blocks|key|3603507|text|要删除该行并将输出打印到标准输出，请执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3603508|sed+'/pattern+to+match/d'+./infile|code-block|syntax|javascript|3603509|要直接修改文件-不适用于BSD+sed：|3603510|sed+-i+'/pattern+to+match/d'+./infile|3603511|相同，但适用于BSD+sed+(Mac和FreeBSD)+-不适用于GNU+sed：|3603512|sed+-i+''+'/pattern+to+match/d'+./infile|3603513|直接修改文件(并创建备份)-适用于BSD和GNU+sed：|3603514|sed+-i.bak+'/pattern+to+match/d'+./infile|3603515|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|Y|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

To remove the line and print the output to standard out:

<pre><code>sed '/pattern to match/d' ./infile
</code></pre>

To directly modify the file – does not work with BSD sed:

<pre><code>sed -i '/pattern to match/d' ./infile
</code></pre>

Same, but for BSD sed (Mac OS X and FreeBSD) – does not work with GNU sed:

<pre><code>sed -i '' '/pattern to match/d' ./infile
</code></pre>

To directly modify the file (and create a backup) – works with BSD and GNU sed:

<pre><code>sed -i.bak '/pattern to match/d' ./infile
</code></pre>

blocks|key|3603539|text|除了sed之外，还有许多其他方法可以删除带有特定字符串的行|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3603540|AWK|3603541|awk+'!/pattern/'+file+>+temp+&&+mv+temp+file|code-block|syntax|javascript|3603542|拼音(1.9%2B)|3603543|ruby+-i.bak+-ne+'print+if+not+/test/'+file|3603544|Perl|3603545|perl+-ni.bak+-e+"print+unless+/pattern/"+file|3603546|Shell+(bash+3.2及更高版本)|3603547|while+read+-r+line
do
++[[+!+$line+=~+pattern+]]+&&+echo+"$line"
done+<file+>+o
mv+o+file|3603548|GNU+grep|3603549|grep+-v+"pattern"+file+>+temp+&&+mv+temp+file|3603550|当然还有sed+(打印反转比实际删除更快)：|3603551|sed+-n+'/pattern/!p'+file|3603552|entityMap^0|2|3|0|0|0|0|0|0|0|0|0|0|0|4|3|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@$9|19|A|1A|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1B|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|1C|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1D|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|1E|8|@]|D|@]|E|$K|L]]|$1|Q|3|R|5|6|7|1F|8|@]|D|@]|E|$]]|$1|S|3|T|5|J|7|1G|8|@]|D|@]|E|$K|L]]|$1|U|3|V|5|6|7|1H|8|@]|D|@]|E|$]]|$1|W|3|X|5|J|7|1I|8|@]|D|@]|E|$K|L]]|$1|Y|3|Z|5|6|7|1J|8|@]|D|@]|E|$]]|$1|10|3|11|5|J|7|1K|8|@]|D|@]|E|$K|L]]|$1|12|3|13|5|6|7|1L|8|@$9|1M|A|1N|B|C]]|D|@]|E|$]]|$1|14|3|15|5|J|7|1O|8|@]|D|@]|E|$K|L]]|$1|16|3|-4|5|6|7|1P|8|@]|D|@]|E|$]]]|17|$]]

There are many other ways to delete lines with specific string besides <code>sed</code>:

<h3>AWK</h3>

<pre><code>awk '!/pattern/' file &gt; temp &amp;&amp; mv temp file
</code></pre>

<h3>Ruby (1.9+)</h3>

<pre><code>ruby -i.bak -ne 'print if not /test/' file
</code></pre>

<h3>Perl</h3>

<pre><code>perl -ni.bak -e "print unless /pattern/" file
</code></pre>

<h3>Shell (bash 3.2 and later)</h3>

<pre><code>while read -r line
do
 [[ ! $line =~ pattern ]] &amp;&amp; echo "$line"
done &lt;file &gt; o
mv o file
</code></pre>

<h3>GNU grep</h3>

<pre><code>grep -v "pattern" file &gt; temp &amp;&amp; mv temp file
</code></pre>

And of course <code>sed</code> (printing the inverse is faster than actual deletion):

<pre><code>sed -n '/pattern/!p' file
</code></pre>

blocks|key|5206179|text|您可以使用sed替换文件中的行。然而，它似乎比使用grep将倒数转换成第二个文件，然后将第二个文件移到原始文件上要慢得多。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5206180|例如：|5206181|sed+-i+'/pattern/d'+filename++++++|code-block|syntax|javascript|5206182|或|5206183|grep+-v+"pattern"+filename+>+filename2;+mv+filename2+filename|5206184|无论如何，第一个命令在我的机器上花费的时间要长3倍。|5206185|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

You can use sed to replace lines in place in a file. However, it seems to be much slower than using grep for the inverse into a second file and then moving the second file over the original.

e.g.

