blocks|key|4195107|text|这可能不是一个好方法，但这是我的第一个想法，我真的很累。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4195108|将所有日期放入一个数组中。date对象必须具有日期名称(星期一)。创建一个搜索数组的方法，当您遇到星期天时，将周计数器加1。一旦你找到你要找的日期，返回周计数器。这是一年中这一天所在的星期。对于一个月中的一周，您必须在每个月的最后一天重置周计数器。|4195109|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

This is probably not a good way to do this but it's my first thought and I'm really tired.

Put all your dates into an array. The date object must have a day name (Monday). Create a method that searches the array and when ever you hit a Sunday you add 1 to a week counter. Once you find the date you're looking for return the week counter. That is the week the day falls in of the year. For the week in the month you have to reset the week counter every time you get to the last day in each month.

blocks|key|2417811|text|这是我尝试过的最令人沮丧的事情--但它就在这里！|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2417812|<?php

++++/**
+++++*+Returns+the+amount+of+weeks+into+the+month+a+date+is
+++++*+@param+$date+a+YYYY-MM-DD+formatted+date
+++++*+@param+$rollover+The+day+on+which+the+week+rolls+over
+++++*/
++++function+getWeeks($date,+$rollover)
++++{
++++++++$cut+=+substr($date,+0,+8);
++++++++$daylen+=+86400;

++++++++$timestamp+=+strtotime($date);
++++++++$first+=+strtotime($cut+.+"00");
++++++++$elapsed+=+($timestamp+-+$first)+/+$daylen;

++++++++$weeks+=+1;

++++++++for+($i+=+1;+$i+<=+$elapsed;+$i%2B%2B)
++++++++{
++++++++++++$dayfind+=+$cut+.+(strlen($i)+<+2+?+'0'+.+$i+:+$i);
++++++++++++$daytimestamp+=+strtotime($dayfind);

++++++++++++$day+=+strtolower(date("l",+$daytimestamp));

++++++++++++if($day+==+strtolower($rollover))++$weeks+%2B%2B;
++++++++}

++++++++return+$weeks;
++++}


++++//
++++echo+getWeeks("2011-06-11",+"sunday");+//outputs+2,+for+the+second+week+of+the+month
?>|code-block|syntax|javascript|2417813|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The most frustrating thing I have ever tried to get working - but here it is!

<pre><code>&lt;?php

 /**
 * Returns the amount of weeks into the month a date is
 * @param $date a YYYY-MM-DD formatted date
 * @param $rollover The day on which the week rolls over
 */
 function getWeeks($date, $rollover)
 {
 $cut = substr($date, 0, 8);
 $daylen = 86400;

 $timestamp = strtotime($date);
 $first = strtotime($cut . "00");
 $elapsed = ($timestamp - $first) / $daylen;

 $weeks = 1;

 for ($i = 1; $i &lt;= $elapsed; $i++)
 {
 $dayfind = $cut . (strlen($i) &lt; 2 ? '0' . $i : $i);
 $daytimestamp = strtotime($dayfind);

 $day = strtolower(date("l", $daytimestamp));

 if($day == strtolower($rollover)) $weeks ++;
 }

 return $weeks;
 }


 //
 echo getWeeks("2011-06-11", "sunday"); //outputs 2, for the second week of the month
?&gt;
</code></pre>

blocks|key|4195176|text|这是我为满足同样的需求而制作的代码片段。希望这能对你有所帮助。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4195177|function+getWeek($timestamp)+{
+$week_year+=+date('W',$timestamp);
+$week+=+0;//date('d',$timestamp)/7;
+$year+=+date('Y',$timestamp);
+$month+=+date('m',$timestamp);
+$day+=+date('d',$timestamp);
+$prev_month+=+date('m',$timestamp)+-1;
if($month+!=+1+){
++++$last_day_prev+=+$year."-".$prev_month."-1";
++++$last_day_prev+=+date('t',strtotime($last_day_prev));
++++$week_year_last_mon+=+date('W',strtotime($year."-".$prev_month."-".$last_day_prev));
++++$week_year_first_this+=+date('W',strtotime($year."-".$month."-1"));
++++if($week_year_first_this+==+$week_year_last_mon){
++++++++$week_diff+=+0;
++++}
++++else{
++++++++$week_diff+=+1;
++++}
++++if($week_year+==1+&&+$month+==+12+){
++++//+to+handle+December's+last+two+days+coming+in+first+week+of+January
++++++++$week_year+=+53;
++++}
++++$week+=+$week_year-$week_year_last_mon+%2B+1+%2B$week_diff;
}
else{
+//+to+handle+first+three+days+January+coming+in+last+week+of+December.
++++$week_year_first_this+=+date('W',strtotime($year."-01-1"));
++++if($week_year_first_this+==52+%7C%7C+$week_year_first_this+==53){
++++++++if($week_year+==+52+%7C%7C+$week_year+==+53){
++++++++++++$week+=1;
++++++++}
++++++++else{
++++++++++++$week+=+$week_year+%2B+1;
++++++++}
++++}
++++else{
++++++++$week+=+$week_year;
++++}
}
return+$week;|code-block|syntax|javascript|4195178|}|4195179|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

This is the snippet that I made to fulfill my requirements for the same. Hope this will help you.

<pre><code>function getWeek($timestamp) {
 $week_year = date('W',$timestamp);
 $week = 0;//date('d',$timestamp)/7;
 $year = date('Y',$timestamp);
 $month = date('m',$timestamp);
 $day = date('d',$timestamp);
 $prev_month = date('m',$timestamp) -1;
if($month != 1 ){
 $last_day_prev = $year."-".$prev_month."-1";
 $last_day_prev = date('t',strtotime($last_day_prev));
 $week_year_last_mon = date('W',strtotime($year."-".$prev_month."-".$last_day_prev));
 $week_year_first_this = date('W',strtotime($year."-".$month."-1"));
 if($week_year_first_this == $week_year_last_mon){
 $week_diff = 0;
 }
 else{
 $week_diff = 1;
 }
 if($week_year ==1 &amp;&amp; $month == 12 ){
 // to handle December's last two days coming in first week of January
 $week_year = 53;
 }
 $week = $week_year-$week_year_last_mon + 1 +$week_diff;
}
else{
 // to handle first three days January coming in last week of December.
 $week_year_first_this = date('W',strtotime($year."-01-1"));
 if($week_year_first_this ==52 || $week_year_first_this ==53){
 if($week_year == 52 || $week_year == 53){
 $week =1;
 }
 else{
 $week = $week_year + 1;
 }
 }
 else{
 $week = $week_year;
 }
}
return $week;
</code></pre>

}

blocks|key|2121386|text|Python:+Number+of+the+Week+in+a+Month|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2121387|这是一个用Python编写的工作示例--应该很容易转换。|2121388|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/7029261/python-number-of-the-week-in-a-month/7029955#7029955^0|0|11|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@$A|O|B|P|1|Q]]|C|$]]|$1|D|3|E|5|6|7|R|8|@]|9|@]|C|$]]|$1|F|3|-4|5|6|7|S|8|@]|9|@]|C|$]]]|G|$H|$5|I|J|K|C|$L|M]]]]

<a href="https://stackoverflow.com/questions/7029261/python-number-of-the-week-in-a-month/7029955#7029955">Python: Number of the Week in a Month</a>

This is a worked example in Python - should be simple to convert.

blocks|key|4195253|text|Srahul07的解决方案非常有效...如果你遵守周一至周日的工作周制度！在这里'murica，非商业人士倾向于周日-周六是一周，所以2011年5月1日是第1周，2011年5月2日仍然是第1周。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4195254|将以下逻辑添加到他的函数的底部，就在它返回$week之前，它会将其转换为周日->星期一系统：|4195255|if+(!date('w',strtotime("$year-$month-01"))+&&+date('w',$timestamp))
++++$week--;
elseif+(date('w',strtotime("$year-$month-01"))+&&+!date('w',$timestamp))
++++$week%2B%2B;|code-block|syntax|javascript|4195256|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Srahul07's solution works perfectly... If you abide by the Monday-Sunday week system! Here in 'murica, non-business folk tend to go by Sunday-Saturday being a week, so May 1, 2011 is week 1 and May 2, 2011 is still week 1.

