blocks|key|621858|text|没有成功吗？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|621859|echo+strtotime("2010-06-19+09:39:23");|code-block|syntax|javascript|621860|给了我|621861|1276940363|621862|(__mktime(9,+39,+23,+6,+19,+2010)给出了相同的时间，因此解析工作正常)|offset|length|style|CODE|621863|621864|为了得到以秒为单位的差异，你可以减去时间戳，例如|621865|$diff+=+time()+-+strtotime("2010-06-19+09:39:23");|621866|如果差值大于86400+(60*60*24)秒，则时间戳的间隔超过一天：|621867|if(time()+-+strtotime("2010-06-19+09:39:23")+>+60*60*24)+{
+++//+timestamp+is+older+than+one+day
}|621868|entityMap^0|0|0|0|0|3|U|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|13|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|15|8|@$M|16|N|17|O|P]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|18|8|@]|9|@]|A|$]]|$1|R|3|S|5|6|7|19|8|@]|9|@]|A|$]]|$1|T|3|U|5|D|7|1A|8|@]|9|@]|A|$E|F]]|$1|V|3|W|5|6|7|1B|8|@]|9|@]|A|$]]|$1|X|3|Y|5|D|7|1C|8|@]|9|@]|A|$E|F]]|$1|Z|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]]|10|$]]

No success?

<pre><code>echo strtotime("2010-06-19 09:39:23");
</code></pre>

gives me 

<pre><code>1276940363
</code></pre>

(<code>mktime(9, 39, 23, 6, 19, 2010)</code> gives the same time, so the parsing works correctly)

<hr>

To get the differences in seconds, you can substract the timestamps, e.g.

<pre><code>$diff = time() - strtotime("2010-06-19 09:39:23");
</code></pre>

If the differences is larger than 86400 (60*60*24) seconds, then the timestamps are more than one day apart:

<pre><code>if(time() - strtotime("2010-06-19 09:39:23") &gt; 60*60*24) {
 // timestamp is older than one day
}
</code></pre>

blocks|key|1370332|text|您还可以执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1370333|SELECT+*+FROM+my_table+WHERE+timestamp+<+NOW()+-+INTERVAL+1+DAY;|code-block|syntax|javascript|1370334|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can also do:

<pre><code>SELECT * FROM my_table WHERE timestamp &lt; NOW() - INTERVAL 1 DAY;
</code></pre>

blocks|key|623990|text|为什么你要把PHP时间和MySQL时间混在一起？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|623991|相反，可以直接在MySQL中进行比较：|623992|要获取MySQL格式的当前日期/时间，请使用NOW()函数。例如，您可以比较2010-06-19+09:39:23'+<+DATE_SUB(NOW(),+INTERVAL+1+DAY)|offset|length|style|CODE|623993|这将检查给定的日期(假设在列中)是否早于24小时。|623994|如果一定要将MySQL时间戳转换为UNIX时间戳，可以使用MySQL的UNIX_TIMESTAMP()函数。|623995|entityMap^0|0|0|M|5|12|1I|0|0|Z|G|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Q|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|R|8|@$F|S|G|T|H|I]|$F|U|G|V|H|I]]|9|@]|A|$]]|$1|J|3|K|5|6|7|W|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|X|8|@$F|Y|G|Z|H|I]]|9|@]|A|$]]|$1|N|3|-4|5|6|7|10|8|@]|9|@]|A|$]]]|O|$]]

Why are you mixing PHP times and MySQL times? 

Instead, do the comparison directly in MySQL:

To get the current date/time in MySQL use the <code>NOW()</code> function. You can compare, for example, <code>2010-06-19 09:39:23' &lt; DATE_SUB(NOW(), INTERVAL 1 DAY)</code>

This would check to see if the given date (presumably in a column) is older than 24 hours.

