blocks|key|3339993|text|如果您希望能够将参数传递给另一个进程，或者处理以空格分隔的参数，最好的方法是重新set参数：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3339994|$+x(){+echo+"Parameter+count+before:+$#";+set+--+"${@:1:2}"+"${@:4:8}";+echo+"$@";+echo+"Parameter+count+after:+$#";+}
$+x+1+2+3+4+5+6+7+8
Parameter+count+before:+8
1+2+4+5+6+7+8
Parameter+count+after:+7|code-block|syntax|javascript|3339995|要测试它是否与非平凡参数一起工作：|3339996|$+x+$'a\n1'+$'b\b2'+'c+3'+'d+4'+'e+5'+'f+6'+'g+7'+$'h\t8'
Parameter+count+before:+8
a
1+2+d+4+e+5+f+6+g+7+h+++8
Parameter+count+after:+7|3339997|(是的，$'\b'是一个退格键)|3339998|entityMap^0|14|3|0|0|0|0|4|5|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|R|$]]

The best way, if you want to be able to pass on the parameters to another process, or handle space separated parameters, is to re-<code>set</code> the parameters:

<pre><code>$ x(){ echo "Parameter count before: $#"; set -- "${@:1:2}" "${@:4:8}"; echo "$@"; echo "Parameter count after: $#"; }
$ x 1 2 3 4 5 6 7 8
Parameter count before: 8
1 2 4 5 6 7 8
Parameter count after: 7
</code></pre>

To test that it works with non-trivial parameters:

<pre><code>$ x $'a\n1' $'b\b2' 'c 3' 'd 4' 'e 5' 'f 6' 'g 7' $'h\t8'
Parameter count before: 8
a
1 2 d 4 e 5 f 6 g 7 h 8
Parameter count after: 7
</code></pre>

(Yes, <code>$'\b'</code> is a backspace)

blocks|key|3340093|text|x(){
++++#CODE
++++params=(+$*+)
++++unset+params[2]
++++set+--+"${params[@]}"

++++echo+"$@"
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3340094|输入:x+1+2+3+4+5+6+7+8|unstyled|3340095|输出:1+2+4+5+6+7+8|3340096|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>x(){
 #CODE
 params=( $* )
 unset params[2]
 set -- "${params[@]}"

 echo "$@"
}
</code></pre>

Input:
x 1 2 3 4 5 6 7 8

Output:
1 2 4 5 6 7 8

blocks|key|5124347|text|来自tldp|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|5124348|#+The+"unset"+command+deletes+elements+of+an+array,+or+entire+array.
unset+colors[1]++++++++++++++#+Remove+2nd+element+of+array.
+++++++++++++++++++++++++++++#+Same+effect+as+++colors[1]=
echo++${colors[@]}+++++++++++#+List+array+again,+missing+2nd+element.

unset+colors+++++++++++++++++#+Delete+entire+array.
+++++++++++++++++++++++++++++#++unset+colors[*]+and
+++++++++++++++++++++++++++++#%2B+unset+colors[@]+also+work.
echo;+echo+-n+"Colors+gone."+++++++++++++++
echo+${colors[@]}++++++++++++#+List+array+again,+now+empty.|code-block|syntax|javascript|5124349|entityMap|0|LINK|mutability|MUTABLE|url|http://tldp.org/LDP/abs/html/arrays.html^0|2|4|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

From <a href="http://tldp.org/LDP/abs/html/arrays.html" rel="noreferrer">tldp</a>

<pre><code># The "unset" command deletes elements of an array, or entire array.
unset colors[1] # Remove 2nd element of array.
 # Same effect as colors[1]=
echo ${colors[@]} # List array again, missing 2nd element.