Adding the following logic to the bottom of his function, right before it returns $week will convert this to a Sunday -> Monday system:

<pre><code>if (!date('w',strtotime("$year-$month-01")) &amp;&amp; date('w',$timestamp))
 $week--;
elseif (date('w',strtotime("$year-$month-01")) &amp;&amp; !date('w',$timestamp))
 $week++;
</code></pre>

blocks|key|4195278|text|这种方法有一个问题。如果经过的日期(假设2012/01/01是星期天)并且"$rollover“日是”星期天“，则此函数将返回2.其中它实际上是第1周。我想我已经在下面的函数中修复了它。请添加评论以使其更好。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4195279|function+getWeeks($date,+$rollover)
{
++++$cut++++++++=+substr($date,+0,+8);
++++$daylen+++++=+86400;
++++$timestamp++=+strtotime($date);
++++$first++++++=+strtotime($cut+.+"01");+++
++++$elapsed++++=+(($timestamp+-+$first)+/+$daylen)%2B1;
++++$i++++++++++=+1;
++++$weeks++++++=+0;
++++for($i==1;+$i<=$elapsed;+$i%2B%2B)
++++{
++++++++$dayfind++++++++=+$cut+.+(strlen($i)+<+2+?+'0'+.+$i+:+$i);
++++++++$daytimestamp+++=+strtotime($dayfind);
++++++++$day++++++++++++=+strtolower(date("l",+$daytimestamp));
++++++++if($day+==+strtolower($rollover))
++++++++{
++++++++++++$weeks%2B%2B;++
++++++++}
++++}+
++++if($weeks==0)
++++{
++++++++$weeks%2B%2B;+
++++}
++++return+$weeks;++
}|code-block|syntax|javascript|4195280|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

there is a problem with this method. if the passing date (Lets say 2012/01/01 which is a Sunday) and "$rollover" day is "Sunday", then this function will return 2. where its actually is 1'st week. i think i have fixed it in following function. 
please add comments to make it better.

<pre><code>function getWeeks($date, $rollover)
{
 $cut = substr($date, 0, 8);
 $daylen = 86400;
 $timestamp = strtotime($date);
 $first = strtotime($cut . "01"); 
 $elapsed = (($timestamp - $first) / $daylen)+1;
 $i = 1;
 $weeks = 0;
 for($i==1; $i&lt;=$elapsed; $i++)
 {
 $dayfind = $cut . (strlen($i) &lt; 2 ? '0' . $i : $i);
 $daytimestamp = strtotime($dayfind);
 $day = strtolower(date("l", $daytimestamp));
 if($day == strtolower($rollover))
 {
 $weeks++; 
 }
 } 
 if($weeks==0)
 {
 $weeks++; 
 }
 return $weeks; 
}
</code></pre>

blocks|key|2406520|text|我找到了一种简单的方法来确定今天是一个月中的哪一周，这将是一个很小的改变，让它在任何其他日期都可以工作。我在这里补充我的两点意见，因为我认为我的方法比所列出的方法更紧凑。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2406521|$monthstart+=+date("N",strtotime(date("n/1/Y")));
$date+=(+date("j")%2B$monthstart+)+/7;
$ddate=+floor(+$date+);
if($ddate+!=+date)+{$ddate%2B%2B;}|code-block|syntax|javascript|2406522|$ddate包含周数，您可以像这样修改它|2406523|function+findweek($indate)
{
++$monthstart+=+date("N",strtotime(date("n/1/Y",strtotime($indate))));
++$date+=(+date("j",strtotime($indate))%2B$monthstart+)+/7;
++$ddate=+floor(+$date+);
++if($ddate+!=+$date)+{$ddate%2B%2B;}
++return+$ddate;
}|2406524|它将返回您给出的日期是一个月中的第几周。它所做的是首先找出从一周的开始到这个月的第一天的天数。然后将其与当前日期相加，然后将新日期除以7，这将得出自本月初以来经过了多少周，包括当前周已过去的部分的小数位。所以我接下来要做的是向下舍入这个数字，然后将向下舍入的版本与原始版本进行比较，如果两个版本在周末与您的匹配，那么它就已经在这个数字中了。如果没有，那么只需在四舍五入的数字上加一，就得到了当前的周数字。|2406525|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

I found a easy way to determine what week of the month today is in, and it would be a small change to have it work on any other date. I'm adding my two cents in here as I think my way is much more compact then the methods listed.

<pre><code>$monthstart = date("N",strtotime(date("n/1/Y")));
$date =( date("j")+$monthstart ) /7;
$ddate= floor( $date );
if($ddate != date) {$ddate++;}
</code></pre>

and $ddate contains the week number you could modify it like so

<pre><code>function findweek($indate)
{
 $monthstart = date("N",strtotime(date("n/1/Y",strtotime($indate))));
 $date =( date("j",strtotime($indate))+$monthstart ) /7;
 $ddate= floor( $date );
 if($ddate != $date) {$ddate++;}
 return $ddate;
}
</code></pre>

and it would return what week of the month any date you give it is.
what it does is first find the number of days from the start of the week to the first of the month. then adds that on to the current date then divides the new date by 7 and that will give you how many weeks have passed since the start of the month, including a decimal place for the part of the the current week that has passed. so what I do next is round down that number, then compare the rounded down version to the original if the two match your at the end of the week so it's already in the number. if they don't then just add one to the rounded down number and voila you have the current week number.

blocks|key|4195399|text|public+function+getWeeks($timestamp)
{
++++$maxday++++=+date("t",$timestamp);
++++$thismonth+=+getdate($timestamp);
++++$timeStamp+=+mktime(0,0,0,$thismonth['mon'],1,$thismonth['year']);++++//Create+time+stamp+of+the+first+day+from+the+give+date.
++++$startday++=+date('w',$timeStamp);++++//get+first+day+of+the+given+month
++++$day+=+$thismonth['mday'];
++++$weeks+=+0;
++++$week_num+=+0;

