blocks|key|5108704|text|是的，就像你做的那样：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5108705|select+something+%2B+somethingElse+as+onlyOneColumn+from+someTable|code-block|syntax|javascript|5108706|如果你查询了数据库，你就会得到正确的答案。|5108707|发生的事情是，你请求一个表达式。一个非常简单的表达式只是一个列名，一个更复杂的表达式可以包含公式等等。|5108708|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Yes, just like you did:

<pre><code>select something + somethingElse as onlyOneColumn from someTable
</code></pre>

If you queried the database, you would have gotten the right answer. 

What happens is you ask for an expression. A very simple expression is just a column name, a more complicated expression can have formulas etc in it.

blocks|key|2074313|text|(SELECT+column1+as+column+FROM+table+)
UNION+
(SELECT+column2+as+column+FROM+table+)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2074314|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>(SELECT column1 as column FROM table )
UNION 
(SELECT column2 as column FROM table )
</code></pre>

blocks|key|1442253|text|是,|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1442254|SELECT+CONCAT(field1,+field2)+AS+WHOLENAME+FROM+TABLE
WHERE+...|code-block|syntax|javascript|1442255|将产生如下的数据集：|1442256|WHOLENAME
field1field2|1442257|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Yes,

<pre><code>SELECT CONCAT(field1, field2) AS WHOLENAME FROM TABLE
WHERE ...
</code></pre>

will result in data set like:

<pre><code>WHOLENAME
field1field2
</code></pre>

blocks|key|3509104|text|其他答案对我都不起作用，但这个答案起作用了：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3509105|SELECT+CONCAT(Cust_First,+'+',+Cust_Last)+AS+CustName+FROM+customer|code-block|syntax|javascript|3509106|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

None of the other answers worked for me but this did:

<pre><code>SELECT CONCAT(Cust_First, ' ', Cust_Last) AS CustName FROM customer
</code></pre>

blocks|key|1442194|text|是的，这是可能的，只要数据类型是兼容的。如果不是，则使用CONVERT()或CAST()|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1442195|SELECT+firstname+%2B+'+'+%2B+lastname+AS+name+FROM+customers|code-block|syntax|javascript|1442196|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Yes it's possible, as long as the datatypes are compatible. If they aren't, use a CONVERT() or CAST()

<pre><code>SELECT firstname + ' ' + lastname AS name FROM customers
</code></pre>

blocks|key|3509048|text|%2B操作符应该可以很好地完成这项工作。但是请记住，如果其中一列为null或没有任何值，它将为您提供NULL结果。取而代之的是，将%2B与函数COALESCE结合使用，您就可以完成设置。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3509049|下面是一个示例：|3509050|SELECT+COALESCE(column1,'')+%2B+COALESCE(column2,'')+FROM+table1.+|code-block|syntax|javascript|3509051|对于本例，如果column1为NULL，则将显示column2的结果，而不是简单的NULL。|3509052|希望这能有所帮助！|3509053|entityMap^0|0|1|1C|4|1R|1|1V|8|0|0|0|7|7|F|4|O|7|15|4|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|11|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|12|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|13|8|@$9|14|A|15|B|C]|$9|16|A|17|B|C]|$9|18|A|19|B|C]|$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|O|3|P|5|6|7|1C|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|1D|8|@]|D|@]|E|$]]]|R|$]]

The <code>+</code> operator should do the trick just fine. Keep something in mind though, if one of the columns is null or does not have any value, it will give you a <code>NULL</code> result. Instead, combine <code>+</code> with the function <code>COALESCE</code> and you'll be set. 

Here is an example: 

<pre><code>SELECT COALESCE(column1,'') + COALESCE(column2,'') FROM table1. 
</code></pre>

For this example, if <code>column1</code> is <code>NULL</code>, then the results of <code>column2</code> will show up, instead of a simple <code>NULL</code>. 

Hope this helps!

blocks|key|3508951|text|是的，您可以非常容易地组合列，例如连接字符数据：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3508952|select+col1+%7C+col+2+as+bothcols+from+tbl+...|code-block|syntax|javascript|3508953|或者添加(例如)数字数据：|3508954|select+col1+%2B+col2+as+bothcols+from+tbl+...|3508955|在这两种情况下，最终都会得到一个包含组合数据的列bothcols。如果列不兼容，则可能必须强制使用数据类型。|offset|length|style|CODE|3508956|entityMap^0|0|0|0|0|O|8|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|W|8|@$M|X|N|Y|O|P]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

Yes, you can combine columns easily enough such as concatenating character data:

<pre><code>select col1 | col 2 as bothcols from tbl ...
</code></pre>

or adding (for example) numeric data:

<pre><code>select col1 + col2 as bothcols from tbl ...
</code></pre>

In both those cases, you end up with a single column <code>bothcols</code>, which contains the combined data. You may have to coerce the data type if the columns are not compatible.

blocks|key|1442424|text|如果其中一列是我经历过的数字，则oracle会将'%2B‘视为sum运算符，而不是串联。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1442425|例如：|1442426|select+(id+%2B+name)+as+one+from+table+1;+(id+is+numeric)+|code-block|syntax|javascript|1442427|抛出无效的数字异常|1442428|在这种情况下，您可以%7C%7C运算符，这是连接。|1442429|select+(id+%7C%7C+name)+as+one+from+table+1;|1442430|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|F|7|V|8|@]|9|@]|A|$G|H]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

if one of the column is number i have experienced the oracle will think '+' as sum operator instead concatenation. 

eg:

<pre><code>select (id + name) as one from table 1; (id is numeric) 
</code></pre>

throws invalid number exception

in such case you can || operator which is concatenation.

