blocks|key|3483405|text|假设您有一个数组users。您可以使用users.sort并传递一个接受两个参数并进行比较的函数(比较器)|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3483406|它应该会返回|3483407|如果第一个参数小于第二个参数，则为负的元素(如果第一个参数大于第二个参数，则应放在第二个参数的前面(如果第一个参数大于第二个参数，则应放在第二个参数之后)。|3483408|0，如果这两个元素相等，则|unordered-list-item|3483409|
|3483410|0。|3483411|3483412|在我们的例子中，如果两个元素是a和b，我们想要比较a.firstname和b.firstname|3483413|示例：|3483414|users.sort(function(a,+b){
++++if(a.firstname+<+b.firstname)+{+return+-1;+}
++++if(a.firstname+>+b.firstname)+{+return+1;+}
++++return+0;
})|code-block|syntax|javascript|3483415|这段代码适用于任何类型。|3483416|请注意，在“现实生活”™中，当您比较字符串时，您通常希望忽略大小写，正确排序变音符号，奇怪的符号，等等，所以您可能想要使用localeCompare。为了清楚起见，请参阅其他答案。|3483417|entityMap^0|8|5|J|A|0|0|0|0|0|0|0|F|1|H|1|P|B|11|B|0|0|0|0|1P|D|0^^$0|@$1|2|3|4|5|6|7|16|8|@$9|17|A|18|B|C]|$9|19|A|1A|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1B|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|1C|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|1D|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|1E|8|@]|D|@]|E|$]]|$1|O|3|P|5|L|7|1F|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|1G|8|@]|D|@]|E|$]]|$1|R|3|S|5|6|7|1H|8|@$9|1I|A|1J|B|C]|$9|1K|A|1L|B|C]|$9|1M|A|1N|B|C]|$9|1O|A|1P|B|C]]|D|@]|E|$]]|$1|T|3|U|5|6|7|1Q|8|@]|D|@]|E|$]]|$1|V|3|W|5|X|7|1R|8|@]|D|@]|E|$Y|Z]]|$1|10|3|11|5|6|7|1S|8|@]|D|@]|E|$]]|$1|12|3|13|5|6|7|1T|8|@$9|1U|A|1V|B|C]]|D|@]|E|$]]|$1|14|3|-4|5|6|7|1W|8|@]|D|@]|E|$]]]|15|$]]

Suppose you have an array <code>users</code>. You may use <code>users.sort</code> and pass a function that takes two arguments and compare them (comparator)
It should return
<ul>
<li>something negative if first argument is less than second (should be placed before the second in resulting array)</li>
<li>something positive if first argument is greater (should be placed after second one)</li>
<li>0 if those two elements are equal.</li>
</ul>
In our case if two elements are <code>a</code> and <code>b</code> we want to compare <code>a.firstname</code> and <code>b.firstname</code>
Example:
<pre><code>users.sort(function(a, b){
 if(a.firstname &lt; b.firstname) { return -1; }
 if(a.firstname &gt; b.firstname) { return 1; }
 return 0;
})
</code></pre>
This code is going to work with any type.
Note that in &quot;real life&quot;™ you often want to ignore case, correctly sort diacritics, weird symbols like ß, etc when you compare strings, so you may want to use <code>localeCompare</code>. See other answers for clarity.

blocks|key|24225|text|用ES6编写尽可能短的代码！|type|unstyled|depth|inlineStyleRanges|entityRanges|data|24226|users.sort((a,+b)+=>+a.firstname.localeCompare(b.firstname))|code-block|syntax|javascript|24227|String.prototype.localeCompare()+basic支持是通用的！|offset|length|24228|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/localeCompare#Browser_compatibility^0|0|0|0|W|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Shortest possible code with ES6!
<pre><code>users.sort((a, b) =&gt; a.firstname.localeCompare(b.firstname))
</code></pre>
<a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/localeCompare#Browser_compatibility" rel="noreferrer">String.prototype.localeCompare()</a> basic support is universal!

