blocks|key|3662667|text|显然，“消失的选择”是设计出来的；它被称为"touch+mode“。我通读了那份文件，但我仍然不知道为什么他们认为这是一个好主意。我的猜测是，由于Android最初是为小屏幕设备设计的，他们希望你在屏幕上填满一个列表，然后，当用户点击一个项目时，移动到另一个屏幕上的新列表。因此，用户不会意识到Android失去了对所选项目的跟踪。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3662668|但是，例如，如果您希望用户选择一个项目，然后在同一屏幕上显示有关该项目的信息，则此行为非常恼人。如果选择消失了，用户如何知道他们点击了什么(当然，假设用户具有金鱼的注意力持续时间)？|3662669|一种可能的解决方案是将所有列表项更改为单选按钮。我真的不喜欢这个解决方案，因为它浪费了屏幕空间。我更愿意使用背景颜色来显示选择了哪一项。到目前为止，我已经看到了一种解决方案，但它并不是完全或通用的。所以这是我的解决方案：|3662670|1.在XML布局文件中|3662671|转到您的ListView元素和以下属性：android:choiceMode="singleChoice"。我不完全确定这是做什么的(它本身不允许用户选择任何东西)，但是如果没有这个属性，下面的代码就不能工作。|style|CODE|3662672|2.定义以下类|3662673|它用于跟踪所选项目，还允许您在Java中模拟按引用传递：|3662674|public+class+IntHolder+{
++++public+int+value;
++++public+IntHolder()+{}
++++public+IntHolder(int+v)+{+value+=+v;+}+
}|code-block|syntax|javascript|3662675|3.将以下代码放在某个位置|3662676|我假设你把它放在你的活动中，但实际上它可以放在任何班级中：|3662677|static+void+setListItems(Context+context,+AdapterView+listView,+List+listItems,+final+IntHolder+selectedPosition)
{
++++setListItems(context,+listView,+listItems,+selectedPosition,+
+++++++++++++++++android.R.layout.simple_list_item_1,+
+++++++++++++++++android.R.layout.simple_spinner_dropdown_item);
}
static+void+setListItems(Context+context,+AdapterView+listView,+List+listItems,+final+IntHolder+selectedPosition,+
+++++++++++++++++++++++++int+list_item_id,+int+dropdown_id)
{
++++listView.setOnItemClickListener(new+AdapterView.OnItemClickListener()+{
++++++++public+void+onItemClick(AdapterView<?>+list,+View+lv,+int+position,+long+id)+{
++++++++++++selectedPosition.value+=+position;
++++++++}
++++});
++++ArrayAdapter<CharSequence>+adapter+=+new+ArrayAdapter<CharSequence>(context,+list_item_id,+listItems)+{+
++++++++@Override
++++++++public+View+getView(int+position,+View+convertView,+ViewGroup+parent)+{
++++++++++++View+itemView+=+super.getView(position,+convertView,+parent);
++++++++++++if+(selectedPosition.value+==+position)
++++++++++++++++itemView.setBackgroundColor(0xA0FF8000);+//+orange
++++++++++++else
++++++++++++++++itemView.setBackgroundColor(Color.TRANSPARENT);
++++++++++++return+itemView;
++++++++}
++++};
++++adapter.setDropDownViewResource(dropdown_id);
++++listView.setAdapter(adapter);
}|3662678|这段代码做了两件事:它将你的列表项(例如List<String>)附加到你的ListView，并且它用一些改变选定项背景的代码覆盖了ArrayAdapter.getView()。|3662679|4.使用该代码设置您的列表|3662680|例如：|3662681|ListView+_list;
IntHolder+_selectedItem+=+new+IntHolder(-1);+//+nothing+selected+at+first

