blocks|key|916138|text|不是的。将date视为字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|916139|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

blocks|key|916150|text|在SQL查询中编写日期时，您将其作为字符串编写；您必须对准备好的语句执行相同的操作，并使用PDO::PARAM_STR，就像您在建议的代码部分中所做的那样。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|916151|对于“时间戳”，如果“时间戳”是指：|916152|PHP时间戳数据类型:它是相同的，您将把它作为一个string|916153|The+PHP+Unix时间戳传递，它是一个整数:您将向它传递一个int.|unordered-list-item|916154|916155|entityMap^0|19|E|0|0|P|6|0|X|3|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|T|8|@$9|U|A|V|B|C]]|D|@]|E|$]]|$1|J|3|K|5|L|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]|$1|N|3|-4|5|6|7|10|8|@]|D|@]|E|$]]]|O|$]]

When writing a date in an SQL query, you are writing it as a string; you have to do the same with prepared statements, and use <code>PDO::PARAM_STR</code>, like you did in the portion of code you proposed.

And for the "timestamp", if by "timestamp" you mean:

<ul>
<li>The MySQL timestamp data-type: it's the same, you'll pass it as a <code>string</code></li>
<li>The PHP Unix timestamp, which is an integer: you'll pass it an <code>int</code>.</li>
</ul>

blocks|key|1303318|text|只需使用php+date函数创建日期，就可以解决这个问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1303319|$handle->execute(array(":date"=>date("Y-m-d+H:i:s",+strtotime($date)),+PDO::PARAM_STR));|code-block|syntax|javascript|1303320|1303321|编辑:请注意，strtotime+(http://php.net/manual/en/function.strtotime.php)并不能处理所有类型的日期格式。|blockquote|offset|length|style|CODE|1303322|1303323|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/function.strtotime.php^0|0|0|0|7|9|I|1B|0|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|10|8|@$K|11|L|12|M|N]]|9|@$K|13|L|14|1|15]]|A|$]]|$1|O|3|-4|5|6|7|16|8|@]|9|@]|A|$]]|$1|P|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|Q|$R|$5|S|T|U|A|$V|W]]]]

Simply creating the date using php date function should fix this issue for you.

<pre><code>$handle-&gt;execute(array(":date"=&gt;date("Y-m-d H:i:s", strtotime($date)), PDO::PARAM_STR));
</code></pre>

<blockquote>
 Edit: Please note though, that <code>strtotime</code>
 (<a href="http://php.net/manual/en/function.strtotime.php" rel="nofollow noreferrer">http://php.net/manual/en/function.strtotime.php</a>) can't handle every
 kind of date formats.
</blockquote>

blocks|key|919023|text|这对我很有效。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|919024|//MS+SQL
$sql+=+"UPDATE+my_table+SET+current_date+=+GETDATE()+WHERE+id+=+43";
$statement+=+$pdo->prepare+($sql);
//$statement->bindParam+(":date",+strtotime+(date+("Y-m-d+H:i:s")),+PDO::PARAM_STR);
$statement->execute+();|code-block|syntax|javascript|919025|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This worked for me.

<pre><code>//MS SQL
$sql = "UPDATE my_table SET current_date = GETDATE() WHERE id = 43";
$statement = $pdo-&gt;prepare ($sql);
//$statement-&gt;bindParam (":date", strtotime (date ("Y-m-d H:i:s")), PDO::PARAM_STR);
$statement-&gt;execute ();
</code></pre>

blocks|key|1303400|text|您必须将日期视为字符串，但您可以创建一个函数，在将其作为参数传递之前检查它是否为有效日期。如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1303401|function+checkValidDate($date,+$format+=+"dd-mm-yyyy"){
++++++++++++if($format+===+"dd-mm-yyyy"){
++++++++++++$day+=+(int)+substr($date,0,2);
++++++++++++$month+=+(int)+substr($date,+3,2);
++++++++++++$year+=+(int)+substr($date,+6,4);