<pre><code>sed -i '/pattern/d' filename 
</code></pre>

or

<pre><code>grep -v "pattern" filename &gt; filename2; mv filename2 filename
</code></pre>

The first command takes 3 times longer on my machine anyway.

blocks|key|3603652|text|最简单的方法就是使用GNU+sed|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3603653|sed+--in-place+'/some+string+here/d'+yourfile|code-block|syntax|javascript|3603654|entityMap^0|E|3|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

The easy way to do it, with GNU <code>sed</code>:

<pre><code>sed --in-place '/some string here/d' yourfile
</code></pre>

blocks|key|5206336|text|我在Mac上为此而苦苦挣扎。另外，我需要使用变量替换。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5206337|所以我使用了：|5206338|sed+-i+''+"/$pattern/d"+$file|offset|length|style|CODE|5206339|其中，$file是需要删除的文件，$pattern是要匹配删除的模式。|5206340|我从这个comment中选择了''。|5206341|这里要注意的是在"/$pattern/d"中使用了双引号。当我们使用单引号时，变量将不起作用。|5206342|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/5410757/delete-a-line-containing-a-specific-string-using-sed#comment28307642_5410784^0|0|0|0|T|0|3|5|H|8|0|F|2|4|7|0|0|8|D|0^^$0|@$1|2|3|4|5|6|7|X|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Y|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|Z|8|@$F|10|G|11|H|I]]|9|@]|A|$]]|$1|J|3|K|5|6|7|12|8|@$F|13|G|14|H|I]|$F|15|G|16|H|I]]|9|@]|A|$]]|$1|L|3|M|5|6|7|17|8|@$F|18|G|19|H|I]]|9|@$F|1A|G|1B|1|1C]]|A|$]]|$1|N|3|O|5|6|7|1D|8|@$F|1E|G|1F|H|I]]|9|@]|A|$]]|$1|P|3|-4|5|6|7|1G|8|@]|9|@]|A|$]]]|Q|$R|$5|S|T|U|A|$V|W]]]]

I was struggling with this on Mac. Plus, I needed to do it using variable replacement.

So I used:

<code>sed -i '' "/$pattern/d" $file</code>

where <code>$file</code> is the file where deletion is needed and <code>$pattern</code> is the pattern to be matched for deletion.

I picked the <code>''</code> from this <a href="https://stackoverflow.com/questions/5410757/delete-a-line-containing-a-specific-string-using-sed#comment28307642_5410784">comment</a>.

The thing to note here is use of double quotes in <code>"/$pattern/d"</code>. Variable won't work when we use single quotes.

blocks|key|5206268|text|您还可以使用以下命令：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5206269|+grep+-v+'pattern'+filename|code-block|syntax|javascript|5206270|在这里，-v将只打印您的模式之外的其他内容(这意味着反转匹配)。|offset|length|style|CODE|5206271|entityMap^0|0|0|4|2|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

You can also use this:

<pre><code> grep -v 'pattern' filename
</code></pre>

Here <code>-v</code> will print only other than your pattern (that means invert match).