blocks|key|3198574|text|如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3198575|array.sort(function(a,+b){
+var+nameA=a.name.toLowerCase(),+nameB=b.name.toLowerCase();
+if+(nameA+<+nameB)+//sort+string+ascending
++return+-1;
+if+(nameA+>+nameB)
++return+1;
+return+0;+//default+return+value+(no+sorting)
});|code-block|syntax|javascript|3198576|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Something like this:

<pre><code>array.sort(function(a, b){
 var nameA=a.name.toLowerCase(), nameB=b.name.toLowerCase();
 if (nameA &lt; nameB) //sort string ascending
 return -1;
 if (nameA &gt; nameB)
 return 1;
 return 0; //default return value (no sorting)
});
</code></pre>

blocks|key|3483488|text|如果比较的字符串包含unicode字符，则可以使用String类的localeCompare+function，如下所示：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3483489|users.sort(function(a,b){
++++return+a.firstname.localeCompare(b.firstname);
})|code-block|syntax|javascript|3483490|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/localeCompare^0|P|6|X|D|X|M|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@$9|X|A|Y|1|Z]]|E|$]]|$1|F|3|G|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

If compared strings contain unicode characters you can use <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/localeCompare"><code>localeCompare</code> function</a> of <code>String</code> class like the following:

<pre><code>users.sort(function(a,b){
 return a.firstname.localeCompare(b.firstname);
})
</code></pre>

blocks|key|3483626|text|漂亮的小ES6+one+liner：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3483627|users.sort((a,+b)+=>+a.firstname+!==+b.firstname+?+a.firstname+<+b.firstname+?+-1+:+1+:+0);|code-block|syntax|javascript|3483628|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Nice little ES6 one liner:

<pre><code>users.sort((a, b) =&gt; a.firstname !== b.firstname ? a.firstname &lt; b.firstname ? -1 : 1 : 0);
</code></pre>

blocks|key|3483804|text|我们可以使用localeCompare，但也需要检查键的False值|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3483805|如果一个条目缺少lname，下面的代码将不起作用。|3483806|obj.sort((a,+b)+=>+a.lname.localeCompare(b.lname))|code-block|syntax|javascript|3483807|因此，我们需要检查False值，如下所示|3483808|​|3483809|let+obj=[
{name:'john',lname:'doe',address:'Alaska'},
{name:'tom',lname:'hopes',address:'California'},
{name:'harry',address:'Texas'}
]
let+field='lname';
console.log(obj.sort((a,+b)+=>+(a[field]+%7C%7C+"").toString().localeCompare((b[field]+%7C%7C+"").toString())));|3483810|3483811|或|3483812|我们可以使用lodash，它非常简单。它将检测返回值，即数字或字符串，并相应地进行排序。|3483813|import+sortBy+from+'lodash/sortBy';
sortBy(obj,'name')|3483814|https://lodash.com/docs/4.17.5#sortBy|offset|length|3483815|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|0|0|0|0|0|0|0|0|0|11|0|0^^$0|@$1|2|3|4|5|6|7|16|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|17|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|18|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|19|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|1A|8|@]|9|@]|A|$]]|$1|M|3|N|5|F|7|1B|8|@]|9|@]|A|$G|H]]|$1|O|3|L|5|6|7|1C|8|@]|9|@]|A|$]]|$1|P|3|Q|5|6|7|1D|8|@]|9|@]|A|$]]|$1|R|3|S|5|6|7|1E|8|@]|9|@]|A|$]]|$1|T|3|U|5|F|7|1F|8|@]|9|@]|A|$G|H]]|$1|V|3|W|5|6|7|1G|8|@]|9|@$X|1H|Y|1I|1|1J]]|A|$]]|$1|Z|3|-4|5|6|7|1K|8|@]|9|@]|A|$]]]|10|$11|$5|12|13|14|A|$15|W]]]]

We can use localeCompare but need to check the keys as well for falsey values

The code below will not work if one entry has missing lname.

