blocks|key|2086664|text|OTOH，几个命令将裁剪文件的第一行和最后一行。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2086665|2086666|head+-n+-1将裁剪文件的最后一行。可以使用类似于awk+'NR>1+{print}'|unordered-list-item|offset|length|style|CODE|2086667|的命令使用|2086668|awk裁剪文件的第一行|2086669|2086670|或者，如果可以通过字符串匹配可靠地识别第一行和最后一行，则可以使用grep+-v过滤掉它们。|2086671|entityMap^0|0|0|0|A|S|I|0|0|0|0|X|7|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|T|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|U|8|@$F|V|G|W|H|I]|$F|X|G|Y|H|I]]|9|@]|A|$]]|$1|J|3|K|5|6|7|Z|8|@]|9|@]|A|$]]|$1|L|3|M|5|E|7|10|8|@]|9|@]|A|$]]|$1|N|3|-4|5|6|7|11|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|12|8|@$F|13|G|14|H|I]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|R|$]]

OTOH, a couple of commands that will clip the first and last line of a file.

<ul>
<li><code>head -n -1</code> will clip the last line of a file.</li>
<li>awk can be used to clip the first line of the file with a command like <code>awk 'NR&gt;1 {print}'</code></li>
</ul>

Alternatively, you can use <code>grep -v</code> to filter out the first and last lines if they can be reliabily identified by string matches.

blocks|key|5061206|text|这很难看，但它似乎有效，至少在你的输入上是这样的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5061207|f='test.txt';+g=`wc+-l+$f`;+h=`echo+$g+%7C+cut+-d+'+'+-f1`;+head+-n+$((h-1))+$f+%7C+tail+-n+$((h-2))|code-block|syntax|javascript|5061208|F是您的文件的名称。我找不到一种更快的方法从wc的输出中去掉文件名。应该有人能打败它。|5061209|如果您想重写相同的文件，只需重定向命令的输出：|5061210|f='test.txt';+g=`wc+-l+$f`;+h=`echo+$g+%7C+cut+-d+'+'+-f1`;+head+-n+$((h-1))+$f+%7C+tail+-n+$((h-2))+>+$f|5061211|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

This is ugly, but it seems to work, at least on your input:

<pre><code>f='test.txt'; g=`wc -l $f`; h=`echo $g | cut -d ' ' -f1`; head -n $((h-1)) $f | tail -n $((h-2))
</code></pre>

f is the name of your file. I couldn't work out a quicker way to get rid of the filename from the output of wc. Someone should be able to beat this.

If you want to rewrite the same file, just redirect the output of the command:

<pre><code>f='test.txt'; g=`wc -l $f`; h=`echo $g | cut -d ' ' -f1`; head -n $((h-1)) $f | tail -n $((h-2)) &gt; $f
</code></pre>

blocks|key|2086704|text|..。并使用sed|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2086705|正如@Baramin所指出的:类型的最小数量是sed+'1d;$d'，下面是它的工作原理：|2086706|按行号|2086707|sed+-i''+-e+'1d'+-e+'$d'+yourfile|code-block|syntax|javascript|2086708|1d删除第一行，$d删除最后一行。|2086709|或按模式|2086710|sed+-r+-i+-e+'/%5E[0-9]+[0-9]{8}+HEADER+RECORD$/d'+\
++++++++++-e+'/%5E[0-9]+[0-9]{8}+TRAILER+RECORD$/d'+yourfile|2086711|{8}扩展正则表达式需要-r。|2086712|或者两者都有|2086713|如果你是个超级书呆子，想用最好的方式掩饰自己：|2086714|sed+-r+-i.bak+-e+'1{/%5E[0-9]+[0-9]{8}+HEADER+RECORD$/d}'+\
++++++++++++++-e+'${/%5E[0-9]+[0-9]{8}+TRAILER+RECORD$/d}'+yourfile|2086715|2086716|-i''将就地更改yourfile。如果您想要将输出存储在另一个文件中(例如，在行尾使用>+outputfile+)，则将其删除。|2086717|entityMap|0|LINK|mutability|MUTABLE|url|http://users/491264/baramin^0|6|3|0|N|B|2|8|0|0|0|0|0|2|8|2|0|0|0|0|3|C|2|0|0|0|0|0|0|4|9|8|18|C|0^^$0|@$1|2|3|4|5|6|7|1D|8|@$9|1E|A|1F|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1G|8|@$9|1H|A|1I|B|C]]|D|@$9|1J|A|1K|1|1L]]|E|$]]|$1|H|3|I|5|6|7|1M|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|1N|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|1O|8|@$9|1P|A|1Q|B|C]|$9|1R|A|1S|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1T|8|@]|D|@]|E|$]]|$1|S|3|T|5|L|7|1U|8|@]|D|@]|E|$M|N]]|$1|U|3|V|5|6|7|1V|8|@$9|1W|A|1X|B|C]|$9|1Y|A|1Z|B|C]]|D|@]|E|$]]|$1|W|3|X|5|6|7|20|8|@]|D|@]|E|$]]|$1|Y|3|Z|5|6|7|21|8|@]|D|@]|E|$]]|$1|10|3|11|5|L|7|22|8|@]|D|@]|E|$M|N]]|$1|12|3|-4|5|6|7|23|8|@]|D|@]|E|$]]|$1|13|3|14|5|6|7|24|8|@$9|25|A|26|B|C]|$9|27|A|28|B|C]|$9|29|A|2A|B|C]]|D|@]|E|$]]|$1|15|3|-4|5|6|7|2B|8|@]|D|@]|E|$]]]|16|$17|$5|18|19|1A|E|$1B|1C]]]]

... and with <code>sed</code>:

As <a href="http://users/491264/baramin" rel="nofollow noreferrer">@Baramin</a> noted: the least amount to type is <code>sed '1d;$d'</code>, here is how it works:

<h2>By line number</h2>

<pre><code>sed -i'' -e '1d' -e '$d' yourfile
</code></pre>

<code>1d</code> deletes first line <code>$d</code> deletes last line.