blocks|key|1536955|text|我用一个大约包含345,000行的文件做了一个小基准测试。在这种情况下，使用grep的方法似乎比使用sed方法快15倍左右。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1536956|我已经尝试了设置和不设置LC_ALL=C，它似乎没有明显改变时间。搜索字符串(CDGA_00004.pdbqt.gz.tar)位于文件中间的某个位置。|1536957|以下是命令和时间：|1536958|time+sed+-i+"/CDGA_00004.pdbqt.gz.tar/d"+/tmp/input.txt

real++++0m0.711s
user++++0m0.179s
sys+++++0m0.530s

time+perl+-ni+-e+'print+unless+/CDGA_00004.pdbqt.gz.tar/'+/tmp/input.txt

real++++0m0.105s
user++++0m0.088s
sys+++++0m0.016s

time+(grep+-v+CDGA_00004.pdbqt.gz.tar+/tmp/input.txt+>+/tmp/input.tmp;+mv+/tmp/input.tmp+/tmp/input.txt+)

real++++0m0.046s
user++++0m0.014s
sys+++++0m0.019s|code-block|syntax|javascript|1536959|entityMap^0|12|4|1E|3|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|W|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|X|8|@]|D|@]|E|$M|N]]|$1|O|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|P|$]]

I have made a small benchmark with a file which contains approximately 345 000 lines. The way with <code>grep</code> seems to be around 15 times faster than the <code>sed</code> method in this case.

I have tried both with and without the setting LC_ALL=C, it does not seem change the timings significantly. The search string (CDGA_00004.pdbqt.gz.tar) is somewhere in the middle of the file.

Here are the commands and the timings:

<pre><code>time sed -i "/CDGA_00004.pdbqt.gz.tar/d" /tmp/input.txt

real 0m0.711s
user 0m0.179s
sys 0m0.530s

time perl -ni -e 'print unless /CDGA_00004.pdbqt.gz.tar/' /tmp/input.txt

real 0m0.105s
user 0m0.088s
sys 0m0.016s

time (grep -v CDGA_00004.pdbqt.gz.tar /tmp/input.txt &gt; /tmp/input.tmp; mv /tmp/input.tmp /tmp/input.txt )

real 0m0.046s
user 0m0.014s
sys 0m0.019s
</code></pre>

blocks|key|5206298|text|要获得grep的原地like结果，您可以这样做：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5206299|echo+"$(grep+-v+"pattern"+filename)"+>filename|code-block|syntax|javascript|5206300|entityMap^0|3|4|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

To get a inplace like result with <code>grep</code> you can do this:

<pre><code>echo "$(grep -v "pattern" filename)" &gt;filename
</code></pre>

blocks|key|2119587|text|SED：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2119588|2119589|'/James\%7CJohn/d'|unordered-list-item|offset|length|style|CODE|2119590|-n+'/James\%7CJohn/!p'|2119591|2119592|AWK：|2119593|2119594|'!/James%7CJohn/'|2119595|/James%7CJohn/+{next;}+{print}|2119596|2119597|GREP：|2119598|2119599|-v+'James\%7CJohn'|2119600|2119601|entityMap|0|LINK|mutability|MUTABLE|url|http://sed.js.org/?gist=d9270c2789f1cc82a4898ad5a7297388|1|http://sed.js.org/?gist=0b78ac2ebeb4dc884083329ab09445ce|2|http://awk.js.org/?gist=b2d6c62828b0daf29d7cf9be3c9e34f5|3|4|http://grep.js.org/?gist=ba9b48ebf847e88fcf060e00ff45203f^0|0|0|0|G|0|G|0|0|0|K|0|K|1|0|0|0|0|0|F|0|F|2|0|0|S|0|S|3|0|0|0|0|0|G|0|G|4|0|0^^$0|@$1|2|3|4|5|6|7|1F|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|1G|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|1H|8|@$F|1I|G|1J|H|I]]|9|@$F|1K|G|1L|1|1M]]|A|$]]|$1|J|3|K|5|E|7|1N|8|@$F|1O|G|1P|H|I]]|9|@$F|1Q|G|1R|1|1S]]|A|$]]|$1|L|3|-4|5|6|7|1T|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|1U|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|1V|8|@]|9|@]|A|$]]|$1|P|3|Q|5|E|7|1W|8|@$F|1X|G|1Y|H|I]]|9|@$F|1Z|G|20|1|21]]|A|$]]|$1|R|3|S|5|E|7|22|8|@$F|23|G|24|H|I]]|9|@$F|25|G|26|1|27]]|A|$]]|$1|T|3|-4|5|6|7|28|8|@]|9|@]|A|$]]|$1|U|3|V|5|6|7|29|8|@]|9|@]|A|$]]|$1|W|3|-4|5|6|7|2A|8|@]|9|@]|A|$]]|$1|X|3|Y|5|E|7|2B|8|@$F|2C|G|2D|H|I]]|9|@$F|2E|G|2F|1|2G]]|A|$]]|$1|Z|3|-4|5|6|7|2H|8|@]|9|@]|A|$]]|$1|10|3|-4|5|6|7|2I|8|@]|9|@]|A|$]]]|11|$12|$5|13|14|15|A|$16|17]]|18|$5|13|14|15|A|$16|19]]|1A|$5|13|14|15|A|$16|1B]]|1C|$5|13|14|15|A|$16|1B]]|1D|$5|13|14|15|A|$16|1E]]]]

