blocks|key|2523983|text|可以使用substring删除字符串的第一个字符|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2523984|var+s1+=+"foobar";
var+s2+=+s1.substring(1);
alert(s2);+//+shows+"oobar"|code-block|syntax|javascript|2523985|要删除字符串开头的所有0，请执行以下操作：|2523986|var+s+=+"0000test";
while(s.charAt(0)+===+'0')
{
+s+=+s.substring(1);
}|2523987|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/substring^0|4|9|4|9|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@$9|Z|A|10|1|11]]|E|$]]|$1|F|3|G|5|H|7|12|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|13|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|15|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

You can remove the first character of a string using <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/substring" rel="noreferrer"><code>substring</code></a>:
<pre><code>var s1 = &quot;foobar&quot;;
var s2 = s1.substring(1);
alert(s2); // shows &quot;oobar&quot;
</code></pre>
To remove all 0's at the start of the string:
<pre><code>var s = &quot;0000test&quot;;
while(s.charAt(0) === '0')
{
 s = s.substring(1);
}
</code></pre>

blocks|key|456527|text|使用.charAt()和.slice()。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|456528|示例：+http://jsfiddle.net/kCpNQ/|BOLD|456529|var+myString+=+"0String";

if(+myString.charAt(+0+)+===+'0'+)
++++myString+=+myString.slice(+1+);|code-block|syntax|javascript|456530|如果开头可能有几个0字符，则可以将if()更改为while()。|456531|示例：+http://jsfiddle.net/kCpNQ/1/|456532|var+myString+=+"0000String";

while(+myString.charAt(+0+)+===+'0'+)
++++myString+=+myString.slice(+1+);|456533|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/charAt|1|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/slice|2|http://jsfiddle.net/kCpNQ/|3|http://jsfiddle.net/kCpNQ/1/^0|2|9|C|8|2|9|0|C|8|1|0|0|3|4|Q|2|0|0|9|1|H|4|O|7|0|0|3|4|S|3|0|0^^$0|@$1|2|3|4|5|6|7|17|8|@$9|18|A|19|B|C]|$9|1A|A|1B|B|C]]|D|@$9|1C|A|1D|1|1E]|$9|1F|A|1G|1|1H]]|E|$]]|$1|F|3|G|5|6|7|1I|8|@$9|1J|A|1K|B|H]]|D|@$9|1L|A|1M|1|1N]]|E|$]]|$1|I|3|J|5|K|7|1O|8|@]|D|@]|E|$L|M]]|$1|N|3|O|5|6|7|1P|8|@$9|1Q|A|1R|B|C]|$9|1S|A|1T|B|C]|$9|1U|A|1V|B|C]]|D|@]|E|$]]|$1|P|3|Q|5|6|7|1W|8|@$9|1X|A|1Y|B|H]]|D|@$9|1Z|A|20|1|21]]|E|$]]|$1|R|3|S|5|K|7|22|8|@]|D|@]|E|$L|M]]|$1|T|3|-4|5|6|7|23|8|@]|D|@]|E|$]]]|U|$V|$5|W|X|Y|E|$Z|10]]|11|$5|W|X|Y|E|$Z|12]]|13|$5|W|X|Y|E|$Z|14]]|15|$5|W|X|Y|E|$Z|16]]]]

Use <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/charAt" rel="noreferrer"><code>.charAt()</code></a> and <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/slice" rel="noreferrer"><code>.slice()</code></a>.
Example: <a href="http://jsfiddle.net/kCpNQ/" rel="noreferrer">http://jsfiddle.net/kCpNQ/</a>
<pre><code>var myString = &quot;0String&quot;;

if( myString.charAt( 0 ) === '0' )
 myString = myString.slice( 1 );
</code></pre>
If there could be several <code>0</code> characters at the beginning, you can change the <code>if()</code> to a <code>while()</code>.
Example: <a href="http://jsfiddle.net/kCpNQ/1/" rel="noreferrer">http://jsfiddle.net/kCpNQ/1/</a>
<pre><code>var myString = &quot;0000String&quot;;

while( myString.charAt( 0 ) === '0' )
 myString = myString.slice( 1 );
</code></pre>

blocks|key|456677|text|删除所有前导0的最简单方法是：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|456678|var+s+=+"00test";
s+=+s.replace(/%5E0%2B/,+"");|code-block|syntax|javascript|456679|如果只剥离单个前导0字符，如问题所示，您可以使用|456680|s+=+s.replace(/%5E0/,+"");|456681|entityMap^0|6|1|0|0|9|1|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|P|$]]