<pre><code>select (id || name) as one from table 1;
</code></pre>

blocks|key|5108725|text|您的语法应该有效，也许可以在列之间添加一个空格，如下所示|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5108726|SELECT+something+%2B+'+'+%2B+somethingElse+as+onlyOneColumn+FROM+someTable|offset|length|style|CODE|5108727|entityMap^0|0|0|1Y|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

Your syntax should work, maybe add a space between the colums like

<code>SELECT something + ' ' + somethingElse as onlyOneColumn FROM someTable</code>

blocks|key|1442475|text|我希望这个答案能有所帮助：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1442476|SELECT+(CAST(id+AS+NVARCHAR)%2B','%2Bname)+AS+COMBINED_COLUMN+FROM+TABLENAME;|code-block|syntax|javascript|1442477|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I hope this answer helps:

<pre><code>SELECT (CAST(id AS NVARCHAR)+','+name) AS COMBINED_COLUMN FROM TABLENAME;
</code></pre>

blocks|key|1442577|text|为了完成@Pete卡特的回答，我将在UNION上添加一个"ALL“(如果您需要保留重复的条目)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1442578|(从表中选择column1作为列)|1442579|联合所有|1442580|(从表中选择column2作为列)|1442581|+DROP+TABLE+IF+EXISTS+#9
++++CREATE+TABLE+#9+
(
++++USER1+int
++++,USER2+int
)
INSERT+INTO+#9
+VALUES(1,+2),+(1,+3),+(1,+4),+(2,+3)
+------------------------------------------------
(SELECT+USER1+AS+'column'+from+#9)
+UNION+ALL
+(SELECT+USER2+AS+'column'+from+#9)|code-block|syntax|javascript|1442582|然后返回：Result|offset|length|1442583|entityMap|0|LINK|mutability|MUTABLE|url|https://i.stack.imgur.com/MyWQ7.png^0|0|0|0|0|0|5|6|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Z|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|10|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|11|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|12|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|13|8|@]|9|@$O|14|P|15|1|16]]|A|$]]|$1|Q|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|R|$S|$5|T|U|V|A|$W|X]]]]

To complete the answer of @Pete Carter, I would add an &quot;ALL&quot; on the UNION (if you need to keep the duplicate entries).
(SELECT column1 as column FROM table )
UNION ALL
(SELECT column2 as column FROM table )
<pre><code> DROP TABLE IF EXISTS #9
 CREATE TABLE #9 
(
 USER1 int
 ,USER2 int
)
INSERT INTO #9
 VALUES(1, 2), (1, 3), (1, 4), (2, 3)
 ------------------------------------------------
(SELECT USER1 AS 'column' from #9)
 UNION ALL
 (SELECT USER2 AS 'column' from #9)
</code></pre>
Would then return : <a href="https://i.stack.imgur.com/MyWQ7.png" rel="nofollow noreferrer">Result</a>

blocks|key|2071713|text|select+column1+%7C%7C+'+'+%7C%7C+column2+as+whole_name+FROM+tablename;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2071714|这里，%7C%7C是用于将它们连接到单个列的concat运算符，而%7C%7C内部的('')用于两列之间的空格。|unstyled|offset|length|style|CODE|2071715|entityMap^0|0|3|2|T|2|Z|2|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]|$G|Q|H|R|I|J]|$G|S|H|T|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|U|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>select column1 || ' ' || column2 as whole_name FROM tablename;
</code></pre>

Here <code>||</code> is the concat operator used for concatenating them to single column and (<code>''</code>) inside <code>||</code> used for space between two columns.

blocks|key|3509166|text|SELECT+firstname+%7C%7C+'+'+%7C%7C+lastname+FROM+users;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3509167|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre class="lang-sql prettyprint-override"><code>SELECT firstname || ' ' || lastname FROM users;
</code></pre>

Is it possible to select 2 columns in just one and combine them?

Example: 

<code>select something + somethingElse as onlyOneColumn from someTable</code>

Select 2 columns in one and combine them

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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是否可以在一列中选择两列并将其组合？示例：select something + somethingElse as onlyOneColumn from someTable

问在一列中选择两列并将其合并
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问在一列中选择两列并将其合并EN

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问在一列中选择两列并将其合并
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