在php中做一个引用
在php中做一个引用
提问于 2016-02-10 00:41:16
我的加法有一个问题:所以我有这样的代码：
$total = 0;
foreach(getHistory($this->id) as $history){
$aHistoryFilter['date'] = $history['date'];
$aHistoryFilter['ls'] = $history['ls']);
$aHistoryFilter['montant'] = $history['montant'];
$aHistoryFilter['total_montant'] = $total+$history['montant'];
$aHistory[] = $aHistoryFilter;
}
return $aHistory;所以我想把最后一个值保存在total_montant中，而不是工作，我不理解why...Can，你能帮我吗？提前进行Thx
回答 3
Stack Overflow用户
发布于 2016-02-10 00:44:48
您还应执行以下操作：
$total = $total + $history['montant'];否则，您不需要添加任何内容(从$total=0;开始)
所以你会得到：
foreach(getHistory($this->id) as $history){
$aHistoryFilter['date'] = $history['date'];
$aHistoryFilter['ls'] = $history['ls']);
$aHistoryFilter['montant'] = $history['montant'];
$aHistoryFilter['total_montant'] = $total+$history['montant'];
$total = $total + $history['montant'];
$aHistory[] = $aHistoryFilter;
}Stack Overflow用户
发布于 2016-02-10 00:45:36
将您的代码更新为：
$total = 0;
foreach(getHistory($this->id) as $history){
$aHistoryFilter['date'] = $history['date'];
$aHistoryFilter['ls'] = $history['ls']);
$aHistoryFilter['montant'] = $history['montant'];
$total = $total+$history['montant'];
$aHistory[] = $aHistoryFilter;
}
$aHistoryFilter['total_montant'] = $total ;因为在您的代码中，您对$total执行$history['montant']操作，但没有将结果赋值给$total
Stack Overflow用户
发布于 2016-02-10 00:46:55
试试这个：
$total = 0;
foreach(getHistory($this->id) as $history){
$aHistoryFilter['date'] = $history['date'];
$aHistoryFilter['ls'] = $history['ls']);
$aHistoryFilter['montant'] = $history['montant'];
// this adds the $history['montant'] to the $total
$total += $history['montant'];
// this adds the $total to your variable
$aHistoryFilter['total_montant'] = $total;
$aHistory[] = $aHistoryFilter;
}
return $aHistory;页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/35297425
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