returned by this inner function"
innerFunction();发布于 2016-01-22 03:03:25
注意第一个冒号-- subscribe是函数类型的公共属性,而不是方法。展开:
public subscribe: // public property, which is
( // of the type of a function, which takes
subscribeFunction: // 1 parameter, which itself is
(state) => void // a function of 1 parameter, returning nothing
) => // and the upon invocation of a function stored in "subscribe" it
() => void; // returns a function of no parameter and no return value因此,您可以将一个函数存储到subscribe属性中,然后在为其提供一个函数作为参数的同时调用它,结果您将获得另一个函数,您可以随后调用该函数:
subscribe = (subscribeFunction: (state) => void) => {
subscribeFunction('A');
return () => {console.log('C');};
};
let subscribed = subscribe((state) => {
console.log(state, 'B');
}); // prints 'A,B'
subscribed(); // prints 'C'发布于 2016-01-27 02:57:18
tx用于反馈,现在我理解了它,我认为最好的解释是:
公共订阅:(subscribeFunction:(state)=>void)
//第一部分用于subscribeFunction,它将接受不返回任何内容的函数
=>()=>void;
//第二部分用于订阅本身,因为它将返回一个不返回任何内容的函数...我同意,像这样的代码应该更明确
https://stackoverflow.com/questions/34931793
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