@Override
protected+void+onCreate(Bundle+savedInstanceState)+{
++++...
++++_list+=+(ListView)findViewById(R.id.list);
++++List<String>+items+=+Arrays.asList("Item+1",+"Item+2",+"Item+3");
++++setListItems(this,+_list,+items,+_selectedItem);
}|3662682|就这样!以上假设您想要单项选择。通过对getView()进行一些小的修改，我想您也可以支持多选，但是您可能应该使用复选框。|3662683|警告：此解决方案需要进一步开发。如果用户使用箭头键或按钮来选择一个项目，则该项目将不会从IntHolder的角度进行选择。如果用户按下未标记的按钮(该按钮的名称是什么？"Enter"?)然后，该项目将变为“正式”选择，但您还会遇到另一个问题，因为如果用户再次使用箭头键，看起来就像选择了两个项目。如果你知道如何使IntHolder中的“内部选择”与“键盘选择”或其他名称保持同步，请留下评论。不管怎么说，它叫什么？|BOLD|3662684|entityMap|0|LINK|mutability|MUTABLE|url|http://developer.android.com/resources/articles/touch-mode.html^0|M|A|0|0|0|0|0|K|X|0|0|0|0|0|0|0|K|C|1U|M|0|0|0|0|0|0|2|0^^$0|@$1|2|3|4|5|6|7|1N|8|@]|9|@$A|1O|B|1P|1|1Q]]|C|$]]|$1|D|3|E|5|6|7|1R|8|@]|9|@]|C|$]]|$1|F|3|G|5|6|7|1S|8|@]|9|@]|C|$]]|$1|H|3|I|5|6|7|1T|8|@]|9|@]|C|$]]|$1|J|3|K|5|6|7|1U|8|@$A|1V|B|1W|L|M]]|9|@]|C|$]]|$1|N|3|O|5|6|7|1X|8|@]|9|@]|C|$]]|$1|P|3|Q|5|6|7|1Y|8|@]|9|@]|C|$]]|$1|R|3|S|5|T|7|1Z|8|@]|9|@]|C|$U|V]]|$1|W|3|X|5|6|7|20|8|@]|9|@]|C|$]]|$1|Y|3|Z|5|6|7|21|8|@]|9|@]|C|$]]|$1|10|3|11|5|T|7|22|8|@]|9|@]|C|$U|V]]|$1|12|3|13|5|6|7|23|8|@$A|24|B|25|L|M]|$A|26|B|27|L|M]]|9|@]|C|$]]|$1|14|3|15|5|6|7|28|8|@]|9|@]|C|$]]|$1|16|3|17|5|6|7|29|8|@]|9|@]|C|$]]|$1|18|3|19|5|T|7|2A|8|@]|9|@]|C|$U|V]]|$1|1A|3|1B|5|6|7|2B|8|@]|9|@]|C|$]]|$1|1C|3|1D|5|6|7|2C|8|@$A|2D|B|2E|L|1E]]|9|@]|C|$]]|$1|1F|3|-4|5|6|7|2F|8|@]|9|@]|C|$]]]|1G|$1H|$5|1I|1J|1K|C|$1L|1M]]]]

Apparently the "disappearing selection" is by design; it's something called "<a href="http://developer.android.com/resources/articles/touch-mode.html">touch mode</a>". I read through that document and still I have no idea why they thought it was a good idea. My guess is that, since Android was originally designed for small-screen devices, they expected that you would fill the screen with a list and then, when the user clicks an item, move to a new list on a different screen. Thus, the user wouldn't be aware that Android lost track of the selected item.

But this behavior is quite annoying if, for example, you want the user to select an item and then show information about that item on the same screen. If the selection disappears, how is the user supposed to know what they clicked (assuming of course that users have the attention span of a goldfish)?

One possible solution is to change all the list items into radio buttons. I don't really like that solution because it wastes screen real estate. I'd rather just use the background color to show which item is selected. I have seen one solution so far but it is not quite complete or general. So here's my solution:

<h2>1. In your XML layout file</h2>

Go to your ListView element and the following attribute: <code>android:choiceMode="singleChoice"</code>. I'm not entirely sure what this does (by itself, it doesn't allow the user to select anything) but without this attribute, the code below doesn't work.

