blocks|key|2574494|text|您只需在代码中添加以下行：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2574495|input.setRawInputType(Configuration.KEYBOARD_12KEY);|code-block|syntax|javascript|2574496|这将只显示数字键盘。|2574497|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You must only add this line on your code:

<pre><code>input.setRawInputType(Configuration.KEYBOARD_12KEY);
</code></pre>

this will show only the numeric keyboard.

blocks|key|1548574|text|android:inputType="phone"
android:digits="1234567890"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1548575|是一种选择|unstyled|1548576|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>android:inputType="phone"
android:digits="1234567890"
</code></pre>

is an option

blocks|key|2574381|text|电话号码簿是我找到的最接近的东西(在EditText上设置inputType="phone"+)。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2574382|entityMap^0|I|8|T|H|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

The phone number pad is the closest thing I've found (set <code>inputType="phone"</code> on your <code>EditText</code>).

blocks|key|1552830|text|被接受的答案对我不起作用(在OnePlus+3t和三星Galaxy+S6/S7手机上进行了测试)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1552831|此解决方案使用numberPassword，但覆盖了EditText的默认转换方法，以显示字符而不是显示点。|1552832|<EditText
++++android:id="@%2Bid/userid"
++++android:inputType="numberPassword"
++++android:maxLength="6"
/>

//+Numeric+6+character+user+id
EditText+input+=+findViewById(R.id.userid);

//+Process+input+and+show+characters+instead+of+dots
input.setTransformationMethod(SingleLineTransformationMethod.getInstance());|code-block|syntax|javascript|1552833|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

The accepted answer did not work for me (tested on OnePlus 3t and Samsung Galaxy S6/S7 phones). 

This solution uses numberPassword but overrides the default transformation method for the EditText to show characters instead of showing dots.

<pre><code>&lt;EditText
 android:id="@+id/userid"
 android:inputType="numberPassword"
 android:maxLength="6"
/&gt;

// Numeric 6 character user id
EditText input = findViewById(R.id.userid);

// Process input and show characters instead of dots
input.setTransformationMethod(SingleLineTransformationMethod.getInstance());
</code></pre>

blocks|key|803446|text|刚刚发布了一个答案here，但为了简单起见重新发布了一下：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|803447|看起来Android已经添加了我们想要的功能。这是我用来输入简单EditText数字的xml：|803448|++++android:inputType="numberPassword"
++++android:digits="0123456789"
++++android:singleLine="true"
++++android:ems="4"
++++android:textColor="@android:color/black"
++++android:gravity="center"|code-block|syntax|javascript|803449|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/33897883/1672231^0|9|4|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

Just posted an answer <a href="https://stackoverflow.com/a/33897883/1672231">here</a> but re-posting for simplicity:

Seems Android has added the functionality we were seeking. This is the xml I use for simple EditText numeric entry:

<pre><code> android:inputType="numberPassword"
 android:digits="0123456789"
 android:singleLine="true"
 android:ems="4"
 android:textColor="@android:color/black"
 android:gravity="center"
</code></pre>

blocks|key|3982578|text|据我所知，Android在这方面没有什么好的选择。最终，我不得不编写自己版本的类似软键盘的用户界面。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3982579|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Last I looked into it, Android did not have any good options for that. I ended up having to write my own version of a soft keyboard-like user interface.

blocks|key|2574603|text|被接受的答案对我不起作用。它不断地显示其他不需要的字符|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2574604|我找到了一种方法来实现我想要的行为，方法是将inputType更改为numberPassword，然后禁用密码点|offset|length|style|CODE|2574605|textInput.inputType+=+InputType.TYPE_CLASS_NUMBER+or+InputType.TYPE_NUMBER_VARIATION_PASSWORD
textInput.transformationMethod+=+SingleLineTransformationMethod()|code-block|syntax|javascript|2574606|entityMap^0|0|Y|E|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@$D|Q|E|R|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|S|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

The accepted answer didn't work for me. It kept showing other unwanted characters

I found a way to accomplish the behavior I wanted by changing the inputType to <code>numberPassword</code> and then disabling the password dots

