blocks|key|3019948|text|这个正则表达式只会去掉它遇到的第一组数字。它在-上也遇到了麻烦。如果你想去掉每一组数字，包括-s，可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3019949|address.replace("%5E\\s*([0-9-]%2B\\s%2B)%2B","");|code-block|syntax|javascript|3019950|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

That regex will only strip out the first group of digits it encounters. It's also having trouble with the -. If you want to strip out every group of digits, including -s, do something like this:

<pre><code>address.replace("^\\s*([0-9-]+\\s+)+","");
</code></pre>

blocks|key|3019975|text|您的正则表达式要求查找:空格、数字、空格，然后不使用任何内容替换它们。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3019976|你的“坏”字符串没有空格，数字，空格，它有空格，数字，破折号。|3019977|如果您想在街道号码中包含破折号，可以尝试这样做："%5E\\s*[0-9-]%2B\\s%2B"|offset|length|style|CODE|3019978|entityMap^0|0|0|O|I|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|N|8|@$F|O|G|P|H|I]]|9|@]|A|$]]|$1|J|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|K|$]]

Your regex says to find: whitespace, digits, whitespace, and then replace them with nothing.

Your "bad" string doesn't have whitespace, digits, whitespace, it has whitespace, digits, dash.

If you want to include the dash in the street number, try this: <code>"^\\s*[0-9-]+\\s+"</code>

blocks|key|1775416|text|如果我可以提个建议..。通过简单地使用正则表达式来操作地址数据，就像使用一个手持钻来雕刻Mt。拉什莫尔出山了。它可能一开始看起来是有效的，但仍然有很多工作要做。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1775417|您是否考虑过以所有形式输入的地址，以及与预期不同的组件顺序？如果街道名称没有数字"th“或"st”，等等(这里列出的案例太多了)。|1775418|我在SmartyStreets工作，我们的专长是标准化和验证地址。对于您的任务，您可以挂钩到CASS认证的API，以返回标准化和组件化的地址，这样您就可以只保留您想要的部分，并且是准确的。我建议你研究一下像LiveAddress这样的东西，它免费提供了这个功能。你自己做一些研究吧，我很乐意帮助你回答其他与地址相关的问题。|offset|length|1775419|entityMap|0|LINK|mutability|MUTABLE|url|http://www.smartystreets.com/|1|http://www.smartystreets.com/Products/LiveAddress-API/^0|0|0|2|D|0|2V|B|1|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|T|8|@]|9|@$F|U|G|V|1|W]|$F|X|G|Y|1|Z]]|A|$]]|$1|H|3|-4|5|6|7|10|8|@]|9|@]|A|$]]]|I|$J|$5|K|L|M|A|$N|O]]|P|$5|K|L|M|A|$N|Q]]]]

If I may make a suggestion... by simply using regular expressions to manipulate address data, it's like using a single jackhammer to carve Mt. Rushmore out of the mountain. It may seem to work at first, but there's still a lot of work ahead.

Have you considered addresses inputted in all forms and with the components in different orders than expected? What about street names without "th" or "st" by the number, etc etc (there are too many cases to list here).

I work for <a href="http://www.smartystreets.com" rel="nofollow">SmartyStreets</a>, where our expertise is standardizing and validating addresses. For your task, you can hook into a CASS-Certified API of sorts to return the address, standardized and componentized (broken into pieces), so you can keep just the parts you want, and be accurate. I suggest you look into something like <a href="http://www.smartystreets.com/Products/LiveAddress-API/" rel="nofollow">LiveAddress</a>, which provides this for free. Do some research on your own, and I'll be happy to help answer other address-related questions you have.

I'm trying to strip out the street number from a mailing address.

I have a regex in Java:

<pre><code>address.replace("^\\s*[0-9]+\\s+","");
</code></pre>

It works on this address:

<pre><code>301 West 23rd Street
</code></pre>

making it:

<pre><code>West 23rd Street
</code></pre>

But when I apply it to this address, the address is unchanged:

<pre><code>70-50 69th Place
</code></pre>

Instead it needs to be:

<pre><code>69th Place
</code></pre>

Any ideas?

Why does this Java regex work inconsistently for stripping street numbers out of US street addresses?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想把邮寄地址上的街道号码去掉。我在Java中有一个正则表达式：address.replace("^\\s*[0-9]+\\s+","");它在这个地址上工作：301 West 23rd Street正在制作中：West 23rd Street但是当我将它应用于这个地址时，地址是不变的：70-50 69th Place...

问为什么这个Java正则表达式不能一致地从美国街道地址中剥离街道编号？
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问为什么这个Java正则表达式不能一致地从美国街道地址中剥离街道编号？EN