++++for+($i=0;+$i<($maxday%2B$startday);+$i%2B%2B)+{
++++++++if(($i+%25+7)+==+0){
++++++++++++$weeks%2B%2B;
++++++++}
++++++++if($day+==+($i+-+$startday+%2B+1)){
++++++++++++$week_num+=+$weeks;
++++++++}
++++++}+++++
++++return+$week_num;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4195400|大家好，我已经挣扎了一整天，试图弄清楚这段代码，我终于弄明白了，所以我想我应该和大家分享一下。|unstyled|4195401|您所需要做的就是在函数中添加一个时间戳，它会将星期数返回给您。|4195402|谢谢|4195403|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|F|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>public function getWeeks($timestamp)
{
 $maxday = date("t",$timestamp);
 $thismonth = getdate($timestamp);
 $timeStamp = mktime(0,0,0,$thismonth['mon'],1,$thismonth['year']); //Create time stamp of the first day from the give date.
 $startday = date('w',$timeStamp); //get first day of the given month
 $day = $thismonth['mday'];
 $weeks = 0;
 $week_num = 0;

 for ($i=0; $i&lt;($maxday+$startday); $i++) {
 if(($i % 7) == 0){
 $weeks++;
 }
 if($day == ($i - $startday + 1)){
 $week_num = $weeks;
 }
 } 
 return $week_num;
}
</code></pre>

Hello all i have been struggling for the whole day trying to figure this code out, i finally figured it out so i thought i would share it with you all.

all you need to do is put a time stamp into the function and it will return the week number back to you.

thanks

blocks|key|2417900|text|编辑:这就是“单行”所需的变量，以避免与条件的重新计算。当我在它的时候抛出了一个默认的参数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2417901|function+weekOfMonth($when+=+null)+{
++++if+($when+===+null)+$when+=+time();
++++$week+=+date('W',+$when);+//+note+that+ISO+weeks+start+on+Monday
++++$firstWeekOfMonth+=+date('W',+strtotime(date('Y-m-01',+$when)));
++++return+1+%2B+($week+<+$firstWeekOfMonth+?+$week+:+$week+-+$firstWeekOfMonth);
}|code-block|syntax|javascript|2417902|请注意，weekOfMonth(strtotime('Oct+31,+2011'));将返回6；一些罕见的月份有6周，这与OP的预期相反。2017年1月是另一个具有6个ISO周的月份-周日是去年一周的第一个秋季，因为ISO周从周一开始。|offset|length|style|CODE|2417903|对于starshine531，要返回0索引的当月周，请将return+1+%2B更改为return+0+%2B或return+(int)。|2417904|对于Justin+Stayton，从周日而不是周一开始的几周内，我会使用strftime('%25U'而不是date('W'，如下所示：|2417905|function+weekOfMonth($when+=+null)+{
++++if+($when+===+null)+$when+=+time();
++++$week+=+strftime('%25U',+$when);+//+weeks+start+on+Sunday
++++$firstWeekOfMonth+=+strftime('%25U',+strtotime(date('Y-m-01',+$when)));
++++return+1+%2B+($week+<+$firstWeekOfMonth+?+$week+:+$week+-+$firstWeekOfMonth);
}|2417906|对于此版本，2017-04-30现在是4月的第6周，而2017-01-31现在是第5周。|2417907|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/5853380/php-get-number-of-week-for-month/13167228?noredirect=1#comment53915505_13167228|1|https://stackoverflow.com/questions/5853380/php-get-number-of-week-for-month/13167228?noredirect=1#comment61619525_13167228^0|0|0|4|13|1A|1|0|I|1|S|A|15|A|1G|C|2|C|0|0|10|D|1G|8|2|E|1|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|16|8|@$I|17|J|18|K|L]|$I|19|J|1A|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|1B|8|@$I|1C|J|1D|K|L]|$I|1E|J|1F|K|L]|$I|1G|J|1H|K|L]|$I|1I|J|1J|K|L]]|9|@$I|1K|J|1L|1|1M]]|A|$]]|$1|O|3|P|5|6|7|1N|8|@$I|1O|J|1P|K|L]|$I|1Q|J|1R|K|L]]|9|@$I|1S|J|1T|1|1U]]|A|$]]|$1|Q|3|R|5|D|7|1V|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|1W|8|@]|9|@]|A|$]]|$1|U|3|-4|5|6|7|1X|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|11]]|12|$5|X|Y|Z|A|$10|13]]]]

Edit: so much for "single line" - needed variables to avoid recomputation with the conditional. Tossed in a default argument while I was at it.

<pre><code>function weekOfMonth($when = null) {
 if ($when === null) $when = time();
 $week = date('W', $when); // note that ISO weeks start on Monday
 $firstWeekOfMonth = date('W', strtotime(date('Y-m-01', $when)));
 return 1 + ($week &lt; $firstWeekOfMonth ? $week : $week - $firstWeekOfMonth);
}
</code></pre>

Please note that <code>weekOfMonth(strtotime('Oct 31, 2011'));</code> will return <code>6</code>; some rare months have 6 weeks in them, contrary to OP's expectation. January 2017 is another month with 6 ISO weeks - Sunday the 1st falls in the last year's week, since ISO weeks start on Monday.

For <a href="https://stackoverflow.com/questions/5853380/php-get-number-of-week-for-month/13167228?noredirect=1#comment53915505_13167228">starshine531</a>, to return a <code>0</code> indexed week of the month, change the <code>return 1 +</code> to <code>return 0 +</code> or <code>return (int)</code>.

For <a href="https://stackoverflow.com/questions/5853380/php-get-number-of-week-for-month/13167228?noredirect=1#comment61619525_13167228">Justin Stayton</a>, for weeks starting on Sunday instead of Monday I would use <code>strftime('%U'</code> instead of <code>date('W'</code>, as follows:

<pre><code>function weekOfMonth($when = null) {
 if ($when === null) $when = time();
 $week = strftime('%U', $when); // weeks start on Sunday
 $firstWeekOfMonth = strftime('%U', strtotime(date('Y-m-01', $when)));
 return 1 + ($week &lt; $firstWeekOfMonth ? $week : $week - $firstWeekOfMonth);
}
</code></pre>

For this version, 2017-04-30 is now in week 6 of April, while 2017-01-31 is now in week 5.

blocks|key|4195444|text|对于星期一到星期日(ISO+8601)的一周(或者，如果你根本不关心)，你可以在一行中完成：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4195445|function+get_week_of_month($date)+{
+return+date('W',+$date)+-+date('W',+strtotime(date("Y-m-01",+$date)))+%2B+1;
}|code-block|syntax|javascript|4195446|(Source|offset|length|4195447|对于其他任何情况(例如，周日到周六)，您只需在函数中调整$date：|4195448|function+get_week_of_month($date)+{
+$date+%2B=+86400;+//For+weeks+starting+on+Sunday
+return+date('W',+$date)+-+date('W',+strtotime(date("Y-m-01",+$date)))+%2B+1;
}|4195449|(Thanks+to+these+guys/gals)|4195450|注意:你可能会在年底遇到一些问题(例如大约12/31，1/1，等等)。Read+more+here.|4195451|entityMap|0|LINK|mutability|MUTABLE|url|http://mybroadband.co.za/vb/showthread.php/66311-Calculating-the-week-in-the-month-(PHP%2529?s=75bffb48a96d677a9088cc32f15d2992&p=946001&viewfull=1#post946001)|1|http://forums.whirlpool.net.au/archive/704023|2^0|0|0|1|6|0|0|0|0|1|P|1|0|Z|F|2|0^^$0|@$1|2|3|4|5|6|7|13|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|15|8|@]|9|@$I|16|J|17|1|18]]|A|$]]|$1|K|3|L|5|6|7|19|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|1A|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|1B|8|@]|9|@$I|1C|J|1D|1|1E]]|A|$]]|$1|Q|3|R|5|6|7|1F|8|@]|9|@$I|1G|J|1H|1|1I]]|A|$]]|$1|S|3|-4|5|6|7|1J|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|Z]]|10|$5|V|W|X|A|$Y|11]]|12|$5|V|W|X|A|$Y|11]]]]

