你将如何从R中的矩阵中生成图像?
矩阵值将对应于图像上的像素强度(尽管我目前只对0,1值白色或黑色感兴趣。),而列和行数对应于图像上的垂直和水平位置。
通过制作图像,我的意思是在屏幕上显示它,并将其保存为jpg格式。
发布于 2011-04-13 01:53:52
这里是第二种方法(同样,垂直轴向下增加)。此方法更易于布局,但对绘图中显示的数值格式的控制较少。
library(plotrix)
#Build the matrix data to look like a correlation matrix
n <- 8
x <- matrix(runif(n*n), nrow=n)
xmin <- 0
xmax <- 1
for (i in 1:n) x[i, i] <- 1.0 #Make the diagonal all 1's
#Generate the palette for the matrix and the legend. Generate labels for the legend
palmat <- color.scale(x, c(1, 0.4), c(1, 0.4), c(0.96, 1))
palleg <- color.gradient(c(1, 0.4), c(1, 0.4), c(0.96, 1), nslices=100)
lableg <- c(formatC(xmin, format="f", digits=2), formatC(1*(xmax-xmin)/4, format="f", digits=2), formatC(2*(xmax-xmin)/4, format="f", digits=2), formatC(3*(xmax-xmin)/4, format="f", digits=2), formatC(xmax, format="f", digits=2))
#Set up the plot area and plot the matrix
par(mar=c(5, 5, 5, 8))
color2D.matplot(x, cellcolors=palmat, main=paste(n, " X ", n, " Matrix Using Color2D.matplot", sep=""), show.values=2, vcol=rgb(0,0,0), axes=FALSE, vcex=0.7)
axis(1, at=seq(1, n, 1)-0.5, labels=seq(1, n, 1), tck=-0.01, padj=-1)
#In the axis() statement below, note that the labels are decreasing. This is because
#the above color2D.matplot() statement has "axes=FALSE" and a normal axis()
#statement was used.
axis(2, at=seq(1, n, 1)-0.5, labels=seq(n, 1, -1), tck=-0.01, padj=0.7)
#Plot the legend
pardat <- par()
color.legend(pardat$usr[2]+0.5, 0, pardat$usr[2]+1, pardat$usr[2], paste(" ", lableg, sep=""), palleg, align="rb", gradient="y", cex=0.7)

https://stackoverflow.com/questions/5638462
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