blocks|key|319704|text|该模块的维护者已经下达了you+should+use+the+standard+JDK+URI类的命令：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|319705|319706|将URI和URIUtils替换为标准Java+URI的原因非常简单:没有人愿意维护这些类。|blockquote|319707|319708|有许多实用程序方法可以帮助解决java.net.URI实现中的各种问题，但除此之外，标准的JRE类应该就足够了，不是吗？|319709|319710|因此，最简单的方法是查看3.1版本中的encodePath源代码，并在您自己的代码中复制它所做的事情(或者直接将方法/类复制到您的代码库中)。|319711|或者，您可以使用您提到的问题的公认答案(但似乎您必须先将URL分成几个部分)：|319712|new+URI(
++++"http",+
++++"search.barnesandnoble.com",+
++++"/booksearch/first+book.pdf",
++++null).toString();|code-block|syntax|javascript|319713|entityMap|0|LINK|mutability|MUTABLE|url|http://marc.info/?l=httpclient-users&m=125425095705062&w=2^0|C|V|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@$A|13|B|14|1|15]]|C|$]]|$1|D|3|-4|5|6|7|16|8|@]|9|@]|C|$]]|$1|E|3|F|5|G|7|17|8|@]|9|@]|C|$]]|$1|H|3|-4|5|6|7|18|8|@]|9|@]|C|$]]|$1|I|3|J|5|6|7|19|8|@]|9|@]|C|$]]|$1|K|3|-4|5|6|7|1A|8|@]|9|@]|C|$]]|$1|L|3|M|5|6|7|1B|8|@]|9|@]|C|$]]|$1|N|3|O|5|6|7|1C|8|@]|9|@]|C|$]]|$1|P|3|Q|5|R|7|1D|8|@]|9|@]|C|$S|T]]|$1|U|3|-4|5|6|7|1E|8|@]|9|@]|C|$]]]|V|$W|$5|X|Y|Z|C|$10|11]]]]

The maintainers of the module have decreed that <a href="http://marc.info/?l=httpclient-users&amp;m=125425095705062&amp;w=2" rel="noreferrer">you should use the standard JDK</a> URI class instead:

<blockquote>
 The reason URI and URIUtils got replaced with the standard Java URI was 
 very simple: there was no one willing to maintain those classes.
 
 There is a number of utility methods that help work around various 
 issues with the java.net.URI implementation but otherwise the standard 
 JRE classes should be sufficient, should not they?
</blockquote>

So, the easiest is to look at the source of encodePath from the 3.1 release and duplicate what it does in your own code (or just copy the method/class into your codebase).

Or you could go with the accepted answer on the question you referred to (but it seems you have to break the URL into parts first):

<pre><code>new URI(
 "http", 
 "search.barnesandnoble.com", 
 "/booksearch/first book.pdf",
 null).toString();
</code></pre>

blocks|key|3010825|text|这可以使用httpclient-4.X+()中的org.apache.http.client.utils.URIBuilder实用程序来实现，如下所示。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3010826|++++public+static+String+encodePath(final+String+path)+{
+++++++if(path.length()+==+0)
++++++++++return+"";
+++++++else
++++++++++return+new+URIBuilder().setPath(path).toString();
++++}|code-block|syntax|javascript|3010827|entityMap^0|O|13|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

This can be achieved using <code>org.apache.http.client.utils.URIBuilder</code> utility in httpclient-4.X () as follows. 

<pre><code> public static String encodePath(final String path) {
 if(path.length() == 0)
 return "";
 else
 return new URIBuilder().setPath(path).toString();
 }
</code></pre>

blocks|key|3010832|text|您可以使用Standard+JDK函数，例如|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3010833|public+static+String+encodeURLPathComponent(String+path)+{
++++try+{
++++++++return+new+URI(null,+null,+path,+null).toASCIIString();
++++}+catch+(URISyntaxException+e)+{
++++++++//+do+some+error+handling
++++}
++++return+"";
}|code-block|syntax|javascript|3010834|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.oracle.com/javase/8/docs/api/java/net/URI.html#URI-java.lang.String-java.lang.String-java.lang.String-int-java.lang.String-java.lang.String-java.lang.String-^0|5|C|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

You can use <a href="https://docs.oracle.com/javase/8/docs/api/java/net/URI.html#URI-java.lang.String-java.lang.String-java.lang.String-int-java.lang.String-java.lang.String-java.lang.String-" rel="nofollow noreferrer">Standard JDK</a> functions, e.g.
<pre><code>public static String encodeURLPathComponent(String path) {
 try {
 return new URI(null, null, path, null).toASCIIString();
 } catch (URISyntaxException e) {
 // do some error handling
 }
 return &quot;&quot;;
}
</code></pre>

I want to do what's described in question <a href="https://stackoverflow.com/questions/724043/http-url-address-encoding-in-java">724043</a>, namely encode the path components of a URI. The class recommended to do that is <a href="http://hc.apache.org/httpclient-3.x/apidocs/org/apache/commons/httpclient/util/URIUtil.html" rel="nofollow noreferrer">URIUtil</a> from Commons HttpClient 3.1. Unfortunately, that class seems to have disappeared from the most recent version of HttpClient. A similarly named class from HttpClient 4.1, <a href="http://hc.apache.org/httpcomponents-client/httpclient/apidocs/org/apache/http/client/utils/URIUtils.html" rel="nofollow noreferrer">URIUtils</a>, doesn't provide the same functionality. Has this class/method been moved to some other library that I'm not aware of or is it just gone? Am I best off just copying the class from the 3.1 release into my code or is there a simpler way?

What happened to URIUtil.encodePath from commons-httpclient-3.1?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想做问题中描述的事情，即对URI的路径组件进行编码。推荐使用的类是Commons HttpClient 3.1中的。不幸的是，这个类似乎已经从最新版本的HttpClient中消失了。来自HttpClient 4.1的一个类似命名的类没有提供相同的功能。这个类/方法是否被移到了我不知道的其他库中，或者它只是消失了？最好...

问commons-httpclient-3.1中的URIUtil.encodePath发生了什么变化？
EN

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问commons-httpclient-3.1中的URIUtil.encodePath发生了什么变化？EN