Python代码无法在Windows中执行
Python代码无法在Windows中执行
提问于 2016-02-28 23:47:14
我的python代码在Ubuntu 14.04上运行成功；但是当我在Windows平台上运行时，它让我陷入了错误。代码：
import pymc
with open("days1.txt") as f:
dataset = map(float, f)
a = pymc.Uniform('a', lower=0, upper=1500000, value=70, doc='Weibull alpha parameter')
b = pymc.Uniform('b', lower=0, upper=1500000, value=70, doc='Weibull beta parameter')
like = pymc.Weibull('like', alpha=a, beta=b, value=dataset, observed=True)
if __name__=='__main__':
import pylab
M = pymc.MCMC([a,b,like])
M.sample(10000,5000,2)
pymc.Matplot.plot(a)
pymc.Matplot.plot(b)
M.summary()
M.write_csv("parameters1.csv") 错误：
C:\Python35-32>python.exe "E:\TCS\Desktop\EarlyWarning\JLR\Data\EJ327000AB\Scrip
ts\Screen 7\Check Python - 1\weibullEstimationOutData - 1.py"
Traceback (most recent call last):
File "C:\Python35-32\lib\site-packages\pymc\PyMCObjects.py", line 742, in __in
it__
self._value = np.array(value, dtype=dtype)
TypeError: float() argument must be a string or a number, not 'map'在处理上述异常的过程中，发生了另一个异常：
Traceback (most recent call last):
File "E:\TCS\Desktop\EarlyWarning\JLR\Data\EJ327000AB\Scripts\Screen 7\Check P
ython - 1\weibullEstimationOutData - 1.py", line 8, in <module>
like = pymc.Weibull('like', alpha=a, beta=b, value=dataset, observed=True)
AttributeError: 'TypeError' object has no attribute 'message'请帮帮忙。提前感谢
回答 1
Stack Overflow用户
发布于 2016-02-29 00:04:58
您在Ubuntu上使用Python 2，在Windows上使用Python 3。安装适用于Windows的Python 2，或将代码移植到Python 3
import pylab
import pymc
with open("days1.txt") as f:
dataset = list(map(float, f))
a = pymc.Uniform('a', lower=0, upper=1500000, value=70, doc='Weibull alpha parameter')
b = pymc.Uniform('b', lower=0, upper=1500000, value=70, doc='Weibull beta parameter')
like = pymc.Weibull('like', alpha=a, beta=b, value=dataset, observed=True)
if __name__=='__main__':
M = pymc.MCMC([a,b,like])
M.sample(10000,5000,2)
pymc.Matplot.plot(a)
pymc.Matplot.plot(b)
M.summary()
M.write_csv("parameters1.csv") 页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/35684628
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