++++++++}else+if($format+===+"yyyy-mm-dd"){
++++++++++++$day+=+(int)+substr($date,8,2);
++++++++++++$month+=+(int)+substr($date,+5,2);
++++++++++++$year+=+(int)+substr($date,+0,4);
++++++++}

++++++++return+checkdate($month,+$day,+$year);
}|code-block|syntax|javascript|1303402|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You have to treat the date as string, but you can create a function to check if is a valid date before pass it as a param.
Like this:

<pre><code>function checkValidDate($date, $format = "dd-mm-yyyy"){
 if($format === "dd-mm-yyyy"){
 $day = (int) substr($date,0,2);
 $month = (int) substr($date, 3,2);
 $year = (int) substr($date, 6,4);

 }else if($format === "yyyy-mm-dd"){
 $day = (int) substr($date,8,2);
 $month = (int) substr($date, 5,2);
 $year = (int) substr($date, 0,4);
 }

 return checkdate($month, $day, $year);
}
</code></pre>

blocks|key|2711980|text|在DateTime中正确存储RDBMS值(作为字符串)的完整部分：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2711981|/**+@const+string+app_date_format+expected+date+format+in+the+PHP+domain+(Swiss)+*/
define(+'app_date_format',+'d.m.Y'+);+

/**+@var+PDOConnection+$db+*/
$db+=+new+\PDO(+$dsn,+$db_user,+$db_pass,+$db_options+);

/**+@var+DateTime+$date+*/
$date+=+\DateTime::createFromFormat(+app_date_format,+'30.11.2020'+);

$stmt+=+$db->+prepare(
++++"UPDATE+`test`
++++SET+`test_date`+=+STR_TO_DATE(:date,+'%25Y-%25m-%25d+%25H:%25i:%25s'+)
++++WHERE+`test`.`test_id`+=+:id"
);

$id+=+1;
$stmt->bindValue(+':id',+$id+);
$stmt->bindValue(+':date',+$date->+format(+'Y-m-d+H:i:s'));
$stmt->execute()+or+die(+$stmt->+errorInfo()[2]+);|code-block|syntax|javascript|2711982|使用PHP7.4.25；MariaDB+10.6.4测试|2711983|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

A complete section to properly store a DateTime value (as a string) in a RDBMS:
<pre><code>/** @const string app_date_format expected date format in the PHP domain (Swiss) */
define( 'app_date_format', 'd.m.Y' ); 

/** @var PDOConnection $db */
$db = new \PDO( $dsn, $db_user, $db_pass, $db_options );

/** @var DateTime $date */
$date = \DateTime::createFromFormat( app_date_format, '30.11.2020' );

$stmt = $db-&gt; prepare(
 &quot;UPDATE `test`
 SET `test_date` = STR_TO_DATE(:date, '%Y-%m-%d %H:%i:%s' )
 WHERE `test`.`test_id` = :id&quot;
);

$id = 1;
$stmt-&gt;bindValue( ':id', $id );
$stmt-&gt;bindValue( ':date', $date-&gt; format( 'Y-m-d H:i:s'));
$stmt-&gt;execute() or die( $stmt-&gt; errorInfo()[2] );
</code></pre>
Tested with PHP 7.4.25; MariaDB 10.6.4

Does some <code>PDO::PARAM_???</code> exist which can be used for dates or timestamps?
Sample code:
<pre><code>$sql = &quot;UPDATE my_table SET current_date = :date WHERE id = 43&quot;;
$statement = $pdo-&gt;prepare ($sql);
$statement-&gt;bindValue (&quot;:date&quot;, strtotime (date (&quot;Y-m-d H:i:s&quot;)), PDO::PARAM_STR);
$statement-&gt;execute ();
</code></pre>

PDO::PARAM for dates?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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是否存在可用于日期或时间戳的PDO::PARAM_???？示例代码：$sql = "UPDATE my_table SET current_date = :date WHERE id = 43";$statement = $pdo->prepare ($sql);$statement->bindValue (":dat...

问PDO::PARAM for date？
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