blocks|key|1256340|text|使用strtotime()|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1256341|for($i+=+1;+$i+<=+10;+$i%2B%2B){
++++echo+strtotime("-$i+days"),+PHP_EOL;
}|code-block|syntax|javascript|1256342|另请参阅以下相关问题和答案：|1256343|1256344|Add+number+of+days+to+a+date|unordered-list-item|1256345|1256346|entityMap|0|LINK|mutability|MUTABLE|url|http://de.php.net/manual/en/function.strtotime.php|1|https://stackoverflow.com/questions/2332681/add-number-of-days-to-a-date/2332688^0|2|B|2|B|0|0|0|0|0|0|S|1|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@$9|12|A|13|B|C]]|D|@$9|14|A|15|1|16]]|E|$]]|$1|F|3|G|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|18|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|19|8|@]|D|@]|E|$]]|$1|N|3|O|5|P|7|1A|8|@]|D|@$9|1B|A|1C|1|1D]]|E|$]]|$1|Q|3|-4|5|6|7|1E|8|@]|D|@]|E|$]]|$1|R|3|-4|5|6|7|1F|8|@]|D|@]|E|$]]]|S|$T|$5|U|V|W|E|$X|Y]]|Z|$5|U|V|W|E|$X|10]]]]

Use <a href="http://de.php.net/manual/en/function.strtotime.php" rel="nofollow noreferrer"><code>strtotime()</code></a>

<pre><code>for($i = 1; $i &lt;= 10; $i++){
 echo strtotime("-$i days"), PHP_EOL;
}
</code></pre>

Also see this related question and answers:

<ul>
<li><a href="https://stackoverflow.com/questions/2332681/add-number-of-days-to-a-date/2332688">Add number of days to a date</a></li>
</ul>

blocks|key|2665876|text|最简单的方法是使用time()函数获取与今天对应的时间戳；并将该时间戳删除7次1天，每个时间戳对应于该时间戳的日期：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2665877|$timestamp+=+time();
for+($i+=+0+;+$i+<+7+;+$i%2B%2B)+{
++++echo+date('Y-m-d',+$timestamp)+.+'<br+/>';
++++$timestamp+-=+24+*+3600;
}|code-block|syntax|javascript|2665878|这将为您提供以下输出：|2665879|2010-02-25
2010-02-24
2010-02-23
2010-02-22
2010-02-21
2010-02-20
2010-02-19|2665880|由于时间戳仅表示自1970-01-01以来的秒数，因此将一天减去时间戳意味着减去24*3600秒。|2665881|2665882|注释后的编辑:|BOLD|2665883|对于月和周的更改，这仍然有效:一天仍然是24*3600秒。|2665884|例如，如果您使用以下代码行进行测试，而不是我在第一个示例中发布的第一行代码：|2665885|$timestamp+=+strtotime('2010-02-03');|2665886|您将获得以下输出：|2665887|2010-02-03
2010-02-02
2010-02-01
2010-01-31
2010-01-30
2010-01-29
2010-01-28|2665888|天气转了个月的晴天。|2665889|对于闰年，如果我使用以下命令进行测试：|2665890|$timestamp+=+strtotime('2008-03-03');|2665891|我得到了：|2665892|2008-03-03
2008-03-02
2008-03-01
2008-02-29
2008-02-28
2008-02-27
2008-02-26|2665893|这看起来很好，因为2008年2月有29天。|2665894|如果我用以下命令测试：|2665895|$timestamp+=+strtotime('2009-03-03');|2665896|2665897|2009-03-03
2009-03-02
2009-03-01
2009-02-28
2009-02-27
2009-02-26
2009-02-25|2665898|看起来也不错。|2665899|entityMap|0|LINK|mutability|MUTABLE|url|http://www.php.net/time^0|9|6|9|6|0|0|0|0|0|9|A|14|7|0|0|4|3|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|1X|8|@$9|1Y|A|1Z|B|C]]|D|@$9|20|A|21|1|22]]|E|$]]|$1|F|3|G|5|H|7|23|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|24|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|25|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|26|8|@$9|27|A|28|B|C]|$9|29|A|2A|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|2B|8|@]|D|@]|E|$]]|$1|R|3|S|5|6|7|2C|8|@$9|2D|A|2E|B|T]]|D|@]|E|$]]|$1|U|3|V|5|6|7|2F|8|@]|D|@]|E|$]]|$1|W|3|X|5|6|7|2G|8|@]|D|@]|E|$]]|$1|Y|3|Z|5|H|7|2H|8|@]|D|@]|E|$I|J]]|$1|10|3|11|5|6|7|2I|8|@]|D|@]|E|$]]|$1|12|3|13|5|H|7|2J|8|@]|D|@]|E|$I|J]]|$1|14|3|15|5|6|7|2K|8|@]|D|@]|E|$]]|$1|16|3|17|5|6|7|2L|8|@]|D|@]|E|$]]|$1|18|3|19|5|H|7|2M|8|@]|D|@]|E|$I|J]]|$1|1A|3|1B|5|6|7|2N|8|@]|D|@]|E|$]]|$1|1C|3|1D|5|H|7|2O|8|@]|D|@]|E|$I|J]]|$1|1E|3|1F|5|6|7|2P|8|@]|D|@]|E|$]]|$1|1G|3|1H|5|6|7|2Q|8|@]|D|@]|E|$]]|$1|1I|3|1J|5|H|7|2R|8|@]|D|@]|E|$I|J]]|$1|1K|3|1B|5|6|7|2S|8|@]|D|@]|E|$]]|$1|1L|3|1M|5|H|7|2T|8|@]|D|@]|E|$I|J]]|$1|1N|3|1O|5|6|7|2U|8|@]|D|@]|E|$]]|$1|1P|3|-4|5|6|7|2V|8|@]|D|@]|E|$]]]|1Q|$1R|$5|1S|1T|1U|E|$1V|1W]]]]