The easiest way to strip all leading <code>0</code>s is:

<pre><code>var s = "00test";
s = s.replace(/^0+/, "");
</code></pre>

If just stripping a single leading <code>0</code> character, as the question implies, you could use

<pre><code>s = s.replace(/^0/, "");
</code></pre>

blocks|key|456744|text|你可以用substring方法来实现：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|456745|let+a+=+"My+test+string";

a+=+a.substring(1);

console.log(a);+//+y+test+string|code-block|syntax|javascript|456746|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/substring^0|4|9|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

You can do it with <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/substring" rel="noreferrer">substring</a> method:

<pre><code>let a = "My test string";

a = a.substring(1);

console.log(a); // y test string
</code></pre>

blocks|key|456411|text|你有没有尝试过substring函数？|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|456412|string+=+string.indexOf(0)+==+'0'+?+string.substring(1)+:+string;|code-block|syntax|javascript|456413|这里有一个参考--+https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/String/substring|456414|而且你总是可以在多个0上这样做：|456415|while(string.indexOf(0)+==+'0')
{
++++string+=+string.substring(1);
}|456416|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/String/substring^0|7|9|0|0|A|2L|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|12|8|@]|D|@$9|13|A|14|1|15]]|E|$]]|$1|M|3|N|5|6|7|16|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|Q|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X]]]]

Did you try the <code>substring</code> function?

<pre><code>string = string.indexOf(0) == '0' ? string.substring(1) : string;
</code></pre>

Here's a reference - <a href="https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/String/substring" rel="noreferrer">https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/String/substring</a>

And you can always do this for multiple 0s:

<pre><code>while(string.indexOf(0) == '0')
{
 string = string.substring(1);
}
</code></pre>

blocks|key|1577201|text|var+s+=+"0test";
if(s.substr(0,1)+==+"0")+{
++++s+=+s.substr(1);
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1577202|对于所有0：http://jsfiddle.net/An4MY/|unstyled|offset|length|style|CODE|1577203|String.prototype.ltrim0+=+function()+{
+return+this.replace(/%5E[0]%2B/,"");
}
var+s+=+"0000test".ltrim0();|1577204|entityMap|0|LINK|mutability|MUTABLE|url|http://jsfiddle.net/An4MY/^0|0|4|1|6|Q|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|V|8|@$G|W|H|X|I|J]]|9|@$G|Y|H|Z|1|10]]|A|$]]|$1|K|3|L|5|6|7|11|8|@]|9|@]|A|$B|C]]|$1|M|3|-4|5|F|7|12|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

<pre><code>var s = "0test";
if(s.substr(0,1) == "0") {
 s = s.substr(1);
}
</code></pre>

For all <code>0</code>s: <a href="http://jsfiddle.net/An4MY/" rel="noreferrer">http://jsfiddle.net/An4MY/</a>

<pre><code>String.prototype.ltrim0 = function() {
 return this.replace(/^[0]+/,"");
}
var s = "0000test".ltrim0();
</code></pre>

blocks|key|1577356|text|//----+remove+first+and+last+char+of+str++++
str+=+str.substring(1,((keyw.length)-1));

//----+remove+only+first+char++++
str+=+str.substring(1,(keyw.length));

//----+remove+only+last+char++++
str+=+str.substring(0,(keyw.length));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1577357|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>//---- remove first and last char of str 
str = str.substring(1,((keyw.length)-1));

//---- remove only first char 
str = str.substring(1,(keyw.length));

