我的安卓应用程序使用Java OAuth库,在Twitter上找到了授权的here。我可以得到一个请求令牌,授权令牌和确认,但是当浏览器尝试回调url来重新连接我的应用程序时,它不会使用我在代码中提供的URL,而是使用我在Twitter注册时提供的URL。
注意:
你知道我做错了什么吗?
相关代码:
public class FirstActivity extends Activity
{
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
OAuthAccessor client = defaultClient();
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(client.consumer.serviceProvider.userAuthorizationURL + "?oauth_token="
+ client.requestToken + "&oauth_callback=" + client.consumer.callbackURL));
startActivity(i);
}
OAuthServiceProvider defaultProvider()
{
return new OAuthServiceProvider(GeneralRuntimeConstants.request_token_URL,
GeneralRuntimeConstants.authorize_url, GeneralRuntimeConstants.access_token_url);
}
OAuthAccessor defaultClient()
{
String callbackUrl = "myapp:///";
OAuthServiceProvider provider = defaultProvider();
OAuthConsumer consumer = new OAuthConsumer(callbackUrl,
GeneralRuntimeConstants.consumer_key, GeneralRuntimeConstants.consumer_secret,
provider);
OAuthAccessor accessor = new OAuthAccessor(consumer);
OAuthClient client = new OAuthClient(new HttpClient4());
try
{
client.getRequestToken(accessor);
} catch (Exception e)
{
e.printStackTrace();
}
return accessor;
}
@Override
protected void onResume()
{
// TODO Auto-generated method stub
super.onResume();
Uri uri = this.getIntent().getData();
if (uri != null)
{
String access_token = uri.getQueryParameter("oauth_token");
}
}
}
// Manifest file
<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name=".FirstActivity"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="myapp"/>
</intent-filter>
</activity>
</application>发布于 2013-02-13 19:12:35
我的问题是,我试图使用与创建Twitter应用程序相同的帐户登录。在我用我的个人资料登录后,回叫工作(到目前为止)。
https://stackoverflow.com/questions/2199357
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