blocks|key|3737487|text|the_styles+?+(function()+{the_styles.appendTo('head');+the_styles=null})()+:+<etc>|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3737488|只需将代码块包装在(function()+{和})()中即可。|unstyled|offset|length|style|CODE|3737489|现在是最难的部分：，为什么你想要这样做？也许有更好的解决方案！|BOLD|3737490|entityMap^0|0|9|D|N|4|0|9|4|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|Q|8|@$G|R|H|S|I|J]|$G|T|H|U|I|J]]|9|@]|A|$]]|$1|K|3|L|5|F|7|V|8|@$G|W|H|X|I|M]]|9|@]|A|$]]|$1|N|3|-4|5|F|7|Y|8|@]|9|@]|A|$]]]|O|$]]

<pre><code>the_styles ? (function() {the_styles.appendTo('head'); the_styles=null})() : &lt;etc&gt;
</code></pre>

Just wrap the code block in <code>(function() {</code> and <code>})()</code>.

Now for the hard part: why would you want to do this? Perhaps there's a better solution!

blocks|key|1426309|text|我同意glowcoder，但如果你仍然想要它：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1426310|the_styles+?+function(){+the_styles.appendTo('head');+the_styles=null;}()+:+the_styles+=+$('.stylesheet').detach();|code-block|syntax|javascript|1426311|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

i agree with glowcoder but if you still want it:

<pre><code>the_styles ? function(){ the_styles.appendTo('head'); the_styles=null;}() : the_styles = $('.stylesheet').detach();
</code></pre>

blocks|key|2329871|text|the_styles+?+the_styles.appendTo('head')+:+the_styles+=+$('.stylesheet').detach();|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2329872|如果你要覆盖它，你不需要将它设为空！|unstyled|2329873|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>the_styles ? the_styles.appendTo('head') : the_styles = $('.stylesheet').detach();
</code></pre>

you dont need to null it if your overwriting it !

blocks|key|1430300|text|the_styles=the_styles+%7C%7C+$('.stylesheet').detach();+the_styles.appendTo('head');|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1430301|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>the_styles=the_styles || $('.stylesheet').detach(); the_styles.appendTo('head');
</code></pre>

blocks|key|3737716|text|按如下方式使用逗号运算符：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3737717|the_styles+?+(the_styles.appendTo('head'),+the_styles=null)+:+the_styles+=++$('.stylesheet').detach();|code-block|syntax|javascript|3737718|以下是Mozilla开发人员中心对逗号操作符的描述：|3737719|3737720|如果要在需要单个表达式的位置包含多个表达式，则可以使用逗号运算符。此运算符最常见的用法是在for循环中提供多个参数。|blockquote|3737721|3737722|点击此处阅读更多信息：https://developer.mozilla.org/en/Core_JavaScript_1.5_Reference/Operators/Special_Operators/Comma_Operator|offset|length|3737723|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en/Core_JavaScript_1.5_Reference/Operators/Special_Operators/Comma_Operator^0|0|0|0|0|0|0|B|2X|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|11|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|12|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|13|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|14|8|@]|9|@]|A|$]]|$1|N|3|O|5|6|7|15|8|@]|9|@$P|16|Q|17|1|18]]|A|$]]|$1|R|3|-4|5|6|7|19|8|@]|9|@]|A|$]]]|S|$T|$5|U|V|W|A|$X|Y]]]]

Use the comma operator this way:

<pre><code>the_styles ? (the_styles.appendTo('head'), the_styles=null) : the_styles = $('.stylesheet').detach();
</code></pre>

Here's what the Mozilla Developer Center writes about the comma operator:

<blockquote>
 You can use the comma operator when you want to include multiple expressions in a location that requires a single expression. The most common usage of this operator is to supply multiple parameters in a for loop.
 
 Read more here: <a href="https://developer.mozilla.org/en/Core_JavaScript_1.5_Reference/Operators/Special_Operators/Comma_Operator" rel="noreferrer">https://developer.mozilla.org/en/Core_JavaScript_1.5_Reference/Operators/Special_Operators/Comma_Operator</a>
</blockquote>

blocks|key|2329974|text|谁需要三元运算符？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2329975|​the_styles+=+!the_styles+&&+$('.stylesheet').detach()​​​​+%7C%7C
+++++++++++++the_styles.appendTo('head')+&&+null;​|code-block|syntax|javascript|2329976|Had必须交换表达式，否则第一个表达式的null值将始终强制计算第二个表达式.detach()。|offset|length|style|CODE|2329977|关于聪明代码的唯一一件事是，一旦你在喝完咖啡后回到它上面，它甚至对你来说也没有任何意义。所以这要好得多：|2329978|if(the_styles)+{
++++the_styles.appendTo('head')
++++the_styles+=+null;
}
else+{
++++the_styles+=+the_styles.detach('.stylesheet');
}|2329979|对我来说，即使是上面的简单化版本也没有任何意义。什么部分是显而易见的，但是为什么要这样做？|BOLD|2329980|entityMap^0|0|0|K|4|12|9|0|0|0|11|3|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|W|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|X|8|@$I|Y|J|Z|K|L]|$I|10|J|11|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|12|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|14|8|@$I|15|J|16|K|S]]|9|@]|A|$]]|$1|T|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|U|$]]

Who needs the ternary operator?

<pre><code>​the_styles = !the_styles &amp;&amp; $('.stylesheet').detach()​​​​ ||
 the_styles.appendTo('head') &amp;&amp; null;​
</code></pre>

Had to switch the expressions around as otherwise the <code>null</code> value of the first expression will always force the second expression <code>.detach()</code> to be evaluated.

The only thing about clever code is that once you come back to it after a coffee break, it won't make any sense even to you. So this is much better:

<pre><code>if(the_styles) {
 the_styles.appendTo('head')
 the_styles = null;
}
else {
 the_styles = the_styles.detach('.stylesheet');
}
</code></pre>

To me, even the above simplistic version doesn't make any sense. The what part is obvious, but why is it doing that?

<pre><code>the_styles ? the_styles.appendTo('head'); the_styles=null : the_styles = $('.stylesheet').detach();
</code></pre>

Obviously, this isn't valid. Notice the ";" between the <code>appendTo()</code> and <code>the_styles=null</code>. How do I write it on 1 line and still have multiple expressions like that?

Ternary Operator in JavaScript With Multiple Expressions?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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the_styles ? the_styles.appendTo('head'); the_styles=null : the_styles = $('.stylesheet').detach();显然，这是无效的。注意appendTo()和the_styles=null之间的";“。我如何在一行代码中使用多个这样的表...

问在具有多个表达式的JavaScript中使用三元运算符？
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问在具有多个表达式的JavaScript中使用三元运算符？EN