<pre><code>obj.sort((a, b) =&gt; a.lname.localeCompare(b.lname))
</code></pre>

So we need to check for falsey value like below

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let obj=[
{name:'john',lname:'doe',address:'Alaska'},
{name:'tom',lname:'hopes',address:'California'},
{name:'harry',address:'Texas'}
]
let field='lname';
console.log(obj.sort((a, b) =&gt; (a[field] || "").toString().localeCompare((b[field] || "").toString())));</code></pre>
</div>
</div>


OR 

we can use lodash , its very simple. It will detect the returned values i.e whether number or string and do sorting accordingly . 

<pre><code>import sortBy from 'lodash/sortBy';
sortBy(obj,'name')
</code></pre>

<a href="https://lodash.com/docs/4.17.5#sortBy" rel="noreferrer">https://lodash.com/docs/4.17.5#sortBy</a>

blocks|key|24298|text|underscorejs提供了非常好的_.sortBy函数：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|24299|_.sortBy([{a:1},{a:3},{a:2}],+"a")|code-block|syntax|javascript|24300|或者，您可以使用自定义排序函数：|24301|_.sortBy([{a:"b"},{a:"c"},{a:"a"}],+function(i)+{return+i.a.toLowerCase()})|24302|entityMap|0|LINK|mutability|MUTABLE|url|http://underscorejs.org/#sortBy^0|0|C|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|Z|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|10|8|@]|9|@]|C|$G|H]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]]]

<a href="http://underscorejs.org/#sortBy">underscorejs</a> offers the very nice _.sortBy function:

<pre><code>_.sortBy([{a:1},{a:3},{a:2}], "a")
</code></pre>

or you can use a custom sort function:

<pre><code>_.sortBy([{a:"b"},{a:"c"},{a:"a"}], function(i) {return i.a.toLowerCase()})
</code></pre>

blocks|key|3483891|text|如果我们要对名称或带有特殊字符的内容进行排序，如ñ或áéíóú+(西班牙语中的commons)，我们可以使用params+locales+(在本例中为西班牙语的es)和options，如下所示：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|3483892|​|3483893|let+user+=+[{'firstname':+'Az'},{'firstname':+'Áb'},{'firstname':'ay'},{'firstname':+'Ña'},{'firstname':+'Nz'},{'firstname':+'ny'}];


user.sort((a,+b)+=>+a.firstname.localeCompare(b.firstname,+'es',+{sensitivity:+'base'}))


console.log(user)|code-block|syntax|javascript|3483894|3483895|官方语言环境选项可以在iana、es+(西班牙语)、de+(德语)、fr+(法语)中找到。关于sensitivity+base意味着：|3483896|3483897|只有基本字母不同的字符串才会比较为不相等。例如:a≠b，a=α，a=A。|blockquote|3483898|3483899|entityMap|0|LINK|mutability|MUTABLE|url|https://www.iana.org/assignments/language-subtag-registry/language-subtag-registry|1|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/localeCompare#Parameters^0|O|1|Q|5|1P|7|2C|7|0|0|0|0|1N|4|B|4|0|1B|B|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@$9|15|A|16|B|C]|$9|17|A|18|B|C]|$9|19|A|1A|B|C]|$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1D|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|1E|8|@]|D|@]|E|$K|L]]|$1|M|3|G|5|6|7|1F|8|@]|D|@]|E|$]]|$1|N|3|O|5|6|7|1G|8|@$9|1H|A|1I|B|C]]|D|@$9|1J|A|1K|1|1L]|$9|1M|A|1N|1|1O]]|E|$]]|$1|P|3|-4|5|6|7|1P|8|@]|D|@]|E|$]]|$1|Q|3|R|5|S|7|1Q|8|@]|D|@]|E|$]]|$1|T|3|-4|5|6|7|1R|8|@]|D|@]|E|$]]|$1|U|3|-4|5|6|7|1S|8|@]|D|@]|E|$]]]|V|$W|$5|X|Y|Z|E|$10|11]]|12|$5|X|Y|Z|E|$10|13]]]]