//---- remove only last char 
str = str.substring(0,(keyw.length));
</code></pre>

blocks|key|4120092|text|试一试|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4120093|s.replace(/%5E0/,'')|code-block|syntax|javascript|4120094|​|4120095|console.log("0string++=>",+"0string".replace(/%5E0/,'')+);
console.log("00string+=>",+"00string".replace(/%5E0/,'')+);
console.log("string00+=>",+"string00".replace(/%5E0/,'')+);|4120096|4120097|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|O|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|P|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Q|8|@]|9|@]|A|$E|F]]|$1|K|3|H|5|6|7|R|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|M|$]]

try

<pre><code>s.replace(/^0/,'')
</code></pre>

<div class="snippet" data-lang="js" data-hide="true" data-console="true" data-babel="false">
<div class="snippet-code snippet-currently-hidden">
<pre class="snippet-code-js lang-js prettyprint-override"><code>console.log("0string =&gt;", "0string".replace(/^0/,'') );
console.log("00string =&gt;", "00string".replace(/^0/,'') );
console.log("string00 =&gt;", "string00".replace(/^0/,'') );</code></pre>
</div>
</div>

blocks|key|456880|text|const+string+=+'0My+string';
const+result+=+string.substring(1);
console.log(result);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|456881|您可以使用javascript+substring()函数。|unstyled|offset|length|style|BOLD|456882|entityMap^0|0|R|3|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>const string = '0My string';
const result = string.substring(1);
console.log(result);
</code></pre>
You can use the substring() javascript function.

blocks|key|4119850|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4119851|String.prototype.trimStartWhile+=+function(predicate)+{
++++if+(typeof+predicate+!==+"function")+{
++++	return+this;
++++}
++++let+len+=+this.length;
++++if+(len+===+0)+{
++++++++return+this;
++++}
++++let+s+=+this,+i+=+0;
++++while+(i+<+len+&&+predicate(s[i]))+{
++++	i%2B%2B;
++++}
++++return+s.substr(i)
}

let+str+=+"0000000000ABC",
++++r+=+str.trimStartWhile(c+=>+c+===+'0');
++++
console.log(r);|code-block|syntax|javascript|4119852|4119853|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|K|8|@]|9|@]|A|$E|F]]|$1|G|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|M|8|@]|9|@]|A|$]]]|I|$]]

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>String.prototype.trimStartWhile = function(predicate) {
 if (typeof predicate !== "function") {
 	return this;
 }
 let len = this.length;
 if (len === 0) {
 return this;
 }
 let s = this, i = 0;
 while (i &lt; len &amp;&amp; predicate(s[i])) {
 	i++;
 }
 return s.substr(i)
}

let str = "0000000000ABC",
 r = str.trimStartWhile(c =&gt; c === '0');
 
console.log(r);</code></pre>
</div>
</div>

blocks|key|4119986|text|这里有一个没有假设输入是string的，使用了substring，并附带了几个单元测试：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4119987|var+cutOutZero+=+function(value)+{
++++if+(value.length+&&+value.length+>+0+&&+value[0]+===+'0')+{
++++++++return+value.substring(1);
++++}

++++return+value;
};|code-block|syntax|javascript|4119988|http://jsfiddle.net/TRU66/1/|4119989|entityMap|0|LINK|mutability|MUTABLE|url^0|C|6|N|9|0|0|0|S|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@$9|U|A|V|B|C]|$9|W|A|X|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Y|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Z|8|@]|D|@$9|10|A|11|1|12]]|E|$]]|$1|M|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|L]]]]

Here's one that doesn't assume the input is a <code>string</code>, uses <code>substring</code>, and comes with a couple of unit tests:

