blocks|key|1800283|text|string[]+elements+=+templine.Split(space).Where((s,+i)+=>+i+!=+1).ToArray();|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1800284|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>string[] elements = templine.Split(space).Where((s, i) =&gt; i != 1).ToArray();
</code></pre>

blocks|key|4563043|text|这里有很多疯狂的LINQ例子。这可能会更有效率，如果这对你很重要：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4563044|public+static+T[]+SkipElement<T>(this+T[]+source,+int+index)
{
++++//+Leaving+out+null/bounds+checking+for+brevity.
++++T[]+array+=+new+T[source.Length+-+1];
++++Array.Copy(source,+0,+array,+0,+index);
++++Array.Copy(source,+index+%2B+1,+array,+index,+source.Length+-+index+-+1);
++++return+array;
}|code-block|syntax|javascript|4563045|有了这个，你可以这样做：|4563046|string[]+elements+=+templine.Split(space,+StringSplitOptions.RemoveEmptyEntries);
elements+=+elements.SkipElement(1);|4563047|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Lots of crazy LINQ examples here. This should probably be more efficient, if that matters to you:

<pre><code>public static T[] SkipElement&lt;T&gt;(this T[] source, int index)
{
 // Leaving out null/bounds checking for brevity.
 T[] array = new T[source.Length - 1];
 Array.Copy(source, 0, array, 0, index);
 Array.Copy(source, index + 1, array, index, source.Length - index - 1);
 return array;
}
</code></pre>

With this you could do:

<pre><code>string[] elements = templine.Split(space, StringSplitOptions.RemoveEmptyEntries);
elements = elements.SkipElement(1);
</code></pre>

blocks|key|2963154|text|List<String>+elements+=+templine.Split
++++++++++++++++++++++++++++++++++(space,+StringSplitOptions.RemoveEmptyEntries).
+++++++++++++++++++++++++++++++++ToList().
+++++++++++++++++++++++++++++++++RemoveAt(1);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2963155|如果您觉得需要返回到数组...|unstyled|2963156|string[]+elements+=+templine.Split
++++++++++++++++++++++++++++++++++(space,+StringSplitOptions.RemoveEmptyEntries).
+++++++++++++++++++++++++++++++++ToList().
+++++++++++++++++++++++++++++++++RemoveAt(1).
+++++++++++++++++++++++++++++++++ToArray();|2963157|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>List&lt;String&gt; elements = templine.Split
 (space, StringSplitOptions.RemoveEmptyEntries).
 ToList().
 RemoveAt(1);
</code></pre>

If you feel the need to go back to an array...

<pre><code>string[] elements = templine.Split
 (space, StringSplitOptions.RemoveEmptyEntries).
 ToList().
 RemoveAt(1).
 ToArray();
</code></pre>

blocks|key|1800254|text|如果你可以使用Linq，你可能会这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1800255|IEnumerable<string>+elements+=+templine.Split(...).Take(1).Skip(1);|code-block|syntax|javascript|1800256|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you can use Linq, you can probably do:

<pre><code>IEnumerable&lt;string&gt; elements = templine.Split(...).Take(1).Skip(1);
</code></pre>

blocks|key|4562927|text|使用Linq，您只需执行以下操作|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4562928|IEnumerable<String>+elements+=+
++empline.Split(space,+StringSplitOptions.RemoveEmptyEntries);
String[]+result+=+
+elements
+.Take(1)
+.Concat(elements
+.Skip(2))
+.ToArray();|code-block|syntax|javascript|4562929|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Using Linq, you can just do