In case we are sorting names or something with special characters, like ñ or áéíóú (commons in Spanish) we could use the params locales (es for spanish in this case ) and options like this:

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let user = [{'firstname': 'Az'},{'firstname': 'Áb'},{'firstname':'ay'},{'firstname': 'Ña'},{'firstname': 'Nz'},{'firstname': 'ny'}];


user.sort((a, b) =&gt; a.firstname.localeCompare(b.firstname, 'es', {sensitivity: 'base'}))


console.log(user)</code></pre>
</div>
</div>


The oficial locale options could be found here in <a href="https://www.iana.org/assignments/language-subtag-registry/language-subtag-registry" rel="noreferrer">iana</a>, es (spanish), de (German), fr (French). About <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/localeCompare#Parameters" rel="noreferrer">sensitivity</a> base means: 

<blockquote>
 Only strings that differ in base letters compare as unequal. Examples: a ≠ b, a = á, a = A.
</blockquote>

blocks|key|24310|text|一种更紧凑的符号：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|24311|user.sort(function(a,+b){
++++return+a.firstname+===+b.firstname+?+0+:+a.firstname+<+b.firstname+?+-1+:+1;
})|code-block|syntax|javascript|24312|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

A more compact notation:

<pre><code>user.sort(function(a, b){
 return a.firstname === b.firstname ? 0 : a.firstname &lt; b.firstname ? -1 : 1;
})
</code></pre>

blocks|key|1583638|text|基本上，您可以使用排序方法对数组进行排序，但如果您想对对象进行排序，则必须将函数传递给数组的排序方法，所以我将使用您的数组给出一个示例|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1583639|user+=+[{
bio:+"<null>",
email:+"user@domain.com",
firstname:+'Anna',
id:+318,
"last_avatar":+"<null>",
"last_message":+"<null>",
lastname:+'Nickson',
nickname:+'anny'
},
{
bio:+"<null>",
email:+"user@domain.com",
firstname:+'Senad',
id:+318,
"last_avatar":+"<null>",
"last_message":+"<null>",
lastname:+'Nickson',
nickname:+'anny'
},
{
bio:+"<null>",
email:+"user@domain.com",
firstname:+'Muhamed',
id:+318,
"last_avatar":+"<null>",
"last_message":+"<null>",
lastname:+'Nickson',
nickname:+'anny'
}];

var+ar+=+user.sort(function(a,+b)
{
++var+nA+=+a.firstname.toLowerCase();
++var+nB+=+b.firstname.toLowerCase();

++if(nA+<+nB)
++++return+-1;
++else+if(nA+>+nB)
++++return+1;
+return+0;
});|code-block|syntax|javascript|1583640|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Basically you can sort arrays with method sort, but if you want to sort objects then you have to pass function to sort method of array, so I will give you an example using your array

<pre><code>user = [{
bio: "&lt;null&gt;",
email: "user@domain.com",
firstname: 'Anna',
id: 318,
"last_avatar": "&lt;null&gt;",
"last_message": "&lt;null&gt;",
lastname: 'Nickson',
nickname: 'anny'
},
{
bio: "&lt;null&gt;",
email: "user@domain.com",
firstname: 'Senad',
id: 318,
"last_avatar": "&lt;null&gt;",
"last_message": "&lt;null&gt;",
lastname: 'Nickson',
nickname: 'anny'
},
{
bio: "&lt;null&gt;",
email: "user@domain.com",
firstname: 'Muhamed',
id: 318,
"last_avatar": "&lt;null&gt;",
"last_message": "&lt;null&gt;",
lastname: 'Nickson',
nickname: 'anny'
}];

var ar = user.sort(function(a, b)
{
 var nA = a.firstname.toLowerCase();
 var nB = b.firstname.toLowerCase();

 if(nA &lt; nB)
 return -1;
 else if(nA &gt; nB)
 return 1;
 return 0;
});
</code></pre>

blocks|key|3483828|text|灵感来自this+answer，|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3483829|users.sort((a,b)+=>+(a.firstname++-+b.firstname));|code-block|syntax|javascript|3483830|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/18920254/872188^0|4|4|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Inspired from <a href="https://stackoverflow.com/a/18920254/872188">this</a> answer,

