blocks|key|3097569|text|Java中的数组不是动态的，就像集合类一样。如果您想要一个支持动态添加和删除的真实集合，请使用ArrayList<>。如果您仍然希望使用普通数组，那么找到string的索引，构造一个比原始数组小1的新数组，并使用System.arraycopy()复制前后的元素。或者手动编写一个带有跳过的复制循环，在小的数组上，差异将可以忽略不计。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3097570|entityMap^0|2Y|I|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

Arrays in Java aren't dynamic, like collection classes. If you want a true collection that supports dynamic addition and deletion, use ArrayList&lt;>. If you still want to live with vanilla arrays, find the index of string, construct a new array with size one less than the original, and use <code>System.arraycopy()</code> to copy the elements before and after. Or write a copy loop with skip by hand, on small arrays the difference will be negligible.

blocks|key|4712982|text|你不能从数组中删除任何东西--它们的长度总是固定的。一旦创建了长度为3的数组，该数组的长度将始终为3。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4712983|你最好有一个List<String>，比如ArrayList<String>|offset|length|style|CODE|4712984|List<String>+list+=+new+ArrayList<String>();
list.add("google");
list.add("microsoft");
list.add("apple");
System.out.println(list.size());+//+3

list.remove("apple");
System.out.println(list.size());+//+2|code-block|syntax|javascript|4712985|这样的集合通常比直接使用数组灵活得多。|4712986|编辑:对于删除：|4712987|void+removeRandomElement(List<?>+list,+Random+random)
{
++++int+index+=+random.nextInt(list.size());
++++list.remove(index);
}|4712988|entityMap^0|0|6|C|L|H|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@$D|W|E|X|F|G]|$D|Y|E|Z|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|10|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|11|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|12|8|@]|9|@]|A|$]]|$1|Q|3|R|5|J|7|13|8|@]|9|@]|A|$K|L]]|$1|S|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|T|$]]

You can't remove anything from an array - they're always fixed length. Once you've created an array of length 3, that array will always have length 3.

You'd be better off with a <code>List&lt;String&gt;</code>, e.g. an <code>ArrayList&lt;String&gt;</code>:

<pre><code>List&lt;String&gt; list = new ArrayList&lt;String&gt;();
list.add("google");
list.add("microsoft");
list.add("apple");
System.out.println(list.size()); // 3

list.remove("apple");
System.out.println(list.size()); // 2
</code></pre>

Collections like this are generally much more flexible than working with arrays directly.

EDIT: For removal:

<pre><code>void removeRandomElement(List&lt;?&gt; list, Random random)
{
 int index = random.nextInt(list.size());
 list.remove(index);
}
</code></pre>

blocks|key|3097651|text|定义“移除”。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3097652|数组的长度是固定的，一旦创建就不能调整大小。可以将元素设置为null来移除对象引用；|offset|length|style|CODE|3097653|for+(int+i+=+0;+i+<+myStringArray.length();+i%2B%2B)
{
++++if+(myStringArray[i].equals(stringToRemove))
++++{
++++++++myStringArray[i]+=+null;
++++++++break;
++++}
}|code-block|syntax|javascript|3097654|或|3097655|myStringArray[indexOfStringToRemove]+=+null;|3097656|如果您想要一个动态调整大小的数组，其中对象被实际移除，并且相应地调整列表(数组)大小，请使用ArrayList|3097657|myArrayList.remove(stringToRemove);+|3097658|3097659|myArrayList.remove(indexOfStringToRemove);|3097660|在下面对OP对其问题和评论的编辑进行编辑|BOLD|3097661|String+r+=+myArrayList.get(rgenerator.nextInt(myArrayList.size()));|3097662|entityMap|0|LINK|mutability|MUTABLE|url|http://download.oracle.com/javase/6/docs/api/java/util/ArrayList.html^0|0|U|4|0|0|0|0|1A|9|0|0|0|0|0|I|2|0|0^^$0|@$1|2|3|4|5|6|7|1A|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|1B|8|@$D|1C|E|1D|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|1E|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|1F|8|@]|9|@]|A|$]]|$1|O|3|P|5|J|7|1G|8|@]|9|@]|A|$K|L]]|$1|Q|3|R|5|6|7|1H|8|@]|9|@$D|1I|E|1J|1|1K]]|A|$]]|$1|S|3|T|5|J|7|1L|8|@]|9|@]|A|$K|L]]|$1|U|3|N|5|6|7|1M|8|@]|9|@]|A|$]]|$1|V|3|W|5|J|7|1N|8|@]|9|@]|A|$K|L]]|$1|X|3|Y|5|6|7|1O|8|@$D|1P|E|1Q|F|Z]]|9|@]|A|$]]|$1|10|3|11|5|J|7|1R|8|@]|9|@]|A|$K|L]]|$1|12|3|-4|5|6|7|1S|8|@]|9|@]|A|$]]]|13|$14|$5|15|16|17|A|$18|19]]]]

Define "remove".