<h2>2. Define the following class</h2>

It is used to keep track of the selected item, and also allows you to simulate pass-by-reference in Java:

<pre><code>public class IntHolder {
 public int value;
 public IntHolder() {}
 public IntHolder(int v) { value = v; } 
}
</code></pre>

<h2>3. Put the following code somewhere</h2>

I'll assume you put it in your Activity, but it could go in any class really:

<pre><code>static void setListItems(Context context, AdapterView listView, List listItems, final IntHolder selectedPosition)
{
 setListItems(context, listView, listItems, selectedPosition, 
 android.R.layout.simple_list_item_1, 
 android.R.layout.simple_spinner_dropdown_item);
}
static void setListItems(Context context, AdapterView listView, List listItems, final IntHolder selectedPosition, 
 int list_item_id, int dropdown_id)
{
 listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
 public void onItemClick(AdapterView&lt;?&gt; list, View lv, int position, long id) {
 selectedPosition.value = position;
 }
 });
 ArrayAdapter&lt;CharSequence&gt; adapter = new ArrayAdapter&lt;CharSequence&gt;(context, list_item_id, listItems) { 
 @Override
 public View getView(int position, View convertView, ViewGroup parent) {
 View itemView = super.getView(position, convertView, parent);
 if (selectedPosition.value == position)
 itemView.setBackgroundColor(0xA0FF8000); // orange
 else
 itemView.setBackgroundColor(Color.TRANSPARENT);
 return itemView;
 }
 };
 adapter.setDropDownViewResource(dropdown_id);
 listView.setAdapter(adapter);
}
</code></pre>

This code does two things: it attaches your list items (e.g. <code>List&lt;String&gt;</code>) to your ListView, and it overrides <code>ArrayAdapter.getView()</code> with some code that changes the background of the selected item.

<h2>4. Use that code to set up your list</h2>

For example:

<pre><code>ListView _list;
IntHolder _selectedItem = new IntHolder(-1); // nothing selected at first

@Override
protected void onCreate(Bundle savedInstanceState) {
 ...
 _list = (ListView)findViewById(R.id.list);
 List&lt;String&gt; items = Arrays.asList("Item 1", "Item 2", "Item 3");
 setListItems(this, _list, items, _selectedItem);
}
</code></pre>

That's all! The above assumes you want single selection. With some small modifications to getView(), you could support multi-selection too, I guess, but you should probably use checkboxes instead.

Warning: this solution needs further development. If the user uses arrow keys or buttons to select an item, that item will not be selected from the IntHolder's perspective. If the user presses the unlabeled button (what's the name of that button? "Enter"?) then the item will become "officially" selected but then you have another problem because if the user uses the arrow keys again, it will sort of look like two items are selected. Leave a comment if you figure out how to keep the "internal selection" in the IntHolder synchronized with the "keyboard selection" or whatever it's called. What is it called, anyway?

blocks|key|646428|text|ListView中有一个名为listSelector的属性：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|646429|646430|可绘制，用于指示列表中当前选定的项。|blockquote|646431|646432|646433|http://developer.android.com/reference/android/widget/AbsListView.html#attr_android:listSelector|offset|length|646434|646435|在注释后编辑|style|BOLD|646436|为了确保ListView保持选中状态，您应该|CODE|646437|1通过xml或以编程方式设置视图的属性choiceMode。|646438|2使用使用实现Checkable接口的视图的适配器，如CheckedTextView+(在simple_list_item_single_choice布局中)。|646439|文件TestActivity.java|646440|public+class+TestActivity+extends+Activity+{

++++private+static+final+int+SINGLE_CHOICE+=+android.R.layout.simple_list_item_single_choice;

++++@Override
++++protected+void+onCreate(Bundle+savedInstanceState)+{
++++++++super.onCreate(savedInstanceState);
++++++++setContentView(R.layout.test);