For a Monday-Sunday (ISO 8601) week (or, if you simply don't care), you can do this in one line:

<pre><code>function get_week_of_month($date) {
 return date('W', $date) - date('W', strtotime(date("Y-m-01", $date))) + 1;
}
</code></pre>

(<a href="http://mybroadband.co.za/vb/showthread.php/66311-Calculating-the-week-in-the-month-(PHP)?s=75bffb48a96d677a9088cc32f15d2992&amp;p=946001&amp;viewfull=1#post946001" rel="nofollow noreferrer">Source</a>)

For anything else, (e.g. a Sunday-Saturday week), you just need to tweak $date inside the function:

<pre><code>function get_week_of_month($date) {
 $date += 86400; //For weeks starting on Sunday
 return date('W', $date) - date('W', strtotime(date("Y-m-01", $date))) + 1;
}
</code></pre>

(<a href="http://forums.whirlpool.net.au/archive/704023" rel="nofollow noreferrer">Thanks to these guys/gals</a>)

NOTE: You may run into some issues at the end of the year (e.g. around 12/31, 1/1, etc.). <a href="http://forums.whirlpool.net.au/archive/704023" rel="nofollow noreferrer">Read more here.</a>

blocks|key|2417941|text|我想我也会分享我的功能。这返回一个以周为单位的数组。每周都是一个数组，关键字是星期日(0..6)，值是月日(1..31)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2417942|函数假设一周从星期日开始。|2417943|享受吧！|2417944|function+get_weeks($year,+$month){

++++$days_in_month+=+date("t",+mktime(0,+0,+0,+$month,+1,+$year));
++++$weeks_in_month+=+1;
++++$weeks+=+array();

++++//loop+through+month
++++for+($day=1;+$day<=$days_in_month;+$day%2B%2B)+{

++++++++$week_day+=+date("w",+mktime(0,+0,+0,+$month,+$day,+$year));//0..6+starting+sunday

++++++++$weeks[$weeks_in_month][$week_day]+=+$day;

++++++++if+($week_day+==+6)+{
++++++++++++$weeks_in_month%2B%2B;
++++++++}

++++}

++++return+$weeks;

}|code-block|syntax|javascript|2417945|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|O|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|P|8|@]|9|@]|A|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Thought I'd share my function as well. This returns an array of weeks. Every week is an array with weeks day (0..6) as key and months day (1..31) as value.

Function assumes that week starts with Sunday.

Enjoy!

<pre><code>function get_weeks($year, $month){

 $days_in_month = date("t", mktime(0, 0, 0, $month, 1, $year));
 $weeks_in_month = 1;
 $weeks = array();

 //loop through month
 for ($day=1; $day&lt;=$days_in_month; $day++) {

 $week_day = date("w", mktime(0, 0, 0, $month, $day, $year));//0..6 starting sunday

 $weeks[$weeks_in_month][$week_day] = $day;

 if ($week_day == 6) {
 $weeks_in_month++;
 }

 }

 return $weeks;

}
</code></pre>

blocks|key|502328|text|我想我找到了一个优雅的解决方案|type|unstyled|depth|inlineStyleRanges|entityRanges|data|502329|$time+=+time();+//+or+whenever
$week_of_the_month+=+ceil(date('d',+$time)/7);|code-block|syntax|javascript|502330|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I think I found an elegant solution

<pre><code>$time = time(); // or whenever
$week_of_the_month = ceil(date('d', $time)/7);
</code></pre>

blocks|key|4195532|text|我的5分：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4195533|/**
*+calculate+number+of+weeks+in+a+particular+month
*/
function+weeksInMonth($month=null,$year=null){

++++if(+null==($year)+)+{
++++++++$year+=++date("Y",time());++
++++}

++++if(null==($month))+{
++++++++$month+=+date("m",time());
++++}

++++//+find+number+of+days+in+this+month
++++$daysInMonths+=++date('t',strtotime($year.'-'.$month.'-01'));

++++$numOfweeks+=+($daysInMonths%257==0?0:1)+%2B+intval($daysInMonths/7);

++++$monthEndingDay=+date('N',strtotime($year.'-'.$month.'-'.$daysInMonths));

++++$monthStartDay+=+date('N',strtotime($year.'-'.$month.'-01'));

++++if($monthEndingDay<$monthStartDay){

++++++++$numOfweeks%2B%2B;

++++}

++++return+$numOfweeks;
}|code-block|syntax|javascript|4195534|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

My 5 cents:

<pre><code>/**
* calculate number of weeks in a particular month
*/
function weeksInMonth($month=null,$year=null){

 if( null==($year) ) {
 $year = date("Y",time()); 
 }

 if(null==($month)) {
 $month = date("m",time());
 }

 // find number of days in this month
 $daysInMonths = date('t',strtotime($year.'-'.$month.'-01'));

 $numOfweeks = ($daysInMonths%7==0?0:1) + intval($daysInMonths/7);

 $monthEndingDay= date('N',strtotime($year.'-'.$month.'-'.$daysInMonths));

 $monthStartDay = date('N',strtotime($year.'-'.$month.'-01'));

 if($monthEndingDay&lt;$monthStartDay){

 $numOfweeks++;

 }

 return $numOfweeks;
}
</code></pre>

blocks|key|2121698|text|只需复制并传递代码，然后传递月份和年份。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2121699|例如month=04+year=2013。|2121700|这正是你需要的。|2121701|$mm=+$_REQUEST['month'];
$yy=+$_REQUEST['year'];
$startdate=date($yy."-".$mm."-01")+;
$current_date=date('Y-m-t');
$ld=+cal_days_in_month(CAL_GREGORIAN,+$mm,+$yy);
$lastday=$yy.'-'.$mm.'-'.$ld;
$start_date+=+date('Y-m-d',+strtotime($startdate));
$end_date+=+date('Y-m-d',+strtotime($lastday));
$end_date1+=+date('Y-m-d',+strtotime($lastday."+%2B+6+days"));
$count_week=0;
$week_array+=+array();

for($date+=+$start_date;+$date+<=+$end_date1;+$date+=+date('Y-m-d',+strtotime($date.+'+%2B+7+days')))
{
++++$getarray=getWeekDates($date,+$start_date,+$end_date);
echo+" ";
$week_array[]=$getarray;
++++echo+"\n";
$count_week%2B%2B;

}

//+its+give+the+number+of+week+for+the+given+month+and+year
echo+$count_week;
//print_r($week_array);

function+getWeekDates($date,+$start_date,+$end_date)
{
++++$week+=++date('W',+strtotime($date));
++++$year+=++date('Y',+strtotime($date));
++++$from+=+date("Y-m-d",+strtotime("{$year}-W{$week}%2B1"));
++++if($from+<+$start_date)+$from+=+$start_date;

++++$to+=+date("Y-m-d",+strtotime("{$year}-W{$week}-6"));+
++++if($to+>+$end_date)+$to+=+$end_date;

$array1+=+array(
++++++++"ssdate"+=>+$from,
++++++++"eedate"+=>+$to,
);

return+$array1;

+++//+echo+"Start+Date-->".$from."End+Date+-->".$to;
}

for($i=0;$i<$count_week;$i%2B%2B)
{+++
$start=+$week_array[$i]['ssdate'];
echo+"--";

$week_array[$i]['eedate'];
echo+" ";
}|code-block|syntax|javascript|2121702|输出：|2121703|week(+0+)=>2013-03-01---2013-03-02

week(+1+)=>2013-03-03---2013-03-09

week(+2+)=>2013-03-10---2013-03-16

week(+3+)=>2013-03-17---2013-03-23

week(+4+)=>2013-03-24---2013-03-30

week(+5+)=>2013-03-31---2013-03-31|2121704|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|S|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|T|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|H|7|V|8|@]|9|@]|A|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Just Copy and Past the code and pass month and year.

e.g month=04 year=2013.