<pre><code>users.sort((a,b) =&gt; (a.firstname - b.firstname));
</code></pre>

blocks|key|3484115|text|我很惊讶没有人提到排序器。除非迫不得已，否则您不应该使用localeCompare，因为它的性能要差得多。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3484116|const+collator+=+new+Intl.Collator('zh-CN');+//+Chinese+Simplified+for+example

function+sortAsc(a,+b)+{
++if+(typeof+a+===+'string'+&&+typeof+b+===+'string')+{
++++return+collator.compare(b,+a)
++}

++return+b+-+a;
}

function+sortDesc(a,+b)+{
++if+(typeof+a+===+'string'+&&+typeof+b+===+'string')+{
++++return+collator.compare(a,+b);
++}

++return+a+-+b;
}|code-block|syntax|javascript|3484117|entityMap^0|S|D|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

I'm surprised no one mentioned Collators. You shouldn't use <code>localeCompare</code> unless you have to as it has significantly worse performance.
<pre><code>const collator = new Intl.Collator('zh-CN'); // Chinese Simplified for example

function sortAsc(a, b) {
 if (typeof a === 'string' &amp;&amp; typeof b === 'string') {
 return collator.compare(b, a)
 }

 return b - a;
}

function sortDesc(a, b) {
 if (typeof a === 'string' &amp;&amp; typeof b === 'string') {
 return collator.compare(a, b);
 }

 return a - b;
}
</code></pre>

blocks|key|24509|text|试一试|type|unstyled|depth|inlineStyleRanges|entityRanges|data|24510|users.sort((a,b)=>+(a.firstname>b.firstname)*2-1)|code-block|syntax|javascript|24511|​|24512|var+users+=+[
++{+firstname:+"Kate",+id:+318,+/*...*/+},
++{+firstname:+"Anna",+id:+319,+/*...*/+},
++{+firstname:+"Cristine",+id:+317,+/*...*/+},
]

console.log(users.sort((a,b)=>+(a.firstname>b.firstname)*2-1)+);|24513|24514|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|O|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|P|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Q|8|@]|9|@]|A|$E|F]]|$1|K|3|H|5|6|7|R|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|M|$]]

try

<pre><code>users.sort((a,b)=&gt; (a.firstname&gt;b.firstname)*2-1)
</code></pre>

<div class="snippet" data-lang="js" data-hide="true" data-console="true" data-babel="false">
<div class="snippet-code snippet-currently-hidden">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var users = [
 { firstname: "Kate", id: 318, /*...*/ },
 { firstname: "Anna", id: 319, /*...*/ },
 { firstname: "Cristine", id: 317, /*...*/ },
]

console.log(users.sort((a,b)=&gt; (a.firstname&gt;b.firstname)*2-1) );</code></pre>
</div>
</div>

blocks|key|3483851|text|同样对于asec和desc排序，你也可以使用这个:假设我们有一个变量SortType，它指定了你想要的升序排序或降序排序：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3483852|+users.sort(function(a,b){
++++++++++++return+++sortType==="asc"?+a.firstName.localeCompare(+b.firstName):+-(+a.firstName.localeCompare(++b.firstName));
++++++++})|code-block|syntax|javascript|3483853|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

also for both asec and desc sort, u can use this :
suppose we have a variable SortType that specify ascending sort or descending sort you want:

