blocks|key|2174343|text|这是一个属性选择器。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2174344|@是jQuery中不再使用的XPath-ism。|offset|length|style|CODE|2174345|此外，较新版本的jQuery要求属性值用引号括起来。|2174346|因此，您应该编写|2174347|$('#'+%2B+v_form_id).find('input[name="content_type"]').val();|code-block|syntax|javascript|2174348|entityMap^0|0|0|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@$D|U|E|V|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|W|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|X|8|@]|9|@]|A|$]]|$1|L|3|M|5|N|7|Y|8|@]|9|@]|A|$O|P]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

This is an attribute selector.

The <code>@</code> is an XPath-ism that is no longer used in jQuery. 
In addition, newer versions of jQuery require the attribute value to be in quotes.

Therefore, you should write

<pre><code>$('#' + v_form_id).find('input[name="content_type"]').val();
</code></pre>

blocks|key|4073419|text|这意味着attribute。input[@name=button_format]的意思是the+input+tag+with+the+name+attribute+equal+to+button_format。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4073420|但是，在最新版本的jQuery中，您需要删除@和引号button_format。这意味着@不是向后兼容的。So+quoth+the+docs。|4073421|4073422|+注意:+jQuery+1.3+@attr样式选择器中的已被删除(它们以前在jQuery+1.2中已被弃用)。只需从您的选择器中删除“@”符号，以使它们再次工作。|blockquote|BOLD|4073423|4073424|entityMap|0|LINK|mutability|MUTABLE|url|http://api.jquery.com/attribute-equals-selector/|1|http://api.jquery.com/category/selectors/attribute-selectors/^0|4|9|E|Q|18|1O|4|9|0|0|18|1|1H|H|1|0|0|1|R|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@$9|Y|A|Z|B|C]|$9|10|A|11|B|C]|$9|12|A|13|B|C]]|D|@$9|14|A|15|1|16]]|E|$]]|$1|F|3|G|5|6|7|17|8|@$9|18|A|19|B|C]]|D|@$9|1A|A|1B|1|1C]]|E|$]]|$1|H|3|-4|5|6|7|1D|8|@]|D|@]|E|$]]|$1|I|3|J|5|K|7|1E|8|@$9|1F|A|1G|B|L]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|1H|8|@]|D|@]|E|$]]|$1|N|3|-4|5|6|7|1I|8|@]|D|@]|E|$]]]|O|$P|$5|Q|R|S|E|$T|U]]|V|$5|Q|R|S|E|$T|W]]]]

That means <a href="http://api.jquery.com/attribute-equals-selector/" rel="nofollow"><code>attribute</code></a>. <code>input[@name=button_format]</code> means <code>the input tag with the name attribute equal to button_format</code>. 

You will need to remove the @ and quote button_format in recent versions jQuery, however. This means <code>@</code> is not backwards compatible. <a href="http://api.jquery.com/category/selectors/attribute-selectors/" rel="nofollow">So quoth the docs</a>.

<blockquote>
 Note: In jQuery 1.3 [@attr] style selectors were removed (they were previously deprecated in jQuery 1.2). Simply remove the “@” symbol from your selectors in order to make them work again.
</blockquote>

blocks|key|3788314|text|+input[@name=button_format]|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3788315|表示name-attribute设置为'button_format‘的输入域，例如：|unstyled|3788316|+<input+name="button_format">|3788317|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code> input[@name=button_format]
</code></pre>

means the input field with the name-attribute set to 'button_format', ie:

<pre><code> &lt;input name="button_format"&gt;
</code></pre>

blocks|key|3788345|text|input[@name=button_format]|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3788346|This+is+old+selector+type.please+remove+if+@+if+you+using+jQuery最新方法是|unstyled|offset|length|style|BOLD|3788347|input[name="button_format"]|3788348|entityMap^0|0|8|C|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|P|8|@$G|Q|H|R|I|J]]|9|@]|A|$]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|M|3|-4|5|F|7|T|8|@]|9|@]|A|$]]]|N|$]]

<pre><code>input[@name=button_format]
</code></pre>

This is old selector type.please remove if @ if you using jQuery latest
new way is

<pre><code>input[name="button_format"]
</code></pre>

blocks|key|3788395|text|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3788396|注意:在jQuery+1.3中，@attr样式选择器已被删除(它们在jQuery+1.2中已被弃用)。只需从您的选择器中删除“@”符号，以使它们再次工作。|blockquote|3788397|3788398|3788399|它是一个不推荐使用的选择器，你必须将它从你的代码中删除，因为它不再被支持并且会导致错误。|3788400|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|-4|4|5|6|J|7|@]|8|@]|9|$]]|$1|A|3|B|4|C|6|K|7|@]|8|@]|9|$]]|$1|D|3|-4|4|5|6|L|7|@]|8|@]|9|$]]|$1|E|3|-4|4|5|6|M|7|@]|8|@]|9|$]]|$1|F|3|G|4|5|6|N|7|@]|8|@]|9|$]]|$1|H|3|-4|4|5|6|O|7|@]|8|@]|9|$]]]|I|$]]

<blockquote>
 Note: In jQuery 1.3 [@attr] style selectors were removed (they were
 previously deprecated in jQuery 1.2). Simply remove the '@' symbol
 from your selectors in order to make them work again.
</blockquote>

it's a deprecated selector, you have to remove it from your code as it's no longer supported and will cause errors.

blocks|key|319683|text|这是一种古老的方法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|319684|它与(并且应该更改为)相同：|319685|$('input[name="button_format"]')|code-block|syntax|javascript|319686|另请注意必需的引号|offset|length|style|BOLD|319687|entityMap^0|0|0|0|4|3|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@$K|U|L|V|M|N]]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

That's the OLD way of doing it.

It is the same as (and should be changed to):

<pre><code>$('input[name="button_format"]')
</code></pre>

Also note the mandatory quotes

blocks|key|4073585|text|属性，就像其他人提到的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4073586|我的建议:这种表示法的灵感来自XPath，它也使用@表示(XML)属性|offset|length|style|CODE|4073587|entityMap^0|0|P|1|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

Attribute as others mentioned.

My 2-cents: The notation is inspired from XPath, which also denotes (XML) attributes using an <code>@</code>

So I have someone else's old code that I am trying to restore. I am not too familiar with jQuery, but what does the <code>@</code> operator specify?

The code is:

<pre><code>v_button_format = $('#' + v_form_id).find('input[@name=button_format]').val();
v_content_type = $('#' + v_form_id).find('input[@name=content_type]').val();
</code></pre>

I am using jQuery 1.3 and it's throwing an "uncaught exception: Syntax error, unrecognized expression: [@name=button_format]" error. Is there a compatibility issue?

jQuery @ operator?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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因此，我有其他人的旧代码，我正在尝试恢复。我对jQuery不是很熟悉，但是@操作符指定了什么？代码是：v_button_format = $('#' + v_form_id).find('input[@name=button_format]').val();v_content_type = $('#' + v_form...

问jQuery @ operator？
EN

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问jQuery @ operator？EN