blocks|key|2440658|text|如果想要在两个条件都为真时打印它，则必须使用and|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2440659|if+(int(one[1])+==+solution)+and+(int(two[1])+==+solution):
++++print+"Hello,+world"|code-block|syntax|javascript|2440660|如果您想打印它，如果一个或多个条件为真，则必须以相同的方式使用or|BOLD|2440661|if+(int(one[1])+==+solution)+or+(int(two[1])+==+solution):
++++print+"Hello,+world"+|2440662|您不应该使用elif。至少如果我理解你的话。|2440663|elif用于测试不同的条件如果if语句中的条件为false，请考虑以下模式|2440664|if+spam:
++++do_eggs()+#+We+arrive+here+if+spam+is+true
elif+ham:
++++do_sausages()+#+Here+if+spam+was+false+but+ham+is+true
else:
++++print+"Camelot!"+#+And+here+if+both+were+false|2440665|PS：|2440666|if+spam:
++++do_eggs()
elif+ham:
++++do_eggs()|2440667|这确实是做if+spam+or+ham:+do_eggs()的一种扭曲的方式，但它真的很丑陋。你不敢用这个，否则你会被炸成碎片。|2440668|entityMap^0|M|3|0|0|A|5|V|2|0|0|6|4|0|0|4|F|2|0|0|0|0|5|P|1B|G|0^^$0|@$1|2|3|4|5|6|7|13|8|@$9|14|A|15|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|17|8|@$9|18|A|19|B|M]|$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|N|3|O|5|H|7|1C|8|@]|D|@]|E|$I|J]]|$1|P|3|Q|5|6|7|1D|8|@$9|1E|A|1F|B|C]]|D|@]|E|$]]|$1|R|3|S|5|6|7|1G|8|@$9|1H|A|1I|B|C]|$9|1J|A|1K|B|C]]|D|@]|E|$]]|$1|T|3|U|5|H|7|1L|8|@]|D|@]|E|$I|J]]|$1|V|3|W|5|6|7|1M|8|@]|D|@]|E|$]]|$1|X|3|Y|5|H|7|1N|8|@]|D|@]|E|$I|J]]|$1|Z|3|10|5|6|7|1O|8|@$9|1P|A|1Q|B|C]|$9|1R|A|1S|B|M]]|D|@]|E|$]]|$1|11|3|-4|5|6|7|1T|8|@]|D|@]|E|$]]]|12|$]]

If you want to print it when both conditions are true you have to use <code>and</code>

<pre><code>if (int(one[1]) == solution) and (int(two[1]) == solution):
 print "Hello, world"
</code></pre>

if you want to print it if one ore more condition is true you have to use <code>or</code> the same way 

<pre><code>if (int(one[1]) == solution) or (int(two[1]) == solution):
 print "Hello, world" 
</code></pre>

You shouldn't have to use <code>elif</code>. At least if I understand you.

<code>elif</code> is for testing a different condition if the condition in the<code>if</code> statement is false, consider this pattern

<pre><code>if spam:
 do_eggs() # We arrive here if spam is true
elif ham:
 do_sausages() # Here if spam was false but ham is true
else:
 print "Camelot!" # And here if both were false
</code></pre>

PS: 

<pre><code>if spam:
 do_eggs()
elif ham:
 do_eggs()
</code></pre>

would indeed be a twisted way of doing <code>if spam or ham: do_eggs()</code> but it really is ugly. Dost thou not dare use this or thou shalt be blown to tiny bits.

blocks|key|4516585|text|if+(int(one[1])+==+solution)+and+(int(two[1])+==+solution):
+++print+'Helloworld'|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4516586|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>if (int(one[1]) == solution) and (int(two[1]) == solution):
 print 'Helloworld'
</code></pre>

blocks|key|824396|text|您所需要的就是它们之间的OR运算：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|824397|if+(int(one[1])+==+solution)+or+(int(two[1])+==+solution)):
++++print+"Hello+World"|code-block|syntax|javascript|824398|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

All you need is an OR between them:

<pre><code>if (int(one[1]) == solution) or (int(two[1]) == solution)):
 print "Hello World"
</code></pre>

blocks|key|4516623|text|if+int(one[1])+==+solution+or+int(two[1])+==+solution:
++++print+"Hello+world"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4516624|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>if int(one[1]) == solution or int(two[1]) == solution:
 print "Hello world"
</code></pre>

blocks|key|2440728|text|您也可以使用列表而不是"or"，这在有很多选择时很方便。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2440729|if+solution+in+[int(one[1]),+int(two[1]),+int(three[0])]:+|code-block|syntax|javascript|2440730|​|2440731|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can also use a list instead of "or", which is handy when there are many choices. <pre><code>if solution in [int(one[1]), int(two[1]), int(three[0])]: </pre></code>

If I wanted a group of if elif statements to execute to a single order; for example:

<pre><code>if int(one[1]) == solution:
</code></pre>

and 

<pre><code>if int(two[1]) == solution:
</code></pre>

to execute a a single statement: 

<pre><code>print "Hello World"
</code></pre>

What would be the best format and syntaxically correct way to input this?

I tried:

<pre><code>if int(two[1]) == solution::
 elif int(one[1]) == solution:
 print "Hello World"
</code></pre>

and other variations but couldn't put my figure on a correct way to do it. Be gentle StackOverflow, I haven't been programming too long. 

And the language I'm programming in is Python. 
Thanks!

UPDATE:

I think this is the correct answer, not AND Abdul Kader. Thank you both though. And in Python I think I'll be typing:

<pre><code>if (int(one[1]) == solution OR int(two[1])== solution)):
 print "Hello World"
</code></pre>

Quick question regarding format of if-elif statements

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如果我想要一组If elif语句以单一顺序执行；例如：if int(one[1]) == solution:和if int(two[1]) == solution:要执行单个语句，请执行以下操作：print "Hello World"输入它的最佳格式和语法正确的方式是什么？我试过了：if int(two[1]) == ...

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