我想选择前10行,然后随机选择他们的5行。
发布于 2010-12-06 19:26:52
必须定义“前10个”,它是这个代码片段中的“某物”。这是针对SQL Server 2000+的
select top 5 
    * 
from 
    (
    select top 10 * from <table>
    order by something --got to have soemthing here to define "first 10"
    ) as a
order by 
    newid()编辑:
为什么需要在派生表中使用ORDER BY
-- large row, same result with and without index/PK
CREATE TABLE #foo (bar int /*PRIMARY KEY NONCLUSTERED (bar)*/, eejit char(8000))
--create rows with value 1-10 + some others
INSERT #foo (bar) VALUES (1)
INSERT #foo (bar)  VALUES (10)
INSERT #foo (bar)  VALUES (20)
INSERT #foo (bar)  VALUES (2)
INSERT #foo (bar)  VALUES (5)
INSERT #foo (bar)  VALUES (45)
INSERT #foo (bar)  VALUES (99)
INSERT #foo (bar)  VALUES (3)
INSERT #foo (bar)  VALUES (9)
INSERT #foo (bar)  VALUES (7)
INSERT #foo (bar)  VALUES (6)
INSERT #foo (bar)  VALUES (4)
INSERT #foo (bar)  VALUES (8)
--create logical fragmentation
DELETE #foo WHERE bar IN (1, 3, 5, 7, 9)
INSERT #foo (bar) VALUES (1)
INSERT #foo (bar) VALUES (3)
INSERT #foo (bar) VALUES (5)
INSERT #foo (bar) VALUES (7)
INSERT #foo (bar) VALUES (9)
-- run this a few times, you will see values > 10
-- "first 10" surely means values between 1 and 10?
select top 5 
    * 
from 
    (
    select top 10 * from #foo
    ) as a
order by 
    newid()
-- always <= 10 because of ORDER BY
select top 5 
    * 
from 
    (
    select top 10 * from #foo
    order by bar --got to have soemthing here to define "first 10"
    ) as a
order by 
    newid()发布于 2010-12-06 19:25:39
select * 
from 
    (select * from table order by id limit 10) as rows  order by rand() limit 5 发布于 2010-12-06 19:22:11
不确定你到底想做什么,但这可能会有帮助(在MySQL中):
 SELECT col1, col2, ... FROM tablename ORDER BY RAND() LIMIT 5使用RAND()和LIMIT实现您想要的目标。
https://stackoverflow.com/questions/4365829
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