blocks|key|539520|text|使用NSView的convertPoint:+fromView+:方法，并将fromView设置为nil，将窗口坐标中的点转换为视图的坐标系。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|539521|在将鼠标指针转换到视图的坐标系后，我将使用NSView的鼠标:inRect:方法而不是NSPointInRect，因为前者也考虑了翻转的坐标系。|539522|或者，您可以使用Tracking+Area+Object。|offset|length|539523|entityMap|0|LINK|mutability|MUTABLE|url|http://developer.apple.com/library/mac/#documentation/Cocoa/Conceptual/EventOverview/TrackingAreaObjects/TrackingAreaObjects.html^0|0|0|8|K|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Q|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|R|8|@]|9|@$F|S|G|T|1|U]]|A|$]]|$1|H|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|I|$J|$5|K|L|M|A|$N|O]]]]

Use NSView's convertPoint:fromView: method with fromView as nil to covert a point in window coordinates to a view's coordinate system.

After converting the mouse point to the view's coordinate system, I would use NSView's mouse:inRect: method instead of NSPointInRect as the former also accounts for flipped coordinate systems.

Alternatively, you could use a <a href="http://developer.apple.com/library/mac/#documentation/Cocoa/Conceptual/EventOverview/TrackingAreaObjects/TrackingAreaObjects.html" rel="noreferrer">Tracking Area Object</a>.

blocks|key|1620933|text|这样的东西对你来说应该是有效的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1620934|NSView*+myView;+//+The+view+you+are+converting+coordinates+to
NSPoint+globalLocation+=+[+NSEvent+mouseLocation+];
NSPoint+windowLocation+=+[+[+myView+window+]+convertScreenToBase:+globalLocation+];
NSPoint+viewLocation+=+[+myView+convertPoint:+windowLocation+fromView:+nil+];
if(+NSPointInRect(+viewLocation,+[+myView+bounds+]+)+)+{
++++//+Do+your+thing+here
}|code-block|syntax|javascript|1620935|我个人并没有使用这么多的局部变量，但希望这能让这个例子更清晰。|1620936|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Something like this should work for you:

<pre><code>NSView* myView; // The view you are converting coordinates to
NSPoint globalLocation = [ NSEvent mouseLocation ];
NSPoint windowLocation = [ [ myView window ] convertScreenToBase: globalLocation ];
NSPoint viewLocation = [ myView convertPoint: windowLocation fromView: nil ];
if( NSPointInRect( viewLocation, [ myView bounds ] ) ) {
 // Do your thing here
}
</code></pre>

I don't personally use this many local variables but hopefully this make this example clearer.

blocks|key|4208603|text|一些使用鼠标的代码:inRect：(推荐的方式；这解释了翻转的坐标)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4208604|CGPoint+point+=+[self+convertPoint:[event+locationInWindow]+fromView:nil];
CGRect+rect+=+[self+bounds];
if+([self+mouse:point+inRect:rect])+{
}|code-block|syntax|javascript|4208605|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Some code making use of mouse:inRect: (the recommended way; that accounts for flipped coordinates)

<pre><code>CGPoint point = [self convertPoint:[event locationInWindow] fromView:nil];
CGRect rect = [self bounds];
if ([self mouse:point inRect:rect]) {
}
</code></pre>

blocks|key|539605|text|NSView+isMousePoint函数适用于我，而不必担心任何CG。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|539606|func+isMouseInView(view:+NSView)+->+Bool?+{
++++if+let+window+=+view.window+{
++++++++return+view.isMousePoint(window.mouseLocationOutsideOfEventStream,+in:+view.frame)
++++}
++++return+nil
}|code-block|syntax|javascript|539607|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.apple.com/documentation/appkit/nsview/1483237-ismousepoint^0|7|C|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

The NSView <a href="https://developer.apple.com/documentation/appkit/nsview/1483237-ismousepoint" rel="noreferrer">isMousePoint</a> function works for me, without having to worry about anything CG.

<pre><code>func isMouseInView(view: NSView) -&gt; Bool? {
 if let window = view.window {
 return view.isMousePoint(window.mouseLocationOutsideOfEventStream, in: view.frame)
 }
 return nil
}
</code></pre>

blocks|key|4208636|text|这些答案都没有考虑到视图可能不是矩形。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|4208637|这是一个通用的方法，也适用于非矩形视图。想一想手表或复杂的路径形状。|4208638|这段代码将为您提供一个来自globalPoint的localPoint+(也称为globalToLocal)。(+0,0窗口空间中的GlobalPoint)如果将参数更改为"toView“，则会得到一个"localToGlobal”点。|4208639|let+localPoint+=+convertPoint(aPoint,+fromView:+self.window?.contentView)++++|code-block|syntax|javascript|4208640|如果点在路径内或不在路径内，下面的代码将返回true或false。|4208641|CGPathContainsPoint(someCGPath,nil,localPoint,true)|CODE|4208642|注意：+aPoint是从hitTest中的参数派生而来的globalPoint，它也可以派生自：|4208643|(self.window?.mouseLocationOutsideOfEventStream)!|4208644|注释：也许有一种更正确的方法可以做到这一点。但这是有效的，并且不关心翻转的视图。|4208645|entityMap^0|0|J|0|0|0|0|0|0|1F|0|0|3|0|0|0|2|0^^$0|@$1|2|3|4|5|6|7|11|8|@$9|12|A|13|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|14|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|15|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|16|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|17|8|@]|D|@]|E|$]]|$1|Q|3|R|5|6|7|18|8|@$9|19|A|1A|B|S]]|D|@]|E|$]]|$1|T|3|U|5|6|7|1B|8|@$9|1C|A|1D|B|C]]|D|@]|E|$]]|$1|V|3|W|5|L|7|1E|8|@]|D|@]|E|$M|N]]|$1|X|3|Y|5|6|7|1F|8|@$9|1G|A|1H|B|C]]|D|@]|E|$]]|$1|Z|3|-4|5|6|7|1I|8|@]|D|@]|E|$]]]|10|$]]

None of these answers take into account that a view might not be rectangular. 

Here is an universal method that works on non-rectangular views as well. Think watch-face or a complex path shape.

This code snippet will give you a localPoint from a globalPoint (aka globalToLocal). (GlobalPoint in 0,0 window space) If you change the argument to "toView" then you get a "localToGlobal" point. 

<pre><code>let localPoint = convertPoint(aPoint, fromView: self.window?.contentView) 
</code></pre>

The bellow code would return true or false if the point was inside the path or not. 

<code>CGPathContainsPoint(someCGPath,nil,localPoint,true)</code>

NOTE:
aPoint is a globalPoint derived from the parameter in hitTest, it can also be derived from:

<pre><code>(self.window?.mouseLocationOutsideOfEventStream)!
</code></pre>

NOTE: 
There might be a more correct way of doing this. But this works,and doesn't care about flipped views.

I need to find if the mouse position is inside an NSView's rect.

I'd use <code>NSPointInRect(point, rect)</code>, but I'd need to convert the rect coordinates to screen coordinates and I'm not sure how. Any help would be much appreciated!

How to find if the mouse is over a view

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

我需要找出鼠标位置是否在NSView的矩形内。我会使用NSPointInRect(point, rect)，但我需要将矩形坐标转换为屏幕坐标，并且我不确定如何转换。任何帮助都将不胜感激！

问如何查找鼠标是否在视图上
EN

回答 5

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问如何查找鼠标是否在视图上EN

回答 5

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问如何查找鼠标是否在视图上
EN