blocks|key|3258554|text|基本上，您可以将日期/时间戳分别转换为日期和时间，然后使用GROUP+BY获得所需的结果。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3258555|MySQL/SQL:+Group+by+date+only+on+a+Datetime+column|offset|length|3258556|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/366603/mysql-sql-group-by-date-only-on-a-datetime-column^0|0|0|1E|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@$D|P|E|Q|1|R]]|A|$]]|$1|F|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|G|$H|$5|I|J|K|A|$L|M]]]]

Basically, you can cast the DATETIME/TIMESTAMP into dates, and times separately, and then use a GROUP BY to get the results you need.

<a href="https://stackoverflow.com/questions/366603/mysql-sql-group-by-date-only-on-a-datetime-column">MySQL/SQL: Group by date only on a Datetime column</a>

blocks|key|3258584|text|您需要聚合您的数据。尝试此查询：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3258585|SELECT+DATE(data_timestamp),+COUNT(visitor_id)
FROM+analytics_table
WHERE+DATE(data_timestamp)+BETWEEN+'2011-05-01'+AND+'2011-05-31'
GROUP+BY+1|code-block|syntax|javascript|3258586|以下是如何填充每月数据(警告:未测试！)：|offset|length|style|BOLD|3258587|<?php
$sql+=+"SELECT+DATE(data_timestamp),+COUNT(visitor_id)
FROM+analytics_table
WHERE+DATE(data_timestamp)+BETWEEN+'2011-05-01'+AND+'2011-05-31'
GROUP+BY+1";

$rs+=+mysql_query($rs);
$date1+=+$datex+=+'2011-05-01';
$date2+=+'2011-05-31';

$arrayData+=+$tmpArray+=+array();

while(+$r+=+mysql_fetch_array($rs)+)
{
+++$tmpArray[$r['date']]+=+$r['count'];
}

while(+$datex+<=+$date2)
{
+++if(+isset($tmpArray[$datex])+)
+++{
++++++$arrayData[$datex]+=+$tmpArray[$datex];
+++}
+++else
+++{
++++++$arrayData[$datex]+=+0;
+++}
+++list(+$y,+$m,+$d)+=+explode('-',+$datex);
+++$datex+=+date('Y-m-d',+mktime(0,+0,+0,+$m,+$d,+$y));
}


?>|3258588|此查询使用：|3258589|3258590|unordered-list-item|3258591|()从您的数据中获取日期，|3258592|+count+()计算该特定日期的总数据。|3258593|和GROUP+BY根据您选择的字段对数据进行分组。|3258594|3258595|entityMap^0|0|0|C|7|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|14|8|@$I|15|J|16|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|18|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|19|8|@]|9|@]|A|$]]|$1|R|3|-4|5|S|7|1A|8|@]|9|@]|A|$]]|$1|T|3|U|5|6|7|1B|8|@]|9|@]|A|$]]|$1|V|3|W|5|S|7|1C|8|@]|9|@]|A|$]]|$1|X|3|Y|5|S|7|1D|8|@]|9|@]|A|$]]|$1|Z|3|-4|5|6|7|1E|8|@]|9|@]|A|$]]|$1|10|3|-4|5|6|7|1F|8|@]|9|@]|A|$]]]|11|$]]

You will need to aggregate your data. Try this query:

<pre><code>SELECT DATE(data_timestamp), COUNT(visitor_id)
FROM analytics_table
WHERE DATE(data_timestamp) BETWEEN '2011-05-01' AND '2011-05-31'
GROUP BY 1
</code></pre>

Here's how you populate your monthly data (WARNING: UNTESTED!):

<pre><code>&lt;?php
$sql = "SELECT DATE(data_timestamp), COUNT(visitor_id)
FROM analytics_table
WHERE DATE(data_timestamp) BETWEEN '2011-05-01' AND '2011-05-31'
GROUP BY 1";

$rs = mysql_query($rs);
$date1 = $datex = '2011-05-01';
$date2 = '2011-05-31';

$arrayData = $tmpArray = array();

while( $r = mysql_fetch_array($rs) )
{
 $tmpArray[$r['date']] = $r['count'];
}

while( $datex &lt;= $date2)
{
 if( isset($tmpArray[$datex]) )
 {
 $arrayData[$datex] = $tmpArray[$datex];
 }
 else
 {
 $arrayData[$datex] = 0;
 }
 list( $y, $m, $d) = explode('-', $datex);
 $datex = date('Y-m-d', mktime(0, 0, 0, $m, $d, $y));
}


?&gt;
</code></pre>

this query use:

<ul>
<li>DATE() to get the date from your data and</li>
<li>COUNT() to count total data from that particular date.</li>
<li>and GROUP BY to group your data based on what field you select.</li>
</ul>

blocks|key|3258637|text|如果某天没有访问者，GROUP+BY不会返回0值。这将导致时间连续性的漏洞。有两种方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3258638|1)像别人说的那样分组，然后找洞|3258639|2)创建包含date、count等字段的聚合表，并通过cron每天在其中插入数据。|3258640|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

GROUP BY doesn't return 0 value if there is no visitor some day. That will yield to the holes in time continuity. There are two ways:

1) Group like others said and then find holes

2) Create aggregation table with fields "date", "count" etc. and insert there data every day by cron.

I've found a few query strings related to what I'm looking for, but nothing that does this. Basically, I have a graph that needs to display unique visitors per time interval (hour, day, month, or year). So, a graph similar to Google Analytics or <a href="http://demo.openwebanalytics.com/owa/" rel="nofollow">this Analytics Graph</a>. The table has a visitor ID column and a timestamp column (in the style 0000-00-00 00:00:00). I need to be able to select the unique or total visitors per interval (eg. 32 visitors on the 5th, 30 on the 6th, etc).

I guess my question is, is there anyway to do this efficiently with just a query? Or will I need to use PHP to get all the data (problem with that is that I would have to do a query for each point on the graph, not efficient)?

How to select unique visitors per date interval?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我已经找到了一些与我要查找的内容相关的查询字符串，但没有一个能做到这一点。基本上，我有一个图表，需要显示每个时间间隔(小时，日，月，或年)的唯一访问者。因此，这是一个类似于谷歌分析或的图表。该表有一个访问者ID列和一个时间戳列(样式为0000-00-00 00:00:00)。我需要能够选择每个时间间隔的唯一或总访问者(...

问如何选择每个日期间隔的唯一访客？
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问如何选择每个日期间隔的唯一访客？EN