问删除目录中除最新N之外的旧文件的脚本

EN

#!/bin/bash

declare -a files
for file in *
do
    files[${#files[@]}]=$file
done

# Bubble sort the files from newest to oldest
declare -i i j count=${#files[@]}
while true
do
    declare -i sorted=1
    for ((i=1;i<count;i++))
    do
        let j=i-1
        if [ ${files[$j]} -ot ${files[$i]} ]
        then
            sorted=0
            f=${files[$j]}
            files[$j]=${files[$i]}
            files[$i]=$f
        fi
    done
    [ $sorted -eq 1 ] && break
done

# Delete everything except the first 5 files
for ((i=5;i<count;i++))
do
    rm "${files[$i]}"
done