blocks|key|338939|text|您要查找的函数是：getpass()。不过，您会注意到它被标记为“遗留”。尽管它不会去任何地方，但该函数不允许指定输入缓冲区的大小，这使得它不是一个很好的接口。正如Jefromi所指出的，glibc手册以一种允许任意输入大小的方式提供了portable+example+code+for+implementing+getpass+from+scratch+(并且不是遗留的)。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|338940|entityMap|0|LINK|mutability|MUTABLE|url|http://opengroup.org/onlinepubs/007908775/xsh/getpass.html|1|http://www.gnu.org/software/libc/manual/html_node/getpass.html^0|9|9|0|3A|1N|1|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@$A|O|B|P|1|Q]|$A|R|B|S|1|T]]|C|$]]|$1|D|3|-4|5|6|7|U|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]|L|$5|G|H|I|C|$J|M]]]]

The function that you are looking for is: <a href="http://opengroup.org/onlinepubs/007908775/xsh/getpass.html" rel="noreferrer">getpass()</a>. You will note, though, that it is marked as "LEGACY". Although it isn't going to go anywhere, the function doesn't allow the size of the input buffer to be specified, which makes it not a very good interface. As Jefromi has noted, the glibc manual provides <a href="http://www.gnu.org/software/libc/manual/html_node/getpass.html" rel="noreferrer">portable example code for implementing getpass from scratch</a> in a way that allows an arbitrary input size (and isn't LEGACY).

blocks|key|338271|text|*这不是ANSI+C(感谢Billy)示例|type|unstyled|depth|inlineStyleRanges|entityRanges|data|338272|您可以使用_kbhit()检测按键，然后使用_getch()获取该值。这两个函数都不会在屏幕上回显内容。|338273|#include+<conio.h>++++++++++//For+keyboard+events
#include+<stdio.h>++++++++++//Include+this+or+iostream
#include+<locale>+++++++++++
int+main()
{
++++bool+bContinue+=+true;
++++char+szBuffer[255]+=+{0};
++++unsigned+int+nbufIndex+=+0;
++++while+(bContinue)
++++{
++++++++if+(_kbhit())
++++++++{
++++++++++++szBuffer[nbufIndex]+=+_getch();
++++++++++++if+(szBuffer[nbufIndex]+==+0xD)
++++++++++++{
++++++++++++++++bContinue+=+false;
++++++++++++}
++++++++++++else
++++++++++++{
++++++++++++++++%2B%2BnbufIndex;
++++++++++++++++printf("*");
++++++++++++}
++++++++}
++++}
++++printf("\n%25s\n",+szBuffer);
++++return+0;
}|code-block|syntax|javascript|338274|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

*This is not ANSI C (Thanks Billy) sample

You can detect keypress with _kbhit(), then get the value using _getch().
Both function will not echo the content on screen.

<pre><code>#include &lt;conio.h&gt; //For keyboard events
#include &lt;stdio.h&gt; //Include this or iostream
#include &lt;locale&gt; 
int main()
{
 bool bContinue = true;
 char szBuffer[255] = {0};
 unsigned int nbufIndex = 0;
 while (bContinue)
 {
 if (_kbhit())
 {
 szBuffer[nbufIndex] = _getch();
 if (szBuffer[nbufIndex] == 0xD)
 {
 bContinue = false;
 }
 else
 {
 ++nbufIndex;
 printf("*");
 }
 }
 }
 printf("\n%s\n", szBuffer);
 return 0;
}
</code></pre>

blocks|key|3047303|text|sudo是用C编写的，所以是的:)。您可能需要使用getpass()函数Safyan+mentioned，但如果您感兴趣，这里是实际的sudo工具实现它的位置：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3047304|http://sudo.ws/repos/sudo/file/dc3bf870f91b/src/tgetpass.c#l70|3047305|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/2634203/enter-password-in-c/2634220#2634220|1^0|P|9|17|9|0|0|0|1Q|1|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@$9|T|A|U|1|V]]|E|$]]|$1|F|3|G|5|6|7|W|8|@]|D|@$9|X|A|Y|1|Z]]|E|$]]|$1|H|3|-4|5|6|7|10|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]|P|$5|K|L|M|E|$N|G]]]]

sudo is written in C, so yes :). The <code>getpass()</code> function Safyan <a href="https://stackoverflow.com/questions/2634203/enter-password-in-c/2634220#2634220">mentioned</a> is probably what you want, but here's where the actual sudo tool does it if you're interested:

<a href="http://sudo.ws/repos/sudo/file/dc3bf870f91b/src/tgetpass.c#l70" rel="nofollow noreferrer">http://sudo.ws/repos/sudo/file/dc3bf870f91b/src/tgetpass.c#l70</a>

blocks|key|338295|text|穷人的方法是逐个字符地读取用户输入的字符，并在接收到每个字符后打印出一个退格字符，后跟*。从技术上讲，输出被发送到控制台，但它会立即被一个星号擦除和覆盖(通常在该帧被绘制到屏幕上之前)。请注意，这并不是一种真正的安全方法，并且有几个安全漏洞，但对于低技术、低安全性的应用程序，它是有效的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|338296|entityMap^0|17|1|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

The poor-man's method of doing this is to read user input character by character, and after each character is received print out a backspace character followed by <code>*</code>. The output is technically sent to the console, but it is immediately erased and overwritten by an asterisk (often before that frame is even drawn to the screen). Note that this is not really a secure method and has several security holes, but for low-tech low-security applications, it works.

blocks|key|1639061|text|#include+<stdio.h>
#include+<conio.h>

void+main()
{

++++char+pwd[15];
++++int+i;
++++printf("Enter+Password+:+");
++++for(i=0;i<15;i%2B%2B)
++++{
++++pwd[i]=getch();
++++++++if(pwd[i]!='\r')
++++++++{
++++++++++++printf("*");
++++++++}
++++++++if(pwd[i]==13)
++++++++++++break;
++++}

++++printf("\n+++++\nPassword+is+:+");
++++for(i=0;i<15;i%2B%2B)
++++{
++++++++printf("%25d+",pwd[i]);
++++}
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1639062|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>#include &lt;stdio.h&gt;
#include &lt;conio.h&gt;

void main()
{

 char pwd[15];
 int i;
 printf("Enter Password : ");
 for(i=0;i&lt;15;i++)
 {
 pwd[i]=getch();
 if(pwd[i]!='\r')
 {
 printf("*");
 }
 if(pwd[i]==13)
 break;
 }

 printf("\n \nPassword is : ");
 for(i=0;i&lt;15;i++)
 {
 printf("%d ",pwd[i]);
 }
}
</code></pre>

I am aware that it is not possible to echo the * while you type in standard ANSI C. But is there a way to display nothing while someone is typing their password in the console. What I mean is like the sudo prompts in a Unix/Linux terminal. Like if you type in the command: <code>sudo cp /etc/somefile ~/somedir</code>. You are usually prompted for the root password. And while you type it in, the terminal displays nothing. Is this effect possible in C? If it is, how?

Enter Password in C

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我知道当你输入标准的ANSI C时，回显*是不可能的。但是，当有人在控制台中输入密码时，有没有办法什么也不显示呢？我的意思是，就像Unix/Linux终端中的sudo提示符。例如，如果您键入命令：sudo cp /etc/somefile ~/somedir。系统通常会提示您输入root密码。当你输入的时候，终端什么也...

问用C输入密码
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