That's exactly what You Need.

<pre><code>$mm= $_REQUEST['month'];
$yy= $_REQUEST['year'];
$startdate=date($yy."-".$mm."-01") ;
$current_date=date('Y-m-t');
$ld= cal_days_in_month(CAL_GREGORIAN, $mm, $yy);
$lastday=$yy.'-'.$mm.'-'.$ld;
$start_date = date('Y-m-d', strtotime($startdate));
$end_date = date('Y-m-d', strtotime($lastday));
$end_date1 = date('Y-m-d', strtotime($lastday." + 6 days"));
$count_week=0;
$week_array = array();

for($date = $start_date; $date &lt;= $end_date1; $date = date('Y-m-d', strtotime($date. ' + 7 days')))
{
 $getarray=getWeekDates($date, $start_date, $end_date);
echo "&lt;br&gt;";
$week_array[]=$getarray;
 echo "\n";
$count_week++;

}

// its give the number of week for the given month and year
echo $count_week;
//print_r($week_array);

function getWeekDates($date, $start_date, $end_date)
{
 $week = date('W', strtotime($date));
 $year = date('Y', strtotime($date));
 $from = date("Y-m-d", strtotime("{$year}-W{$week}+1"));
 if($from &lt; $start_date) $from = $start_date;

 $to = date("Y-m-d", strtotime("{$year}-W{$week}-6")); 
 if($to &gt; $end_date) $to = $end_date;

$array1 = array(
 "ssdate" =&gt; $from,
 "eedate" =&gt; $to,
);

return $array1;

 // echo "Start Date--&gt;".$from."End Date --&gt;".$to;
}

for($i=0;$i&lt;$count_week;$i++)
{ 
$start= $week_array[$i]['ssdate'];
echo "--";

$week_array[$i]['eedate'];
echo "&lt;br&gt;";
}
</code></pre>

OUTPUT:

<pre><code>week( 0 )=&gt;2013-03-01---2013-03-02

week( 1 )=&gt;2013-03-03---2013-03-09

week( 2 )=&gt;2013-03-10---2013-03-16

week( 3 )=&gt;2013-03-17---2013-03-23

week( 4 )=&gt;2013-03-24---2013-03-30

week( 5 )=&gt;2013-03-31---2013-03-31
</code></pre>

blocks|key|502378|text|经过多次尝试，我找到了解决方案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|502379|<?php

function+getWeeks($month,$year)
{
++++$month+=+intval($month);++++++++//force+month+to+single+integer+if+'0x'
++++$suff+=+array('st','nd','rd','th','th','th');+++++++//week+suffixes
++++$end+=+date('t',mktime(0,0,0,$month,1,$year));++++++//last+date+day+of+month:+28+-+31
++++$start+=+date('w',mktime(0,0,0,$month,1,$year));++++//1st+day+of+month:+0+-+6+(Sun+-+Sat)
++++$last+=+7+-+$start;+++++++++++++++++++++//get+last+day+date+(Sat)+of+first+week
++++$noweeks+=+ceil((($end+-+($last+%2B+1))/7)+%2B+1);++++++//total+no.+weeks+in+month
++++$output+=+"";+++++++++++++++++++++++//initialize+string+++++
++++$monthlabel+=+str_pad($month,+2,+'0',+STR_PAD_LEFT);
++++for($x=1;$x<$noweeks%2B1;$x%2B%2B)
++++{+++
++++++++if($x+==+1)
++++++++{
++++++++++++$startdate+=+"$year-$monthlabel-01";
++++++++++++$day+=+$last+-+6;
++++++++}
++++++++else
++++++++{
++++++++++++$day+=+$last+%2B+1+%2B+(($x-2)*7);
++++++++++++$day+=+str_pad($day,+2,+'0',+STR_PAD_LEFT);
++++++++++++$startdate+=+"$year-$monthlabel-$day";
++++++++}
++++++++if($x+==+$noweeks)
++++++++{
++++++++++++$enddate+=+"$year-$monthlabel-$end";
++++++++}
++++++++else
++++++++{
++++++++++++$dayend+=+$day+%2B+6;
++++++++++++$dayend+=+str_pad($dayend,+2,+'0',+STR_PAD_LEFT);
++++++++++++$enddate+=+"$year-$monthlabel-$dayend";
++++++++}
++++++++$j=1;
++++++++if($j--)
++++++++{
++++++++++++$k=getTotalDate($startdate,$enddate);
++++++++++++$j=1;
++++++++}

++++$output+.=+"Week+".$xyz."+week+->+Start+date=$startdate+End+date=$enddate+<br+/>";++
++++}
++++return+$output;
}

if(isset($_POST)+&&+!empty($_POST)){
++++$month+=+$_POST['m'];
++++$year+=+$_POST['y'];+
++++echo+getWeeks($month,$year);
}
?>

<form+method="post">
++M:
++<input+name="m"+value=""+/>
++Y:
++<input+name="y"+value=""+/>
++<input+type="submit"+value="go"+/>
</form>|code-block|syntax|javascript|502380|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

After alot of efoort i found the solution

<pre><code>&lt;?php

function getWeeks($month,$year)
{
 $month = intval($month); //force month to single integer if '0x'
 $suff = array('st','nd','rd','th','th','th'); //week suffixes
 $end = date('t',mktime(0,0,0,$month,1,$year)); //last date day of month: 28 - 31
 $start = date('w',mktime(0,0,0,$month,1,$year)); //1st day of month: 0 - 6 (Sun - Sat)
 $last = 7 - $start; //get last day date (Sat) of first week
 $noweeks = ceil((($end - ($last + 1))/7) + 1); //total no. weeks in month
 $output = ""; //initialize string 
 $monthlabel = str_pad($month, 2, '0', STR_PAD_LEFT);
 for($x=1;$x&lt;$noweeks+1;$x++)
 { 
 if($x == 1)
 {
 $startdate = "$year-$monthlabel-01";
 $day = $last - 6;
 }
 else
 {
 $day = $last + 1 + (($x-2)*7);
 $day = str_pad($day, 2, '0', STR_PAD_LEFT);
 $startdate = "$year-$monthlabel-$day";
 }
 if($x == $noweeks)
 {
 $enddate = "$year-$monthlabel-$end";
 }
 else
 {
 $dayend = $day + 6;
 $dayend = str_pad($dayend, 2, '0', STR_PAD_LEFT);
 $enddate = "$year-$monthlabel-$dayend";
 }
 $j=1;
 if($j--)
 {
 $k=getTotalDate($startdate,$enddate);
 $j=1;
 }

 $output .= "Week ".$xyz." week -&gt; Start date=$startdate End date=$enddate &lt;br /&gt;"; 
 }
 return $output;
}

if(isset($_POST) &amp;&amp; !empty($_POST)){
 $month = $_POST['m'];
 $year = $_POST['y']; 
 echo getWeeks($month,$year);
}
?&gt;