++++++++String[]+items+=+{"test+1",+"test+2",+"test+3"};
++++++++ListAdapter+adapter+=+new+ArrayAdapter<String>(this,+SINGLE_CHOICE,+items);
++++++++ListView+list+=+(ListView)+findViewById(R.id.testList);
++++++++list.setChoiceMode(ListView.CHOICE_MODE_SINGLE);
++++++++list.setAdapter(adapter);
++++}
}|code-block|syntax|javascript|646441|entityMap|0|LINK|mutability|MUTABLE|url|1|http://developer.android.com/reference/android/widget/Checkable.html|2|http://developer.android.com/reference/android/widget/CheckedTextView.html|3|http://grepcode.com/file/repository.grepcode.com/java/ext/com.google.android/android/4.3_r2.1/frameworks/base/core/res/res/layout/simple_list_item_single_choice.xml?av=f^0|0|0|0|0|0|0|2O|0|0|0|0|6|0|4|8|0|J|A|0|7|9|R|F|19|U|7|9|1|R|F|2|19|U|3|0|2|H|0|0^^$0|@$1|2|3|4|5|6|7|1H|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|1I|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|1J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|1K|8|@]|9|@]|A|$]]|$1|G|3|-4|5|6|7|1L|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|1M|8|@]|9|@$J|1N|K|1O|1|1P]]|A|$]]|$1|L|3|-4|5|6|7|1Q|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|1R|8|@$J|1S|K|1T|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1U|8|@$J|1V|K|1W|O|S]]|9|@]|A|$]]|$1|T|3|U|5|6|7|1X|8|@$J|1Y|K|1Z|O|S]]|9|@]|A|$]]|$1|V|3|W|5|6|7|20|8|@$J|21|K|22|O|S]|$J|23|K|24|O|S]|$J|25|K|26|O|S]]|9|@$J|27|K|28|1|29]|$J|2A|K|2B|1|2C]|$J|2D|K|2E|1|2F]]|A|$]]|$1|X|3|Y|5|6|7|2G|8|@$J|2H|K|2I|O|S]]|9|@]|A|$]]|$1|Z|3|10|5|11|7|2J|8|@]|9|@]|A|$12|13]]|$1|14|3|-4|5|6|7|2K|8|@]|9|@]|A|$]]]|15|$16|$5|17|18|19|A|$1A|I]]|1B|$5|17|18|19|A|$1A|1C]]|1D|$5|17|18|19|A|$1A|1E]]|1F|$5|17|18|19|A|$1A|1G]]]]

There is an attribute in ListView called listSelector:

<blockquote>
 Drawable used to indicate the currently selected item in the list.
</blockquote>

<a href="http://developer.android.com/reference/android/widget/AbsListView.html#attr_android:listSelector" rel="nofollow noreferrer">http://developer.android.com/reference/android/widget/AbsListView.html#attr_android:listSelector</a>

<hr>

EDIT after <a href="https://stackoverflow.com/users/1811719/stan">Stan</a> comment

To ensure that a <code>ListView</code> stays selected, you should

① Set the view's attribute <code>choiceMode</code> via xml or programmatically.

② Use an adapter that uses views which implement <a href="http://developer.android.com/reference/android/widget/Checkable.html" rel="nofollow noreferrer"><code>Checkable</code></a> interface, like <a href="http://developer.android.com/reference/android/widget/CheckedTextView.html" rel="nofollow noreferrer"><code>CheckedTextView</code></a> (inside <a href="http://grepcode.com/file/repository.grepcode.com/java/ext/com.google.android/android/4.3_r2.1/frameworks/base/core/res/res/layout/simple_list_item_single_choice.xml?av=f" rel="nofollow noreferrer"><code>simple_list_item_single_choice</code></a> layout).

File <code>TestActivity.java</code>

<pre><code>public class TestActivity extends Activity {

 private static final int SINGLE_CHOICE = android.R.layout.simple_list_item_single_choice;

 @Override
 protected void onCreate(Bundle savedInstanceState) {
 super.onCreate(savedInstanceState);
 setContentView(R.layout.test);

 String[] items = {"test 1", "test 2", "test 3"};
 ListAdapter adapter = new ArrayAdapter&lt;String&gt;(this, SINGLE_CHOICE, items);
 ListView list = (ListView) findViewById(R.id.testList);
 list.setChoiceMode(ListView.CHOICE_MODE_SINGLE);
 list.setAdapter(adapter);
 }
}
</code></pre>

blocks|key|2254962|text|这个答案是有效的，试试这个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2254963|@Override
++++public+void+onItemClick(AdapterView<?>+parent,+View+view,+int+position,+long+arg3)
++++{
++++++++for(int+a+=+0;+a+<+parent.getChildCount();+a%2B%2B)
++++++++{
++++++++++++parent.getChildAt(a).setBackgroundColor(Color.TRANSPARENT);
++++++++}
++++view.setBackgroundColor(Color.GREEN);
}|code-block|syntax|javascript|2254964|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This answer is working try this one