unset colors # Delete entire array.
 # unset colors[*] and
 #+ unset colors[@] also work.
echo; echo -n "Colors gone." 
echo ${colors[@]} # List array again, now empty.
</code></pre>

blocks|key|1438869|text|您可以随时调用set并重置位置参数，例如|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1438870|function+q+{
echo+${@}
set+$2+$3+$4
echo+${@}
set+$4
echo+${@}
}

q+1+2+3+4|code-block|syntax|javascript|1438871|然后从数组中切出你不想要的东西，下面的代码做到了这一点…虽然不确定这是否是最好的方法，但在堆栈中正在寻找更好的方法；)|1438872|#!/bin/bash


q=(+one+two+three+four+five+)

echo+-e+"
++(remove)+{+[:range:]+}+<-+[:list:]
++++++++++++++++%7C+[:range:]+=>+return+list+with+range+removed+range+is+in+the+form+of+[:digit:]-[:digit:]
"

function+remove+{
++if+[[+$1+=~+([[:digit:]])(-([[:digit:]]))?+++]];+then
++++from=${BASH_REMATCH[1]}
++++to=${BASH_REMATCH[3]}
++else
++++echo+bad+range
++fi;shift
++array=(+${@}+)
++local+start=${array[@]::${from}}
++local+rest
++[+-n+"$to"+]+&&+rest=${array[@]:((${to}%2B1))}++%7C%7C+rest=${array[@]:((${from}%2B1))}
++echo+${start[@]}+${rest[@]}
}

q=(+`remove+1+${q[*]}`+)
echo+${q[@]}|1438873|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You can call set and reset the positional paramaters at any time 
for example 

<pre><code>function q {
echo ${@}
set $2 $3 $4
echo ${@}
set $4
echo ${@}
}

q 1 2 3 4
</code></pre>

then slice out what you dont want from the array, the below code does that... not sure if its the best way to do it though, was on stack looking for a better way ; )

<pre><code>#!/bin/bash


q=( one two three four five )

echo -e "
 (remove) { [:range:] } &lt;- [:list:]
 | [:range:] =&gt; return list with range removed range is in the form of [:digit:]-[:digit:]
"

function remove {
 if [[ $1 =~ ([[:digit:]])(-([[:digit:]]))? ]]; then
 from=${BASH_REMATCH[1]}
 to=${BASH_REMATCH[3]}
 else
 echo bad range
 fi;shift
 array=( ${@} )
 local start=${array[@]::${from}}
 local rest
 [ -n "$to" ] &amp;&amp; rest=${array[@]:((${to}+1))} || rest=${array[@]:((${from}+1))}
 echo ${start[@]} ${rest[@]}
}

q=( `remove 1 ${q[*]}` )
echo ${q[@]}
</code></pre>

blocks|key|3054527|text|使用shift+%2Bset在"$@“上循环时:将每个参数从第一个位置移动到最后一个位置，但"test”除外。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3054528|#+remove+option+"test"+from+positional+parameters
i=1
while+[+$i+-le+$#+]
++do
++++var="$1"
++++case+"$var"+in
++++++test)
++++++++echo+"param+\"$var\"+deleted"
++++++++i=$(($i-1))
++++++;;
++++++*)
++++++++set+--+"$@"+"$var"
++++++;;
++++esac
++++shift
++++i=$(($i%2B1))
done|code-block|syntax|javascript|3054529|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

while loop over "$@" with shift + set: move each parameter from first to last position, except "test"

<pre><code># remove option "test" from positional parameters
i=1
while [ $i -le $# ]
 do
 var="$1"
 case "$var" in
 test)
 echo "param \"$var\" deleted"
 i=$(($i-1))
 ;;
 *)
 set -- "$@" "$var"
 ;;
 esac
 shift
 i=$(($i+1))
done
</code></pre>

You can skip positional parameters with <code>shift</code> but can you delete positional parameters by passing the position?

<pre><code>x(){ CODE; echo "$@"; }; x 1 2 3 4 5 6 7 8
&gt; 1 2 4 5 6 7 8
</code></pre>

I would like to add CODE to <code>x()</code> to delete positional parameter 3. I don't want to do <code>echo "${@:1:2} ${@:4:8}"</code>. After running CODE, <code>$@</code> should only contain "1 2 4 5 6 7 8".

Delete positional parameters in Bash?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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您可以使用shift跳过位置参数，但是您可以通过传递位置来删除位置参数吗？x(){ CODE; echo "$@"; }; x 1 2 3 4 5 6 7 8> 1 2 4 5 6 7 8我想在x()中添加删除位置参数3的代码。我不想做echo "${@:1:2} ${@:4:8}"。运行代码后，$@应该只包含“%1 2%4%5%6%7% 8”。

问是否删除Bash中的位置参数？
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回答 5

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问是否删除Bash中的位置参数？EN

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问是否删除Bash中的位置参数？
EN