<pre><code>var cutOutZero = function(value) {
 if (value.length &amp;&amp; value.length &gt; 0 &amp;&amp; value[0] === '0') {
 return value.substring(1);
 }

 return value;
};
</code></pre>

<a href="http://jsfiddle.net/TRU66/1/" rel="nofollow">http://jsfiddle.net/TRU66/1/</a>

blocks|key|456816|text|一种简单的解决方案是使用splice()方法，并使用传递1作为参数|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|BOLD|entityRanges|data|456817|let+str+=+"khattak01"|456818|let+resStr+=+str.slice(1)|456819|console.log(resStr)|456820|​|456821|结果：hattak01|456822|entityMap^0|C|8|Q|7|0|0|L|0|0|P|0|0|J|0|0|3|8|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|D]]|E|@]|F|$]]|$1|G|3|H|5|6|7|X|8|@$9|Y|A|Z|B|C]]|E|@]|F|$]]|$1|I|3|J|5|6|7|10|8|@$9|11|A|12|B|C]]|E|@]|F|$]]|$1|K|3|L|5|6|7|13|8|@$9|14|A|15|B|C]]|E|@]|F|$]]|$1|M|3|N|5|6|7|16|8|@]|E|@]|F|$]]|$1|O|3|P|5|6|7|17|8|@$9|18|A|19|B|D]]|E|@]|F|$]]|$1|Q|3|-4|5|6|7|1A|8|@]|E|@]|F|$]]]|R|$]]

one simple solution is to use <code>splice()</code> method, and pass 1 as a parameter

&nbsp;&nbsp;&nbsp;&nbsp;<code>let str = "khattak01"</code> 
&nbsp;&nbsp;&nbsp;&nbsp;<code>let resStr = str.slice(1) </code> 
&nbsp;&nbsp;&nbsp;&nbsp;<code>console.log(resStr)</code> 

 
Result : hattak01

blocks|key|4119863|text|var+test+=+'0test';
test+=+test.replace(/0(.*)/,+'$1');|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4119864|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>var test = '0test';
test = test.replace(/0(.*)/, '$1');
</code></pre>

blocks|key|1579326|text|从trim()+>的Javascript实现中删除字符串中的前导或结尾空格。这里是这个问题答案的一个修改后的实现。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1579327|var+str+=+"0000one+two+three0000";+//TEST++
str+=+str.replace(/%5E\s%2B%7C\s%2B$/g,'0');+//ANSWER|code-block|syntax|javascript|1579328|在JS上的原始实现|1579329|string.trim():
if+(!String.prototype.trim)+{
+String.prototype.trim+=+function()+{
++return+this.replace(/%5E\s%2B%7C\s%2B$/g,'');
+}
}|1579330|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

From the Javascript implementation of trim() > that removes and leading or ending spaces from strings. Here is an altered implementation of the answer for this question.

<pre><code>var str = "0000one two three0000"; //TEST 
str = str.replace(/^\s+|\s+$/g,'0'); //ANSWER
</code></pre>

Original implementation for this on JS 

<pre><code>string.trim():
if (!String.prototype.trim) {
 String.prototype.trim = function() {
 return this.replace(/^\s+|\s+$/g,'');
 }
}
</code></pre>

blocks|key|1579371|text|删除第一个字符后获取该字符的另一种方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1579372|//+Example+string
let+string+=+'Example';

//+Getting+the+first+character+and+updtated+string
[character,+string]+=+[string[0],+string.substr(1)];

console.log(character);
//+'E'

console.log(string);
//+'xample'|code-block|syntax|javascript|1579373|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Another alternative to get the first character after deleting it:
<pre class="lang-js prettyprint-override"><code>// Example string
let string = 'Example';

// Getting the first character and updtated string
[character, string] = [string[0], string.substr(1)];

console.log(character);
// 'E'

console.log(string);
// 'xample'

</code></pre>

I want to delete the first character of a string, if the first character is a 0. The 0 can be there more than once.

Is there a simple function that checks the first character and deletes it if it is 0?

Right now, I'm trying it with the JS <code>slice()</code> function but it is very awkward.

Delete first character of a string in Javascript

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想删除字符串的第一个字符，如果第一个字符是0。0可以多次出现在那里。是否有一个简单的函数可以检查第一个字符，如果第一个字符为0，则将其删除？现在，我正在使用JS slice()函数来尝试它，但它非常笨拙。

问删除Javascript中字符串的第一个字符
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回答 15

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回答 15

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问删除Javascript中字符串的第一个字符
EN