wit.ai -如何在Java中发送请求？
wit.ai -如何在Java中发送请求？
提问于 2016-02-12 16:46:56
我正在用Java语言开发一个使用wit.ai的虚拟助手，但我无法发出HTTP请求。我不是Java中HTTP请求的专家，我一直收到一个错误400。
这是我的代码：
public class CommandHandler {
public static String getCommand(String command) throws Exception {
String url = "https://api.wit.ai/message";
String key = "TOKEN HERE";
String param1 = "20141022";
String param2 = command;
String charset = "UTF-8";
String query = String.format("v=%s&q=%s",
URLEncoder.encode(param1, charset),
URLEncoder.encode(param2, charset));
URLConnection connection = new URL(url + "?" + query).openConnection();
connection.setRequestProperty ("Authorization Bearer", key);
connection.setRequestProperty("Accept-Charset", charset);
InputStream response = connection.getInputStream();
return response.toString();
}}
这是wit.ai给出的例子：
$ curl \
-H 'Authorization: Bearer $TOKEN' \
'https://api.wit.ai/message?v=20141022&q=hello'我希望有人能帮助我。
回答 2
Stack Overflow用户
发布于 2017-02-18 17:44:17
以下是快速检查rest api的简单代码
try {
URL url = new URL("https://api.wit.ai/message?v=20170218&q=Hello");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
conn.setRequestProperty("Accept", "application/json");
conn.setRequestProperty("Authorization", "Bearer addkeyhere");
if (conn.getResponseCode() != 200) {
throw new RuntimeException("Failed : HTTP error code : "
+ conn.getResponseCode());
}
BufferedReader br = new BufferedReader(new InputStreamReader(
(conn.getInputStream())));
String output;
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null) {
System.out.println(output);
}
conn.disconnect();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}Stack Overflow用户
发布于 2016-09-03 19:29:48
这对我来说非常有效！
connection.setRequestProperty ("Authorization": "Bearer "+key);页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/35358232
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