blocks|key|2364498|text|像这样的东西应该是有效的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2364499|<%25=+link_to+"Back+to+#{@post.author.name}+page",+@post.author+%25>|code-block|syntax|javascript|2364500|这是在假设您有一个具有post数据和author+belongs_to+post的实例变量@post的情况下工作的。|offset|length|style|CODE|2364501|当然，更详细的方法是显式地声明路由，如下所示：|2364502|<%25=+link_to+"Back+to+#{@post.author.name}+page",+author_path(@post.author)+%25>|2364503|entityMap^0|0|0|19|5|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

Something like this should work:

<pre><code>&lt;%= link_to "Back to #{@post.author.name} page", @post.author %&gt;
</code></pre>

This is working under the assumption that you have a instance variable <code>@post</code> that has the post data, and author belongs_to post.

Of course a more verbose way is to explicitly state the route like so:

<pre><code>&lt;%= link_to "Back to #{@post.author.name} page", author_path(@post.author) %&gt;
</code></pre>

blocks|key|4087999|text|<%25=+link_to+"Back+to+author+#{@author.name}",+author_path(@author)+%25>|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4088000|假设@author是Author对象|unstyled|4088001|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>&lt;%= link_to "Back to author #{@author.name}", author_path(@author) %&gt;
</code></pre>

assuming @author is Author object

blocks|key|4088037|text|你需要有一个特定作者的链接。authors_path是指向作者控制器(列出所有作者)的索引操作的路径。你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4088038|<%25=+link_to+@author.name,+author_path(@author.id)+%25>|code-block|syntax|javascript|4088039|或者，更简洁地说：|4088040|<%25=+link_to+@author.name,+@author+%25>|4088041|这将给出作者控制器的show操作的路径。|4088042|有关更多信息，请查看http://guides.rubyonrails.org/routing.html+(其他指南也很不错)。|offset|length|4088043|编辑:与前面提到的其他答案一样，假设@author是您的Author对象。|4088044|entityMap|0|LINK|mutability|MUTABLE|url|http://guides.rubyonrails.org/routing.html^0|0|0|0|0|0|A|16|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|12|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|14|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|15|8|@]|9|@$O|16|P|17|1|18]]|A|$]]|$1|Q|3|R|5|6|7|19|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|1A|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|Z]]]]

You need to have a link to the specific author. authors_path is the path to the index action for the Authors controller (which lists all authors). You can do it as:

<pre><code>&lt;%= link_to @author.name, author_path(@author.id) %&gt;
</code></pre>

or, more succinctly:

<pre><code>&lt;%= link_to @author.name, @author %&gt;
</code></pre>

That will give the path to the show action for the Authors controller.

Check out <a href="http://guides.rubyonrails.org/routing.html" rel="nofollow">http://guides.rubyonrails.org/routing.html</a> (and the other guides are good) for more info.

Edit: Like other answers mentioned, assuming @author is your Author object.

I am new to rails and I am creating a basic blog application.

When I have created a post it has an author. If you locate the author it displays a list of posts that have been created by that author on their own individual page. Each of these links can be selected. 

I want to now create a link on each post page which displays the name of the author and then allows you to select this and go back to the author's individual page.

So far I have added the following code to the pages view:

<pre><code>&lt;%= link_to 'Back to List of Authors', authors_path %&gt;
</code></pre>

I'm now not sure how to change it so that instead if saying <code>'Back to List of Authors'</code> it displays the authors name and allows it to be selected and takes the user back to the author's individual page. Currently it takes you back to the complete list of authors and not in individual author. 

Any advice will be appreciated.

Linking in Rails

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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