Easiest way would be to get a timestamp that corresponds to today, using the <a href="http://www.php.net/time" rel="nofollow noreferrer"><code>time()</code></a> function ; and 7 times remove 1 day to that timestamp, each echoing the date that corresponds to that timestamp :

<pre><code>$timestamp = time();
for ($i = 0 ; $i &lt; 7 ; $i++) {
 echo date('Y-m-d', $timestamp) . '&lt;br /&gt;';
 $timestamp -= 24 * 3600;
}
</code></pre>

Which will get you this output :

<pre><code>2010-02-25
2010-02-24
2010-02-23
2010-02-22
2010-02-21
2010-02-20
2010-02-19
</code></pre>

Because a timestamp only represents the number of seconds since <code>1970-01-01</code>, substracting one day to a timestamp means substracting <code>24*3600</code> seconds.

<hr>

Edit after the comments : 

For month and weeks changes, this will still work : one day is still 24*3600 seconds.

For instance, if you test using this line instead of the first one I posted in my first example :

<pre><code>$timestamp = strtotime('2010-02-03');
</code></pre>

You'll get this output :

<pre><code>2010-02-03
2010-02-02
2010-02-01
2010-01-31
2010-01-30
2010-01-29
2010-01-28
</code></pre>

It changed of month fine.

 
For leap years, if I test using this :

<pre><code>$timestamp = strtotime('2008-03-03');
</code></pre>

I get :

<pre><code>2008-03-03
2008-03-02
2008-03-01
2008-02-29
2008-02-28
2008-02-27
2008-02-26
</code></pre>

Which looks fine, as there were 29 days in february 2008.

And if I test with :

<pre><code>$timestamp = strtotime('2009-03-03');
</code></pre>

I get :

<pre><code>2009-03-03
2009-03-02
2009-03-01
2009-02-28
2009-02-27
2009-02-26
2009-02-25
</code></pre>

Which looks fine too.

blocks|key|1256435|text|要生成过去10天(包括今天)的12am时间戳，可以使用以下代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1256436|<?php
for+($i=0;+$i<=10;+$i%2B%2B)+{
++echo+mktime+(0,+0,+0,+date('m'),+date('d')-$i,+date('Y'));
}
?>|code-block|syntax|javascript|1256437|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To generate the timestamp of 12am for the last 10 days (including today) the following code will do:

<pre><code>&lt;?php
for ($i=0; $i&lt;=10; $i++) {
 echo mktime (0, 0, 0, date('m'), date('d')-$i, date('Y'));
}
?&gt;
</code></pre>

blocks|key|1256450|text|您需要的一切都可以在this+page+of+the+php+manual中找到。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1256451|entityMap|0|LINK|mutability|MUTABLE|url|http://www.php.net/manual/en/function.date.php^0|A|R|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

