blocks|key|3304711|text|使用ajax+post表单|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3304712|$.ajax({
url:'yoururl',
data:$("form").serialize(),
type:'POST',
success:function(data){
alert("success");
},
error:function(jxhr){
alert(jxhr.responseText);
}

});|code-block|syntax|javascript|3304713|3304714|entityMap^0|7|4|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Q|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|R|8|@]|D|@]|E|$]]|$1|L|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|M|$]]

<code>post</code> the form using ajax

<pre><code>$.ajax({
url:'yoururl',
data:$("form").serialize(),
type:'POST',
success:function(data){
alert("success");
},
error:function(jxhr){
alert(jxhr.responseText);
}

});
</code></pre>

<a href="http://api.jquery.com/jQuery.ajax/" rel="nofollow">jQuery.ajax() – jQuery API</a>

blocks|key|3304753|text|发布到同一页应该可以做到这一点。为此，不需要使用ajax|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3304754|>+<?php+
>+
>+//do+stuff+with+$_POST+
>+?>
>+
>+<html>+<body>+<form+method="post">
>+
>+<?php+echo+$result+?>
>+
>+</form>+
>+</body>|code-block|syntax|javascript|3304755|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Posting to the same page should do the trick. No need to use ajax for that

<pre><code>&gt; &lt;?php 
&gt; 
&gt; //do stuff with $_POST 
&gt; ?&gt;
&gt; 
&gt; &lt;html&gt; &lt;body&gt; &lt;form method="post"&gt;
&gt; 
&gt; &lt;?php echo $result ?&gt;
&gt; 
&gt; &lt;/form&gt; 
&gt; &lt;/body&gt;
</code></pre>

blocks|key|3304785|text|菲克|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3304786|使用ajax来实现这一点，让我们假设在您的实践中尝试以下方法|3304787|var+string+=+$("#string").val();
var+dataString+=+'string='+%2B+string+;
if(string==''){
++++alert('enter+any+string');
}
else{
++++$.ajax({
++++++++type:+"POST",
++++++++url:+"path+of+php+file",
++++++++data:+dataString,
++++++++suceess:+function(){
++++++++++++//do+something
++++++++},
++++++++error:+function(){
++++++++++++//do+something
++++++++}
++++});
}|code-block|syntax|javascript|3304788|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Fike

use ajax for this, lets suppose try this one for your practice 

<pre><code>var string = $("#string").val();
var dataString = 'string=' + string ;
if(string==''){
 alert('enter any string');
}
else{
 $.ajax({
 type: "POST",
 url: "path of php file",
 data: dataString,
 suceess: function(){
 //do something
 },
 error: function(){
 //do something
 }
 });
}
</code></pre>

blocks|key|3590219|text|您可以使用jQuery或Prototype+JS库进行简单的AJAX调用。使用jQuery的示例如下：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3590220|$.ajax({
++url:'hashed.php',
++data:$("form").serialize(),
++type:'POST',
++success:+function(data){
++++$('hashmd5').html(data.md5);
++++$('hashsha1').html(data.sha1);
++},
++error:+function(jxhr){
++++alert(jxhr.responseText);
++}
});|code-block|syntax|javascript|3590221|不要在HTML中使用相同的id值，永远不要。它们必须是唯一的，才能正确地对元素执行JavaScript函数。|3590222|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can use jQuery or Prototype JS libraries to make an easy AJAX call. Example using jQuery would be:

<pre><code>
$.ajax({
 url:'hashed.php',
 data:$("form").serialize(),
 type:'POST',
 success: function(data){
 $('hashmd5').html(data.md5);
 $('hashsha1').html(data.sha1);
 },
 error: function(jxhr){
 alert(jxhr.responseText);
 }
});
</code></pre>

Don't use the same id value in HTML, never ever. They must be unique to correct perform JavaScript functions on elements.

blocks|key|3590256|text|是的，这是可能的。编写一个在提交时触发的javascript函数，禁用提交按钮，这样用户就不能再次按下它，最后通过ajax请求服务器。在成功响应时，更新内容。类似于Jquery中的following|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3590257|++++$('.form-submit').click(function(event))+{
+++++++++event.preventDefault();
+++++++++if(form+is+valid+and+not+empty)+{
++++++++++++++$.ajax({
+++++++++++++++++++type:+"POST",
+++++++++++++++++++url:+"path+to+script+that+will+handle+insetion",
+++++++++++++++++++data:+"data+from+form",+//like+({username+:+$('#username').val()}),
+++++++++++++++++++suceess:+function(data){
++++++++++++++++++++++++//update+the+content+or+what.+data+is+the+response+got+from+server.+you+can+also+do+like+this+to+show+feedback+etc...
++++++++++++++++++++++++$('.feedback').html("Data+has+been+saved+successfully");
+++++++++++++++++++},
+++++++++++++++++++error:+function(){
++++++++++++++++++++++++$('.feedback').html("Data+couldn't+be+saved");
+++++++++++++++++++}
+++++++++++++++});
+++++++++}

++++}|code-block|syntax|javascript|3590258|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

yes it is possible. Write a javascript function that would trigger on submit, disable the submit button so user couldn't press it again, and finally request the server via ajax. on successful response update the content. Something like following in Jquery

<pre><code> $('.form-submit').click(function(event)) {
 event.preventDefault();
 if(form is valid and not empty) {
 $.ajax({
 type: "POST",
 url: "path to script that will handle insetion",
 data: "data from form", //like ({username : $('#username').val()}),
 suceess: function(data){
 //update the content or what. data is the response got from server. you can also do like this to show feedback etc...
 $('.feedback').html("Data has been saved successfully");
 },
 error: function(){
 $('.feedback').html("Data couldn't be saved");
 }
 });
 }

 }
</code></pre>

I'm currently learning PHP. I've made a simple script @ <a href="http://hash.techho.me" rel="nofollow">http://hash.techho.me</a>, only thing is, I want the form to submit then load the results via AJAX, without the user leaving the page. Possible?

Forms/PHP/Ajax load?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我目前正在学习PHP。我已经创建了一个简单的脚本@ ，唯一的事情是，我希望表单提交，然后通过AJAX加载结果，而不需要用户离开页面。有可能吗？

问表单/PHP/Ajax加载？
EN

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问表单/PHP/Ajax加载？EN