blocks|key|829597|text|var+i;
for(i+=+0;+i+<+arrayObj.length;+i%2B%2B){
++++arrayObj[i].stroke+=+arrayObj[i]['key1'];
++++delete+arrayObj[i].key1;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|829598|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>var i;
for(i = 0; i &lt; arrayObj.length; i++){
    arrayObj[i].stroke = arrayObj[i]['key1'];
    delete arrayObj[i].key1;
}
</code></pre>


blocks|key|614320|text|function+changeKey(originalKey,+newKey,+arr)
{
++var+newArr+=+[];
++for(var+i+=+0;+i+<+arr.length;+i%2B%2B)
++{
++++var+obj+=+arr[i];
++++obj[newKey]+=+obj[originalKey];
++++delete(obj[originalKey]);
++++newArr.push(obj);
++}
++return+newArr;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|614321|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>function changeKey(originalKey, newKey, arr)
{
  var newArr = [];
  for(var i = 0; i &lt; arr.length; i++)
  {
    var obj = arr[i];
    obj[newKey] = obj[originalKey];
    delete(obj[originalKey]);
    newArr.push(obj);
  }
  return newArr;
}
</code></pre>


blocks|key|614441|text|您不需要更改密钥名称。您可以指定一个新的密钥名称/值，然后根据需要删除以前的密钥。在您的示例中：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|614442|var+arrayObj+=+[{key1,'value1',+key2:'value2'},{key1,'value1',+key2:'value2'}];
var+o+=+arrayObj[0];+++//+get+first+object
var+val+=+o.key1;++++++//+get+current+value
o.stroke+=+val;++++++++//+assign+to+new+key
delete+o.key1;+++++++++//+remove+previous+key|code-block|syntax|javascript|614443|如果要对主数组中的所有对象执行此操作，只需将其放入循环中，该循环将遍历数组的内容。我在这里放了更多的中间任务，只是为了记录正在发生的事情。|614444|或者循环中的缩写版本：|614445|for+(var+i+=+0;+i+<+arrayObj.length;+i%2B%2B)+{
++++var+o+=+arrayObj[i];
++++o.stroke+=+o.key1;
++++delete+o.key1;
}|614446|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

<p>You don't change a key name.  You can assign a new key name/value and then remove the previous key if you want.  In your example:</p>

<pre><code>var arrayObj = [{key1,'value1', key2:'value2'},{key1,'value1', key2:'value2'}];
var o = arrayObj[0];   // get first object
var val = o.key1;      // get current value
o.stroke = val;        // assign to new key
delete o.key1;         // remove previous key
</code></pre>

<p>If you wanted to do that for all the objects in your main array, you would just put that in a loop that iterates over the contents of your array.  I've put more intermediate assignments in here than neccessary just to document what's going on.</p>

<p>Or a shortened version in a loop:</p>

<pre><code>for (var i = 0; i &lt; arrayObj.length; i++) {
    var o = arrayObj[i];
    o.stroke = o.key1;
    delete o.key1;
}
</code></pre>


blocks|key|614507|text|您不能更改属性名称，您必须使用新名称添加值并删除旧属性：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|614508|for+(var+i+=+0;+i+<+arrayObj.length;+i%2B%2B)+{
++arrayObj[i].stroke+=+arrayObj[i].key1;
++delete+arrayObj[i].key1;
}|code-block|syntax|javascript|614509|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>You can't change a property name, you have to add the value with a new name and delete the old property:</p>

<pre><code>for (var i = 0; i &lt; arrayObj.length; i++) {
  arrayObj[i].stroke = arrayObj[i].key1;
  delete arrayObj[i].key1;
}
</code></pre>


blocks|key|614583|text|在最近的JavaScript+(和TypeScript)中，使用destructuring+with+rest+syntax、spread+syntax和array+map替换对象数组中的一个关键字符串。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|614584|​|614585|const+arrayOfObj+=+[{
++key1:+'value1',
++key2:+'value2'
},+{
++key1:+'value1',
++key2:+'value2'
}];
const+newArrayOfObj+=+arrayOfObj.map(({
++key1:+stroke,
++...rest
})+=>+({
++stroke,
++...rest
}));