<h2>Or by pattern</h2>

<pre><code>sed -r -i -e '/^[0-9] [0-9]{8} HEADER RECORD$/d' \
 -e '/^[0-9] [0-9]{8} TRAILER RECORD$/d' yourfile
</code></pre>

<code>-r</code> is needed for the <code>{8}</code> extended regular-expression.

<h2>Or both</h2>

If you are super pedantic, and want to cover your ass in the most thorow way:

<pre><code>sed -r -i.bak -e '1{/^[0-9] [0-9]{8} HEADER RECORD$/d}' \
 -e '${/^[0-9] [0-9]{8} TRAILER RECORD$/d}' yourfile
</code></pre>

<hr>

The <code>-i''</code> will change <code>yourfile</code> in-place. Drop it if you want to store the output in another file (e.g. with <code>&gt; outputfile</code> at the end of your line).

blocks|key|1342339|text|tail+-n+%2B2+filename+%7C+head+-n+-1|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1342340|我没有我的unix机器来测试，所以这些数字可能是1或2，我不记得他们是机器人1，都是2还是什么，但我总是这样做(我只是在运行命令之前体验一下，看看它是1还是2……tail+...应该删除第一行，head+...应该删除最后一行|unstyled|offset|length|style|CODE|1342341|entityMap^0|0|29|8|2P|8|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]|$G|Q|H|R|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|S|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>tail -n +2 filename | head -n -1
</code></pre>

don't have my unix box to test on so those numbers might be 1 or 2, i can't remember if they are bot 1, both 2 or what but i ise this all the time (i just experement right before i run the cmd to see if its 1 or two... the <code>tail ...</code> should remove the first line and the <code>head ...</code> should remove the last

blocks|key|5061329|text|我是这样得到的..感谢大家的帮助。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5061330|wc+-l+fileman+%7Cawk+'{print+$1-0}'+%7Cxargs+-i+head+-{}+filename+%7C+sed+-n+'2,$p'+>+filename|code-block|syntax|javascript|5061331|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I got it in this way.. and thanks all for your help.

<pre><code>wc -l fileman |awk '{print $1-0}' |xargs -i head -{} filename | sed -n '2,$p' &gt; filename
</code></pre>

blocks|key|1344336|text|只是为了抛出更多的选择：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1344337|awk+-v+last=$(wc+-l+<+filename)+'NR+==+1+%7C%7C+NR+==+last+{next}+{print}'+filename
awk+'NR==1+{next}+NR==2+{prev+=+$0;+next}+{print+prev;+prev+=+$0}'+filename|code-block|syntax|javascript|1344338|要覆盖当前文件，请执行以下操作|1344339|(+whatever+%7C+pipeline+)+<filename+>filename.tmp+&&+
ln+filename+filename.bak+&&
mv+filename.tmp+filename|1344340|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Just to throw out a couple more alternatives:

<pre><code>awk -v last=$(wc -l &lt; filename) 'NR == 1 || NR == last {next} {print}' filename
awk 'NR==1 {next} NR==2 {prev = $0; next} {print prev; prev = $0}' filename
</code></pre>

To overwrite the current file, if you're not using <code>sed -i</code>:

<pre><code>( whatever | pipeline ) &lt;filename &gt;filename.tmp &amp;&amp; 
ln filename filename.bak &amp;&amp;
mv filename.tmp filename
</code></pre>

blocks|key|5061392|text|您的问题的非常简单的解决方案|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5061393|sed+-i+'1d;$d'+yourfile|code-block|syntax|javascript|5061394|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Very simple solution for your question

<pre><code>sed -i '1d;$d' yourfile
</code></pre>

blocks|key|3650459|text|这里有另一个更简单的选择(如果你的尾巴支持%2B语义)|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3650460|tail+-n+%2B2+<file>+%7C+head+-n+-1|3650461|entityMap^0|L|1|0|0|U|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|P|8|@]|D|@]|E|$]]]|I|$]]

Here is another option that is simpler (if your tail supports <code>+</code> semantics)

<code>tail -n +2 &lt;file&gt; | head -n -1</code>

I am having a flat file as give below. How do I delete the header and footer from the file using UNIX shell script and rewrite the same file.

<pre><code>9 20050427 HEADER RECORD
0000000 00000 000000000 123456 00 654321 DATARECORD
0000000 00000 000000000 123456 00 654321 DATARECORD
0000000 00000 000000000 123456 00 654321 DATARECORD
0000000 00000 000000000 123456 00 654321 DATARECORD
6 20050427 TRAILER RECORD
</code></pre>

Thanks,
Arun

How to remove header and footer records of a flat file using UNIX shell script?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个平面文件，如下所示。如何使用UNIX shell脚本从文件中删除页眉和页脚并重写相同的文件。9 20050427 HEADER RECORD0000000 00000 000000000 123456 00 654321 DATARECORD0000000 00000 000000000 123456 00 6...

问如何使用UNIX shell脚本删除平面文件的页眉和页脚记录？
EN

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问如何使用UNIX shell脚本删除平面文件的页眉和页脚记录？EN