<pre><code>@Override
 public void onItemClick(AdapterView&lt;?&gt; parent, View view, int position, long arg3)
 {
 for(int a = 0; a &lt; parent.getChildCount(); a++)
 {
 parent.getChildAt(a).setBackgroundColor(Color.TRANSPARENT);
 }
 view.setBackgroundColor(Color.GREEN);
}
</code></pre>

blocks|key|1389432|text|这里有一个比Qwertie更简单的解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1389433|不要依赖给定的选择机制。自己的事情自己做。|1389434|View+mSelectedItemView+=+null;+//class+member+variable
View+mTouchedItemView+=+null;+//class+member+variable

ListView+v+=+(ListView)+getActivity().findViewById(R.id.listView);
//+select+on+click
v.setOnItemClickListener(new+OnItemClickListener()+{
++++@Override
++++public+void+onItemClick(AdapterView<?>+adapter,
++++++++++++View+clickedViewItem,+int+position,+long+id)+{
++++++++if+(mSelectedItemView+!=+null)
++++++++++++selectedItemView.setBackgroundColor(Color.WHITE);
++++++++clickedViewItem.setBackgroundColor(Color.YELLOW);
++++++++mSelectedItemView+=+clickedViewItem;
++++}
});
//+highlight+on+touch
v.setOnTouchListener(new+OnTouchListener()+{
++++@Override
++++public+boolean+onTouch(View+v,+MotionEvent+event)+{
++++++++if+(v+instanceof+ListView)+{
++++++++++++ListView+listView+=+(ListView)+v;
++++++++++++//+Find+the+child+view+that+was+touched+(perform+a
++++++++++++//+hit+test)
++++++++++++Rect+rect+=+new+Rect();
++++++++++++int+childCount+=+listView.getChildCount();
++++++++++++int[]+listViewCoords+=+new+int[2];
++++++++++++v.getLocationOnScreen(listViewCoords);
++++++++++++int+x+=+(int)+event.getRawX()+-+listViewCoords[0];
++++++++++++int+y+=+(int)+event.getRawY()+-+listViewCoords[1];
++++++++++++View+child;
++++++++++++for+(int+i+=+0;+i+<+childCount;+i%2B%2B)+{
++++++++++++++++child+=+listView.getChildAt(i);
++++++++++++++++child.getHitRect(rect);
++++++++++++++++if+(rect.contains(x,+y))+{
++++++++++++++++++++View+touchedView+=+child;
++++++++++++++++++++if+(event.getAction()+==+MotionEvent.ACTION_DOWN)+{
++++++++++++++++++++++++touchedView
++++++++++++++++++++++++++++++++.setBackgroundColor(Color.RED);
++++++++++++++++++++++++mTouchedItemView+=+touchedView;
++++++++++++++++++++}+else+if+(event.getAction()+==+MotionEvent.ACTION_UP)+{
++++++++++++++++++++++++mTouchedItemView+
++++++++++++++++++++++++++++++++.setBackgroundColor(Color.WHITE);
++++++++++++++++++++}
++++++++++++++++}
++++++++++++}
++++++++}
++++++++return+false;
++++}
});|code-block|syntax|javascript|1389435|此外，此方法仅处理单击，如果用户使用箭头键，则此方法将不起作用。|1389436|免责声明:触摸后取消高亮显示不可靠。|offset|length|style|BOLD|1389437|感人的部分请访问ozik.dev：Get+Item+from+ListView+only+with+OnTouchListener|1389438|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/17384131/get-item-from-listview-only-with-ontouchlistener^0|0|0|0|0|0|I|0|H|1C|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|11|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|12|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|13|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|14|8|@$M|15|N|16|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|17|8|@]|9|@$M|18|N|19|1|1A]]|A|$]]|$1|S|3|-4|5|6|7|1B|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|Z]]]]

Here a simpler solution than Qwertie's:

Do not rely on given selection mechanism. Do it yourself.

