blocks|key|2528972|text|你不能把它们“捆绑”在一起，因为它们在两个不同的处理过程中运行，php在服务器上处理，而javascript在浏览器中处理。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2528973|但是，您可以在php文件中呈现javascript。|2528974|如果您的javascript包含在php页面的<script>标记中，那么您的示例应该可以正常工作。在脚本被发送到浏览器之前，php会将urls呈现到脚本中。|offset|length|style|CODE|2528975|如果你想用php包含的urls加载外部的javascript文件，你需要设置合适的头文件并像普通的.js文件一样包含php文件。|2528976|关于这个主题的好文章HERE|2528977|entityMap|0|LINK|mutability|MUTABLE|url|http://www.javascriptkit.com/javatutors/externalphp.shtml^0|0|0|N|8|0|0|A|4|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|W|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|X|8|@$F|Y|G|Z|H|I]]|9|@]|A|$]]|$1|J|3|K|5|6|7|10|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|11|8|@]|9|@$F|12|G|13|1|14]]|A|$]]|$1|N|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|O|$P|$5|Q|R|S|A|$T|U]]]]

you can't necessarily "tie" them together because they operate in two different spectrums of processing, php being processed on the server, and javascript being processed in the browser.

You can however render javascript within a php file.

if your javascript is included within a <code>&lt;script&gt;</code> tag within your php page your example should work should actually work. The php would render the urls into the script before it is sent to the browser.

if you are wanting to load external javascript files with php inlcuded urls, you will need to set the proper headers and include the php file just as you would a normal .js file.

good article on this topic <a href="http://www.javascriptkit.com/javatutors/externalphp.shtml" rel="nofollow">HERE</a>

blocks|key|461775|text|如果javascript在.php文件中，则可以使用<?php+echo+$url+?>；如果该文件是.js，则不能使用<?php+?>|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|461776|entityMap^0|D|4|Q|I|1F|3|1O|8|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]|$9|M|A|N|B|C]|$9|O|A|P|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|G|$]]

If javascript is in <code>.php</code> file you can use <code>&lt;?php echo $url ?&gt;</code> and if the file is <code>.js</code> you can't use <code>&lt;?php ?&gt;</code>

blocks|key|461805|text|我不清楚你想要达到什么目的。我假设您正在使用jQuery+load()函数，如果是，您应该说明一下。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|461806|您不能在javascript执行期间加载php，因为php已经被处理并呈现为HTML并发送回客户端。因为PHP是在服务器上处理的，所以您不能在客户端运行它是合乎逻辑的。|461807|当然，您可以向运行某个php页面的服务器发送一个AJAX请求，这样您就可以随心所欲地使用响应了。|461808|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

It is not clear to me what you are trying to achieve. I assume you are using the jQuery load() function, if yes, you should state so.

You can't load php during javascript execution because the php has already been processes and rendered as HTML and sent back to the client. As PHP is processes on the server it is logical that you cannot run it on the client side.

You could of course send an AJAX request to the server that runs a certain php page and you will be able to use the response as you please.

blocks|key|461865|text|您说得对:)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|461866|461867|是的，这是错误的地狱笑，但我相信有人知道|blockquote|461868|461869|461870|无论如何，从您的php脚本中，将url作为javascript代码输出到脚本中用于ajax调用的javascript之前的任何位置，例如|461871|<?php
++++echo+'<script+language="javascript">+var+g_ajax_url+=+"'.+$the_url+.+'";</script>';
?>|code-block|syntax|javascript|461872|在你的javascript中，这样使用它。|461873|$fetchContent+=+$('#grav').load(g_ajax_url+%2B+'+#poppu');|461874|它所做的只是将g_ajax_url定义为一个具有适当php值的全局变量，您可以像使用其他变量一样在js中使用该变量。|461875|要将php与js直接绑定，请尝试查看xmlrpc主题。|461876|entityMap^0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|10|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|11|8|@]|9|@]|A|$]]|$1|G|3|-4|5|6|7|12|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|13|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|14|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|15|8|@]|9|@]|A|$]]|$1|Q|3|R|5|L|7|16|8|@]|9|@]|A|$M|N]]|$1|S|3|T|5|6|7|17|8|@]|9|@]|A|$]]|$1|U|3|V|5|6|7|18|8|@]|9|@]|A|$]]|$1|W|3|-4|5|6|7|19|8|@]|9|@]|A|$]]]|X|$]]

You said it right :)

<blockquote>
 Yep, thats wrong as hell lol, but i'm
 sure someone knows
</blockquote>

Anyway, from your php script, output the url as a javascript code anywhere in the script before the javascript used for ajax call, e.g.

<pre><code>&lt;?php
 echo '&lt;script language="javascript"&gt; var g_ajax_url = "'. $the_url . '";&lt;/script&gt;';
?&gt;
</code></pre>

and in your javascript, use it this way

<pre><code>$fetchContent = $('#grav').load(g_ajax_url + ' #poppu');
</code></pre>

What it simply does is define g_ajax_url as a global variable with the proper php value, and you can use that variable in your js as you use other variables.

To tie php with js directly, try looking into xmlrpc topic.

blocks|key|461917|text|您不能在JavaScript中执行<?php+?>，但是在PHP中您可以将全局变量声明为：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|461918|var+x+=+'<?php+echo+x;?>';|code-block|syntax|javascript|461919|或者，如果它是一个数组，则将其存储为JSON：|461920|var+x+=+<?php+json_encode(x);+?>|461921|然后访问外部JavaScript中的JavaScript变量。|461922|entityMap^0|H|8|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|Y|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|R|$]]

You cannot execute <code>&lt;?php ?&gt;</code> inside JavaScript, but inside PHP you can declare a global variable as:

<pre><code>var x = '&lt;?php echo x;?&gt;';
</code></pre>

or, if it's an array, store it as JSON:

<pre><code>var x = &lt;?php json_encode(x); ?&gt;
</code></pre>

then access the JavaScript variables inside the external JavaScript.

I was wondering how i could achieve using <code>&lt;?php?&gt;</code> in javascript for url's? There's a certain route you have to go, Anyone know?

the normal way for example:

<pre><code>$fetchContent = $('#div').load('website/members #content');
</code></pre>

What i'm trying to do:

<pre><code>$fetchContent = $('#grav').load('&lt;?php?&gt; #poppu');
</code></pre>

Yep, thats wrong as hell lol, but i'm sure someone knows

I would also like to know how to tie php with javascript, but thats probably a whole new topic

How to implement php tags in javascript for url's or anything

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想知道如何在url的javascript中使用<?php?>？你必须走一条特定的路线，有人知道吗？正常的方式，例如：$fetchContent = $('#div').load('website/members #content');我想要做的是：$fetchContent = $('#grav').load('<?...

问如何在javascript中为url或任何东西实现php标签
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问如何在javascript中为url或任何东西实现php标签EN