将值从类传递到不同的窗体上显示&以编程方式单击事件处理？
我目前已经创建了一个棋盘，填充了棋子的图像，并对棋盘进行了着色等，我有2个点击事件方法的问题，我希望你能帮助我？当一个正方形被点击时，我当前的方法改变了正方形的颜色，并显示一个消息框，显示xy坐标和棋子的类型，或者如果它没有被棋子占据，就显示坐标：
问题1:如果我再次单击相同的方块或不同的方块，如何让颜色变回原来的颜色？
问题2:如何在文本框或标签中显示Form1.cs上的信息，而不是显示meesagebox？
下面是我的GridSqaure.cs类中的代码：
namespace Chess
{
public class GridSquare : PictureBox
{
private int x;
private int y;
private ChessPiece piece;
public int X { get { return x; } }
public int Y { get { return y; } }
public ChessPiece Piece
{
get { return piece; }
set
{
piece = value;
if (value == null)
this.BackgroundImage = null;
else
this.BackgroundImage = piece.GetImage();
}
}
public GridSquare(int x, int y)
{
int ButtonWidth = 64;
int ButtonHeight = 64;
int Distance = 20;
int start_x = 10;
int start_y = 10;
this.x = x;
this.y = y;
this.Top = start_x + (x * ButtonHeight + Distance + x);
this.Left = start_y + (y * ButtonWidth + Distance + y);
this.Width = ButtonWidth;
this.Height = ButtonHeight;
this.Text = "X: " + x.ToString() + " Y: " + y.ToString();
this.BorderStyle = System.Windows.Forms.BorderStyle.FixedSingle;
this.Click += new System.EventHandler(gridSquare_Click);
}
private void gridSquare_Click(object sender, EventArgs e)
{
GridSquare gs = (GridSquare)sender;
if (gs.Piece != null)
{
//Change: need to show xy of sqaure clicked on a label or textbox on the main window.
MessageBox.Show("You clicked a " + gs.Piece.GetName() + " at (" + gs.X + ", " + gs.Y + ")");
//Change: need to click for change in colour, then second click to revert back
this.BackColor = Color.LightBlue;
}
else
{
//Change: need to show xy of clicked square but including meesage stating the sqaure needs to be occupied by a piece.
MessageBox.Show("You clicked (" + gs.X + ", " + gs.Y + ")");
}
}
}
}回答 4
Stack Overflow用户
发布于 2011-10-19 18:05:04
我会避免让一个类处理它自己的事件。这不是一个好的做法。
相反，我会使用回调策略。
首先，重新编码GridSquare，如下所示：
public class GridSquare : PictureBox
{
/* As before */
public GridSquare(int x, int y, Action<GridSquare> clicked)
{
/* As before */
this.Click += (s, e) => clicked(this);
}
/* NO private void gridSquare_Click(object sender, EventArgs e) */
}现在该由调用代码来完成这项繁重的工作了。
我假设您正在使用类似嵌套的for循环来创建面板，这些循环会将创建的每个GridSquare添加到表单的Controls集合中。如果是这样的话，你需要像这样写代码：
for (var x = 0; x < 8; x++)
{
for (var y = 0; y < 8; y++)
{
this.Controls.Add(new GridSquare(x, y, clicked));
}
}现在您只需要定义clicked -单击每个GridSquare时的回调-该代码如下所示：
GridSquare lastClicked = null;
Color lastBackColor = Color.Transparent;
Action<GridSquare> clicked = gs =>
{
lastClicked.BackColor = lastBackColor;
if (!lastClicked.Equals(gs))
{
lastClicked = gs;
lastBackColor = gs.BackColor;
gs.BackColor = Color.LightBlue;
var inner = gs.Piece != null
? String.Format("a {0} at ", gs.Piece.GetName())
: "";
var msg = String.Format("You clicked {0}({1}, {2})", inner, gs.X, gs.Y);
MessageBox.Show(msg);
}
};显然，这段代码是在创建网格方块之前进行的。
这应该相对容易理解，但如果不是，只需询问，我将详细说明。
如果这对你有效，请告诉我。
Stack Overflow用户
发布于 2011-10-19 17:28:55
首先将长方体的实际颜色存储在一个color类的对象中，让我们假设对象名为"BoxColor“，现在请看以下代码。
if (gs.Piece != null)
{
//Change: need to show xy of sqaure clicked on a label or textbox on the main window.
label1.Text = "You clicked a " + gs.Piece.GetName() + " at (" + gs.X + ", " + gs.Y + ")";
//Change: need to click for change in colour, then second click to revert back
this.BackColor = Color.LightBlue;
}
else
{
//Change: need to show xy of clicked square but including meesage stating the sqaure needs to be occupied by a piece.
this.BackColor = BoxColor //setting back the original color if the box is clicked again.
label1.Text = "You clicked (" + gs.X + ", " + gs.Y + ")";
} 还要设置一个布尔变量，只有当框的颜色从实际颜色改变时才启用它，现在如果用户单击任何其他框，检查这些标志，并检查它是否为真，重置颜色。
Stack Overflow用户
发布于 2011-10-19 17:31:49
- 您可以在
GridSquare类的作用域上创建一个boolean变量。然后在gridSquare_Click事件处理程序上使用此变量，如下所示：
公共类GridSquare : PictureBox { bool isFirstClick = true；.......private void gridSquare_Click(object sender，EventArgs e) { if( isFirstClick ) { isFirstClick = false；//设置一种颜色} else {isFirstClick= true；//设置其他颜色}
- 只需使用
Text或Label的属性即可
https://stackoverflow.com/questions/7819084
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