SED:

<ul>
<li><a href="http://sed.js.org/?gist=d9270c2789f1cc82a4898ad5a7297388" rel="noreferrer"><code>'/James\|John/d'</code></a></li>
<li><a href="http://sed.js.org/?gist=0b78ac2ebeb4dc884083329ab09445ce" rel="noreferrer"><code>-n '/James\|John/!p'</code></a></li>
</ul>

AWK:

<ul>
<li><a href="http://awk.js.org/?gist=b2d6c62828b0daf29d7cf9be3c9e34f5" rel="noreferrer"><code>'!/James|John/'</code></a></li>
<li><a href="http://awk.js.org/?gist=b2d6c62828b0daf29d7cf9be3c9e34f5" rel="noreferrer"><code>/James|John/ {next;} {print}</code></a></li>
</ul>

GREP:

<ul>
<li><a href="http://grep.js.org/?gist=ba9b48ebf847e88fcf060e00ff45203f" rel="noreferrer"><code>-v 'James\|John'</code></a></li>
</ul>

blocks|key|3603615|text|perl+-i++++-nle'/regexp/%7C%7Cprint'+file1+file2+file3
perl+-i.bk+-nle'/regexp/%7C%7Cprint'+file1+file2+file3|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3603616|第一个命令就地编辑文件(-i)。|unstyled|3603617|第二个命令做同样的事情，但是通过将.bk添加到文件名(可以将.bk更改为任何内容)来保留原始文件的副本或备份。|3603618|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>perl -i -nle'/regexp/||print' file1 file2 file3
perl -i.bk -nle'/regexp/||print' file1 file2 file3
</code></pre>

The first command edits the file(s) inplace (-i).

The second command does the same thing but keeps a copy or backup of the original file(s) by adding .bk to the file names (.bk can be changed to anything).

blocks|key|5206616|text|您还可以删除文件中的一系列行。例如，删除SQL文件中的存储过程。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5206617|sed+'/CREATE+PROCEDURE.*/,/END+;/d'+sqllines.sql|offset|length|style|CODE|5206618|这将删除CREATE+PROCEDURE和END；之间的所有行。|5206619|我已经用这个sed命令清理了很多sql文件。|5206620|entityMap^0|0|0|1C|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@$D|P|E|Q|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|R|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|S|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|M|$]]

You can also delete a range of lines in a file.
For example to delete stored procedures in a SQL file.
<code>sed '/CREATE PROCEDURE.*/,/END ;/d' sqllines.sql</code>
This will remove all lines between CREATE PROCEDURE and END ;.
I have cleaned up many sql files withe this sed command.

blocks|key|5206396|text|echo+-e+"/thing_to_delete\ndd\033:x\n"+%7C+vim+file_to_edit.txt|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5206397|entityMap^0|0|1P|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

<code>echo -e "/thing_to_delete\ndd\033:x\n" | vim file_to_edit.txt
</code>

blocks|key|3603819|text|以防有人想要精确匹配字符串，您可以在grep+-w中使用-w标志来表示整体。例如，如果要删除编号为11的行，但保留编号为111的行：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3603820|-bash-4.1$+head+file
1
11
111

-bash-4.1$+grep+-v+"11"+file
1

-bash-4.1$+grep+-w+-v+"11"+file
1
111|code-block|syntax|javascript|3603821|如果您想一次排除几个确切的模式，它还可以与-f标志一起使用。如果黑名单是一个文件，每行有几个模式，您想要从文件中删除：|3603822|grep+-w+-v+-f+blacklist+file|3603823|entityMap^0|S|2|0|0|L|2|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|P|$]]