<pre><code> users.sort(function(a,b){
 return sortType==="asc"? a.firstName.localeCompare( b.firstName): -( a.firstName.localeCompare( b.firstName));
 })
</code></pre>

blocks|key|24499|text|一个广义函数可以像下面这样写成|type|unstyled|depth|inlineStyleRanges|entityRanges|data|24500|++++function+getSortedData(data,+prop,+isAsc)+{
++++++++return+data.sort((a,+b)+=>+(a[prop]+<+b[prop]+?+-1+:+1)+*+(isAsc+?+1+:+-1));
+++}|code-block|syntax|javascript|24501|您可以传递以下参数|24502|最后一个参数是boolean类型的，最后一个参数是|24503|ordered-list-item|24504|24505|，最后一个参数是boolean类型。它检查您是要按升序排序还是按降序排序|24506|24507|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|V|8|@]|9|@]|A|$]]|$1|K|3|-4|5|L|7|W|8|@]|9|@]|A|$]]|$1|M|3|-4|5|L|7|X|8|@]|9|@]|A|$]]|$1|N|3|O|5|L|7|Y|8|@]|9|@]|A|$]]|$1|P|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|10|8|@]|9|@]|A|$]]]|R|$]]

A generalized function can be written like below

<pre><code> function getSortedData(data, prop, isAsc) {
 return data.sort((a, b) =&gt; (a[prop] &lt; b[prop] ? -1 : 1) * (isAsc ? 1 : -1));
 }
</code></pre>

you can pass the below parameters

<ol>
<li>The data which you want to sort</li>
<li>The property in the data by it should be sorted</li>
<li>The last parameter is of boolean type. It checks if you want to sort by ascending or by descending </li>
</ol>

blocks|key|24380|text|简而言之，您可以使用此方法|type|unstyled|depth|inlineStyleRanges|entityRanges|data|24381|users.sort(function(a,b){return+a.firstname+<+b.firstname+?+-1+:+1});|code-block|syntax|javascript|24382|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

in simply words you can use this method

<pre><code>users.sort(function(a,b){return a.firstname &lt; b.firstname ? -1 : 1});
</code></pre>

blocks|key|1583920|text|您可以将其用于对象|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1583921|transform(array:+any[],+field:+string):+any[]+{
return+array.sort((a,+b)+=>+a[field].toLowerCase()+!==+b[field].toLowerCase()+?+a[field].toLowerCase()+<+b[field].toLowerCase()+?+-1+:+1+:+0);}|code-block|syntax|javascript|1583922|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use this for objects

<pre><code>transform(array: any[], field: string): any[] {
return array.sort((a, b) =&gt; a[field].toLowerCase() !== b[field].toLowerCase() ? a[field].toLowerCase() &lt; b[field].toLowerCase() ? -1 : 1 : 0);}
</code></pre>

blocks|key|3198827|text|将排名靠前的答案放入原型中，以便按键排序。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3198828|Array.prototype.alphaSortByKey=+function+(key)+{
++++this.sort(function+(a,+b)+{
++++++++if+(a[key]+<+b[key])
++++++++++++return+-1;
++++++++if+(a[key]+>+b[key])
++++++++++++return+1;
++++++++return+0;
++++});
++++return+this;
};|code-block|syntax|javascript|3198829|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Pushed the top answers into a prototype to sort by key.

<pre><code>Array.prototype.alphaSortByKey= function (key) {
 this.sort(function (a, b) {
 if (a[key] &lt; b[key])
 return -1;
 if (a[key] &gt; b[key])
 return 1;
 return 0;
 });
 return this;
};
</code></pre>

blocks|key|3484080|text|仅供记录，如果您想要有一个命名的排序函数，语法如下：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3484081|let+sortFunction+=+(a,+b)+=>+{
+if(a.firstname+<+b.firstname)+{+return+-1;+}
+if(a.firstname+>+b.firstname)+{+return+1;+}
+return+0;
})
users.sort(sortFunction)|code-block|syntax|javascript|3484082|请注意，以下内容不起作用：|3484083|users.sort(sortFunction(a,b))|3484084|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Just for the record, if you want to have a named sort-function, the syntax is as follows: 

