我想堆叠一个框架,但我想我没有使用正确的方法……
myframe
sex = F
q8
cars N U Y
1 35 31 10
2 34 23 7
3 132 109 35
4 38 36 14
5 7 5 2
, , sex = M
q8
cars N U Y
1 49 22 16
2 24 13 8
3 136 52 33
4 37 31 32
5 15 10 4
f = c(myframe[1:15])
m = c(myframe[16:30])
S <- stack(data.frame(f,m))
names(S)=c("num","gender")
group=c("1","1","1","2","2","2","3","3","3","4","4","4","5","5","5","6","6","6","1","1","1","2","2","2","3","3","3","4","4","4","5","5","5")
num=S$num
gender=S$gender
twoway.df=data.frame(num,group,gender)
twoway.df
1 1 35 f
2 1 31 f
3 1 10 f
4 2 24 f
5 2 13 f
....你能帮我做得更好吗?
发布于 2011-05-02 18:56:55
要将表转换为data.frame,应使用基本函数as.data.frame.table。
然而,下面是我会怎么做:
myframe <- as.table(array(c(35, 34, 132, 38, 7, 31, 23, 109, 36, 5,
10, 7, 35, 14, 2, 49, 24, 136, 37, 15,
22, 13, 52, 31, 10, 16, 8, 33, 32, 4),
dim=c(5, 3, 2),
dimnames=list(cars=1:5, q8=c("N","U","Y"),
sex=c("F","M"))))
library(reshape)
melt(myframe)用于获取包含所有变量的data.frame。如果您只想将q8和sex作为因子保留在data.frame中,请改用melt(myframe)[,-1]。
有关详细信息,请参阅help(melt.array)。
https://stackoverflow.com/questions/5855225
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