&lt;form method="post"&gt;
 M:
 &lt;input name="m" value="" /&gt;
 Y:
 &lt;input name="y" value="" /&gt;
 &lt;input type="submit" value="go" /&gt;
&lt;/form&gt;
</code></pre>

blocks|key|2417991|text|function+get_week_of_month(+$timestamp+)
{
++++$week_of_month+=+0;+
++++$month+=+date(+'j',+$timestamp+);
++++$test_month+=+$month;
++++while(+$test_month+==+$month+)
++++{
++++++++$week_of_month%2B%2B;
++++++++$timestamp+=+strtotime(+'-1+week',+$timestamp+);
++++++++$test_month+=+date(+'j',+$timestamp+);
++++}
++++return+$week_of_month;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2417992|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>function get_week_of_month( $timestamp )
{
 $week_of_month = 0; 
 $month = date( 'j', $timestamp );
 $test_month = $month;
 while( $test_month == $month )
 {
 $week_of_month++;
 $timestamp = strtotime( '-1 week', $timestamp );
 $test_month = date( 'j', $timestamp );
 }
 return $week_of_month;
}
</code></pre>

blocks|key|4195619|text|我真的很喜欢@michaelc的回答。然而，我在几点上卡住了。似乎每到星期天，就会有一个偏移量。我认为这与一周中哪一天是一周的开始有关。无论如何，为了可读性，我对它做了一些细微的修改：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4195620|function+wom(\DateTime+$date)+{
++++//+The+week+of+the+year+of+the+current+month
++++$cw+=+date('W',+$date->getTimestamp());

++++//+The+week+of+the+year+of+the+first+of+the+given+month
++++$fw+=+date('W',strtotime(date('Y-m-01',$date->getTimeStamp())));

++++//+Offset
++++$o+=+1;

++++//+If+it+is+a+Saturday,+offset+by+two.
++++if(+date('N',$date->getTimestamp())+==+7+)+{
++++++++$o+=+2;
++++}

++++return+$cw+-$fw+%2B+$o;
}|code-block|syntax|javascript|4195621|所以如果日期是2013年11月9日...|4195622|$cw+=+45
$fw+=+44|4195623|当偏移量为1时，它正确地返回2。|4195624|如果日期是2013年11月10日，则$cw和$fw与之前相同，但偏移量为2，并且正确返回3。|offset|length|style|CODE|4195625|entityMap^0|0|0|0|0|0|I|3|M|3|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|Y|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|Z|8|@$O|10|P|11|Q|R]|$O|12|P|13|Q|R]]|9|@]|A|$]]|$1|S|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|T|$]]

I really liked @michaelc's answer. However, I got stuck on a few points. It seemed that every time Sunday rolled around, there was an offset of one. I think it has to do with what day of the week is the start of the week. In any case, here is my slight alteration to it, expanded a bit for readability:

<pre><code>function wom(\DateTime $date) {
 // The week of the year of the current month
 $cw = date('W', $date-&gt;getTimestamp());

 // The week of the year of the first of the given month
 $fw = date('W',strtotime(date('Y-m-01',$date-&gt;getTimeStamp())));

 // Offset
 $o = 1;

 // If it is a Saturday, offset by two.
 if( date('N',$date-&gt;getTimestamp()) == 7 ) {
 $o = 2;
 }

 return $cw -$fw + $o;
}
</code></pre>

So if the date is Nov. 9, 2013...

<pre><code>$cw = 45
$fw = 44
</code></pre>

and with the offset of 1, it correctly returns 2.

If the date is Nov. 10, 2013, <code>$cw</code> and <code>$fw</code> are the same as before, but the offset is 2, and it correctly returns 3.

blocks|key|502433|text|这是一个基于sberry的数学解的解决方案，但是使用了PHP+DateTime类。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|502434|function+week_of_month($date)+{
++++$first_of_month+=+new+DateObject($date->format('Y/m/1'));
++++$day_of_first+=+$first_of_month->format('N');
++++$day_of_month+=+$date->format('j');
++++return+floor(($day_of_first+%2B+$day_of_month+-+1)+/+7)+%2B+1;
}|code-block|syntax|javascript|502435|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/class.datetime.php^0|V|8|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

This is a solution based on sberry's mathematical solution but using the PHP <a href="http://php.net/manual/en/class.datetime.php" rel="nofollow noreferrer">DateTime</a> class instead.

<pre><code>function week_of_month($date) {
 $first_of_month = new DateObject($date-&gt;format('Y/m/1'));
 $day_of_first = $first_of_month-&gt;format('N');
 $day_of_month = $date-&gt;format('j');
 return floor(($day_of_first + $day_of_month - 1) / 7) + 1;
}
</code></pre>

blocks|key|4195671|text|我创建这个函数，来自巴西:)我希望它是有用的|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4195672|function+weekofmonth($time)+{

++++$firstday+++++++=+1;
++++$lastday++++++++=+date('j',$time);
++++$lastdayweek+=+6;+//Saturday

++++$week+=+1;
++++for+($day=1;$day<=$lastday;$day%2B%2B)+{
++++++++$timetmp+=+mktime(0,+0,+0,+date('n',$time),+$day,+date('Y',$time));
++++++++if+(date('N',$timetmp)+==+$lastdayweek)+{
++++++++++++$week%2B%2B;
++++++++}
++++}
++++if+(date('N',$time)==$lastdayweek)+{
++++++++$week--;
++++}

++++return+$week;
}

$time+=+mktime(0,+0,+0,+9,+30,+2014);
echo+weekofmonth($time);|code-block|syntax|javascript|4195673|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I create this function, from brazil :) I hope it is useful

<pre><code>function weekofmonth($time) {

 $firstday = 1;
 $lastday = date('j',$time);
 $lastdayweek = 6; //Saturday

 $week = 1;
 for ($day=1;$day&lt;=$lastday;$day++) {
 $timetmp = mktime(0, 0, 0, date('n',$time), $day, date('Y',$time));
 if (date('N',$timetmp) == $lastdayweek) {
 $week++;
 }
 }
 if (date('N',$time)==$lastdayweek) {
 $week--;
 }

 return $week;
}

$time = mktime(0, 0, 0, 9, 30, 2014);
echo weekofmonth($time);
</code></pre>

blocks|key|4195702|text|我在网上找到了这个：http://kcwebprogrammers.blogspot.de/2009/03/current-week-in-month-php.html|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4195703|他有一个非常简单的解决方案，似乎对我很有效。|4195704|$currentWeek+=+ceiling((date("d")+-+date("w")+-+1)+/+7)+%2B+1;|code-block|syntax|javascript|4195705|举个例子：|4195706|$now+=+strtotime("today");
$weekOfMonth+=+ceil((date("d",+$now)+-+date("w",+$now)+-+1)+/+7)+%2B+1;|4195707|entityMap|0|LINK|mutability|MUTABLE|url|http://kcwebprogrammers.blogspot.de/2009/03/current-week-in-month-php.html^0|A|22|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|6|7|10|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|11|8|@]|9|@]|C|$I|J]]|$1|K|3|L|5|6|7|12|8|@]|9|@]|C|$]]|$1|M|3|N|5|H|7|13|8|@]|9|@]|C|$I|J]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]]]

I found this online:
<a href="http://kcwebprogrammers.blogspot.de/2009/03/current-week-in-month-php.html" rel="nofollow">http://kcwebprogrammers.blogspot.de/2009/03/current-week-in-month-php.html</a>

He has a very simple solution which seems to work fine for me.