Just in case someone wants to do it for exact matches of strings, you can use the <code>-w</code> flag in grep - w for whole. That is, for example if you want to delete the lines that have number 11, but keep the lines with number 111:

<pre><code>-bash-4.1$ head file
1
11
111

-bash-4.1$ grep -v "11" file
1

-bash-4.1$ grep -w -v "11" file
1
111
</code></pre>

It also works with the <code>-f</code> flag if you want to exclude several exact patterns at once. If "blacklist" is a file with several patterns on each line that you want to delete from "file":

<pre><code>grep -w -v -f blacklist file
</code></pre>

blocks|key|2119644|text|cat+filename+%7C+grep+-v+"pattern"+>+filename.1
mv+filename.1+filename|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2119645|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>cat filename | grep -v "pattern" &gt; filename.1
mv filename.1 filename
</code></pre>

blocks|key|2122530|text|在控制台中显示处理过的文本|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2122531|cat+filename+%7C+sed+'/text+to+remove/d'+|code-block|syntax|javascript|2122532|将处理过的文本保存到文件中|2122533|cat+filename+%7C+sed+'/text+to+remove/d'+>+newfile|2122534|将已处理的文本信息附加到现有文件|2122535|cat+filename+%7C+sed+'/text+to+remove/d'+>>+newfile|2122536|要处理已处理的文本，在这种情况下，请删除已删除的更多行|2122537|cat+filename+%7C+sed+'/text+to+remove/d'+%7C+sed+'/remove+this+too/d'+%7C+more|2122538|%7C+more将一次显示一个页面中的文本块。|offset|length|style|CODE|2122539|entityMap^0|0|0|0|0|0|0|0|0|0|6|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|12|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|14|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|16|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|18|8|@$U|19|V|1A|W|X]]|9|@]|A|$]]|$1|Y|3|-4|5|6|7|1B|8|@]|9|@]|A|$]]]|Z|$]]

to show the treated text in console

<pre><code>cat filename | sed '/text to remove/d' 
</code></pre>

to save treated text into a file 

<pre><code>cat filename | sed '/text to remove/d' &gt; newfile
</code></pre>

to append treated text info an existing file

<pre><code>cat filename | sed '/text to remove/d' &gt;&gt; newfile
</code></pre>

to treat already treated text, in this case remove more lines of what has been removed

<pre><code>cat filename | sed '/text to remove/d' | sed '/remove this too/d' | more
</code></pre>

the <code>| more</code> will show text in chunks of one page at a time.

blocks|key|2122615|text|奇怪的是，公认的答案实际上并没有直接回答这个问题。该问题询问使用sed替换字符串，但答案似乎预先假定了如何将任意字符串转换为正则表达式。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2122616|许多编程语言库都具有执行这种转换的功能，例如|2122617|python:+re.escape(STRING)
ruby:+Regexp.escape(STRING)
java:++Pattern.quote(STRING)|code-block|syntax|javascript|2122618|但是如何在命令行上做到这一点？|2122619|由于这是一个面向sed的问题，一种方法是使用sed本身：|2122620|sed+'s/$[\[/({.*%2B%5E$?]$/\\\1/g'|2122621|因此，给定一个任意字符串$STRING，我们可以编写如下内容：|2122622|re=$(sed+'s/$[\[({.*%2B%5E$?]$/\\\1/g'+<<<+"$STRING")
sed+"/$re/d"+FILE|2122623|或者作为一行代码：|2122624|+sed+"/$(sed+'s/$[\[/({.*%2B%5E$?]$/\\\1/g'+<<<+"$STRING")/d"+|2122625|具有本页其他地方描述的变体。|2122626|entityMap^0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|11|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|12|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|13|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|14|8|@]|9|@]|A|$]]|$1|M|3|N|5|F|7|15|8|@]|9|@]|A|$G|H]]|$1|O|3|P|5|6|7|16|8|@]|9|@]|A|$]]|$1|Q|3|R|5|F|7|17|8|@]|9|@]|A|$G|H]]|$1|S|3|T|5|6|7|18|8|@]|9|@]|A|$]]|$1|U|3|V|5|F|7|19|8|@]|9|@]|A|$G|H]]|$1|W|3|X|5|6|7|1A|8|@]|9|@]|A|$]]|$1|Y|3|-4|5|6|7|1B|8|@]|9|@]|A|$]]]|Z|$]]