<pre><code>let sortFunction = (a, b) =&gt; {
 if(a.firstname &lt; b.firstname) { return -1; }
 if(a.firstname &gt; b.firstname) { return 1; }
 return 0;
})
users.sort(sortFunction)
</code></pre>

Note that the following does NOT work: 

<pre><code>users.sort(sortFunction(a,b))
</code></pre>

blocks|key|3198795|text|您可以使用类似的方法，去掉区分大小写的|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3198796|users.sort(function(a,+b){

++//compare+two+values
++if(a.firstname.toLowerCase()+<+b.firstname.toLowerCase())+return+-1;
++if(a.firstname.toLowerCase()+>+b.firstname.toLowerCase())+return+1;
++return+0;

})|code-block|syntax|javascript|3198797|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use something similar, to get rid of case sensitive 

<pre><code>users.sort(function(a, b){

 //compare two values
 if(a.firstname.toLowerCase() &lt; b.firstname.toLowerCase()) return -1;
 if(a.firstname.toLowerCase() &gt; b.firstname.toLowerCase()) return 1;
 return 0;

})
</code></pre>

blocks|key|3483997|text|我的实现在旧的ES版本中工作得很好：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3483998|sortObject+=+function(data)+{
++++var+keys+=+Object.keys(data);
++++var+result+=+{};

++++keys.sort();

++++for(var+i+=+0;+i+<+keys.length;+i%2B%2B)+{
++++++++var+key+=+keys[i];

++++++++result[key]+=+data[key];
++++}

++++return+result;
};|code-block|syntax|javascript|3483999|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

My implementation, works great in older ES versions:

<pre><code>sortObject = function(data) {
 var keys = Object.keys(data);
 var result = {};

 keys.sort();

 for(var i = 0; i &lt; keys.length; i++) {
 var key = keys[i];

 result[key] = data[key];
 }

 return result;
};
</code></pre>

blocks|key|1584300|text|对于双因素排序(姓名和姓氏)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1584301|​|1584302|users.sort((a,+b)+=>+a.name.toLowerCase()+<+b.name.toLowerCase()+?+-1+:+a.name.toLowerCase()+>+b.name.toLowerCase()+?+1+:+a.lastname.toLowerCase()+<+b.lastname.toLowerCase()+?+-1+:+a.lastname.toLowerCase()+>+b.lastname.toLowerCase()+?+1+:+0)|code-block|syntax|javascript|1584303|1584304|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

for a two factors sort (name and lastname):
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>users.sort((a, b) =&gt; a.name.toLowerCase() &lt; b.name.toLowerCase() ? -1 : a.name.toLowerCase() &gt; b.name.toLowerCase() ? 1 : a.lastname.toLowerCase() &lt; b.lastname.toLowerCase() ? -1 : a.lastname.toLowerCase() &gt; b.lastname.toLowerCase() ? 1 : 0)</code></pre>
</div>
</div>

I got an array (see below for one object in the array) that I need to sort by firstname using JavaScript.
How can I do it?

<pre><code>var user = {
 bio: null,
 email: "user@domain.com",
 firstname: "Anna",
 id: 318,
 lastAvatar: null,
 lastMessage: null,
 lastname: "Nickson",
 nickname: "anny"
};
</code></pre>

Sort array by firstname (alphabetically) in Javascript

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我得到了一个数组(参见下面的数组中的一个对象)，我需要使用JavaScript按名字进行排序。我该怎么做呢？var user = {   bio: null,   email:  "user@domain.com",   firstname: "Anna",   id: 318,   lastAvatar: null,   lastMessage: null,   lastname: "Nicks

问在Javascript中按名字(字母顺序)对数组排序
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回答 22

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