<pre><code>IEnumerable&lt;String&gt; elements = 
 empline.Split(space, StringSplitOptions.RemoveEmptyEntries);
String[] result = 
 elements
 .Take(1)
 .Concat(elements
 .Skip(2))
 .ToArray();
</code></pre>

blocks|key|4563004|text|你要么去问你弟弟Jon|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4563005|或者你可以这样做：|4563006|var+elements+=+templine.Split(space,+StringSplitOptions.RemoveEmptyEntries).Skip(1).ToArray();|code-block|syntax|javascript|4563007|这将为您提供一个包含除第一个元素之外的所有元素的数组。如果你想要第一个，而不是第二个(正如你的问题所暗示的)，你可以这样做：|4563008|var+allElements+=+templine.Split(space,+StringSplitOptions.RemoveEmptyEntries);
var+someElements+=+allElements.Take(1).Concat(allElements.Skip(2)).ToArray();|4563009|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/users/22656/jon-skeet^0|8|3|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|6|7|10|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|11|8|@]|9|@]|C|$I|J]]|$1|K|3|L|5|6|7|12|8|@]|9|@]|C|$]]|$1|M|3|N|5|H|7|13|8|@]|9|@]|C|$I|J]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]]]

Well, you could either ask your brother <a href="https://stackoverflow.com/users/22656/jon-skeet">Jon</a>

Or you could do something like this:

<pre><code>var elements = templine.Split(space, StringSplitOptions.RemoveEmptyEntries).Skip(1).ToArray();
</code></pre>

This will give you an array that contains all but the first element. If you want the first, but not the second (as your question sort of suggests), you could do this:

<pre><code>var allElements = templine.Split(space, StringSplitOptions.RemoveEmptyEntries);
var someElements = allElements.Take(1).Concat(allElements.Skip(2)).ToArray();
</code></pre>

blocks|key|895717|text|string[]+elements+=+templine.Split
++++(space,+StringSplitOptions.RemoveEmptyEntries).Where(s+=>+s+!=+"[1]").ToArray();|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|895718|如果您想要删除第二个元素|unstyled|895719|string[]+elements+=+templine.Split
++++++++(space,+StringSplitOptions.RemoveEmptyEntries).Where((s,+i)+=>+i+!=+1).ToArray();|895720|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>string[] elements = templine.Split
 (space, StringSplitOptions.RemoveEmptyEntries).Where(s =&gt; s != "[1]").ToArray();
</code></pre>

if you mean you'd like to remove the second element

<pre><code>string[] elements = templine.Split
 (space, StringSplitOptions.RemoveEmptyEntries).Where((s, i) =&gt; i != 1).ToArray();
</code></pre>

blocks|key|4563095|text|在上面的代码之后：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4563096|elements+=+elements.Take(1).Concat(elements.Skip(2)).ToArray();|code-block|syntax|javascript|4563097|4563098|我想指出的一件事是:即使原始elements太短，Take和Skip也不会抛出错误；它们只会生成空的IEnumerable(可以安全地连接在一起，并且可以安全地调用其方法)。|offset|length|style|CODE|4563099|entityMap^0|0|0|0|E|8|P|4|U|4|1E|B|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Q|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|R|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|S|8|@$J|T|K|U|L|M]|$J|V|K|W|L|M]|$J|X|K|Y|L|M]|$J|Z|K|10|L|M]]|9|@]|A|$]]|$1|N|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|O|$]]

After your code above:

<pre><code>elements = elements.Take(1).Concat(elements.Skip(2)).ToArray();
</code></pre>

<hr>

One thing I want to point out: <code>Take</code> and <code>Skip</code> will not throw errors even if the original <code>elements</code> is too short; they'll simply produce empty <code>IEnumerable</code>s (which can be safely concatenated, and whose methods can be safely called).

I am splitting a string like this:

<pre><code>string[] elements = templine.Split
 (space, StringSplitOptions.RemoveEmptyEntries);
</code></pre>

How can I get every element from <code>templine</code> except for <code>[1]</code> and assign it to <code>string[] elements</code>?

Splitting a string on a space and removing empty entries

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我像这样拆分字符串：string[] elements = templine.Split                            (space, StringSplitOptions.RemoveEmptyEntries);如何从templine中获取除[1]之外的所有元素并将其分配给string[] elements

问在空格上拆分字符串并删除空条目
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