<pre><code>$currentWeek = ceiling((date("d") - date("w") - 1) / 7) + 1;
</code></pre>

So for example:

<pre><code>$now = strtotime("today");
$weekOfMonth = ceil((date("d", $now) - date("w", $now) - 1) / 7) + 1;
</code></pre>

blocks|key|2121853|text|你可以在更新的php版本中使用W。http://php.net/manual/en/function.date.php|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2121854|我是这样使用它的：|2121855|function+getWeek($date)+{+
$month_start=strtotime("1+".date('F+Y',$date));
$current_date=strtotime(date('j+F+Y',$date));

$month_week=date("W",$month_start);
$current_week=date("W",$current_date);
return+($current_week-$month_week);

}//0+is+the+week+of+the+first.|code-block|syntax|javascript|2121856|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/function.date.php^0|H|16|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

you can use W in newer php versions. <a href="http://php.net/manual/en/function.date.php" rel="nofollow">http://php.net/manual/en/function.date.php</a>

i have used it like so:

<pre><code>function getWeek($date) { 
$month_start=strtotime("1 ".date('F Y',$date));
$current_date=strtotime(date('j F Y',$date));

$month_week=date("W",$month_start);
$current_week=date("W",$current_date);
return ($current_week-$month_week);

}//0 is the week of the first.
</code></pre>

blocks|key|4195771|text|简明扼要：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4195772|//+Function+accepts+$date+as+a+string,
//+Returns+the+week+number+in+which+the+given+date+falls.
//+Assumed+week+starts+on+Sunday.
function+wom($date)+{
++$date+=+strtotime($date);
++$weeknoofday+=+date('w',+$date);
++$day+=+date('j',+$date);
++$weekofmonth+=+ceil(($day+%2B+(7-($weeknoofday%2B1)))+/+7);
++return+$weekofmonth;
}
//+Test
foreach+(range(1,+31)+as+$day)+{
++++$test_date+=+"2015-01-"+.+str_pad($day,+2,+'0',+STR_PAD_LEFT);
++++echo+"$test_date+-+";
++++echo+wom($test_date)+.+"\n";
}|code-block|syntax|javascript|4195773|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Short and foolproof:

<pre><code>// Function accepts $date as a string,
// Returns the week number in which the given date falls.
// Assumed week starts on Sunday.
function wom($date) {
 $date = strtotime($date);
 $weeknoofday = date('w', $date);
 $day = date('j', $date);
 $weekofmonth = ceil(($day + (7-($weeknoofday+1))) / 7);
 return $weekofmonth;
}
// Test
foreach (range(1, 31) as $day) {
 $test_date = "2015-01-" . str_pad($day, 2, '0', STR_PAD_LEFT);
 echo "$test_date - ";
 echo wom($test_date) . "\n";
}
</code></pre>

blocks|key|4195777|text|我使用这个简单的函数：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4195778|function+weekNumberInMonth($timestampDate)
{
++++$firstDayOfMonth+=+strtotime(date('01-M-Y+00:00:00',+$timestampDate));
++++$firstWeekdayOfMonth+=+date(+'w',+$firstDayOfMonth);
++++$dayNumberInMonth+=+date('d',+$timestampDate);
++++$weekNumberInMonth+=+ceil(($dayNumberInMonth+%2B+$firstWeekdayOfMonth)+/+7);
++++return+$weekNumberInMonth;
}|code-block|syntax|javascript|4195779|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I use this simple function:

<pre><code>function weekNumberInMonth($timestampDate)
{
 $firstDayOfMonth = strtotime(date('01-M-Y 00:00:00', $timestampDate));
 $firstWeekdayOfMonth = date( 'w', $firstDayOfMonth);
 $dayNumberInMonth = date('d', $timestampDate);
 $weekNumberInMonth = ceil(($dayNumberInMonth + $firstWeekdayOfMonth) / 7);
 return $weekNumberInMonth;
}
</code></pre>

blocks|key|502551|text|这里有两个线条：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|502552|function+getWeekOfMonth(DateTime+$date)+{
++++$firstDayOfMonth+=+new+DateTime($date->format('Y-m-1'));

++++return+ceil(($firstDayOfMonth->format('N')+%2B+$date->format('j')+-+1)+/+7);
}|code-block|syntax|javascript|502553|而且Wtower's+solutions也不能100%25正常工作。|offset|length|502554|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/22686627/5355492^0|0|0|2|I|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Here comes two liner:

<pre><code>function getWeekOfMonth(DateTime $date) {
 $firstDayOfMonth = new DateTime($date-&gt;format('Y-m-1'));

 return ceil(($firstDayOfMonth-&gt;format('N') + $date-&gt;format('j') - 1) / 7);
}
</code></pre>

And <a href="https://stackoverflow.com/a/22686627/5355492">Wtower's solutions</a> doesn't work 100% properly.

blocks|key|4195841|text|如果我理解正确的话，问题是如何识别特定日期的一个月内的第几个星期……我正在寻找类似的解决方案。我使用了上述答案的一些想法来开发我自己的解决方案。希望能对某些人有所帮助。如果是，那么UpVote我的答案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4195842|function+week_number_within_month($datenew){

++++++++$year+=++date("Y",strtotime($datenew));++
++++++++$month+=+date("m",strtotime($datenew));

++++//+find+number+of+days+in+this+month
++++$daysInMonths+=++date('t',strtotime($year.'-'.$month.'-01'));
++++$numOfweeks+=+($daysInMonths%257==0?0:1)+%2B+intval($daysInMonths/7);
++++$monthEndingDay=+date('N',strtotime($year.'-'.$month.'-'.$daysInMonths));
++++$monthStartDay+=+date('N',strtotime($year.'-'.$month.'-01'));
++++if($monthEndingDay<$monthStartDay){
++++++++$numOfweeks%2B%2B;
++++}
++++$date=date('Y/m/d',+strtotime($year.'-'.+$month.'-01'));
++++$week_array=Array();
++++for+($i=1;+$i<=$numOfweeks;+$i%2B%2B){+++///+create+an+Array+of+all+days+of+month+separated+by+weeks+as+a+keys
++++++++++++$max+=+7;
++++++++++++if+($i+==1){+$max+=+8+-+$monthStartDay;}
++++++++++++if+($i+==+$numOfweeks){+$max+=+$monthEndingDay;}
++++++++++++for+($r=1;+$r<=$max;+$r%2B%2B){

++++++++++++++++++++$week_array[$i][]=$date;
++++++++++++++++++++$date+=+date('Y/m/d',strtotime($date+.+"%2B1+days"));
++++++++++++}
++++}
++++$new_datenew+=+date('Y/m/d',+strtotime($datenew));
++++$week_result='';
++++++++foreach+($week_array+as+$key+=>+$val){++///+finding+what+week+number+of+my+date+from+week_array
++++++++++++foreach+($val+as+$kr+=>+$value){
++++++++++++if+($new_datenew+==+$value){
++++++++++++++++$week_result+=+$key;
++++++++++++}+
++++++++++++}
++++++++}
++++return+$week_result;
}
print+week_number_within_month('2016-09-15');|code-block|syntax|javascript|4195843|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

if I understand correct, the question is how to identify what number of week within a month of a specific day... I was looking for similar solution. I used some ideas of above answers to develop my own solution. Hope it can be helpful for somebody. If Yes, then UpVote my answer.