console.log(newArrayOfObj);|code-block|syntax|javascript|614586|614587|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Destructuring_assignment|1|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Spread_syntax|2|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map^0|2B|3|W|U|0|1R|D|1|25|9|2|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@$9|10|A|11|B|C]]|D|@$9|12|A|13|1|14]|$9|15|A|16|1|17]|$9|18|A|19|1|1A]]|E|$]]|$1|F|3|G|5|6|7|1B|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|1C|8|@]|D|@]|E|$K|L]]|$1|M|3|G|5|6|7|1D|8|@]|D|@]|E|$]]|$1|N|3|-4|5|6|7|1E|8|@]|D|@]|E|$]]]|O|$P|$5|Q|R|S|E|$T|U]]|V|$5|Q|R|S|E|$T|W]]|X|$5|Q|R|S|E|$T|Y]]]]

<p>In recent JavaScript (and TypeScript), use <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Destructuring_assignment" rel="noreferrer">destructuring with rest syntax</a>, <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Spread_syntax" rel="noreferrer">spread syntax</a>, and <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map" rel="noreferrer">array <code>map</code></a> to replace one of the key strings in an array of objects.</p>
<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const arrayOfObj = [{
  key1: 'value1',
  key2: 'value2'
}, {
  key1: 'value1',
  key2: 'value2'
}];
const newArrayOfObj = arrayOfObj.map(({
  key1: stroke,
  ...rest
}) =&gt; ({
  stroke,
  ...rest
}));

console.log(newArrayOfObj);</code></pre>
</div>
</div>
</p>


blocks|key|829952|text|ES6+map()方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|829953|let+arrayObj+=+[{key1:'value1',+key2:'value2'},{key1:'value1',+key2:'value2'}];

arrayObj+=+arrayObj.map(item+=>+{
++++++return+{
++++++++stroke:+item.key1,
++++++++key2:+item.key2
++++++};
++++});|code-block|syntax|javascript|829954|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map^0|4|5|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

<p>ES6 <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map" rel="noreferrer">map()</a> method:</p>
<pre><code>let arrayObj = [{key1:'value1', key2:'value2'},{key1:'value1', key2:'value2'}];

arrayObj = arrayObj.map(item =&gt; {
      return {
        stroke: item.key1,
        key2: item.key2
      };
    });
</code></pre>


blocks|key|830048|text|ES6只需要一行代码|type|unstyled|depth|inlineStyleRanges|entityRanges|data|830049|尝试以下代码：|830050|arrayObj.map(({+stroke,+key2+})+=>+({+yourNewKey:+stroke,+yourNewKey2:+key2+}));|code-block|syntax|javascript|830051|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

<p>just one line of code needed with ES6</p>

<p>try following code :</p>

<pre><code>arrayObj.map(({ stroke, key2 }) =&gt; ({ yourNewKey: stroke, yourNewKey2: key2 }));
</code></pre>


blocks|key|830071|text|const+company+=++[{+id:"1",+name:"somename"},{+id:"1",+name:"somename"}]

company.map(({+id,+name+})+=>+({+companyId:+id,+companyName:+name+}));

//+output
//[{+companyId:"1",+companyName:"somename"},{+companyId:"1",+//companyName:"somename"}]|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|830072|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre class="lang-js prettyprint-override"><code>
const company =  [{ id:"1", name:"somename"},{ id:"1", name:"somename"}]

company.map(({ id, name }) =&gt; ({ companyId: id, companyName: name }));

// output
//[{ companyId:"1", companyName:"somename"},{ companyId:"1", //companyName:"somename"}]

