问在自赋值过程中，复制和交换习惯用法是如何工作的？

EN

class Container
{
    int*   mArray;
};

// Copy and swap
Container& operator=(Container const& rhs)
{
    Container   other(rhs);  // You make a copy of the rhs.
                             // This means you have done a deep copy of mArray

    other.swap(*this);       // This swaps the mArray pointer.
                             // So if rhs and *this are the same object it
                             // does not matter because other and *this are
                             // definitely not the same object.

    return *this;
}

Container& operator=(Container other)
                       // ^^^^^^^^     Notice here the lack of `const &`
                       //              This means it is a pass by value parameter.
                       //              The copy was made implicitly as the parameter was passed. 
{
    other.swap(*this);

    return *this;
}