blocks|key|2334834|text|你没有播种你的随机生成器。您应该在所有对next的调用中共享相同的随机实例：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2334835|var+randomGenerator+=+new+Random(DateTime.Now.Milliseconds);|code-block|syntax|javascript|2334836|然后，只需调用一个生成器：|2334837|dp.x+=+randomGenerator.Next(0000,+9999);
dp.y+=+randomGenerator.Next(0000,+9999);|2334838|通过这种方式，您已经为生成器设定了种子，并且每次调用next都应该生成一个新的“随机”数。|2334839|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

You are not seeding your random generator. You should be sharing the same random instance across all calls to next:

<pre><code>var randomGenerator = new Random(DateTime.Now.Milliseconds);
</code></pre>

Then, just call the one generator:

<pre><code>dp.x = randomGenerator.Next(0000, 9999);
dp.y = randomGenerator.Next(0000, 9999);
</code></pre>

This way, you've both seeded the generator with something, and each call to next should generate a new 'random' number.

blocks|key|334222|text|您在每次迭代中实例化一个新的Random()。由于循环进行得如此之快，每个Random()对象基本上都以相同的值开始，这将产生相同的结果。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|334223|将您的代码更改为类似于：|334224|public+List<candle>+Getcandles(int+can)+++++{
+++++List<candle>+dpl+=+new+List<candle>();
++++++Random+generator+=+new+Random();

++++++for+(int+i+=+0;+i+<+can;+i%2B%2B)+++++++++{
+++++++++candle+dp+=+new+candle();
+++++++++dp.x+=+generator.Next(0000,+9999);
+++++++++dp.y+=+generator.Next(0000,+9999);
+++++++++dpl.Add(dp);
+++++++}
++++++return+dpl;
++}+|code-block|syntax|javascript|334225|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Your instantiating a new Random() on each iteration. Because the loop is going so fast each Random() object is basically starting with the same value which is going to yield identical results.

Change your code to something like:

<pre><code>public List&lt;candle&gt; Getcandles(int can) {
 List&lt;candle&gt; dpl = new List&lt;candle&gt;();
 Random generator = new Random();

 for (int i = 0; i &lt; can; i++) {
 candle dp = new candle();
 dp.x = generator.Next(0000, 9999);
 dp.y = generator.Next(0000, 9999);
 dpl.Add(dp);
 }
 return dpl;
 } 
</code></pre>

blocks|key|1953787|text|System.Random()：来自MSDN|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1953788|1953789|使用与时间相关的默认种子值初始化Random类的新实例|blockquote|1953790|1953791|1953792|没有调试器，你就太快了。|1953793|试试这个：|1953794|public+List<candle>+Getcandles(int+can)
{
++++List<candle>+dpl+=+new+List<candle>();
++++var+rnd+=+new+Random(DateTime.Now.Milliseconds);
++++for+(int+i+=+0;+i+<+can;+i%2B%2B)
++++{
++++++++candle+dp+=+new+candle();
++++++++dp.x+=+rnd.Next(0000,+9999);
++++++++dp.y+=+rnd.Next(0000,+9999);++++++++++++++
++++++++dpl.Add(dp);++++++++++++++++

++++}

++++return+dpl;

}|code-block|syntax|javascript|1953795|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|T|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|U|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|V|8|@]|9|@]|A|$]]|$1|G|3|-4|5|6|7|W|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|X|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|Y|8|@]|9|@]|A|$]]|$1|L|3|M|5|N|7|Z|8|@]|9|@]|A|$O|P]]|$1|Q|3|-4|5|6|7|10|8|@]|9|@]|A|$]]]|R|$]]

System.Random(): From MSDN

<blockquote>
 Initializes a new instance of the
 Random class, using a time-dependent
 default seed value
</blockquote>

without the debugger you are too fast.

try this:

<pre><code>public List&lt;candle&gt; Getcandles(int can)
{
 List&lt;candle&gt; dpl = new List&lt;candle&gt;();
 var rnd = new Random(DateTime.Now.Milliseconds);
 for (int i = 0; i &lt; can; i++)
 {
 candle dp = new candle();
 dp.x = rnd.Next(0000, 9999);
 dp.y = rnd.Next(0000, 9999); 
 dpl.Add(dp); 

 }

 return dpl;

}
</code></pre>

blocks|key|2334880|text|将新的Random()放在for循环之外。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2334881|++++public+List<candle>+Getcandles(int+can)
++++{
++++++++List<candle>+dpl+=+new+List<candle>();
++++++++var+random+=new+Random()+

++++++++for+(int+i+=+0;+i+<+can;+i%2B%2B)
++++++++{
++++++++++++candle+dp+=+new+candle();
++++++++++++dp.x+=+random+.Next(0000,+9999);
++++++++++++dp.y+=+random+.Next(0000,+9999);++++++++++++++
++++++++++++dpl.Add(dp);++++++++++++++++

++++++++}

++++++++return+dpl;

++++}|code-block|syntax|javascript|2334882|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Take the new Random() outside the for loop. 

<pre><code> public List&lt;candle&gt; Getcandles(int can)
 {
 List&lt;candle&gt; dpl = new List&lt;candle&gt;();
 var random =new Random() 

 for (int i = 0; i &lt; can; i++)
 {
 candle dp = new candle();
 dp.x = random .Next(0000, 9999);
 dp.y = random .Next(0000, 9999); 
 dpl.Add(dp); 

 }

 return dpl;

 }
</code></pre>

I'm trying to create a new instance of a custom object inside a for loop, if i add a breakpoint i can see the object and properties changing and it returns x number of DIFFERENT candle objects. However, if i remove the breakpoint all the objects returned in the List are the same. Any ideas?

Thanks

<pre><code> public List&lt;candle&gt; Getcandles(int can)
 {
 List&lt;candle&gt; dpl = new List&lt;candle&gt;();

 for (int i = 0; i &lt; can; i++)
 {
 candle dp = new candle();
 dp.x = new Random().Next(0000, 9999);
 dp.y = new Random().Next(0000, 9999); 
 dpl.Add(dp); 

 }

 return dpl;

 }
</code></pre>

c# creating new instances of a object in a for loop

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我试图在for循环中创建一个自定义对象的新实例，如果我添加一个断点，我可以看到对象和属性发生了变化，它返回了x个不同的candle对象。但是，如果我删除断点，列表中返回的所有对象都是相同的。有什么想法吗？谢谢 public List<candle> Getcandles(int can) { ...

问在c#循环中创建对象的新实例
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