以下是我用来从应用程序中的摄像头捕获图像的代码
public void startCamera()
{
Log.d("ANDRO_CAMERA", "Starting camera on the phone...");
String fileName = "testphoto.jpg";
ContentValues values = new ContentValues();
values.put(MediaStore.Images.Media.TITLE, fileName);
values.put(MediaStore.Images.Media.DESCRIPTION,"Image capture by camera");
values.put(MediaStore.Images.Media.MIME_TYPE, "image/jpeg");
imageUri = getContentResolver().insert(MediaStore.Images.Media.EXTERNAL_CONTENT_URI, values);
Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
intent.putExtra(MediaStore.EXTRA_OUTPUT, imageUri);
intent.putExtra(MediaStore.EXTRA_VIDEO_QUALITY, 1);
startActivityForResult(intent, IMAGE_CAPTURE);
}
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
if (requestCode == IMAGE_CAPTURE)
{
if (resultCode == RESULT_OK)
{
Log.d("ANDRO_CAMERA","Picture taken!!!");
imageView.setImageURI(imageUri);
}
}
}捕获图像后,当我选择insert时,它将存储在内存中,但我希望将其发送到一个URL,并希望在另一个活动中查看它。
如何做到这一点请帮助我...
发布于 2011-04-05 19:52:15
您需要图像的URL。
public void startCamera(){
Intent cameraIntent = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE);
startActivityForResult(cameraIntent, CAMERA_PIC_REQUEST);
}
Uri selectedImageUri;
private static final int CAMERA_PIC_REQUEST = 1337;
@Override
public void onActivityResult(int requestCode, int resultCode, Intent intent){
if (requestCode == CAMERA_PIC_REQUEST) {
selectedImageUri = Intent.getData();
} 您将获得SelectedImageURI格式的URI,然后可以使用Intent.putExtra();发送该URI
这对我很有效。
https://stackoverflow.com/questions/5551224
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