blocks|key|4445960|text|我将抛出另一个方法，因为这是我能想到的最短的方法|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4445961|a.sort_by(&:to_i)|code-block|syntax|javascript|4445962|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I'll throw another method out there since it's the shortest way I can think of

<pre><code>a.sort_by(&amp;:to_i)
</code></pre>

blocks|key|647865|text|正如您更新的问题所述：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|647866|array.sort_by+{%7Celt%7C+ary+=+elt.split("-").map(&:to_i);+ary[0]+%2B+ary[1]}|code-block|syntax|javascript|647867|甚至更极客：|647868|array.sort_by+{%7Celt%7C+ary+=+elt.split("-").map(&:to_i).inject(&:%2B)}|647869|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

As your updated question states:

<pre><code>array.sort_by {|elt| ary = elt.split("-").map(&amp;:to_i); ary[0] + ary[1]}
</code></pre>

even geekier:

<pre><code>array.sort_by {|elt| ary = elt.split("-").map(&amp;:to_i).inject(&amp;:+)}
</code></pre>

blocks|key|2831122|text|如果您事先将所有字符串转换为整数，它应该会按预期工作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2831123|a.map(&:to_i).sort
=>+[1,+2,+3,+4,+5,+6,+7,+8,+9,+10]|code-block|syntax|javascript|2831124|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you convert all strings to integers beforehand, it should work as expected:

<pre><code>a.map(&amp;:to_i).sort
=&gt; [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
</code></pre>

blocks|key|4445788|text|a.sort+{+%7Ca,b%7C+a.to_i+<=>+b.to_i+}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4445789|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

blocks|key|4728743|text|另一种选择，可以在示例或其他数组中使用，例如|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4728744|a+=+["teste",+"test",+"teste2",+"tes3te",+"10teste"]|code-block|syntax|javascript|4728745|是：|4728746|a.sort_by!+{%7Cs%7C+s[/\d%2B/].to_i}|4728747|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Another option, that can be used in your example or others arrays like

<pre><code>a = ["teste", "test", "teste2", "tes3te", "10teste"]
</code></pre>

is:

<pre><code>a.sort_by! {|s| s[/\d+/].to_i}
</code></pre>

blocks|key|2831078|text|此行为的原因是您有一个字符串数组，并且所应用的排序是基于字符串的。要获得正确的数字排序，您必须将字符串转换为数字，或者首先将它们保留为数字。你的数组中填充这样的字符串有什么原因吗：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2831079|a+=+["3",+"5",+"8",+"4",+"1",+"2",+"9",+"10",+"7",+"6"]|code-block|syntax|javascript|2831080|而不是像这样的数字：|2831081|a+=+[3,+5,+8,+4,+1,+2,+9,+1,+7,+6]|2831082|2831083|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|O|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|P|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Q|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|R|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|M|$]]

The reason for this behavior is that you have an array of strings and the sort that is being applied is string-based. To get the proper, numeric, sorting you have to convert the strings to numbers or just keep them as numbers in the first place. Is there a reason that your array is being populate with strings like this:

<pre><code>a = ["3", "5", "8", "4", "1", "2", "9", "10", "7", "6"]
</code></pre>

Rather than numbers like this:

<pre><code>a = [3, 5, 8, 4, 1, 2, 9, 1, 7, 6]
</code></pre>

?

blocks|key|647809|text|最便宜的方法是在左边填零，并使所有数字都是两位数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|647810|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

The cheap way would be to zero fill on the left and make all numbers 2 digit.

blocks|key|2831207|text|对于你提到的特殊情况(电子商务价目表)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2831208|a+=+["0-10",+"11-20",+"21-30",+"31-40"]|code-block|syntax|javascript|2831209|让我们在这个数组中再添加几个值(因为它被称为价格列表)。所以|2831210|a+=+["0-10",+"11-20",+"120-150",+"110-120",+"21-30",+"31-40"]|2831211|我们可以使用下面的代码对这样的数组进行排序|2831212|a.sort.sort_by(&:length)|2831213|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

For the special case (e-commerce price list) you mentioned
<pre><code>a = [&quot;0-10&quot;, &quot;11-20&quot;, &quot;21-30&quot;, &quot;31-40&quot;]
</code></pre>
let's add a few more values to this array (as it was mentioned as price list). so
<pre><code>a = [&quot;0-10&quot;, &quot;11-20&quot;, &quot;120-150&quot;, &quot;110-120&quot;, &quot;21-30&quot;, &quot;31-40&quot;]
</code></pre>
we can sort such an array using the following
<pre><code>a.sort.sort_by(&amp;:length)
</code></pre>

Let's say I have an unsorted array from 1 to 10, as shown below...
<pre><code>a = [&quot;3&quot;, &quot;5&quot;, &quot;8&quot;, &quot;4&quot;, &quot;1&quot;, &quot;2&quot;, &quot;9&quot;, &quot;10&quot;, &quot;7&quot;, &quot;6&quot;]
</code></pre>
If I use the sort method on this array, it returns this...
<pre><code>a.sort = [&quot;1&quot;, &quot;10&quot;, &quot;2&quot;, &quot;3&quot;, &quot;4&quot;, &quot;5&quot;, &quot;6&quot;, &quot;7&quot;, &quot;8&quot;, &quot;9&quot;]
</code></pre>
As you can see, the 10, appears before the 2, which is incorrect. How can I sort these numbers so that 10 appears correctly?
EDIT: Thank you all for your responses. I should explain my problem a little better. The array I need sorted is for an e-commerce price list. So the array appears as follows...
<pre><code>a = [&quot;0-10&quot;, &quot;11-20&quot;, &quot;21-30&quot;, &quot;31-40&quot; etc.]
</code></pre>
So the strings cannot be converted to integers. I should have put this when I wrote the question. I did not think that there would be much difference in the fix. My mistake, I apologise for making this assumption! How though can I sort this array? Thanks!

Sort an Array of Strings by their Integer Values

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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假设我有一个从1到10的未排序数组，如下所示...a = ["3", "5", "8", "4", "1", "2", "9", "10", "7", "6"]如果我在这个数组上使用sort方法，它会返回这个...a.sort = ["1", "10", "2", "3", "4", "5", "6", "7", "8", "9"]如您所见，10出现在2之前，这是不正确的。如何对这些数字进行排序，

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