</code></pre>


blocks|key|830120|text|纯javascript|type|unstyled|depth|inlineStyleRanges|entityRanges|data|830121|var+array=[{oldkey:'oldkeyvalue',oldkey2:'oldkey2'}]
var+result=array.map(({+oldkey:+newkey,+...rest+})+=>+({+newkey,+...rest+}));
console.log(result)|code-block|syntax|javascript|830122|​|830123|加反划线或下划线js|830124|//Lodash/underscore.js
_.map(array,(({+oldkey:+newkey,+...rest+}))=>({+oldkey:+newkey,+...rest+}))|830125|上述技术不能设置字符串名称|830126|例如:全名或姓|830127|错误的方式：|830128|name:full+name|830129|正确的方式|830130|name:full_name|830131|您可以使用map以相同的方式实现string对象|830132|array.map((x)=>{
var+y={};
//also+use+spread+operator+if+necessary+but+key+want+to+remove+manually

y['full+name']=x['name'];
return+y;
})|830133|entityMap^0|0|0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|16|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|17|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|18|8|@]|9|@]|A|$E|F]]|$1|M|3|N|5|6|7|19|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|1A|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1B|8|@]|9|@]|A|$]]|$1|S|3|T|5|D|7|1C|8|@]|9|@]|A|$E|F]]|$1|U|3|V|5|6|7|1D|8|@]|9|@]|A|$]]|$1|W|3|X|5|D|7|1E|8|@]|9|@]|A|$E|F]]|$1|Y|3|Z|5|6|7|1F|8|@]|9|@]|A|$]]|$1|10|3|11|5|D|7|1G|8|@]|9|@]|A|$E|F]]|$1|12|3|-4|5|6|7|1H|8|@]|9|@]|A|$]]]|13|$]]

<p>pure javascript
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var array=[{oldkey:'oldkeyvalue',oldkey2:'oldkey2'}]
var result=array.map(({ oldkey: newkey, ...rest }) =&gt; ({ newkey, ...rest }));
console.log(result)</code></pre>
</div>
</div>
</p>
<p>lodash or underscore js</p>
<pre><code>//Lodash/underscore.js
_.map(array,(({ oldkey: newkey, ...rest }))=&gt;({ oldkey: newkey, ...rest }))
</code></pre>
<p>The above technique cant set  string name</p>
<p>eg:full name or last name</p>
<p>wrong way:</p>
<pre><code>name:full name
</code></pre>
<p>right way</p>
<pre><code>name:full_name
</code></pre>
<p>you can achieve string object in same way using map</p>
<pre><code>array.map((x)=&gt;{
var y={};
//also use spread operator if necessary but key want to remove manually

y['full name']=x['name'];
return y;
})
</code></pre>


blocks|key|830185|text|您可以使用一种不可变的方式来更改对象。还可以向对象添加新的键值对|type|unstyled|depth|inlineStyleRanges|entityRanges|data|830186|​|830187|let+arrayOfObj+=+[{id:"0",name:'myName'},{id:"2",name:'myNewName'}]
const+newArr+=+arrayOfObj.map(item+=>+({+...item,+id+:+Number(item.id),someRandomKey:'RandomValue'+}))
console.log(newArr)|code-block|syntax|javascript|830188|830189|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

<p>You can use an immutable way of changing an object.
You can also add new key-value pairs to the object</p>
<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let arrayOfObj = [{id:"0",name:'myName'},{id:"2",name:'myNewName'}]
const newArr = arrayOfObj.map(item =&gt; ({ ...item, id : Number(item.id),someRandomKey:'RandomValue' }))
console.log(newArr)</code></pre>
</div>
</div>
</p>


<p>How can I change the key name in an array of objects?</p>

<pre><code>var arrayObj = [{key1:'value1', key2:'value2'},{key1:'value1', key2:'value2'}];
</code></pre>

<p>How can I change each <code>key1</code> to <code>stroke</code> so that I get:</p>

<pre><code>var arrayObj = [{stroke:'value1', key2:'value2'},{stroke:'value1', key2:'value2'}];
</code></pre>


Changing the key name in an array of objects?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如何更改对象数组中的键名？var arrayObj = [{key1:'value1', key2:'value2'},{key1:'value1', key2:'value2'}];如何将每个key1更改为stroke，以便获得：var arrayObj = [{stroke:'value1', key2:'valu...

问更改对象数组中的键名？
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问更改对象数组中的键名？EN