在MySQL中,我的sql如下所示
SELECT * , IF( `Word` = 'sim', 1, IF( `Word` LIKE 'sim%', 2, IF( `Word` LIKE '%sim', 4, 3 ) ) ) AS `sort`
FROM `dblist`
WHERE `Word` LIKE '%sim%'
ORDER BY `sort` , `Word`此sql在SQlite中不起作用。我想做结果排序。
SELECT * FROM dblist where word like 'sim' or word like 'sim%' or word like '%sim%' or word like '%sim'等于sim是第一个,sim%是第二个,%sim%是第三个,然后%sim是最后一个。
目前我还不能像sqlite中的mysql那样排序。如何更改sql以对结果进行排序?
发布于 2010-05-10 13:43:40
您应该使用CASE expression而不是IF,因为SQLite不支持后者。以下是您需要的SQL:
SELECT
*,
CASE WHEN `Word` = 'sim' THEN 1
WHEN `Word` LIKE 'sim%' THEN 2
WHEN `Word` LIKE '%sim' THEN 4
ELSE 3
END `sort`
FROM `dblist`
WHERE `Word` LIKE '%sim%'
ORDER BY `sort` , `Word`发布于 2010-05-10 13:50:59
SELECT * , case when `Word` = 'sim' then 1 else case when `Word` LIKE 'sim%' then 2 else case when `Word` LIKE '%sim' then 4 else 3 end end end as sort
FROM `dblist`
WHERE `Word` LIKE '%sim%'
ORDER BY `sort` , `Wordhttps://stackoverflow.com/questions/2800534
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