<pre><code>function week_number_within_month($datenew){

 $year = date("Y",strtotime($datenew)); 
 $month = date("m",strtotime($datenew));

 // find number of days in this month
 $daysInMonths = date('t',strtotime($year.'-'.$month.'-01'));
 $numOfweeks = ($daysInMonths%7==0?0:1) + intval($daysInMonths/7);
 $monthEndingDay= date('N',strtotime($year.'-'.$month.'-'.$daysInMonths));
 $monthStartDay = date('N',strtotime($year.'-'.$month.'-01'));
 if($monthEndingDay&lt;$monthStartDay){
 $numOfweeks++;
 }
 $date=date('Y/m/d', strtotime($year.'-'. $month.'-01'));
 $week_array=Array();
 for ($i=1; $i&lt;=$numOfweeks; $i++){ /// create an Array of all days of month separated by weeks as a keys
 $max = 7;
 if ($i ==1){ $max = 8 - $monthStartDay;}
 if ($i == $numOfweeks){ $max = $monthEndingDay;}
 for ($r=1; $r&lt;=$max; $r++){

 $week_array[$i][]=$date;
 $date = date('Y/m/d',strtotime($date . "+1 days"));
 }
 }
 $new_datenew = date('Y/m/d', strtotime($datenew));
 $week_result='';
 foreach ($week_array as $key =&gt; $val){ /// finding what week number of my date from week_array
 foreach ($val as $kr =&gt; $value){
 if ($new_datenew == $value){
 $week_result = $key;
 } 
 }
 }
 return $week_result;
}
print week_number_within_month('2016-09-15');
</code></pre>

blocks|key|2121940|text|function+getWeekOfMonth(\DateTime+$date)
{
++++$firstWeekdayOfMonth+=+new+DateTime("first+weekday+0+{$date->format('M')}+{$date->format('Y')}");
++++$offset+=+$firstWeekdayOfMonth->format('N')-1;
++++return+intval(($date->format('j')+%2B+$offset)/7)%2B1;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2121941|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>function getWeekOfMonth(\DateTime $date)
{
 $firstWeekdayOfMonth = new DateTime("first weekday 0 {$date-&gt;format('M')} {$date-&gt;format('Y')}");
 $offset = $firstWeekdayOfMonth-&gt;format('N')-1;
 return intval(($date-&gt;format('j') + $offset)/7)+1;
}
</code></pre>

blocks|key|2121949|text|/**
+++++++++*+In+case+of+Week+we+can+get+the+week+of+year.+So+whenever+we+will+get+the+week+of+the+month+then+we+have+to
+++++++++*+subtract+the+until+last+month+weeks+from+it+will+give+us+the+current+month+week.
+++++++++*/
++++++++$dateComponents+=+getdate();

++++++++if($dateComponents['mon']+==+1)
++++++++++++$weekOfMonth+=+date('W',+strtotime($dateComponents['year'].'-'.$dateComponents['mon'].'-'.$dateComponents['mday']))-1;+//+We+subtract+-1+to+map+it+to+the+array
++++++++else
++++++++++++$weekOfMonth+=+date('W',+strtotime($dateComponents['year'].'-'.$dateComponents['mon'].'-'.$dateComponents['mday']))-date('W',+strtotime($dateComponents['year'].'-'.$dateComponents['mon'].'-01'));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2121950|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>/**
 * In case of Week we can get the week of year. So whenever we will get the week of the month then we have to
 * subtract the until last month weeks from it will give us the current month week.
 */
 $dateComponents = getdate();

 if($dateComponents['mon'] == 1)
 $weekOfMonth = date('W', strtotime($dateComponents['year'].'-'.$dateComponents['mon'].'-'.$dateComponents['mday']))-1; // We subtract -1 to map it to the array
 else
 $weekOfMonth = date('W', strtotime($dateComponents['year'].'-'.$dateComponents['mon'].'-'.$dateComponents['mday']))-date('W', strtotime($dateComponents['year'].'-'.$dateComponents['mon'].'-01'));
</code></pre>

blocks|key|502632|text|使用碳：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|502633|502634|+$date+=+Carbon::now()；$d1+=+$date->startOfMonth()；$d2+=+$date->endOfMonth()；|blockquote|502635|502636|$weeks+=+$d1->diffInWeeks($d2);|502637|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|L|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|M|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|N|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|J|$]]

Using Carbon:

<blockquote>
 $date = Carbon::now();
 $d1 = $date->startOfMonth();
 $d2 = $date->endOfMonth();
 
 $weeks = $d1->diffInWeeks($d2);
</blockquote>

blocks|key|4195923|text|如果你想把一个月分成4周，你可以使用这个函数。这是很有帮助的，如果你想|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4195924|4195925|“每月的第一个星期一”|unordered-list-item|4195926|“每月的第三个星期四”等。|4195927|4195928|我们开始吧|4195929|/**
*+This+Calculates+(and+returns)+the+week+number+within+a+month,+based+on+date('j')+day+of+month.
*+This+is+useful,+if+you+want+to+have+(for+instance)+the+first+Thu+in+month,+regardless+of+date
*+@param+$Timestamp
*+@return+float%7Cint
*/
function+getWeekOfMonth($Timestamp)
{
++++$DayOfMonth=date('j',+$Timestamp);+//+Day+of+the+month+without+leading+zeros+0-31

++++if($DayOfMonth>21)+return+4;
++++if($DayOfMonth>14)+return+3;
++++if($DayOfMonth>7)+return+2;
++++return+1;
}|code-block|syntax|javascript|4195930|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|S|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|T|8|@]|9|@]|A|$]]|$1|F|3|G|5|E|7|U|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|V|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|W|8|@]|9|@]|A|$]]|$1|K|3|L|5|M|7|X|8|@]|9|@]|A|$N|O]]|$1|P|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|Q|$]]

If you clearly want to separate a month into 4 Weeks, you can use this function.
This is helpful, if you want 

<ul>
<li>"the first monday of month"</li>
<li>"the third thursday of month" etc.</li>
</ul>

Here we go

<pre><code>/**
* This Calculates (and returns) the week number within a month, based on date('j') day of month.
* This is useful, if you want to have (for instance) the first Thu in month, regardless of date
* @param $Timestamp
* @return float|int
*/
function getWeekOfMonth($Timestamp)
{
 $DayOfMonth=date('j', $Timestamp); // Day of the month without leading zeros 0-31

 if($DayOfMonth&gt;21) return 4;
 if($DayOfMonth&gt;14) return 3;
 if($DayOfMonth&gt;7) return 2;
 return 1;
}
</code></pre>

blocks|key|4195958|text|来自碳：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4195959|return+(int)+ceil((new+Datetime())->format('d')+/+7);|code-block|syntax|javascript|4195960|尽可能简单:)|4195961|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

From carbon:

<pre><code>return (int) ceil((new Datetime())-&gt;format('d') / 7);
</code></pre>

As simple as possible :)

So I have a script that returns the number of weeks in a particular month and year. How can I take a specific day from that month and determine if it is part of week 1,2,3,4 or 5 of that month?

PHP get number of week for month

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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因此，我有一个返回特定月份和年份的周数的脚本。如何从该月中选择特定的一天，并确定它是该月的第1、2、3、4或5周的一部分吗？

问PHP获取月份的周数
EN

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