问题
如何在PHP中删除空的xml标记?
示例:
$value1 = "2";
$value2 = "4";
$value3 = "";
xml = '<parentnode>
<tag1> ' .$value1. '</tag1>
<tag2> ' .$value2. '</tag2>
<tag3> ' .$value3. '</tag3>
</parentnode>';XML结果:
<parentnode>
<tag1>2</tag1>
<tag2>4</tag2>
<tag3></tag3> // <- Empty tag
</parentnode>我想要的!
<parentnode>
<tag1>2</tag1>
<tag2>4</tag2>
</parentnode>不带"tag3“等空标记的XML
谢谢!
发布于 2011-12-22 19:38:47
可以结合使用XPath和predicate not(node())来选择没有子节点的所有元素。
<?php
$doc = new DOMDocument;
$doc->preserveWhiteSpace = false;
$doc->loadxml('<parentnode>
<tag1>2</tag1>
<tag2>4</tag2>
<tag3></tag3>
<tag2>4</tag2>
<tag3></tag3>
<tag2>4</tag2>
<tag3></tag3>
</parentnode>');
$xpath = new DOMXPath($doc);
foreach( $xpath->query('//*[not(node())]') as $node ) {
$node->parentNode->removeChild($node);
}
$doc->formatOutput = true;
echo $doc->savexml();打印
<?xml version="1.0"?>
<parentnode>
<tag1>2</tag1>
<tag2>4</tag2>
<tag2>4</tag2>
<tag2>4</tag2>
</parentnode>发布于 2014-02-01 07:38:21
这将以递归方式工作,并删除符合以下条件的节点:
// not(*) does not have children elements
// not(@*) does not have attributes
// text()[normalize-space()] nodes that include whitespace text
while (($node_list = $xpath->query('//*[not(*) and not(@*) and not(text()[normalize-space()])]')) && $node_list->length) {
foreach ($node_list as $node) {
$node->parentNode->removeChild($node);
}
}发布于 2011-12-22 19:32:35
$dom = new DOMDocument;
$dom->loadXML($xml);
$elements = $dom->getElementsByTagName('*');
foreach($elements as $element) {
if ( ! $element->hasChildNodes() OR $element->nodeValue == '') {
$element->parentNode->removeChild($element);
}
}
echo $dom->saveXML();CodePad。
https://stackoverflow.com/questions/8603237
复制相似问题