Curiously enough, the accepted answer does not actually answer the question directly. The question asks about using sed to replace a string, but the answer seems to presuppose knowledge of how to convert an arbitrary string into a regex.
Many programming language libraries have a function to perform such a transformation, e.g.
<pre><code>python: re.escape(STRING)
ruby: Regexp.escape(STRING)
java: Pattern.quote(STRING)
</code></pre>
But how to do it on the command line?
Since this is a sed-oriented question, one approach would be to use sed itself:
<pre><code>sed 's/$[\[/({.*+^$?]$/\\\1/g'
</code></pre>
So given an arbitrary string $STRING we could write something like:
<pre><code>re=$(sed 's/$[\[({.*+^$?]$/\\\1/g' &lt;&lt;&lt; &quot;$STRING&quot;)
sed &quot;/$re/d&quot; FILE
</code></pre>
or as a one-liner:
<pre><code> sed &quot;/$(sed 's/$[\[/({.*+^$?]$/\\\1/g' &lt;&lt;&lt; &quot;$STRING&quot;)/d&quot; 
</code></pre>
with variations as described elsewhere on this page.

blocks|key|3604125|text|从匹配匹配的所有文件中删除行|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3604126|grep+-rl+'text_to_search'+.+%7C+xargs+sed+-i+'/text_to_search/d'|code-block|syntax|javascript|3604127|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Delete lines from all files that match the match
<pre><code>grep -rl 'text_to_search' . | xargs sed -i '/text_to_search/d'
</code></pre>

blocks|key|2119669|text|您可以使用传统的ed以类似于使用ex的the+answer的方式编辑文件。在这种情况下，最大的区别是ed通过标准输入接受命令，而不是像ex那样作为命令行参数。当在脚本中使用它时，通常的方法是使用printf将命令传递给它：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2119670|printf+"%25s\n"+"g/pattern/d"+w+%7C+ed+-s+filename|code-block|syntax|javascript|2119671|或者使用以下文档：|2119672|ed+-s+filename+<<EOF
g/pattern/d
w
EOF|2119673|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/33186317/9952196^0|8|2|G|2|1E|2|1V|2|2P|6|J|A|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]|$9|13|A|14|B|C]|$9|15|A|16|B|C]]|D|@$9|17|A|18|1|19]]|E|$]]|$1|F|3|G|5|H|7|1A|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1B|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|1C|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|1D|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

You can use good old <code>ed</code> to edit a file in a similar fashion to <a href="https://stackoverflow.com/a/33186317/9952196">the answer</a> that uses <code>ex</code>. The big difference in this case is that <code>ed</code> takes its commands via standard input, not as command line arguments like <code>ex</code> can. When using it in a script, the usual way to accomodate this is to use <code>printf</code> to pipe commands to it:

<pre><code>printf "%s\n" "g/pattern/d" w | ed -s filename
</code></pre>

or with a heredoc:

<pre><code>ed -s filename &lt;&lt;EOF
g/pattern/d
w
EOF
</code></pre>

blocks|key|1537196|text|我发现大多数答案对我来说都没有用，如果你使用vim，我发现这非常简单和直接：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1537197|:g/<pattern>/d|offset|length|style|CODE|1537198|Source|1537199|entityMap|0|LINK|mutability|MUTABLE|url|https://vim.fandom.com/wiki/Delete_all_lines_containing_a_pattern^0|0|0|E|0|0|6|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@$D|T|E|U|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|V|8|@]|9|@$D|W|E|X|1|Y]]|A|$]]|$1|J|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|K|$L|$5|M|N|O|A|$P|Q]]]]

I found most of the answers not useful for me, If you use vim I found this very easy and straightforward:
<code>:g/&lt;pattern&gt;/d</code>
<a href="https://vim.fandom.com/wiki/Delete_all_lines_containing_a_pattern" rel="nofollow noreferrer">Source</a>

How would I use sed to delete all lines in a text file that contain a specific string?

How to delete from a text file, all lines that contain a specific string?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如何使用sed删除文本文件中包含特定字符串的所有行？

问如何从文本文件中删除包含特定字符串的所有行？
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