extern "C" int RTinet_lookup( const char * host,RTinet_address *address,RTinet_port port)
{
struct addrinfo,*res;
int errcode;
char addrstr[INET6_ADDRSTRLEN];
memset (&hints, 0, sizeof (hints));
hints.ai_family = AF_UNSPEC;
hints.ai_socktype = SOCK_STREAM;
hints.ai_protocol = IPPROTO_TCP;
hints.ai_flags |= AI_CANONNAME;
errcode = getaddrinfo (host, NULL , &hints, &res);
if (errcode != 0)
{
INFO("getaddrinfo");
return -1;
}
INFO(STR("Host: %s", host));
if(res == NULL)
{
INFO(STR("NULL VALUE OF RES"));
}
else
{INFO(STR("IN ELSE PART"));
while (res)
{
INFO(STR("Inside while condition with res "));
switch (res->ai_family)
{
case AF_INET:
inet_ntop(AF_INET, &((struct sockaddr_in *) res->ai_addr)->sin_addr,addrstr, INET_ADDRSTRLEN);
break;
case AF_INET6:
inet_ntop(AF_INET6, &((struct sockaddr_in6 *) res->ai_addr)->sin6_addr ,addrstr, INET6_ADDRSTRLEN);
break;
}
res = res->ai_next;
}
}
INFO(STR("IPv%d address: %s ", res->ai_family == AF_INET6 ? 6 : 4, addrstr));
return 1;
}
在这里,我传递"::1"
作为主机地址,这是一个IPV6形式。但在痕迹中我得到了
Host: ::1
IPv4 address: ::1
为什么要用IPv4?它应该以IPv6作为地址族,在本例中应该是AF_INET6
发布于 2011-05-12 22:20:40
res
指向NULL,因此您最后一条打印语句无效,因为您假设ai_family != AF_INET6
必须为AF_INET
。
编辑:为了进一步解释,这里是您的代码问题的要点,删除了不相关的点:
while (res)
{
res = res->ai_next;
}
INFO(STR("IPv%d address: %s ", res->ai_family == AF_INET6 ? 6 : 4, addrstr));
当while
循环完成时,问问自己res
的值是什么。
https://stackoverflow.com/questions/5978651
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