blocks|key|2471970|text|if+(numerator+is+int)+{+...+}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2471971|或|unstyled|2471972|if+(numerator.GetType()+==+typeof(int))+{...}|2471973|前者通常更好。|2471974|编辑:Н我们说问题出在从字符串表示中解析数字。我担心，这里最好的方法是调用type.TryParse并检查给定的字符串是否可以被解析为给定类型的数量。|offset|length|style|CODE|2471975|例如。|2471976|var+tokens+=+line.Split('/');
double+dArg1,dArg2;+int+iArg1,+iArg2;
if+(int.TryParse(tokens[0],+out+iArg1)+
++++&&+int.TryParse(tokens[1],+out+iArg2)){
++++return+iArg1/iArg2;
}+else+if+(double.TryParse(tokens[0],+out+dArg1)+
+++++++++++&&+double.TryParse(tokens[1],+out+dArg2)){
++++return+dArg1/dArg2;
}+else+{+/*+handle+error+*/+}|2471977|请注意，所有的ints都可以解析为doubles，因此您需要先尝试将token解析为int，然后再尝试将其解析为`+`double。|2471978|entityMap^0|0|0|0|0|11|D|0|0|0|7|3|H|6|16|3|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|Z|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|10|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|11|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|12|8|@$M|13|N|14|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|F|7|15|8|@]|9|@]|A|$]]|$1|S|3|T|5|6|7|16|8|@]|9|@]|A|$B|C]]|$1|U|3|V|5|F|7|17|8|@$M|18|N|19|O|P]|$M|1A|N|1B|O|P]|$M|1C|N|1D|O|P]]|9|@]|A|$]]|$1|W|3|-4|5|F|7|1E|8|@]|9|@]|A|$]]]|X|$]]

<pre><code>if (numerator is int) { ... }
</code></pre>

or 

<pre><code>if (numerator.GetType() == typeof(int)) {...}
</code></pre>

The former is usually better.

EDIT:
Нou say the problem is parsing numbers from string representation. I'm afraid, the best approach here is to call <code>type.TryParse</code> and check if given string can be parsed as a number of given type.

E.g.

<pre><code>var tokens = line.Split('/');
double dArg1,dArg2; int iArg1, iArg2;
if (int.TryParse(tokens[0], out iArg1) 
 &amp;&amp; int.TryParse(tokens[1], out iArg2)){
 return iArg1/iArg2;
} else if (double.TryParse(tokens[0], out dArg1) 
 &amp;&amp; double.TryParse(tokens[1], out dArg2)){
 return dArg1/dArg2;
} else { /* handle error */ }
</code></pre>

Note that all <code>int</code>s can be parsed as <code>double</code>s, so you need to try to parse token as <code>int</code> before trying to parse it as `double.

blocks|key|4547514|text|if+(numerator.GetType()+==+typeof(int))
{
++++...
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4547515|typeof+(MSDN)|unstyled|offset|length|4547516|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/58918ffs%2528v=VS.100%2529.aspx^0|0|0|D|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@$G|S|H|T|1|U]]|A|$]]|$1|I|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]]]

<pre><code>if (numerator.GetType() == typeof(int))
{
 ...
}
</code></pre>

<a href="http://msdn.microsoft.com/en-us/library/58918ffs%28v=VS.100%29.aspx" rel="noreferrer">typeof (MSDN)</a>

blocks|key|2757579|text|您可以使用typeof-运算符：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2757580|if(typeof(int)+==+numerator.GetType())
{
++++//put+code+here
}|code-block|syntax|javascript|2757581|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use the typeof-operator:

<pre><code>if(typeof(int) == numerator.GetType())
{
 //put code here
}
</code></pre>

blocks|key|2757564|text|您应该尝试is/as操作符：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2757565|if+(numerator+is+int)+{...}|code-block|syntax|javascript|2757566|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You should try the is/as operator:

<pre><code>if (numerator is int) {...}
</code></pre>

blocks|key|2757583|text|使用+operator+in+C#。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2757584|if(number+is+int)|code-block|syntax|javascript|2757585|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/scekt9xw%2528v=VS.80%2529.aspx^0|2|F|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Use the <a href="http://msdn.microsoft.com/en-us/library/scekt9xw%28v=VS.80%29.aspx" rel="nofollow">is operator in C#</a>.

<pre><code>if(number is int)
</code></pre>

blocks|key|4547648|text|使用以下内容：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4547649|if+(+value+is+int+)+{+}|code-block|syntax|javascript|4547650|您可能还想看看Generic+Methods+(C#+Programming+Guide)|offset|length|4547651|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/twcad0zb%2528v=VS.100%2529.aspx^0|0|0|7|12|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Use the following:

<pre><code>if ( value is int ) { }
</code></pre>

You may also want to take a look at <a href="http://msdn.microsoft.com/en-us/library/twcad0zb%28v=VS.100%29.aspx" rel="nofollow">Generic Methods (C# Programming Guide)</a>

blocks|key|4547634|text|这应该是可行的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4547635|if+(numerator.GetType()+==+typeof(int))
{
+++//+it's+an+int

}

else+if+(numerator.GetType()+==+typeof(double))
{
+++//+it's+a+double
}|code-block|syntax|javascript|4547636|不知道你为什么要这么做...|4547637|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

This should work:

<pre><code>if (numerator.GetType() == typeof(int))
{
 // it's an int

}

else if (numerator.GetType() == typeof(double))
{
 // it's a double
}
</code></pre>

Not sure why you'd want to do that though...

blocks|key|855145|text|C#+7|type|unstyled|depth|inlineStyleRanges|entityRanges|data|855146|if+(number+is+int+myint)+{//;+do+something+with+myint}+OR

if+(number+is+double+mydouble)+{//;+do+something+with+mydouble}|code-block|syntax|javascript|855147|如果类型匹配，则每种情况都为真。cast值将被放入变量中。|855148|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

C# 7

<pre><code>if (number is int myint) {//; do something with myint} OR

if (number is double mydouble) {//; do something with mydouble}
</code></pre>

Each case is true if the type matches. The cast value will be placed in the variable.

if I have int number in nominator, I will do one method from my1.cs, if I have double number in nominator/denominator I will do method from another class called my2.cs . How I may code IF, 

<code>if (number = int) {//; bla bla bla...}</code> 
OR

<code>if (number = double) {//; bla bla bla...}</code>

How to code this if-statement: <code>if (numerator.GetType==int){...}</code> ?

The main trouble is in this: I read nominator and denominator from textbox, with var dr1 = textBox1.Text.Split('/'); ! split, but how i can gettype from string ???

If-statement GetType() c#

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

如果我在nominator中有int number，我将从my1.cs中做一个方法，如果我在nominator/denominator中有两个number，我将从另一个名为my2.cs的类中做方法。我该如何编码如果，if (number = int) {//; bla bla bla...} ORif (number = double) {//; bla bla bla...}如何编写这个if-s

问If语句GetType() c#
EN

回答 8

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问If语句GetType() c#EN

回答 8

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问If语句GetType() c#
EN