<pre><code>textInput.inputType = InputType.TYPE_CLASS_NUMBER or InputType.TYPE_NUMBER_VARIATION_PASSWORD
textInput.transformationMethod = SingleLineTransformationMethod()
</code></pre>

blocks|key|803476|text|我用Xamarin为android实现了这一点。我的代码是用C#编写的。但本金保持不变。可以将edittext的属性设置为android:inputType="numberPassword"。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|803477|然后在您的代码中，将自定义转换方法附加到edittext视图。|803478|holder.edtxtQty.TransformationMethod+=+new+HiddenPasswordTransformationMethod();

private+class+HiddenPasswordTransformationMethod+:+global::Android.Text.Method.PasswordTransformationMethod
++++++++{
++++++++++++public+override+Java.Lang.ICharSequence+GetTransformationFormatted(Java.Lang.ICharSequence+source,+View+view)
++++++++++++{
++++++++++++++++return+new+PasswordCharSequence(source);
++++++++++++}
++++++++}

++++private+class+PasswordCharSequence+:+Java.Lang.Object,+Java.Lang.ICharSequence
++++{
++++++++private+char+DOT+=+'\u2022';

++++++++private+Java.Lang.ICharSequence+_source;
++++++++public+PasswordCharSequence(Java.Lang.ICharSequence+source)
++++++++{
++++++++++++_source+=+source;
++++++++}

++++++++public+char+CharAt(int+index)
++++++++{
++++++++++++return+_source.CharAt(index);
++++++++}

++++++++public+int+Length()
++++++++{
++++++++++++return+_source.Length();
++++++++}

++++++++public+Java.Lang.ICharSequence+SubSequenceFormatted(int+start,+int+end)
++++++++{
++++++++++++return+_source.SubSequenceFormatted(start,+end);+//+Return+default
++++++++}

++++++++public+IEnumerator<char>+GetEnumerator()
++++++++{
++++++++++++return+_source.GetEnumerator();
++++++++}

++++++++System.Collections.IEnumerator+System.Collections.IEnumerable.GetEnumerator()
++++++++{
++++++++++++return+_source.GetEnumerator();
++++++++}
++++}|code-block|syntax|javascript|803479|entityMap^0|1P|Y|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|R|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|S|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

I had implemented this for android in Xamarin. So, my code is in C#. But the principal stays the same. You can set attribute of edittext to <code>android:inputType="numberPassword"</code>.

Then within your code you attach custom transformation method to your edittext view.

<pre><code>holder.edtxtQty.TransformationMethod = new HiddenPasswordTransformationMethod();

private class HiddenPasswordTransformationMethod : global::Android.Text.Method.PasswordTransformationMethod
 {
 public override Java.Lang.ICharSequence GetTransformationFormatted(Java.Lang.ICharSequence source, View view)
 {
 return new PasswordCharSequence(source);
 }
 }

 private class PasswordCharSequence : Java.Lang.Object, Java.Lang.ICharSequence
 {
 private char DOT = '\u2022';

 private Java.Lang.ICharSequence _source;
 public PasswordCharSequence(Java.Lang.ICharSequence source)
 {
 _source = source;
 }

 public char CharAt(int index)
 {
 return _source.CharAt(index);
 }

 public int Length()
 {
 return _source.Length();
 }

 public Java.Lang.ICharSequence SubSequenceFormatted(int start, int end)
 {
 return _source.SubSequenceFormatted(start, end); // Return default
 }

 public IEnumerator&lt;char&gt; GetEnumerator()
 {
 return _source.GetEnumerator();
 }

 System.Collections.IEnumerator System.Collections.IEnumerable.GetEnumerator()
 {
 return _source.GetEnumerator();
 }
 }
</code></pre>

blocks|key|1548689|text|来自代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1548690|et.setInputType(InputType.TYPE_CLASS_NUMBER)|code-block|syntax|javascript|1548691|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

From code:
<pre><code>et.setInputType(InputType.TYPE_CLASS_NUMBER)
</code></pre>

On the soft keyboard in Android you can set the soft keyboard to show the numbers instead of a-z keyboard using <code>android:inputType="numberDecimal"</code>. However, what do I do if I only want to show the top number row <code>1 2 3 4 5 6 7 8 9 0</code> and not the following rows starting with <code>@ # $ % ...</code>?

Thanx for listening!

Only show number buttons on Soft Keyboard in Android?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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在Android的软键盘上，你可以使用android:inputType="numberDecimal"设置软键盘来显示数字，而不是a-z键盘。但是，如果我只想显示顶部数字行1 2 3 4 5 6 7 8 9 0，而不是以@ # $ % ...开头的后续行，该怎么办感谢您的收听！

问在Android中只在软键盘上显示数字按钮？
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