<pre><code>View mSelectedItemView = null; //class member variable
View mTouchedItemView = null; //class member variable

ListView v = (ListView) getActivity().findViewById(R.id.listView);
// select on click
v.setOnItemClickListener(new OnItemClickListener() {
 @Override
 public void onItemClick(AdapterView&lt;?&gt; adapter,
 View clickedViewItem, int position, long id) {
 if (mSelectedItemView != null)
 selectedItemView.setBackgroundColor(Color.WHITE);
 clickedViewItem.setBackgroundColor(Color.YELLOW);
 mSelectedItemView = clickedViewItem;
 }
});
// highlight on touch
v.setOnTouchListener(new OnTouchListener() {
 @Override
 public boolean onTouch(View v, MotionEvent event) {
 if (v instanceof ListView) {
 ListView listView = (ListView) v;
 // Find the child view that was touched (perform a
 // hit test)
 Rect rect = new Rect();
 int childCount = listView.getChildCount();
 int[] listViewCoords = new int[2];
 v.getLocationOnScreen(listViewCoords);
 int x = (int) event.getRawX() - listViewCoords[0];
 int y = (int) event.getRawY() - listViewCoords[1];
 View child;
 for (int i = 0; i &lt; childCount; i++) {
 child = listView.getChildAt(i);
 child.getHitRect(rect);
 if (rect.contains(x, y)) {
 View touchedView = child;
 if (event.getAction() == MotionEvent.ACTION_DOWN) {
 touchedView
 .setBackgroundColor(Color.RED);
 mTouchedItemView = touchedView;
 } else if (event.getAction() == MotionEvent.ACTION_UP) {
 mTouchedItemView 
 .setBackgroundColor(Color.WHITE);
 }
 }
 }
 }
 return false;
 }
});
</code></pre>

Also this method only deals with clicks and will not work if the user uses the arrow keys.

Disclaimer: De-highlighting after touch does not work reliably.

Credits for the touching part go to ozik.dev: 
<a href="https://stackoverflow.com/questions/17384131/get-item-from-listview-only-with-ontouchlistener">Get Item from ListView only with OnTouchListener</a>

blocks|key|2255012|text|只需将此代码添加到列表视图布局即可|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2255013|+android:listSelector="@drawable/selector_expandable_listview"+
+android:drawSelectorOnTop="true"|code-block|syntax|javascript|2255014|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

just add this to your listview layout

<pre><code> android:listSelector="@drawable/selector_expandable_listview" 
 android:drawSelectorOnTop="true"
</code></pre>

blocks|key|644377|text|使用Selector.XML文件和以下代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|644378|++++//SetOnClickListner+to+catch+Events
++++listView.setOnItemClickListener(new+AdapterView.OnItemClickListener()+{
++++++++@Override
++++++++public+void+onItemClick(AdapterView<?>+parent,+View+view,+int+position,+long+id)+{
+++++++++view.setSelected(true);
++++++++}
++++});|code-block|syntax|javascript|644379|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use a Selector.XML File and this code:

<pre><code> //SetOnClickListner to catch Events
 listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
 @Override
 public void onItemClick(AdapterView&lt;?&gt; parent, View view, int position, long id) {
 view.setSelected(true);
 }
 });
</code></pre>

blocks|key|1393205|text|只需将以下内容添加到您的ListView中：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1393206|android:listSelector="@color/my_color"|code-block|syntax|javascript|1393207|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Just add this to your ListView:

<pre><code>android:listSelector="@color/my_color"
</code></pre>

I have a list view full of items, after the users selects an item it lights up, and then it goes back to normal. Is there a way to make it so that when the user selects an item in my ListView it stays selected, and highlighted?

ListView stay selected?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个充满项目的列表视图，在用户选择一个项目后，它会亮起，然后它就会恢复正常。有没有办法让它在用户选择my ListView中的项目时保持选中并突出显示？

问ListView是否保持选中状态？
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问ListView是否保持选中状态？EN