If it's absolutely necessary to convert a MySQL timestamp to a UNIX timestamp, you can use MySQL's <code>UNIX_TIMESTAMP()</code> function to do so.

blocks|key|3617704|text|我写了一个函数，通过它可以确定第一个给定日期是大于还是小于第二个给定日期一天或n天。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3617705|$date1+=+"2013/03/01";
$date2+=+"2013/03/01";
$sign++=+"-";
$diff++=+1;
$result+=+isDaysSmallerBigger($date1,+$date2,+$sign,+$diff);
var_dump($result);

/**
+*+Note:+this+function+is+only+supported+in+php+5.3+or+above
+*+1.+If+$date1+-+$date2+=+$sign+$diff+days,+return+true;
+*+2.+If+$date1+equals+$date2+and+$diff+euqals+0,+whether+$sign+is+"%2B"+or+"-",+return+true
+*+3.+Else+return+false;+
+*+@param+unknown_type+$date1
+*+@param+unknown_type+$date2
+*+@param+string+$sign:+"-":+$date1+<+$date2;+"%2B":+$date1+>+$date2;+
+*+Besides+if+$diff+is+0,+then+both+"-"+and+"%2B"+means+$date1+===+$date2;
+*+@param+integer+$diff:+date+difference+between+two+given+dates
+*/
function+isDaysSmallerBigger($date1,+$date2,+$sign,+$diff)+{
++++$dateTime1+=+new+DateTime($date1);
++++$dateTime2+=+new+DateTime($date2);

++++$interval+=+$dateTime2->diff($dateTime1);
++++$dayDiff++=+$interval->format('%25a');
++++$diffSign+=+$interval->format('%25R');+

++++if((int)$dayDiff+===+(int)$diff)+{
++++++++//+Correct+date+difference

++++++++if((int)$diff+!==+0)+{
++++++++++//+Day+difference+is+not+0
++++++++++if($diffSign+===+$sign)+{
++++++++++++return+true;
++++++++++}+else+{
++++++++++++return+false;
++++++++++}
++++++++}+else+if((int)$diff+===+0)+{
++++++++++//+Day+difference+is+0,+then+both+given+"%2B"+and+"-"+return+true
++++++++++return+true;
++++++++}+
++++}+else+{
++++++++//+Incorrect+date+difference
++++++++return+false;+++
++++}+++
}|code-block|syntax|javascript|3617706|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I wrote a function, by which you can determine if the first given date is one day or n days bigger or smaller than the second given date.

<pre><code>$date1 = "2013/03/01";
$date2 = "2013/03/01";
$sign = "-";
$diff = 1;
$result = isDaysSmallerBigger($date1, $date2, $sign, $diff);
var_dump($result);

/**
 * Note: this function is only supported in php 5.3 or above
 * 1. If $date1 - $date2 = $sign $diff days, return true;
 * 2. If $date1 equals $date2 and $diff euqals 0, whether $sign is "+" or "-", return true
 * 3. Else return false; 
 * @param unknown_type $date1
 * @param unknown_type $date2
 * @param string $sign: "-": $date1 &lt; $date2; "+": $date1 &gt; $date2; 
 * Besides if $diff is 0, then both "-" and "+" means $date1 === $date2;
 * @param integer $diff: date difference between two given dates
 */
function isDaysSmallerBigger($date1, $date2, $sign, $diff) {
 $dateTime1 = new DateTime($date1);
 $dateTime2 = new DateTime($date2);

 $interval = $dateTime2-&gt;diff($dateTime1);
 $dayDiff = $interval-&gt;format('%a');
 $diffSign = $interval-&gt;format('%R'); 

 if((int)$dayDiff === (int)$diff) {
 // Correct date difference

 if((int)$diff !== 0) {
 // Day difference is not 0
 if($diffSign === $sign) {
 return true;
 } else {
 return false;
 }
 } else if((int)$diff === 0) {
 // Day difference is 0, then both given "+" and "-" return true
 return true;
 } 
 } else {
 // Incorrect date difference
 return false; 
 } 
}
</code></pre>

I have a record returned from MySQL that has a datetime field. What I want to do is take this value and see if it is older then 24 hours, I presume using PHP's time() to get the current time.

At the moment if I echo them out I get:

<pre><code> 1276954824 this is php's time()
 2010-06-19 09:39:23 this is the MySQL datetime
</code></pre>

I presume the top one is a unix time? Have been playing around with strtotime but with not much success..

ANy help welcome!

Checking if mySql datetime is older then 1 day from php now()

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个从MySQL返回的记录，它有一个datetime字段。我想要做的是获取这个值，看看它是否早于24小时，我假设使用PHP的time()来获取当前时间。现在，如果我把它们说出来，我会得到： 1276954824            this is php's time() 2010-06-19 09:39:23   this is the MySQL datetime我假设最上面的是unix

问检查mySql datetime是否早于php now()的1天
EN

回答 4

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问检查mySql datetime是否早于php now()的1天EN

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