blocks|key|3168039|text|选项1:按任务对象上的键顺序输出：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3168040|也许有一种更优雅的方法，但这种方法将所有任务的键从对象中取出，对它们进行排序，然后使用有序索引数组按键的顺序遍历原始对象(如果我正确理解您要做的事情的话)。|3168041|var+indexArray+=+[];
var+i;
for+(i+in+tasks)+{
++++indexArray.push(i);+++//+collect+all+indexes
}
indexArray.sort(function(a,b)+{return(a-b);});++//+sort+the+array+in+numeric+order
for+(i+=+0;+i+<+indexArray.length;+i%2B%2B)+{
++++console.log(tasks[indexArray[i]].name);
}|code-block|syntax|javascript|3168042|您可以使用tasks.keys作为获取对象索引的快捷方式，但这并不是普遍可用的，因此无论如何您都必须有一种替代方法。|3168043|选项2:按嵌入索引tasksi.index的顺序输出：|3168044|再读一遍你的问题，我意识到可能还有另一种方式来解释你的问题。也许您是指在索引顺序中，.name旁边的.index数据，而不是tasks对象上的索引键。如果是这样的话，就需要一个不同的例程：|3168045|var+sorted+=+[];
var+i;
for+(i+in+tasks)+{
++++sorted.push(tasks[i]);+++//+collect+items+from+tasks+into+a+sortable+array
}
sorted.sort(function(a,b)+{return(a.index+-+b.index);});++//+sort+the+array+in+numeric+order+by+embedded+index
for+(i+=+0;+i+<+sorted.length;+i%2B%2B)+{
++++console.log(sorted[i].name);
}|3168046|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|V|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|W|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|X|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

<h2>Option 1: Output in order of the keys on the task object:</h2>

<p>Perhaps there is a more elegant way, but this way gets all the tasks keys out of the object, sorts them and then uses the ordered index array to cycle through the original object in key order (if I understood correctly what you're trying to do).</p>

<pre><code>var indexArray = [];
var i;
for (i in tasks) {
    indexArray.push(i);   // collect all indexes
}
indexArray.sort(function(a,b) {return(a-b);});  // sort the array in numeric order
for (i = 0; i &lt; indexArray.length; i++) {
    console.log(tasks[indexArray[i]].name);
}
</code></pre>

<p>You could use tasks.keys as a shortcut to getting the object indexes, but that is not universally available so you'd have to have an alternate way of doing it anyway.</p>

<h2>Option 2: Output in order of the embedded index tasks[i].index:</h2>

<p>Reading your question again, I realized that there may be another way to interpret your question.  Perhaps you meant in index order where it's the .index data right next to the .name, not the index key on the tasks object.  If so, that would take a different routine:</p>

<pre><code>var sorted = [];
var i;
for (i in tasks) {
    sorted.push(tasks[i]);   // collect items from tasks into a sortable array
}
sorted.sort(function(a,b) {return(a.index - b.index);});  // sort the array in numeric order by embedded index
for (i = 0; i &lt; sorted.length; i++) {
    console.log(sorted[i].name);
}
</code></pre>


blocks|key|8548|text|您可以将所有名称放在一个临时数组中，然后对该数组调用sort()方法。检查此link|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|8549|问候|8550|entityMap|0|LINK|mutability|MUTABLE|url|http://www.w3schools.com/jsref/jsref_sort.asp^0|Q|6|12|4|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@$9|S|A|T|1|U]]|E|$]]|$1|F|3|G|5|6|7|V|8|@]|D|@]|E|$]]|$1|H|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]]]

<p>You could stick all names in a temp array and then call the <code>sort()</code> method on that array.
Check this <a href="http://www.w3schools.com/jsref/jsref_sort.asp" rel="nofollow">link</a></p>

<p>Regards</p>


blocks|key|3168092|text|可以将函数传递给array对象的sort方法，该方法用于确定数组中对象的顺序。默认情况下，它按字母和数字顺序执行此操作，但数字方式有点混乱。下面是我如何解决您的问题，假设您用来对它们进行排序的索引是数字的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3168093|tasks.sort(function(obj1,obj2){
++++return+obj1.index+-+obj2.index;
});|code-block|syntax|javascript|3168094|如果为object1>object2，则传递给sort方法的函数应返回正整数；如果为object1=object2，则返回0；如果为object1，则返回负整数|3168095|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

<p>You can pass a function to the sort method of the Array object, which is used to determine the order of the objects in the array. By default, it does this alphabetically and numerically but the numerical way is a bit messed up. Here is how I'd solve your case, assuming that the indexes you're using to sort them are numerical:</p>

<pre><code>tasks.sort(function(obj1,obj2){
    return obj1.index - obj2.index;
});
</code></pre>

<p>The function passed to the sort method should return a positive integer if object1>object2, 0 if object1=object2, and a negative integer if object1


<p>I have an Object of Objects. (because I want to use associative array, so object of objects, not numeric array of objects)</p>

<pre><code>var tasks=new Object();

for(...){
tasks[foo-i]={};
tasks[foo-i].index=....;
tasks[foo-i].name=...;
}
</code></pre>

<p>I have a function that'll output the name of the tasks, but they have to be according to the index in ascending order. So, I'll have to have a temporary sort-function.
How would you do that?
Thanks</p>


javascript sort object of objects

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

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我有一个对象的对象。(因为我要使用关联数组，所以对象的对象，而不是对象的数值数组)var tasks=new Object();for(...){tasks[foo-i]={};tasks[foo-i].index=....;tasks[foo-i].name=...;}我有一个输出任务名称的函数，但它们必须按照索引的...

问javascript对对象的对象排序
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