Everything you need you can find in <a href="http://www.php.net/manual/en/function.date.php" rel="nofollow noreferrer">this page of the php manual</a>.

blocks|key|2666004|text|如果您足够幸运能够使用PHP+5.3+(何乐而不为呢？)然后，DateTime/Interval/Period类也会变得非常有用。下面的示例打印前7天(以及今天)相对于今天的日期。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2666005|$start++=+new+DateTime('-7+days',+new+DateTimeZone('UTC'));
$period+=+new+DatePeriod($start,+new+DateInterval('P1D'),+7);

foreach+($period+as+$date)+{
++++var_dump($date->format('D+d-m-Y'));
}|code-block|syntax|javascript|2666006|它输出类似以下内容：|2666007|string(14)+"Thu+18-02-2010"
string(14)+"Fri+19-02-2010"
string(14)+"Sat+20-02-2010"
string(14)+"Sun+21-02-2010"
string(14)+"Mon+22-02-2010"
string(14)+"Tue+23-02-2010"
string(14)+"Wed+24-02-2010"
string(14)+"Thu+25-02-2010"|2666008|使用strtotime可以相对容易地完成类似的操作，如下面的代码片段所示(它会产生与上面相同的输出)：|2666009|for+($i+=+7;+$i+>=+0;+$i--)+{
++++var_dump(date('D+d-m-Y',+strtotime("-$i+days")));
}|2666010|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/datetime|1|http://php.net/dateinterval|2|http://php.net/dateperiod|3|http://php.net/strtotime^0|V|8|0|14|8|1|1D|6|2|0|0|0|0|2|9|3|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@$A|15|B|16|1|17]|$A|18|B|19|1|1A]|$A|1B|B|1C|1|1D]]|C|$]]|$1|D|3|E|5|F|7|1E|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|1F|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|1G|8|@]|9|@]|C|$G|H]]|$1|M|3|N|5|6|7|1H|8|@]|9|@$A|1I|B|1J|1|1K]]|C|$]]|$1|O|3|P|5|F|7|1L|8|@]|9|@]|C|$G|H]]|$1|Q|3|-4|5|6|7|1M|8|@]|9|@]|C|$]]]|R|$S|$5|T|U|V|C|$W|X]]|Y|$5|T|U|V|C|$W|Z]]|10|$5|T|U|V|C|$W|11]]|12|$5|T|U|V|C|$W|13]]]]

If you're lucky enough to be able to play with PHP 5.3 (why not?) then the <a href="http://php.net/datetime" rel="nofollow noreferrer">DateTime</a>/<a href="http://php.net/dateinterval" rel="nofollow noreferrer">Interval</a>/<a href="http://php.net/dateperiod" rel="nofollow noreferrer">Period</a> classes will also come in exceptionally useful. The following example prints the dates for the previous 7 days (along with today) relative to today.

<pre><code>$start = new DateTime('-7 days', new DateTimeZone('UTC'));
$period = new DatePeriod($start, new DateInterval('P1D'), 7);

foreach ($period as $date) {
 var_dump($date-&gt;format('D d-m-Y'));
}
</code></pre>

Which outputs something like:

<pre><code>string(14) "Thu 18-02-2010"
string(14) "Fri 19-02-2010"
string(14) "Sat 20-02-2010"
string(14) "Sun 21-02-2010"
string(14) "Mon 22-02-2010"
string(14) "Tue 23-02-2010"
string(14) "Wed 24-02-2010"
string(14) "Thu 25-02-2010"
</code></pre>

Similar can be done relatively easily with <a href="http://php.net/strtotime" rel="nofollow noreferrer">strtotime</a> as in the snippet below (which produces the same output as above):

<pre><code>for ($i = 7; $i &gt;= 0; $i--) {
 var_dump(date('D d-m-Y', strtotime("-$i days")));
}
</code></pre>

I need help regarding generating dates and days of the last seven to ten days with respect to today. How an accurate timestamp can be created which can take care of week, month and year change ?

generating dates of previous seven days in php

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我需要帮助生成的日期和天数的最后七到十天相对于今天。如何创建一个准确的时间戳来处理周、月和年的变化？

问在php中生成前七天的日期
EN

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问在php中生成前七天的日期EN