Arrays are fixed length and can not be resized once created. You can set an element to <code>null</code> to remove an object reference;

<pre><code>for (int i = 0; i &lt; myStringArray.length(); i++)
{
 if (myStringArray[i].equals(stringToRemove))
 {
 myStringArray[i] = null;
 break;
 }
}
</code></pre>

or

<pre><code>myStringArray[indexOfStringToRemove] = null;
</code></pre>

If you want a dynamically sized array where the object is actually removed and the list (array) size is adjusted accordingly, use an <a href="http://download.oracle.com/javase/6/docs/api/java/util/ArrayList.html">ArrayList&lt;String&gt;</a>

<pre><code>myArrayList.remove(stringToRemove); 
</code></pre>

or 

<pre><code>myArrayList.remove(indexOfStringToRemove);
</code></pre>

Edit in response to OP's edit to his question and comment below

<pre><code>String r = myArrayList.get(rgenerator.nextInt(myArrayList.size()));
</code></pre>

blocks|key|4995959|text|在on+step中是不可能的，或者您需要保留对数组的引用。如果您可以更改引用，这将有所帮助：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4995960|++++++String[]+n+=+new+String[]{"google","microsoft","apple"};
++++++final+List<String>+list+=++new+ArrayList<String>();
++++++Collections.addAll(list,+n);+
++++++list.remove("apple");
++++++n+=+list.toArray(new+String[list.size()]);|code-block|syntax|javascript|4995961|我不推荐以下方法，但如果您担心性能问题：|4995962|++++++String[]+n+=+new+String[]{"google","microsoft","apple"};
++++++final+String[]+n2+=+new+String[2];+
++++++System.arraycopy(n,+0,+n2,+0,+n2.length);
++++++for+(int+i+=+0,+j+=+0;+i+<+n.length;+i%2B%2B)
++++++{
++++++++if+(!n[i].equals("apple"))
++++++++{
++++++++++n2[j]+=+n[i];
++++++++++j%2B%2B;
++++++++}++++++
++++++}|4995963|我不推荐这样做，因为代码更难阅读和维护。|4995964|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

It is not possible in on step or you need to keep the reference to the array.
If you can change the reference this can help:

<pre><code> String[] n = new String[]{"google","microsoft","apple"};
 final List&lt;String&gt; list = new ArrayList&lt;String&gt;();
 Collections.addAll(list, n); 
 list.remove("apple");
 n = list.toArray(new String[list.size()]);
</code></pre>

I not recommend the following but if you worry about performance:

<pre><code> String[] n = new String[]{"google","microsoft","apple"};
 final String[] n2 = new String[2]; 
 System.arraycopy(n, 0, n2, 0, n2.length);
 for (int i = 0, j = 0; i &lt; n.length; i++)
 {
 if (!n[i].equals("apple"))
 {
 n2[j] = n[i];
 j++;
 } 
 }
</code></pre>

I not recommend it because the code is a lot more difficult to read and maintain.

blocks|key|3097709|text|import+java.util.*;

class+Array+{
++++public+static+void+main(String+args[])+{
++++++++ArrayList+al+=+new+ArrayList();
++++++++al.add("google");
++++++++al.add("microsoft");
++++++++al.add("apple");
++++++++System.out.println(al);
++++++++//i+only+remove+the+apple//
++++++++al.remove(2);
++++++++System.out.println(al);
++++}
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3097710|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import java.util.*;

class Array {
 public static void main(String args[]) {
 ArrayList al = new ArrayList();
 al.add("google");
 al.add("microsoft");
 al.add("apple");
 System.out.println(al);
 //i only remove the apple//
 al.remove(2);
 System.out.println(al);
 }
}
</code></pre>

I have an array like this:

<pre><code>String n[] = {"google","microsoft","apple"};
</code></pre>

What I want to do is to remove "apple". 

My problem is very basic,however,I searched the website and I found out that java doesn't really support the deleting feature from an array.I also heard to use Java Utils, because it's so simple to remove an item....I tried to find Java Utils on google, but almost all links are dead.

So finally...is there any way to remove a string from an array of string?

Even if I use an ArrayList I can't find a method to generate a random item in it! For ex: in a normal array I generate a string like this:

<pre><code>String r = myAL[rgenerator.nextInt(myAL.length)];
</code></pre>

In an arraylist it doesn't work....maybe you know a solution...

Remove a specific string from an array of string

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个这样的数组：String n[] = {"google","microsoft","apple"};我想做的是去掉"apple“这个词。我的问题很基本，然而，我搜索了网站，我发现java并不真正支持从数组中删除功能。我也听说过使用Java Utils，因为删除一个项目太简单了……我试着在google上查找Jav...

问从字符串数组中删除特定字符串
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